Extraction of the year

Similar Questions

• How can I extract the year of a variable?

  Hi all

  I want to extract the year of a parameter.

  I tried the following, I make mistakes.

  When I run the code below,

  SELECT TO_CHAR(:X_PRM_YR_END_DT,'YYYY') FROM dual;

  I got the following error.

  ORA-number 01722:invalid

  When I run the code below,

  SELECT TO_DATE(:X_PRM_YR_END_DT,'YYYY') FROM dual;

  SELECT to_char (TO_DATE (: X_PRM_YR_END_DT, "YYYY")) FROM dual;

  I got the following error.

  ORA-01830: date format end before you convert all of the input string

  When I run the code below,

  SELECT extract (YEAR FROM: X_PRM_YR_END_DT) FROM dual;

  SELECT extract (YEAR FROM 01/11/2013) FROM dual;

  I got the following error.

  ORA-30076: invalid field extracted from source

  How can I extract the year of a variable?

  Help me please

  Oracle9i Enterprise Edition Release 9.2.0.1.0 - Production.

  Try this,

   

  SELECT TO_CHAR (to_date (' 01/01/1980 ',' dd/mm/yyyy'), 'YYYY') FROM dual;

• extracting remaning months of the year during the current month

  Hello
  
  I like allows you to retrieve the other months of the year from the current date.
  Can I do this?
  
  For example, it is today, July 23, 2012.
  Then, I would like to have:
  
  August
  September
  October
  November
  December
  
  Thank you
  Diana

  Hi, Diana,.

  Here's one way:

  SELECT     TO_CHAR ( ADD_MONTHS (SYSDATE, LEVEL)
            , 'Month'
            )    AS month_name
  FROM     dual
  CONNECT BY     LEVEL     <= 12 - EXTRACT (MONTH FROM SYSDATE)
  ;
  

  What output would you want in December?

• How to extract the first day of the year quarter

  Hello
  
  How can I write a query to extract the first day in a neighborhood of declaration
  
  for example: -.
  
  Q1 starts from April 1 to June 30, second quarter starts from July 1 to September 30, third quarter starts from 1 October to 31 December and the fourth quarter begins from January 1 to March 31.
  
  How can I recover then the first day of these quarters, regardless of the year. The year can be any year.

  Hello

  don't know exactly what you want, but if you want the first day of a quarter for any given date and then

  select trunc(sysdate,'Q') from dual;
  

  Sysdate obviously could be a valid date.

  André

• Extract data based on the year and month

  My clients have taken a field TimeStamp DB Oracle and downloaded the access in a TEXT field format.
  Samples: 20060401001348CS
  
  Everything I'm doing is extracted from the data based on the year and the month. I equal to 200604 *, 200604%. Have also tried to use AS.
  Nothing works. It may just be that dificult. Help, please. Thank you

  Mike

  I'm SO sorry. I have 35 years of Experinece in this area and I have my data (assuming) was all a 200604 date and he was not. The query did work. I'll have more questions and that you do not want to loose credability with this site. Again, I am sorry. Sincere to help thanks.
  Ron

• extract the week of the year

  Hello
  
  How to extract of the week from the date in the obiee11g functions
  
  
  Thank you

  Syntax: WEEK_OF_YEAR ("calendar". "Date") "

  for week:WEEK_OF_YEAR (current_date) courses

  Kind regards
  Disney

• Thunderbird has suddenly charge only 200 emails on behalf of yahoo of the year 2011 and nothing else. What's wrong? -Due to problems with Yahoo.

  I use Thunderbird to access 3 e-mail accounts. A few days before, all the emails of one of these missing accounts and now Thunderbird does not charge that 200 emails from this account of the year 2011. News, incoming mail does not appear, and I can't know how to extract or import any emails which are newer than 2011.

  What is your email provider?

• Suggest the Sql query to get the years, months, days of the two dates.

  Hi all

  SELECT TO_DATE('06-02-2014','DD-MM-YYYY') - TO_DATE('01-04-1998','DD-MM-YYYY') SERVICE_DAYS OF THE DOUBLE

  5790 SERVICE_DAYS

  POWER REQUIRED:
  YEARS MONTHS DAYS
  15 10 5

  OUTPUT DISPLAY:

  Select
  Floor(5790/ 365.25),
  Floor (mod (5790,365.25) / (365.25 / 12)),.
  ceil (mod(5790,365.25 / 12))
  Double;

  YEARS MONTHS DAYS
  15 10 7 - TWO DAYS MORE

  
  How they calculate manually is as follows:

  2014 02-06
  1998-04-01
  ---------------
  05 - days
  
  2014 02-06
  1998-04-01
  + 12
  ---------------
  10 month 02 is lower than 04, so we borrow 12 months of TI (2014) years will be (2013)
  
  2014 02-06
  1998-04-01
  -(1).
  ---------------
  15. for the years since we-1

  Kind regards

  Afzal.

