First/last in a group of

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• Names of participants blackBerry Smartphones meeting (first, last vs. last, first)

  Updated to 4.6 DM, and now Outlook meetings (with the participants) remains in line with harm during synchronization with my 8310.  I have synced several times, and it maintains see these different between Outlook and your handheld.  The ONLY difference seems to be the order of the names of participants (first, last vs. last, first).

  How can I fix it?    Thank you

  As with most of the problems, you will need to dig a little deeper.  Here's how I solved it:

  (1) under Options/language there is a setting for the display name.  I changed it to "First name" "Last, first".

  (2) but then I've always had some problems so I examined the difference in names more in detail (by cut and paste to WORD and then comparing the documents).   Here is the ROOT of the problem:

  • Several of the guests at the meetings were invited by third parties in Outlook
  • I have several of my names of colleagues, phone numbers and the email addresses in my phone Contact list - but not everyone in the company.
  • There are several cases where people in the Outlook e-mail database name was DIFFERENT then how I was entered in their names in my phone.   If (for example) Robert Jones was in my phone: Bob Jones - but the email addresses are the same of course.
  • Apparently with this version of DM (and I've also updated my phone to 4.5.0.81) emails AND THE NAMES are compared and MUST BE IDENTICAL.

  The solution was to compare it and then change my Outlook Contact file so that the names are the same as in the corporate e-mail system superior, including initial and same averages the number of spaces between the names!

  Once I did, the problem disappeared.   Thought I'd document it here, because someone else may have the same problem.  This did not appear until I upgraded to 4.6 DM.

• mark the first value of a group

  I get the following
  

  16:57:28 >r
    1  with my_table as
    2       (
    3      select 'M082012' pera, to_number(10584338) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    4      select 'M092012' pera, to_number(15965177) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    5      select 'M082012' pera, to_number(14254501) snr, to_number(20) pnr, 'Wallen' name, 'Monika' f_name from dual union all
    6      select 'M082012' pera, to_number(10584339) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    7      select 'M092012' pera, to_number(15965178) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    8      select 'M012013' pera, to_number(10674833) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    9      select 'M012013' pera, to_number(10674834) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
   10      select 'M012013' pera, to_number(10539210) snr, to_number(30) pnr, 'Klose' name, 'Werner' f_name from dual union all
   11      select 'M012013' pera, to_number(12345678) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   12      select 'M012013' pera, to_number(22345789) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   13      select 'M082012' pera, to_number(10584346) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   14      select 'M062012' pera, to_number(10550971) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   15      select 'M092012' pera, to_number(15965185) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   16      select 'M082012' pera, to_number(10584352) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   17      select 'M092012' pera, to_number(15965191) snr, to_number(80) pnr, 'Duster' name, 'Hucke' f_name from dual)
   18  select case when pera = 'M012013' then '*' end mark,
   19         pera, snr, pnr, name, f_name
   20  from (
   21        select pera, snr, pnr, name, f_name,
   22               max(case when pera = 'M012013' then 'Y' end)
   23                 over(partition by upper(name||f_name)) m_flag,
   24               count(*) over(partition by upper(name||f_name)) cnt
   25        from my_table
   26       )
   27  where m_flag = 'Y'
   28  and cnt > 1
   29* order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc
  
  MARK  PERA           SNR        PNR NAME   F_NAME
  ----- ------- ---------- ---------- ------ ------
  *     M012013   10674834         15 Tester Toni
  *     M012013   10674833         15 Tester Toni
        M092012   15965177         15 Tester Toni
  *     M012013   22345789         50 Meier  Otto
  *     M012013   12345678         50 Meier  Otto
        M082012   10584352         50 Meier  Otto

  I would like to mark only the first value in the group with an asterisk as follows.
  

