Explanation of the instr function
HelloI have been helped with a query and received the following code. The code does what I wanted to do, but I don't really understand how it works. I tried Googling, but examples are different in this one and do not contain the value > 0 or | (Which I guess makes reference to a column. Could someone please explain it to me.
SET Financial_Review = ( case when instr(Debt_Review||Judgement||Liquidation||under_admin,'Y') > 0 then 'Y' else 'N' end)
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Debt_Review||Judgement||Liquidation||under_admin
You concatenate 4 columns. then
instr(Debt_Review||Judgement||Liquidation||under_admin,'Y')
You check if the letter there exist in the concatenated string. INSTR returns the position of the character of research. So if the position is greater than 0 that means that the search string exists.
So eventually, if it exists, you define Y n else.
Tags: Database
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I need a little help with the INSTR function
Hello everyone,
im still new to pl sql and experienced an issue with the INSTR function. I need to analyze some values of a CLOB containing the xml code and use INSTR to determine the beginning and end of the value, I would like to analyze.
the data I need is in a <!-[CDATA [[Some Text]]]-> block. up to this point, I managed to take the start of the word, but I can't seem to capture the end of the CDATA block. I use this statement:
POS: = INSTR (TO_CHAR (input_clob) [,'] ', pos2 + 6, 1);
but it doesn't have the desired effect. [It seems to sort of go back to the length of the string, while the]-sign is actually in the xml file. my result would look to "Some Text]]--> < xmlxml >... < / xmlxml >...» ». [I tried to escape by writing ' \] "but if I do, the function returns zero and my parsed string is left blank.
Unfortunately I can't use regular expressions, because I work with oracle 9.2i. Anyone know what I'm doing wrong?
Thank you
Edited by: user8719779 the 25.08.2009 02:23with my_tab as (select '
'||chr(10)|| ' ' col1 from dual) -- end of mimicking your data; USE SQL below: select substr(col1, instr(col1, '', 1, 1) - instr(col1, 'Hi all'||chr(10)|| ' '||chr(10)|| ' '||chr(10)|| '
I have a querry as
Is simple index on column Col1. If we use the index will be used or full table scan will happen in this scenario?Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0 ;
Please give me explanatory answer because I have doubts
DhabasHello
You must use the index function if you want to avoid the full table scan. Check this box
SQL> create table tab1(col1 varchar(20)) 2 / Table created. SQL> insert into tab1 values ('XXAB') 2 / 1 row created. SQL> create index col1_idx on tab1(col1); Index created. SQL> explain plan for Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0; Explained. SQL> set autotrace on SQL> Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0; XXAB Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=5 Card=1 Bytes=12) 1 0 TABLE ACCESS (FULL) OF 'TAB1' (TABLE) (Cost=5 Card=1 Bytes =12) Statistics ---------------------------------------------------------- 4 recursive calls 0 db block gets 32 consistent gets 0 physical reads 0 redo size 234 bytes sent via SQL*Net to client 280 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed SQL> create index col1_idx2 on tab1(Instr(Col1,'XX')); Index created. SQL> Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0; XXAB Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=2 Card=1 Bytes=12) 1 0 TABLE ACCESS (BY INDEX ROWID) OF 'TAB1' (TABLE) (Cost=2 Ca rd=1 Bytes=12) 2 1 INDEX (RANGE SCAN) OF 'COL1_IDX2' (INDEX) (Cost=1 Card=1 ) Statistics ---------------------------------------------------------- 28 recursive calls 0 db block gets 22 consistent gets 0 physical reads 0 redo size 234 bytes sent via SQL*Net to client 280 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed SQL>
Thank you
AJ -
Need help with the INSTR function
I try to use SUBSTR and INSTR function to parse a variable without breaking to the top of the variable. As you can see that the problem is space, negotiating
How can I enter the number of characters in name only? It lists just to the right of the 1st blank_space.DECLARE blank_space NUMBER(2); full_name VARCHAR2(30) := 'Robert P. Simmons'); first_name VARCHAR2(30); last_name VARCHAR2(30); BEGIN blank_space := INSTR(full_name, ' '); first_name := SUBSTR(full_name, 1, (blank_space -1)); DBMS_OUTPUT.PUT_LINE( 'Your first name is ' || first_name); last_name := SUBSTR(full_name, (blank_space + 1), (LENGTH(full_name) - blank_space)); DBMS_OUTPUT.PUT_LINE( 'You have ' || LENGTH(last_name) || ' characters in your last name!'); END;
Thank youSQL> declare blank_space number (2); full_name varchar2 (30) := 'Robert P. Simmons'; first_name varchar2 (30); last_name varchar2 (30); begin blank_space := instr (full_name, ' '); first_name := substr (full_name, 1, (blank_space - 1)); dbms_output.put_line ('Your first name is ' || first_name); dbms_output.put_line ('You have ' || length (substr (full_name, instr (full_name, ' ', -1) + 1)) || ' characters in your last name!'); end; / Your first name is Robert You have 7 characters in your last name! PL/SQL procedure successfully completed.