  OK... so try not not to multiply the reminder to add_months with 30 but to solve the 'day-thing' in a different way...

  first step (data) is only my implementation testdata.

  WITH DATA AS (SELECT TO_DATE('02-03-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('07-04-2008','DD-MM-YYYY') AS dayfrom

  OF the double

  UNION ALL

  SELECT TO_DATE('12-04-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('11-05-1994','DD-MM-YYYY') AS dayfrom

  OF the double

  UNION ALL

  SELECT TO_DATE('06-02-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('01-04-1998','DD-MM-YYYY') AS dayfrom

  OF the double

  )

  calc AS (SELECT months_between (dayto, dayfrom) SERVICE_DAYS

  Degnide

  dayfrom

  DATA)

  SELECT Degnide

  dayfrom

  floor(service_days/12) IN years

  floor (mod(service_days,12)) AS month

  , BUSINESS sign (EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom))

  WHEN THEN-1 EXTRACT (DAY FROM Degnide) + 30 - EXTRACT (DAY OF THE dayfrom)

  WHEN 0 then 0

  WHEN 1 THEN EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom)

  0 OTHERWISE

  end as days

  CALC

  HTH

• With the help of SQL, need to display the previous year, current year and the year next to single variable

  Hi all

  We have an obligation to state the previous year, current year and values of the year next as a LOV in the ADF page.

  This is the query that retrieves the previous year, current year and next year. But the result of this query displays values in 3 columns:

  Select (Extract(year from sysdate)-1), extract (year sysdate), (extract (year sysdate) + 1) twice;

  Output:

  2012 2013 2014

  
  

  But I want to display them in a single with 3 rows as column:

  2012

  2013

  2014
  

  
  

  Please your ideas.

  or in the same way

  SELECT EXTRACT (YEAR FROM ADD_MONTHS (SYSDATE, 12 *(LEVEL-2)))

  OF the double

  connect by level<>

• Summary of the sum of the year or Analytics

  I would like to find a way to summarize some data and do calculations without Hardcoding. Trying to add up the numbers by year and then show the numbers for 4 years and 6 years without Hardcoding if possible. 4 years would be calculated by adding 390 to the cohortterm (390 + 200540 = 200930) 6 years would be calculated by adding the cohortterm (200540 + 590 = 201130) 590.
  
  The last 2 passes, that I haven't done yet would be a percentage based on Gradyr4 divided by the staff and the other for Gradyr6 divided by membership. If the WPS is too complicated, I can copy the results to excel for this part. Eventually, I'll have to further break down charges according to sex and the membership ethnic, but if all goes well, I can understand it once I know the syntax to make the number.
  
  BANNER
  Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production
  
  Example of output based on the query I've built so far using sum and hard coding for one year only. Actual results would show account and not from 0 in the lines of the year displayed below:
  

  COHORTTERM     HEADCOUNT     GRADYR4     GRADYR6     PCT4Yr  PCT6Yr
  200340          0          0     0
  200440          0          0     0
  200540          600          403     539     (403/600)
  200640          0          0     0
  200740          0          0     0

  SQL

  select cohortterm, 
           sum(case when cohortterm = '200540' then 1 else 0 end) as headcount,
           sum(
                  CASE WHEN cohortterm = '200540' and gradtermban < ''200930' then 1 else 0 end
                  ) as gradyr4,
                  
           sum(
                  CASE WHEN cohortterm = '200540' and gradtermban < '201130' then 1 else 0 end
                  ) as gradyr6
           null as pct4yr, null as pct6yr       
                 
  from cohorts
  where cohortterm between '200340' and '201240'
  and substr(ftpt,1,1) = 'F'
  group by cohortterm
  order by 1

  Based on your code example, here's a guess at what you want. You just need to extract the part of the year, add 4 or 6, then replace with the correct value for the period. Put two bits of information in the same column is also against the theory of database "normal form".