  MARK  PERA           SNR        PNR NAME   F_NAME
  ----- ------- ---------- ---------- ------ ------
  *     M012013   10674834         15 Tester Toni
        M012013   10674833         15 Tester Toni
        M092012   15965177         15 Tester Toni
  *     M012013   22345789         50 Meier  Otto
        M012013   12345678         50 Meier  Otto
        M082012   10584352         50 Meier  Otto

  Perhaps this example might be useful for you. the code uses the same code that you published with additional analytical query to return the row grouping for the name, the NRP and columns pera. then use that line number to determine which will be placed at the first mark.

  SQL>   with my_table as
    2         (
    3        select 'M082012' pera, to_number(10584338) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    4        select 'M092012' pera, to_number(15965177) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    5        select 'M082012' pera, to_number(14254501) snr, to_number(20) pnr, 'Wallen' name, 'Monika' f_name from dual union all
    6        select 'M082012' pera, to_number(10584339) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    7        select 'M092012' pera, to_number(15965178) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    8        select 'M012013' pera, to_number(10674833) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    9        select 'M012013' pera, to_number(10674834) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
   10        select 'M012013' pera, to_number(10539210) snr, to_number(30) pnr, 'Klose' name, 'Werner' f_name from dual union all
   11        select 'M012013' pera, to_number(12345678) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   12        select 'M012013' pera, to_number(22345789) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   13        select 'M082012' pera, to_number(10584346) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   14        select 'M062012' pera, to_number(10550971) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   15        select 'M092012' pera, to_number(15965185) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   16        select 'M082012' pera, to_number(10584352) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   17        select 'M092012' pera, to_number(15965191) snr, to_number(80) pnr, 'Duster' name, 'Hucke' f_name from dual)
   18    select case when pera = 'M012013' and rn = 1 then '*' end mark,
   19           pera,
   20           snr,
   21           pnr,
   22           name,
   23           f_name
   24      from (select pera, snr, pnr, name, f_name,
   25                   row_number() over (partition by pera, pnr, name, f_name order by pera, pnr, name) rn
   26              from (select pera, snr, pnr, name, f_name,
   27                           max(case when pera = 'M012013' then 'Y' end)
   28                           over(partition by upper(name||f_name)) m_flag,
   29                           count(*) over(partition by upper(name||f_name)) cnt
   30                      from my_table)
   31                     where m_flag = 'Y'
   32                       and cnt > 1
   33             order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc)
   34    order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc;
  
  MARK PERA           SNR        PNR NAME   F_NAME
  ---- ------- ---------- ---------- ------ ------
  *    M012013   10674834         15 Tester Toni
       M012013   10674833         15 Tester Toni
       M092012   15965177         15 Tester Toni
  *    M012013   22345789         50 Meier  Otto
       M012013   12345678         50 Meier  Otto
       M082012   10584352         50 Meier  Otto
  
  6 rows selected
  
  SQL> 
  

• Select records of first and the last in the Group results - Oracle 11 g

  I have the following information in the Oracle 11 g table:

  Qty.	Production order	Date and time
  20	00000000000000001	12 JANUARY 14 00:02
  20	00000000000000001	12 JANUARY 14 00:05
  20	00000000000000001	12 JANUARY 14 00:07
  20	00000000000000001	JANUARY 13, 14 00:09
  30	00000000000000002	12 JANUARY 14 00:11
  30	00000000000000002	JANUARY 12/14 00:15
  30	00000000000000002	12 JANUARY 14 00:20
  30	00000000000000002	14 JANUARY 14 00:29

  I here to write a query that returns the following:

  Qty.	Production order	First	Last
  80	00000000000000001	12 JANUARY 14 00:02	JANUARY 13, 14 00:09
  120	00000000000000002	12 JANUARY 14 00:11	14 JANUARY 14 00:29

  Is the sum of the Qty. grouping column by Production order and the time of the first and last records for each Production order .

