Finding missing sequence

Hi all.

I use the Oracle Database 10g. I'm trying to understand how to write a simple sql query to:

find the numbers that are missing in an array say 86002895 and 86005197 (inclusive)

Ex: Current Scenario: table_1:

tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10

Expected Result1:

"lack of tracking_id" where id_value = 10 of table_1;

86002897
86002898
86002900 to 86002910
86002910 to 86005196

Thanks in advance :)

user8635888 wrote:

Ex: Current Scenario: table_1:

tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10

Expected Result1:

"lack of tracking_id" where id_value = 10 of table_1;

86002897
86002898
86002900 to 86002910
86002910 to 86005196

Thanks in advance :)

Perhaps something like the following:

SQL> SELECT * FROM TEST_TAB
  2  /

TRACKING_NO   ID_VALUE
----------- ----------
   86002895         10
   86002896         10
   86002899         10
   86002900         10
   86002910         10
   86005196         10
   86005197         10

7 rows selected.

SQL> SELECT   CASE
  2              WHEN tracking_no + 1 = lead_no - 1 THEN TO_CHAR (tracking_no +1)
  3              ELSE TO_CHAR (tracking_no + 1) || '-' || TO_CHAR (lead_no - 1)
  4           END
  5              Missing_track_no
  6    FROM   (SELECT   tracking_no,
  7                     LEAD (tracking_no, 1, NULL)
  8                        OVER (ORDER BY tracking_no ASC)
  9                        lead_no
 10              FROM   test_tab
 11             WHERE   ID_VALUE = 10)
 12   WHERE   lead_no != tracking_no + 1
 13  /

MISSING_TRACK_NO
--------------------------------------

86002897-86002898
86002901-86002909
86002911-86005195

3 rows selected.

SQL>

You can change the query above to match your needs.

I hope this helps.

Kind regards
JO

Tags: Database

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