Final cost

Similar Questions

• What is the total final cost for the composition of the creative cloud for students? (

  Because, it is said that the amount I'm paying per year

  but he didn't tell me how many years I'll pay this for

  I live in Korea, so it is said that my payment is 227 200 per year

  There is no final total cost. It's software subscription.

  If you want to use the software, you keep paying your monthly fees.

  When you stop paying, the software stops working.

• Caveat "the formula uses a Boolean value instead of a number" would dismiss

  Hello!

  I do a "Calculator" to get estimates of price for the projects, according to which processes the customer wants.

  Rates for each process are added in another table, and I use the list of control buttons to enable or disable the various processes.

  Here is an example of a formula:

  

  D3 determines if the part of the project modeling is performed, so the price will be or will not be calculated.

  If D3 is true, the result is multiplied by 1, give me a positive amount. If false, the result will be multiplied by 0, 0, so nothing to add to the final cost he send me some.

  Same for B4 in the same formula.

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  Everything works fine, but I got those blue triangles warning me of "the formula uses a Boolean value instead of the number". That's fine with me, I like the use of the Boolean types, and they make my formulas work well in my calculator. How can I reject the blue triangles?

  

  They are a little annoying. And they do not really correspond with the general style of my calculator.

  I saw someone talking other types of formulas, with SEARCH and yews, but who is really complicated and I don't know how to do... Especially for a simple calculator

  Is there a way to simply do not display warnings?

  Using the version 3.6.2 on a MacBook Pro, OSX El Capitan 10.11.5

  Thank you!

  Hi Sinshassan,

  I don't know a way to escape your blue flags except to make a formula which is consistent with the expected numbers. It is not difficult.

  

  My formula D2 = yew (AND(D1,B2), C2, 0)

  The IF statement tests the two D1 AND B2. If they are true, then it indicates the value of C2 your carbon Modeling::High Poly #1, if one or both are false (unchecked) then 0 is displayed.

  Give it a try.

  Quinn

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• Deployment device 42xx Cisco IDS network taps

  Hi all

  Someone at - he experiences of deployment of IDS 42xx (4235 and 4215) appliances with network taps (e.g. Finisar UTP IT Tap/1)? I have several of the device IDS deployed a few months back using the taps of Finisar, and thought that it worked fine, until I discovered that I have am capture only one side of the circulation, due to the nature of the taps! It seems that I need to put in another card network on the device IDS (a Cisco 4235), but is - it possible? Is there a way I can turn the power of 4235 on channel binding or Etherchannel?

  The last option, I think if the ideas above are not possible is to put in another switch and reflect the two ports from the tap water, but that doesn't look good for the final cost...

  Suggestions are most welcomed!

  Thank you

  Kian Wei

  Monitoring network taps with a Cisco IDS device is not officially supported by Cisco.

  That said, howewever, several customers have successfully deployed with taps.

  Faucets, as you've seen have 2 outputs.

  If tap is placed on the connection between computers A and B, one of the outputs will be for traffic from A to B, and the other will be for traffic from B to A.

  To analyze the tap water, the sensor will need to see the two outputs.

  You could do this by connecting the taps to a switch and then extending over 2 ports to the IDS sensor monitoring port.

  Or you may be able to use a second interface on the sensor itself.

  The IDS-4235 4250 IDS and IDS-4215 are able to be upgraded with a 4 ports 10/100 card, for a total of 5 ports to sniff.

  If the connection you type is a 10Mb or 100 MB connection, then purchase 4 port 10/100 for the sensor and the 2 tap on 2 of the ports of the NETWORK adapter card.

  NOTE: The sensor combine incoming packets on all interfaces and treat them as if they are part of the same network.

  You just need to place all interfaces in 'Group 0' and select 'non-stop' each sniffing interface.

  Here is the part number for the 4 ports 10/100 cards:

  ID-4FE-INT =

  Refer to the installation guide for more information on how to install the card and to configure the sensor:

  http://www.Cisco.com/univercd/CC/TD/doc/product/iaabu/csids/csids10/hwguide/index.htm

  Now if you type is a 1 Gig copper or fiber optic connection then you will need to buy a switch to combine 2 outputs from the taps and extend towards the sensor sniffing port.