  I came up with a query that gave this result:

  Qty.	Production order	First	Last
  80	00000000000000001	12 JANUARY 14 00:02	14 JANUARY 14 00:29
  120	00000000000000002	12 JANUARY 14 00:02	14 JANUARY 14 00:29

  Wwhich means that the and last columns show the first and last date / time the whole table. Please note that there is a shadow table. Sorry, I am now allowed to write the actual query

  , I came with given work policies don't allow me to share. Also, I tried with windowing functions such as rank()and row_number() but my user has not enough privileges to do so.

  Help or advice will be greatly appreciated.

  Due to the fact that Oracle does not have the lines in a particular order, it would be wrong that the first 'date' would be the first line to be processed by the query.

  So, you will need to provide another column if you do not want to look at the table as ordered by date.

  Any analytic function must also allows you to provide the 'to' and if that's the date, then just a simple query:

  SQL > WITH Tab1 (quantity, Production_Order, patch)

  2 ALSO (SELECT 20, '00000000000000001', TO_DATE (12 JANUARY 14 00:02 ', 'DD-MON-YY HH24') FROM DUAL UNION ALL)

  20. SELECT 3, '00000000000000001', TO_DATE (12 JANUARY 14 00:05 ', 'DD-MON-YY HH24') FROM DUAL UNION ALL

  4. SELECT 20, '00000000000000001', TO_DATE (12 JANUARY 14 00:07 ', 'DD-MON-YY HH24') FROM DUAL UNION ALL

  20. SELECT 5, '00000000000000001', TO_DATE (13 JANUARY 14 00:09 ', 'DD-MON-YY HH24') FROM DUAL UNION ALL

  6. SELECT 30, '00000000000000002', TO_DATE (12 JANUARY 14 00:11 ', 'DD-MON-YY HH24') FROM DUAL UNION ALL

  30 SELECT 7, '00000000000000002', TO_DATE (12 JANUARY 14 00:15 ', 'HH24 LUN-JJ-AA') OF ANY UNION DOUBLE

  8. SELECT 30, '00000000000000002', TO_DATE (12 JANUARY 14 00:20 ', 'DD-MON-YY HH24') FROM DUAL UNION ALL

  9 SELECT 30, '00000000000000002', TO_DATE (14 JANUARY 14 00:29 ', 'DD-MON-YY HH24') FROM DUAL)

  10. SELECT SUM (Qty), Production_Order, MIN (update), MAX (updated)

  11 OF Tab1

  GROUP of 12 BY Production_Order

  13 * ORDER BY Production_Order

  SQL > /.

  SUM (QTY) PRODUCTION_ORDER (PDATE) MIN MAX (PDATE)

  ---------- -------------------- ----------------------------- -----------------------------

  80 00000000000000001 12 January 2014 00:02:00 January 13, 2014 00:09:00

  120 00000000000000002 12 January 2014 00:11:00 January 14, 2014 00:29:00

• Best way to details data and show of force only last result in Group

  Hi all! First, just let all the world know that it is a great place to explore and learn Oracle - I learned more here than I have in some classes. Come and explore the forums and looking for an answer lead me to the functions that I hadn't known otherwise existed.
  
  Here's what I'm trying to do now... Let's say I have a table that contains information about the family - if two or more persons associated with a family (determined by a separate table) then it should return the person identification and then the details of the group.
  
  For example, the following data are contained in two tables, the follow-up of current results and then the result, that I'm looking...
  