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Problem with Textfield autocomplete-->; only use the INSTR function
Hello team dev,
I use the new "textfield autocomplete" item type APEX and you have a crazy problem with it.
I have a table with an index on the same column I want to search with AutoComplete field.
Index:
Select which is automatically generated by APEX 4:CREATE BITMAP INDEX TEST.GEO_DATA_IDX1 ON TEST.GEO_DATA (postcode) NOLOGGING TABLESPACE TS_INDEX;
The APEX 3, I used the addon of Tyler Muth with my own Select:SELECT a.* FROM ( SELECT DISTINCT postcode AS RV FROM TEST.GEO_DATA WHERE country_id = :P1_COUNTRY ORDER BY 1) a WHERE INSTR ("RV", :p$_search_string) > 0 AND ROWNUM <= :p$_max_rows; -- plan Plan SELECT STATEMENT ALL_ROWSCost: 4,308 Bytes: 45,31 Cardinality: 1,97 2 SORT UNIQUE Cost: 4,307 Bytes: 45,31 Cardinality: 1,97 1 TABLE ACCESS FULL TABLE #TABLE# Cost: 4,306 Bytes: 47,311 Cardinality: 2,057
Is there a chance to get my INDEX used by the new element of the APEX? I do not. But I still want to ask before I just rebuild. :)SELECT DISTINCT postcode AS DV, postcode AS RV FROM TEST.GEO_DATA WHERE country_id = L_COUNTRY AND postcode like l_search||'%' ORDER BY 1 -- Plan SELECT STATEMENT ALL_ROWSCost: 840 Bytes: 152,867 Cardinality: 13,897 8 SORT ORDER BY Cost: 840 Bytes: 152,867 Cardinality: 13,897 7 HASH UNIQUE Cost: 838 Bytes: 152,867 Cardinality: 13,897 6 VIEW VIEW index$_join$_001 Cost: 836 Bytes: 232,111 Cardinality: 21,101 5 HASH JOIN 2 BITMAP CONVERSION TO ROWIDS Cost: 31 Bytes: 232,111 Cardinality: 21,101 1 BITMAP INDEX RANGE SCAN INDEX (BITMAP) #INDEX# 4 BITMAP CONVERSION TO ROWIDS Cost: 45 Bytes: 232,111 Cardinality: 21,101 3 BITMAP INDEX SINGLE VALUE INDEX (BITMAP) #INDEX#
Best regards
TobiasHi Tobias,.
I guess that you are currently using "contains and case sensitivity ' to the attribute of"search ". Have you ever tried out "Exact and case sensitivity? Because that internally uses the LIKE operator as does your original query and the % is at the end, she must allow the use of an index. But it might still work, because ORDER BY can be run at a different time in your original example, but it's worth a try.
Concerning
Patrick
-----------
My Blog: http://www.inside-oracle-apex.com
APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
Twitter: http://www.twitter.com/patrickwolf -
The INSTR function in where clause
Hello
I need to check if part of the separate past comma is there in one of the values of table column, if its present, then I need to go looking for this file in the same table.