  Cisco currently offers no additional copper Gig cards.

  Cisco offers a map of fiber unique Gig for the IDS 4250 SX port but can't stand not place these cards in the sensor 2.

  Cisco also offers a dual port fiber Gig, known as the XL card. The XL card has hardware acceleration for the monitoring of the faster speeds. However, the XL card does not currently work with taps.

  So if followed by a 10/100 connection then try the 4 ports 10/100 card, but if touching a Gig connection, then you will need a switch to aggregate outputs 2.

  What some users have also done is to use the switch and do not worry with the faucet.

  They connect computer A to machine B to the switch and the switch. Then cover the traffic to the port of the sensor.

• Calc script - question of averages

  Hello everyone,

  I have the following calc to calculate the average of the previous three months and put this value in a period of "Beg Balance".

  DIFFICULTY (/ * SUN: scenario * / 'FcstDev' / * SUN: Version * / 'Final', 'Cost center', 'BegBalance', and fcstYear1, "Chg")

  "810000")
  IF ("Calc Driver"-> "NoView"-> "no Center cost' is 3)
  '810000' = (@PRIORS (SKIPNONE, "810000"-> & fcstperstart, 2") + @PRIORS (SKIPNONE,"810000-> & fcstperstart, 3") + @PRIORS (SKIPNONE," 810000 "-> & fcstperstart, 1")) / 3;
  ENDIF ;)

  ENDFIX

  / * & fcstperstart = Jul * /.

  / * Calc Driver ID 3 = 3 MB Avg * /.

  I wrote this calc this way then I could limit the number of variables that I would need to put in place even if I know that the following would work too:

  '810000' =@AVGRANGE (SKIPNONE, "810000"->"law"->"Final",@XRANGE (& Fcst3Range))

  / * & fcst3range = 'April', 'June ' * /.

  I'm very well so be it for the "3 mo avg" but I am also the creation of these "6 mo avg" and «12 MB avg»  I was curious to know if anyone had any advice/suggestions on how they would accomplish that.

  Thanks in advance,

  Bret

  Well, I found the solution, apparently in typing this out in a help discussion:

  DIFFICULTY (/ * SUN: scenario * / 'FcstDev' / * SUN: Version * / 'Final', '033', & fcstYear1, "Chg")
  / * STARTCOMPONENT: FORMULA * /.

  "810000")
  IF (@ISMBR (& fcstperstart) AND ('Calc Driver "->" NoView'-> 'No cost center'-> 'BegBalance' == 3))
  "810000'-> 'begbalance' = @AVGRANGE (SKIPNONE,"810000",@CURRMBRRANGE (period, LEV, 0, -3, -1));

  ENDIF ;)
  / * ENDCOMPONENT * /.
  ENDFIX

  Bret

• Parallel DML may be downgraded to the DML series?

  Oracle Database Enterprise Edition 11.2.0.3.0

  When you run a parallel query (e.g. SELECT * FROM parallel_table WHERE a <?), the optimizer may choose a parallel or series, the selectivity of the predicate function plan and availability different access roads - usually a scan interval series index for highly selective queries (a small number of return lines), and a parallel table full scan for less selective queries (returning a large number of lines).

  However, with parallel DML enabled, no such optimization seems to happen. There may be a very effective for a query as series plan "DELETE FROM parallel_table WHERE a <? ', but once parallel DML is activated, the optimizer based on CSSTidy always seems to choose a parallel plan.

  Is there a way to allow the optimizer to choose between series and parallel DML according to predicates in the query? I wish I could enable parallel DML, but knowing that, in the case of a very selective, query optimizer will not parallel DML use but will use a series DML.

  Note that I'm allowing to the DML, not no force in parallel it (although it seems more to do with the fact that a table series is considered parallel, without having to refer to the query).

  Here is an example of this behavior, deleted 18 m rows in a table of rows of 300 m:

  First, the cost of a DML series operation is 59,000, using an index to access the lines:

  COMMIT;

  ALTER SESSION DISABLE PARALLEL DML.