  PERSONS TABLE
  ----------------------
  PERSON         PERSON_ID           ADDRESS
  John Smith     101                     1 Oracle Drive
  Jane Smith     102                     1 Oracle Drive

  RELATIONSHIPS TABLE
  -----------------------------
  PERSON_ID      RELATEDPERSON_ID
  101                 102
  102                 101

  A simple query would result in the following text:

  WITH PERSONS AS
  (
    SELECT 'John Smith' AS person, 101 AS person_id, '101 Oracle Drive' AS address FROM dual union all
    SELECT 'Jane Smith', 102, '101 Oracle Drive' FROM dual
  )
  ,    RELATIONSHIPS AS
  (
    SELECT 101 AS person_id, 102 AS relatedperson_id FROM dual union all
    SELECT 102, 101 FROM dual
  )
  SELECT
      person
    , address
  FROM  PERSONS p
  JOIN  RELATIONSHIPS r ON r.person_id = p.person_id

  RESULT

  PERSON      ADDRESS
  John Smith      101 Oracle Drive
  Jane Smith      101 Oracle Drive

  I'm looking to produce the following result, but I do not know how... I am convinced that it is something simple.
  
  DESIRED RESULT

  PERSON      ADDRESS
  John Smith     
  Jane Smith      101 Oracle Drive

  Note that the address for members of the family is not displayed until the last member of the family is returned. It repeats this process for each family.
  
  Thank you all for any help you can provide! 31%
  
  Published by: nage62587 on October 16, 2012 20:20

  Hello

  nage62587 wrote:
  I did a lot of searching the forum and revised my question a bit hopefully make things a little clearer... I got a request Frank wrote and revised to meet my criteria.

  The forum search (and other places on the web) is great! Not only are you things, but the people on this forum are more likely to help you when they see you do everything you can.
  If you find something that you are trying to adapt, post a link to it. Seeing the correct way to adapt it can be very instructive.

  essentially, if I can determine which members of the family someone is, then I can create a unique "FAMILY_ID" for them - once I have that, it would seem that I could then use the FAMILY_ID to combine their addresses and other information.

  The problem I have is that if a RELATEDPERSON_ID is linked to a PERSON_ID (PERSON_ID related RELATEDPERSON_ID works very well), he attributes them a new FAMILY_ID, rather than include them in the correct family.

  Here is my sql

  WITH PERSONS AS
  (
  SELECT 'John Smith' AS person, 101 AS person_id, '1 Oracle Drive' AS address FROM dual union all
  SELECT 'Jane Smith', 102, '1 Oracle Drive' FROM dual union all
  SELECT 'Jack Smith', 103, '8 Oracle Drive' FROM dual union all
  SELECT 'John Doe', 104, '10 Oracle Drive' FROM dual union all
  SELECT 'Jane Doe', 105, '10 Oracle Drive' FROM dual union all
  SELECT 'Pete Smith', 106, '1 Oracle Drive' FROM dual
  )
  ,    RELATIONSHIPS AS
  (
  SELECT 101 AS person_id, 102 AS relatedperson_id FROM dual union all
  SELECT 102, 101 FROM dual union all
  SELECT 104, 105 FROM dual union all
  SELECT 105, 104 FROM dual union all
  SELECT 106, 101 FROM dual
  )
  , table_x
  AS
  (
  SELECT   person_id         AS col1
  ,        relatedperson_id  AS col2
  FROM     relationships
  )
  ,     got_relatives     AS
  (
       SELECT     col1
       ,     CONNECT_BY_ROOT col2     AS relative
       FROM     table_x
       CONNECT BY NOCYCLE     col1     =  col2
  OR  col2  =  col1
  )
  SELECT       col1
  ,       DENSE_RANK () OVER ( ORDER BY  MIN (relative)
  ) AS family_id
  FROM      got_relatives
  GROUP BY  col1
  

  I think the result is:

  COL1   FAMILY_ID
  -----   ----------
  102     1
  106     1
  101     1
  105     2
  104     2
  

  I suspect that whatever you copied originally had the FIRST keyword somewhere in the CONNECT BY clause.