Example of
--------
Table1:
col1 col2
-----------
01 john
Raj 02
and I'm passing '02,04,06' as the value of parameter input and according to this value, I need to check in a table and get a record.
procedure p1 (v_string varchar2)
is
Select col1, col2
in a, b
FROM table1
where instr (v_string, - here I need to apply the logic
end;
output
------
Raj 02
Please help me with this logic
RDS,
Nagainstr(','||v_string||',',','||col1||',') > 0
Nicolas.
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Discoverer INSTR function does not have a hyphen in the ID Oppty
I need to identify the IDS that have a number that produces a hyphen. INSTR (opportunity ID,'-', 1, 1) calculation identifies the location of the hyphen for most of ID. However, it does not recognize the hyphen in some. Identifiers that have hyphens that are not recognized, I know that the hyphen is counted as a character because Discover include the hyphen when I use a calculation of LENGTH on the field service ID.
Example:
INSTR (field ID,'-', 1, 1) calculation for ID 3 - XXXXX1 = 2; but for ID 3 - XXXXX2 = 0.
Calculations of LENGTH (ID field) for the two ID = 8.
Anyone who has ever encountered this problem and found a resolution?
Any help would be greatly appreciated... Thank you!
Published by: user740605 on Sep 8, 2010 13:43
Published by: user740605 on Sep 8, 2010 13:45
Published by: user740605 on Sep 8, 2010 13:47
Published by: user740605 on Sep 8, 2010 13:47Hello
I suspect that the character is not hyphenated, but hyphenated "windows". If the text was cut and paste from a windows like word or excel application, then it will probably contain the hyphen of windows which is a different character.
You can use the lengthB function to check if there are 2-byte characters or use the dump function to watch the ascii characters in the field.
Rod West
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allocation of an array of 2d in labVIEW and move to the DLL function to obtain data
Hi all!
I searched a lot about this, but one cannot find any solution. Please find attached the vi that I try to get a unit of 32 channels data,
100000 samples per channel with 14-bit resolution. And please also find enclosed the header for my dll file. (in the header, it is the GetBuffers function).
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Because there is much more data in a single channel (million samples or more)
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/ * LabVIEW created typedef * /.
typedef struct {}
Int32 dimSizes [2];
Double elt [1];
} TD1;
typedef TD1 * TD1Hdl;I hope this helps.
Best regards:
Andrew Valko
NOR Hungary
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alternatives without using the regexp_replace function
SELECT
REGEXP_REPLACE (phone_number,
"([[: digit:]] {3})------." ([[: digit:]] {3}). ([[: digit:]] {4})',
"\2-\3 (\1)") "REGEXP_REPLACE.
Employees;
is there another without using the regexp_replace function...
Another way
(eliminating instr... function as your problem focuses on one length fixed)
WITH t AS (SELECT '112.345.6789' FROM DUAL str).
TT AS (SELECT REPLACE (str, '.') t str)
SELECT ' (')
|| SUBSTR (str, 1, 3)
|| ') '
|| SUBSTR (str, 4, 3)
|| '-'
|| SUBSTR (str, 7)
TT;
See you soon,.
Manik.
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How to use the NVL function to a parameter with comma delimited values
Gurus,
It is confusing to me. I am trying to use the NVL function, but the setting that I'm passing in my cursor contains multiple values with commas. The NVL function is confused when analyzing the values.
'Where' cursor clause...
and nvl (sn.c_attribute1,'x@#$%') in nvl (p_desig,'x@#$%'( )
translated parameter values...
and nvl (sn.c_attribute1,'x@#$%') in nvl ('SPRT''GOOD' 'BAD' 'x@#$%') -NVL does not parse the value correctly
Any idea on how to get NVL recognize 'x@#$%' , if p_desig is null?
Thank you
Scott
HI, Scott.
Whenever you have a problem, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) of all the tables involved, so that people who want to help you can recreate the problem and test their ideas.
Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum: https://forums.oracle.com/message/9362002#9362002
My best guess, based on what you posted bone is present, that your problem is discussed in the following:
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County, based on the soundex function
Hi all
I a bit confused with request asked of me.
the query is
indicate the account number of the last part of each word in the same row according to the soundex function
for example
the first line has set out four in the same line
Does it say I have divided the each statement and get soundex for the last part which is located in this example is------.ACD BCD AAA AFD BCF BDE AAC AFC BCF AAE
So the soundex only for AAA and AAE is same average I've update table b in the column of Gen by two and son on for others.AAA BCF AFC AAE
The result iscreate table a(id number(9), Gen_Value varchar2(200)); insert into a vlaues(1, 'ACD BCD AAA, AFD BCF , BDE AAC AFC,BCF AAE'); insert into a vlaues(2, 'AVF BCD, BBA BBG BCEV, GACD MNF BCV'); insert into a vlaues(3, 'AFC ABC, BBG HUH ABCE, JHU KK MNK'); create table b(id number(9), Gen_Value varchar2(200), id number(9)); insert into b values( 'AAA', '0',1); insert into b values ('BCEV ','0',2); insert into b values ('AFC','0',1); insert into b values ('BCD','0',2); insert into b values ('MNK','0',3); insert into b values ('ABCE','0',3);
see you soonGen count id AAA 2 1 BCEV 2 2 AFC 1 1 BCD 1 2 MNK 1 3 ABCE 2 3
Benjamin
Published by: 973907 on November 29, 2012 12:54 AM
Published by: 973907 on November 29, 2012 12:55973907 wrote:
We choose one of them. 'AAA' or AAE. or the word that has long term.No prob
with data as ( select id ,gen_value||',' gen_value from a ) ,r (id, gen_value, l) as ( select id ,substr(gen_value, instr(gen_value, ',') + 1) ,substr( trim(substr(gen_value,1, instr(gen_value, ',') - 1)) ,instr(trim(substr(gen_value,1, instr(gen_value, ',') - 1)),' ',-1) ) from data union all select id ,substr(gen_value, instr(gen_value, ',') + 1) ,substr( trim(substr(gen_value,1, instr(gen_value, ',') - 1)) ,instr(trim(substr(gen_value,1, instr(gen_value, ',') - 1)),' ',-1) ) from r where length(gen_value) > 0 ) select soundex(l) ,count(*) cnt ,max(l) keep ( dense_rank last order by length(l), l desc nulls first) v from r group by soundex(l) order by 1 SOUNDEX(L) CNT V A000 2 AAA A120 3 ABCE B210 3 BCEV B230 1 BCD M200 1 MNK
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help in the application without using the pivot function
Hi gurus,
Can you please help write the query without using the PIVOT function.
Thanks in advance!...WITH indata AS (SELECT 1 sn, '123:456,789,323:456,213,344,345:5454' x from dual UNION ALL SELECT 2, 'abcd:fgrfr,rfrf,rfred,tg:tg,tg:ophhh,op,vdfgbh:poijn' x from dual), instr AS (SELECT a.SN, rownum RN, B.column_value || CASE WHEN B.column_value NOT LIKE '%:%' THEN ':' END column_value FROM indata a, TABLE(CAST(multiset (SELECT trim(SUBSTR(x, (CASE LEVEL WHEN 1 THEN 1 ELSE instr(x, ',', 1, LEVEL - 1) + 1 END), (CASE instr(x, ',', 1, LEVEL) WHEN 0 then 4000 ELSE instr(x, ',', 1, LEVEL) - 1 - (CASE LEVEL WHEN 1 THEN 0 ELSE instr(x, ',', 1, level - 1) END) END))) FROM dual CONNECT BY level <= LENGTH(x) - LENGTH(REPLACE(x, ',', '')) + 1) AS sys.odcivarchar2list)) b) SELECT col1_val2, col1_val1, col2_val2, col2_val1, systimestamp FROM (select SN, ROW_NUMBER() over(partition by SN order by RN) RN, SUBSTR(column_value, INSTR(column_value, ':') + 1) VAL1, substr(column_value, 1, instr(column_value, ':') - 1) val2 FROM instr ) PIVOT(MAX(VAL1) VAL1, MAX(VAL2) VAL2 FOR SN IN(1 as col1,2 as col2));
Any help would be appreciated.user590978 wrote:
Can you please help write the query without using the PIVOT function.