  DELETE

  OF parallel_table

  WHERE the DATETIME_a < sysdate - 650;

  ---------------------------------------------------------------------------------------------

  | ID | Operation | Name                    | Lines | Bytes | Cost (% CPU). Time |

  ---------------------------------------------------------------------------------------------

  |   0 | DELETE STATEMENT.                         |    18 M |  2037M | 58723 (1) | 00:11:45 |

  |   1.  REMOVE | PARALLEL_TABLE |       |       |            |          |

  |*  2 |   INDEX RANGE SCAN | IDX_PT_DATETIME_A |    18 M |  2037M | 58723 (1) | 00:11:45 |

  ---------------------------------------------------------------------------------------------

  Now, by allowing parallel DML, the optimizer chooses a parallel full table much more expensive for the same request, cost 926 000 scan. Why he won't come back in terms of the series?

  COMMIT;

  ALTER SESSION ENABLE PARALLEL DML.

  DELETE

  OF parallel_table

  WHERE the DATETIME_a < sysdate - 650;

  ----------------------------------------------------------------------------------------------------------------------------

  | ID | Operation | Name               | Lines | Bytes | Cost (% CPU). Time |    TQ | IN-OUT | PQ Distrib.

  ----------------------------------------------------------------------------------------------------------------------------

  |   0 | DELETE STATEMENT.                    |    18 M |  2037M |   926K (1) | 03:05:22 |        |      |            |

  |   1.  COORDINATOR OF PX |                    |       |       |            |          |        |      |            |

  |   2.   PX SEND QC (RANDOM). : TQ10001 |    18 M |  2037M |   926K (1) | 03:05:22 |  Q1, 01 | P > S | QC (RAND) |

  |   3.    INDEX MAINTENANCE | PARALLEL_TABLE |       |       |            |          |  Q1, 01 | SVCP |            |

  |   4.     RECEIVE PX |                    |    18 M |  2037M |   926K (1) | 03:05:22 |  Q1, 01 | SVCP |            |

  |   5.      RANGE OF SEND PX | : TQ10000 |    18 M |  2037M |   926K (1) | 03:05:22 |  Q1 00 | P > P | RANGE |

  |   6.       REMOVE | PARALLEL_TABLE |       |       |            |          |  Q1 00 | SVCP |            |

  |   7.        ITERATOR BLOCK PX |                    |    18 M |  2037M |   926K (1) | 03:05:22 |  Q1 00 | ISSUE |            |

  |*  8 |         TABLE ACCESS FULL | PARALLEL_TABLE |    18 M |  2037M |   926K (1) | 03:05:22 |  Q1 00 | SVCP |            |

  ----------------------------------------------------------------------------------------------------------------------------

  Dan.Jan wrote:

  So in summary, by adding a second index to the table, the optimizer computes a much higher estimate of the costs for the use of a scan of the index systematic range. As a result, he opts for the full table scan, which is not necessarily the most efficient plan. I am inclined to think that it is a bug with optimizer, as much as it manifests itself only in the line superior (0) plan.

  It's a pretty good reason to be suspicious - and I think you are right that it is a bug.

  The cost of a removal is the cost of the selection the ROWID of the lines to remove, which is in this very simple case: ' selectivity * leaf_blocks ' for the index. However, when you create the second FINAL cost index seems to change to "selectivity * (leaf_blocks + clustering_factor) ' (I ran your test case, tried a few simple variations and looked 10053 files trace - so my conclusion is not a complete analysis of the question.)

  Since you have a test case, raise a SR with Oracle.

  Concerning

  Jonathan Lewis

  (Update: added missing 'leaf_blocks' to the 2nd expression)

• outer join when there are several tables are involved

  Could not put up the question correctly to the last channel, my problem is with the join when there are several tables are involved, this is just one example of the task that I have to carry.

  Tab1 aura model id retailer_id information for all the weeks (from the first Monday) of the month of JUNE with cost and Helen

  Tab1

  model_id	retailer_id	sell_date	cost	Helene
  1	12	June 3, 13	100	40
  1

  12

  June 10, 13

  200

  20

  1

  12

  17 June 13

  300

  20

  1

  12

  24 June 13

  400

  20

  2

  12

  June 3, 13

  300

  10

  2

  12

  June 10, 13

  200

  20

  2

  12

  17 June 13

  300

  20

  2

  12

  24 June 13

  400

  20

  Tab2:

  each retailer belongs to a dealer, under the table has the same information

  retailer_id Dealer_id 12 100

  13

  100

  14

  101

  15

  101

  16

  101

  Tab 3

  There is a third layer where each dealership is having a garage band

  Dealer_id	Dealer_group
  100	1001

  101

  1001

  102

  2001

  103

  2001

  104

  3001

  105

  3001

  Tab4:

  Of this table for each model and dealer discount information for the month of June (every week)

  model_id

  Dealer_group

  discount_date

  discount

  1

  1001

  June 3, 13

  10

  1

  1001

  June 10, 13

  20

  1

  1001

  17 June 13

  10

  1

  1001

  24 June 13

  30

  2

  1001

  June 3, 13

  10

  2

  1001

  June 10, 13

  20

  2

  1001

  17 June 13

  10

  2

  1001

  24 June 13

  30

  3

  2001

  June 3, 13

  10

  3

  2001

  June 10, 13

  20

  3

  2001

  17 June 13

  10

  3

  2001

  24 June 13

  30

  Master_info:

  It's the main table which is the master table for model /retailer information

  Model_id	retailer_id
  1

  12

  2

  12

  3

  12

  4

  12

  1

  13

  2

  13

  Output

  model_id

  retailer_id

  sell_date

  cost

  Helene

  Final (cost-helene-discount)

  1

  12

  June 3, 13

  100

  40

  50

  1

  12

  June 10, 13

  200

  20

  160

  1

  12

  17 June 13

  300

  20

  270

  1

  12

  24 June 13

  400

  20

  350

  2

  12

  June 3, 13

  300

  10

  280

  2

  12

  June 10, 13

  200

  20

  160

  2

  12

  17 June 13

  300

  20

  270

  2

  12

  24 June 13

  400

  20

  350

  3

  12

  June 3, 13

  0

  0

  0

  3

  12

  June 10, 13

  0

  0

  0

  3

  12

  17 June 13

  0

  0

  0

  3

  12

  24 June 13

  0

  0

  0

  4

  12

  June 3, 13

  0

  0

  0

  4

  12

  June 10, 13

  0

  0

  0

  4

  12

  17 June 13

  0

  0

  0

  4

  12

  24 June 13

  0

  0

  0

  1

  13

  June 3, 13

  0

  0

  0

  1

  13

  June 10, 13

  0

  0

  0

  1

  13

  17 June 13

  0

  0

  0

  1

  13

  24 June 13

  0

  0

  0

  2

  13

  June 3, 13

  0

  0

  0

  2

  13

  June 10, 13

  0

  0

  0

  2

  13

  17 June 13

  0

  0

  0

  1

  13

  24 June 13

  0

  0

  0

  For highted above records (model_id / retailer_id combination) there is no record in tab1 but they have entered in master_info then the recordings should come for all model_id/retailer_id with all the 0 values

  Hello

  Thanks for posting the sample data.

  It is unclear what dates you want to include in the output.  The following query shows how you can generate every Monday in a given range.  If you only want to include the dates that are actually present in tabl1 and/or tab4, you can simplify this a bit.

  WITH date_range AS

  (

  SELECT TRUNC (TO_DATE (' 3 June 2013', 'DD-Mon-YYYY'))

  , 'IW '.

  ) AS first_monday

  , TRUNC (TO_DATE (24 June 2013 ', 'DD-Mon-YYYY') + 6)

  , 'IW '.

  ) AS last_monday

  OF the double

  )

  all_mondays AS

  (

  First_monday SELECT + (7 * (LEVEL - 1)) AS sell_date

  OF date_range

  CONNECT BY LEVEL<= 1="" +="" (="" (last_monday="" -="">

  / 7

  )

  )

  SELECT mi.model_id

  mi.retailer_id

  am.sell_date

  , Cost of NVL (t1.cost, 0) AS

  , NVL (t1.rebat, 0) IN the refund

  , NVL (t1.cost, 0)

  -(NVL (t1.rebat, 0))

  + NVL (t4.discount, 0)

  ) AS final

  E master_info

  CROSS JOIN all_mondays am

  LEFT OUTER JOIN tab1 t1 ON t1.model_id = mi.model_id

  AND t1.retailer_id = mi.retailer_id

  AND t1.sell_date = am.sell_date

  LEFT OUTER JOIN tab2 t2 ON t2.retailer_id = mi.retailer_id

  LEFT OUTER JOIN tab 3 t3 ON t3.dealer_id = t2.dealer_id

  LEFT OUTER JOIN tab4 t4 ON t4.model_id = t1.model_id

  AND t4.dealer_group = t3.dealer_group

  AND t4.discount_date = t1.sell_date

  ORDER BY mi.retailer_id

  mi.model_id

  am.sell_date

  ;

  The results are not exactly what said you you wanted.  I suspect it's because of typos in that you posted.