  Here's a way to do what you want:

  WITH    all_relationships     AS
  (
       SELECT  person_id
       ,     relatedperson_id
       FROM     relationships
      UNION
       SELECT  relatedperson_id     AS person_id
       ,     person_id          AS relatedperson_id
       FROM     relationships
  )
  ,     got_relatives     AS
  (
       SELECT     CONNECT_BY_ROOT person_id     AS person_id
       ,     relatedperson_id
       FROM     all_relationships
       CONNECT BY NOCYCLE     person_id       = PRIOR relatedperson_id
               OR          relatedperson_id  = PRIOR person_id
  )
  ,     got_family_id     AS
  (
       SELECT       person_id
       ,       MIN (relatedperson_id)     AS family_id
       ,       ROW_NUMBER () OVER ( PARTITION BY  MIN (relatedperson_id)
                                    ORDER BY          person_id     DESC
                                  )            AS r_num
       FROM       got_relatives
       GROUP BY  person_id
  )
  SELECT       p.person
  ,       CASE
             WHEN  f.r_num  = 1
             THEN  p.address
         END          AS address
  ,       p.person_id
  ,       f.family_id
  FROM       got_family_id  f
  JOIN       persons      p  ON  p.person_id  = f.person_id
  ORDER BY  family_id
  ,            person_id
  ;
  

  Output:

  PERSON     ADDRESS          PERSON_ID  FAMILY_ID
  ---------- --------------- ---------- ----------
  John Smith                        101        101
  Jane Smith                        102        101
  Pete Smith 1 Oracle Drive         106        101
  John Doe                          104        104
  Jane Doe   10 Oracle Drive        105        104
  

  Obviously, you don't have to see all the columns, I posted above in your first post, you said you wanted only person and address. In your last message, you said you wanted only person_id and family_id. change the SELECT main clause just as you wish.

  I used the lowest person_id in each family as the family_id. You can use DENSE_RANK if you really want to have families numbered 1, 2, 3,..., but I suspect that you really care what family_id, as long as all the members of the family have the same value.

  Table of relationship a you certain symmetrical, such as relationships

  SELECT 104, 105 FROM dual union all
  SELECT 105, 104 FROM dual union all
  

  and a few asymmetric relations. For example, the only relationship involving person_id = 106 is

  SELECT 106, 101 FROM dual
  

  in other words, there is no line of mirror-image:

  -- SELECT 101, 106 FROM dual union all   -- THIS IS NOT IN THE SAMPLE DATA
  

  I guess it didn't matter to that. As long as 101 and 106 appear on the same line, they are in the same family, regardless of the person_id and which is the relatedperson_id.
  The first thing I did above was therefore to ensure that all lines of the mirror-image were represented. This is what all_relationships does.
  The following subquery, got_relatives, is probably what you mean to adapt, but you let him operators PREREQUISITES.
  Got_family_id does the grouping and also calculates r_num to determine which is the last member of the family. Address of this member of the family only will be displayed in the main query.
  You could combine got_family_id and the main request; you don't need really a subquery for this. It would be a little less coding, but I wrote it that way because I think it's a little easier to understand and maintain.

• IMAQ edge tool 2 'first + last edge' - returns the position of the first border

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• FIRST, LAST, COUNTY collection

  Hello

  I need to know how these values are coming to Arry.FIRST, Arry.LAST and Arry.COUNT.

  SQL > DECLARE

  Arry_t TYPE 2 IS the TABLE OF THE PLS_INTEGER;

  3 Arry Arry_t: = Arry_t();

  4 BEGIN

  5. FOR i IN 1.10 LOOP

  6 Arry.EXTEND (i + 3);

  7 Arry(i+3): = - 100 + 2 * i;

  8 END OF LOOP;

  9 DBMS_OUTPUT. Put_line ("FIRST value" |) Arry.FIRST);

  10 DBMS_OUTPUT. Put_line (' LAST value ' |) Arry.LAST);

  11 DBMS_OUTPUT. Put_line (' COUNT value ' |) Arry.COUNT);

  12 DBMS_OUTPUT. Put_line ("FIRST value" |) Arry.FIRST);

  13. FOR I IN 1.10 LOOP

  14 DBMS_OUTPUT. Put_line (' value to the index ' |) I |' is ' | Arry (i));

  15 END LOOP;

  16 END;

  17.