with indata as ( select 1 sn,'123:456,789,323:456,213,344,345:5454' x from dual union all select 2, 'abcd:fgrfr,rfrf,rfred,tg:tg,tg:ophhh,op,vdfgbh:poijn' x from dual ), t1 as ( select x from indata where sn = 1 ), t2 as ( select x from indata where sn = 2 ), t3 as ( select level lvl, substr( x, instr(',' || x,',',1,level), instr(x || ',',',',1,level) - instr(',' || x,',',1,level) ) col1 from t1 connect by level <= length(x) - length(translate(x,'A,','A')) + 1 ), t4 as ( select level lvl, substr( x, instr(',' || x,',',1,level), instr(x || ',',',',1,level) - instr(',' || x,',',1,level) ) col2 from t2 connect by level <= length(x) - length(translate(x,'A,','A')) + 1 ), t5 as ( select lvl, substr(col1,1,instr(col1 || ':',':') - 1) col1_val1, substr(col1,instr(col1 || ':',':') + 1) col1_val2 from t3 ), t6 as ( select lvl, substr(col2,1,instr(col2 || ':',':') - 1) col2_val1, substr(col2,instr(col2 || ':',':') + 1) col2_val2 from t4 ) select col1_val1, col1_val2, col2_val1, col2_val2, systimestamp from t5 full join t6 on ( t6.lvl = t5.lvl ) order by coalesce(t5.lvl,t6.lvl) / COL1_VAL1 COL1_VAL2 COL2_VAL1 COL2_VAL2 SYSTIMESTAMP ---------- ---------- ---------- ---------- ------------------------------------- 123 456 abcd fgrfr 23-OCT-12 11.50.12.015000 AM -04:00 789 rfrf 23-OCT-12 11.50.12.015000 AM -04:00 323 456 rfred 23-OCT-12 11.50.12.015000 AM -04:00 213 tg tg 23-OCT-12 11.50.12.015000 AM -04:00 344 tg ophhh 23-OCT-12 11.50.12.015000 AM -04:00 345 5454 op 23-OCT-12 11.50.12.015000 AM -04:00 vdfgbh poijn 23-OCT-12 11.50.12.015000 AM -04:00 7 rows selected. SQL>
SY.
-
101: explanation of the tools in the Panel?
I'm going through the tutorials but seem to Miss where I can find an explanation of the tool panels and their functions. The tutorials do not necessarily explain it (sometimes they do).
Hello
Very well! So let's start with gold playhead in the timeline panel. This is different from the PIN tool, because that's literally what you can use to define where you want keyframes to be manually in your timeline. You can also use this to navigate backwards in the timeline by clicking on the read head gold and drag through the timeline. This is also known as rub. The best way to think of the read head is to be considered as a "bookmark" in your timeline.
The Pin tool is a great little tool that is unique on board animate. Significantly, it improves your productivity while animating and eliminates the need from keyframe to the hand.
With the selected PIN tool, you will notice a blue pin in your timeline. You can click and drag this PIN back and forth to set a literal "PIN" in your timeline. When you do so, you will notice that your head stays in place. It is because what makes the tool of corner is literally "remembers" where your head is and then act as a second head for you so that you can keyframe with ease.
Thus, for example, if you have a rectangle with an opacity of 100% at 0 seconds. If you click on the tool spindle and slide forward in the timeline to 1 second and then change the opacity to 0%, the Pin will be keyframe for you opacity to 0 seconds and 1 second, which makes the task of animating this transition easier. The rectangle fade from 0% to 100% opacity over a second.
Another point to remember about the PIN tool, it's you will notice little rafters in the blue bar that extends from the time you dragged your corner tool. The rafters help explain where your animation is transient. They stress also everywhere where is your head. You can move the playback cursor in front of the PIN tool to have your key frame be the change of departure.