• Creating additional shipping charges to perishable...

  Hi all!

  We work with a Deli and I have a few questions about how to get BC to work with us on some shipping options:

  1. Some items are perishable and must join the customer within 1-2 days max. These items will have a certain amount of ice / coolant to keep them fresh during transportation.
  2. Sometimes the order contains non-perishable items and perishable.

  How can we:

  1. Set parameters for different products or catalogs together (ie: perishable catalogs) to include the cost of coolant, cooler and extra shipping (depending on weight and dimensions to provide the necessary capacity cooler) to exactly to provide final costs related to navigation.
  2. How can we auto-split perishable in a separate order to help the client to save on shipping costs?

  Thanks in advance for any idea to these challenges!

  A lot of views, but nobody has any ideas? Wow, I've blocked everyone!

• Creation of database

  Hi I'm looking for some help with my request. I'm not sure how to model my database.
  It's a phone shop system that displays reports on orders and products of customers details.
  
  There are 3 tables which must contain the following data
  
  
  Product details are generally the following:
  • Identifying unique internal product,.
  • The name of the product, which is not necessarily unique,
  • A description of the product,
  • Special features for certain products,
  • A classification of the products in the range of 1 to 5,
  • The price of retail as well as
  • A cost price.
  
  You can include several product details if you wish.
  Details of the client include:
  • The name, which generally consists of a title, first name, middle name and family name
  • An address, which consists of the house number, street, city, postal code and
  • Contact information, like a phone home phone, cell phone number and e-mail address.
  
  The order must contain:
  • Details of the customer concerned,.
  • The date on which the order was received.
  • The date of delivery,
  • A list of the products and their quantities ordered and
  • The final cost including VAT (17.5%).
  
  Which has been modeled as shown in this DR.
  
  
  
  Uploaded with ImageShack.us
  
  I need the orders table to link correctly to the products_ordered table.
  
  If I need to restructure the database please let me know any information would be greatly appreciated and if more information is needed to determine a solution, I am happy to oblige.
  
  Thanks in advance for any comments

  Bryan,

  If understand the error message, he referred to a new table and relaxation for me, PHONE_RETAILER. Can update you your DR. I can see how this table is modeled in reference to you other tables?

  ORA-01403: no data available ORA-06512: at "PHONE_RETAILER. PRODUCTS_ORDERED_GET_PRICE', line 4 ORA-04088: error during execution of trigger ' PHONE_RETAILER. PRODUCTS_ORDERED_GET_PRICE'

  It is also time to push these tables up to apex.oracle.com and provide me with an account so that we can work together on this. If this is you, shoot me an email with my account information.

  Jeff

• Calculation field not updated until I add something?

  Hello

  I created a PDF form to act as a purchase order.

  Each line has a number of product, product name, quantity, unit price and total based on how I buy. The calculation of the total price works very well at the end of each line.

  However, at the bottom of the last column (total price), I have a total cost field, which is the final cost of all (sum of all fields in the total price).

  The problem is the field on the bottom (total cost), do not accept the last calculation that I do in the last row. I have to start a fake in the following line, and then delete this one to get the total to be correct? In other words, the last line, fill, never gets added to the Total cost? I tried to click on the Enter key or return or Tab... but nothing. I have to add an amount of false to the line right underneath the last of them to get the last calculation to add to the total.

  Is it possible to add some sort of field validation button so that when I did it and I hit him, the total final is available in? Other wise, I will add that amount wrong number, press tab, then the total is good and I have to remove it. Seems very strange... has anyone else had this happen to them?

  Thank you!

  Babs

  The field calculation order is incorrect. Set it to anything that makes sense for your form. In Acrobat 9, go into editing mode and select forms: forms > edit fields > Set field calculation order...