  DROP TABLE T;
  CREATE TABLE T(COHORTTERM VARCHAR2(6), GRADTERMBAN VARCHAR2(6));
  INSERT ALL
  into t values('200304', '200620')
  INTO T VALUES('200304', '200720')
  INTO T VALUES('200304', '200820')
  INTO T VALUES('200304', '200920')
  INTO T VALUES('200404', '200620')
  INTO T VALUES('200404', '200720')
  INTO T VALUES('200404', '200820')
  INTO T VALUES('200404', '200920')
  SELECT NULL FROM DUAL;
  
  SELECT
  COUNT(*) CNT,
  SUM(CASE WHEN GRADTERMBAN < TO_NUMBER(SUBSTR(COHORTTERM,1,4))+4||'03' THEN 1 END) YEAR4,
  sum(case when gradtermban < TO_NUMBER(SUBSTR(COHORTTERM,1,4))+6||'03' then 1 end) year6
  FROM T
  group by cohortterm;
  
         CNT      YEAR4      YEAR6
  ---------- ---------- ----------
           4          2          4
           4          1          3
  

• Displays the quarter of the year as a select list

  Hi all
  
  I need to display the quarter of the current year in the selection list.
  for example, the year is 2012
  I want Jan to March 2012, April-June 2012, 2012 July-September, October-December 2012 in the selection list.
  
  
  Thanks in advance
  
  Kind regards
  Jitendra

  Hi Jitendra,

  You can do it like this:

    select 'Jan-Mar '||extract(year from sysdate) d, 1 r from dual
    union all
    select 'Apr-Jun '||extract(year from sysdate) d, 2 r from dual
    union all
    select 'July-Sep '||extract(year from sysdate) d, 3 r from dual
    union all
    select 'Oct-Dec '||extract(year from sysdate) d, 4 r from dual
  

  BR,
  Marko Goricki

• 5 digit unique random number based on the year

  Hello
  I need 5 digit unique random number based on the year. If the new year then duplicate random number allowed.
  Thank you

  If only 5-digit numbers are needed you can extract some transformation injective (http://en.wikipedia.org/wiki/Injective_function) and you could easily check for uniqueness:
  substr (to_char (ln (sequence_value)), 10, 5)
  substr (to_char (exp(1 / sequence_value)), 20, 5)
  ...

  Concerning

  Etbin

• Can extend us the years of no.of to an existing application.

  Peer Hai,
  
  (1) I use Hyperion11.1.1.3 can extend us the years of no.of to an existing application.
  
  (2) I know use the Standard calendar, but how can we use custom calendar and the calendar is set manually, what are their purpose.
  
  How can I create a periodic weekly application. I'm new to HFM can someone explain to me.

  Sorry, let me clarify start menu and file locations for you.

  On the Windows computer with HFM App Server installed:

  Start--> all programs--> Oracle EPM system--> financial management--> Utilities--> year upgrade

  The location of the file should be:

  \EPMSystem11R1\products\FinancialManagement\Utilities\FMChangeNumberOfYearsForApp.exe (or FMChangeNumberOfYearsForApp_x64.exe)

  example: C:\Oracle\Middleware\EPMSystem11R1\products\FinancialManagement\Utilities\FMChangeNumberOfYearsForApp_x64.exe

  If she is not there, maybe the version your have does not include it again? (I have 11.1.2.1) If she is not there, you can:

  a.) log in to the oracle support (support.oracle.com), then find the item of data by another user in this thread
  (b) download the components for HFM App Server to a version that has the utility (i.e. 11.1.2.1) and extract compressed files. [Probably not recommended unless you are comfortable dealing with files from archive, etc.]

• How to make a difference in the years of sysdate

  Hi all
  
  I want to display the years 2005 to sysdate. I tried this, but it gives the same year SYSDATEs 6 times.
  
  SELECT EXTRACT (YEAR SYSDATE + LEVEL-1) FROM DUAL CONNECT BY LEVEL < TRUNC (MONTHS_BETWEEN (SYSDATE, TO_DATE('2005','YYYY')) / 12)
  
  Thanks in advance,
  PAL

  PAL,

  hope below allows

   select extract(year from sysdate) - level +1 from dual connect by level <= ( extract(year from sysdate) - 2005 + 1) ;
  

  Kind regards
  Vijay.

• How to get only the year of a date?

  I try to shoot only the year of a date and does not know how this can be done. I tried the SUBSTR function but its does not not how I think. What I want to do, it is write a condition indicating the year of birth of point = current year minus 23, I have a calc than the figures of the age of the difference in the date of birth and the current year, but I'd really like to just write a condition based just a years. Is this possible?

  Hello
  SUBSTR only works on a string. To extract parts of a date, you must use the TO_CHAR command.

  For the year, you would use this: TO_CHAR (the_date, 'YYYY')

  To_char takes 2 switches, the date to be handled and the part to be extracted, with the portion between apostrophes.

  Once you get used to manipulate dates as this other common areas are: DD - extracts the day of the month, MY snippet code to 3 characters for the month.

  For example, you can use this: TO_CHAR(sysdate,'DD-MON-YYYY') and it converts the current date, June 7, 2012 to June 7, 2012

  Hope this helps
  Best wishes
  Michael