Finding missing sequence
Hi all.I use the Oracle Database 10g. I'm trying to understand how to write a simple sql query to:
find the numbers that are missing in an array say 86002895 and 86005197 (inclusive)
Ex: Current Scenario: table_1:
tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10
Expected Result1:
"lack of tracking_id" where id_value = 10 of table_1;
86002897
86002898
86002900 to 86002910
86002910 to 86005196
Thanks in advance :)
user8635888 wrote:
Ex: Current Scenario: table_1:
tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10Expected Result1:
"lack of tracking_id" where id_value = 10 of table_1;
86002897
86002898
86002900 to 86002910
86002910 to 86005196Thanks in advance :)
Perhaps something like the following:
SQL> SELECT * FROM TEST_TAB
2 /
TRACKING_NO ID_VALUE
----------- ----------
86002895 10
86002896 10
86002899 10
86002900 10
86002910 10
86005196 10
86005197 10
7 rows selected.
SQL> SELECT CASE
2 WHEN tracking_no + 1 = lead_no - 1 THEN TO_CHAR (tracking_no +1)
3 ELSE TO_CHAR (tracking_no + 1) || '-' || TO_CHAR (lead_no - 1)
4 END
5 Missing_track_no
6 FROM (SELECT tracking_no,
7 LEAD (tracking_no, 1, NULL)
8 OVER (ORDER BY tracking_no ASC)
9 lead_no
10 FROM test_tab
11 WHERE ID_VALUE = 10)
12 WHERE lead_no != tracking_no + 1
13 /
MISSING_TRACK_NO
--------------------------------------
86002897-86002898
86002901-86002909
86002911-86005195
3 rows selected.
SQL>
You can change the query above to match your needs.
I hope this helps.
Kind regards
JO
Tags: Database
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