Find the number of occurrences in the chain, to break out

Iha ve a string which can contain 12345, or 12335,6789, or 123435,6789,9999, etc... Unlimited

When I display the string is very long, lengthwise. So, I want to break up and display on the other.

I started to use the search function instead of the helmet in position of the comma, then uses the Mid function to get the first value, the rehearsal process similar to get the values of second and third. It seems to work and the display is as I want.

However, I know that I have three values inside the string, so I can adjust accordinly. What happens if I don't know how many there are values? How to separate to get the result desired?

This is my code so far, based on three values:

< cfset pos1 = Find(",","#qry.carrierTracking#") >

< cfif pos1 is not 0 >
< cfset carrier1 = #mid (qry.carrierTracking, 1, (pos1 - 1)) # >
< cfset carrier2 = #mid (qry.carrierTracking, (pos1 + 1), 50) # >
< / cfif >

< cfset pos2 = Find(",","#carrier2#") >

< cfif pos2 isn't 0 >
< cfset carrier2A = #mid (carrier2, 1, (pos2 - 1)) # >
< cfset #mid = carrier3 (carrier2, (pos2 + 1), 50) # >
< / cfif >


< cfif pos1 is not 0 and pos2 is not 0 >
< cfoutput > #carrier1 # < br > #carrier2A # < br > #carrier3 # < br > < / cfoutput >
< / cfif >


', 'all') > '.

#carrierTracking #.

Tags: ColdFusion

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