As with our example before, if you have your rectangle to 100% opacity and you have selected the tool pin so you move the playback cursor forward. You can change the opacity to 0% and the rectangle now fade from 100% to 0% more than one second.
I'll explain the image auto key and automatic transition in a second post tools. I hope this helps explain the tool spindle and the read head better!
-
Hi gurus,
I have the data as follows:
data
-----------------------------------------------------------------------------------------------------------------------
' BIDIE01H / TXT:ZUNE = HA011, CellIndex = 144 /CAI:452 - 01-32201-47001 / CAI:45201F7dc9b79a'
' BIDIE01H / TXT:ZUNE = HA111, CellIndex = 124 /CAI:452 - 01-32201-471 / CAI:45201F7dc9b79b'
and I'm writing a SQL results:
CAI
---------
452 01-32201-47001
452 01-32201-471
Any idea to do? I tried around with SUBSTR and INSTR functions but not yet sucessed.
Thank you
Alexsomething like:
with my_tab as (select 'BIDIE01H/TXT:ZUNE=HA011, CellIndex=144 /CAI:452-01-32201-47001/CAI:45201F7dc9b79a' col1 from dual union all select 'BIDIE01H/TXT:ZUNE=HA111, CellIndex=124 /CAI:452-01-32201-471/CAI:45201F7dc9b79b' col1 from dual) -- end of mimicking your data: USE SQL below: select substr(col1, instr(col1, '/CAI:', 1) + 5, instr(col1, '/CAI:', 1, 2) - instr(col1, '/CAI:', 1) - 5 ) CAI from my_tab CAI -------------------------------------------------------------------------------- 452-01-32201-47001 452-01-32201-471
-
Use the Trim function in this case?
Oracle 10.2 g
I have the following code (thanks to michaels 2):
Desired output:SQL> with t as ( select to_date('11/14/2003 7:39:00 PM','MM/DD/RRRR hh:mi:ss pm') time, 11122 home_team_id,null away_team_id,null home_team_name, 'parks' away_team_name,'Steve' offensive_player_moniker, 'Smith' offensive_player_last_name from dual union all select to_date('11/14/2003 7:32:00 PM','MM/DD/RRRR hh:mi:ss pm'), null, 24555, null, 'bombers', 'Chris', 'Carter' from dual union all select to_date('12/14/2008 1:35:00 PM','MM/DD/RRRR hh:mi:ss pm'), null, 33211, null, 'carts', 'Marty', 'Booker' from dual union all select to_date('12/14/2008 1:30:00 PM','MM/DD/RRRR hh:mi:ss pm'), 15555, null, null, 'sharks', 'Bob', 'Sanders' from dual union all select to_date('12/14/2008 1:38:00 PM','MM/DD/RRRR hh:mi:ss pm'), 15555, null, null, 'sharks', 'Marvin','Harrison' from dual ) select away_team_name || ': ' || xmlagg(xmlelement(e, offensive_player_moniker || ' ' || offensive_player_last_name || ' (' || to_char(time,'hh:mi') || '), ')).extract('//text()') x from t group by away_team_name / X -------------------------------------------------------------------------------- bombers: Chris Carter (07:32), carts: Marty Booker (01:35), parks: Steve Smith (07:39), sharks: Bob Sanders (01:30), Marvin Harrison (01:38),
How can I go about removing the unnecessary extra at the end when coma. I have "guess the TRIM function could do with an if-else clause, well I don't know what would go in the if-else clausebombers: Chris Carter (07:32) carts: Marty Booker (01:35) parks: Steve Smith (07:39) sharks: Bob Sanders (01:30), Marvin Harrison (01:38)
Hello
Select substr(x, 1, instr(x, ',', -1) - 1) from (select away_team_name || ': ' || xmlagg(xmlelement(e, offensive_player_moniker || ' ' || offensive_player_last_name || ' (' || to_char(time, 'hh:mi') || '), ')) .extract('//text()') x from t group by away_team_name)
Kind regards
Christian Balz
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