  FIRST value 1

  LAST value 85

  Value of COUNT 85

  Value at index 1 is

  Value at index 2 is

  Value at index 3 is

  Value at index 4 is - 98

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  Value at index 6 is - 94

  Value at index 7 is - 92

  8 index value is - 90

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  Value to the index 10 is - 86

  PL/SQL procedure successfully completed.

  Arry.FIRST should be 4, Arry.LAST and COUNT must be 10 and 7 respectively. So how is it random values are to come.

  Hello

  When you create arry, its NUMBER is 0.

  Then you throw in the loop (beginning on line 5) 10 times.

  When the 1st time in the loop, I = 1, you add 1 + 3 = 4 points and put the 1 + 3 = a 4th.

  The 2nd time in the loop, when I = 2, you add 2 + 3 = 5 points more and put the 2 + 3 = 5.

  When the 3rd time in the loop, I = 3, you add 3 + 3 = 6 points more and put the 3 + 3 = 6 a.

  ...

  The 10th time through the loop, when I = 10, you add 10 + 3 = 13 points more and set them 10 + 3 = a 13th.

  The other inputs (i.e., 1-3 and 14-85) never get assigned to all values.

  4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 = 85.

• My address book in v. 32.0 will not sort correctly for example by first, last, etc. ; How can I fix this?

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  Convergent Design and Adobe are aware of the problem and working on a fix.  You need to roll back to 2015.3 for the moment.

• Differences in the performance of nividia geforce gtx 860, 870, 880 first last on

  Hello guys, I'm about to pass a big load of money on a new laptop and I was wondering how high the power difference of performance between geforce gtx 860 to 870 880 on the latest edition of the first's. It's really the question of the difference in price of about 800 euros, so before decide me on this matter, I would really like to know if it is worth. Once again: there will be a considerable advantage to work first with the geforce 880 or 870 as opposed to 860?

  Hope someone can help me here. Thank you

  See the compatibility list first. I don't see any of the three top! They CAN work, and I think that these are more recent model processors that are specifically designed for CUDA.

  Don't know all about laptops, but on the desktop the other variable (which you don't mention) is the amount of RAM on the video card itself. 800 euros is a huge difference; If the RAM is the same, and all three are on the list of compatibility for playback of mercury, I don't know that you can justify the difference. If the RAM is 1 GB on the cheapest and 4 or 6 on the most expensive, it's a different calculation.

  I speculate that the differences between these three cards would be more apparent to players for video editors, but that's just my opinion... what makes the difference in the first is the fact that transcode the video RAM made and perceived effect much faster as the RAM system can, and to do so effectively, it takes like RAM video as much as possible. I think it's the number you want to watch, rather than 860 vs 870 or 880.

• the index of the first/last numerical value

  Hello
  
  I want to find the index of the first numeric value in a string. I can do this by using built-in features of Oracle? (Without creating a new function)

  I want to find the index of the first numeric value in a string

  regexp_instr could do (for the first digit):

  SQL> select regexp_instr('abc1def2', '\d') first_digit from dual
  /
  FIRST_DIGIT
  -----------
            4
  1 row selected.
  

• Find first & last day of the week of the given date

  Hi all

  I have the input query, below

  WITH TEM AS (SELECT 11 January 13 ' DT dual union SELECT June 16, 12 'from dual union SELECT 4 July 12' dual Union SELECT 9 January 13 'from dual union SELECT 10 January 13' dual Union SELECT 4 January 13 'from dual union SELECT 7 January 13' from dual union SELECT 4 June 13 'from dual union SELECT 8 January 13' double) TO_DATE (DT) SELECT D1 ,' WEEK ' | To_char (to_date (DT), 'IW-YYYY') tem WK;

  I would like to get output that is below start date week (Saturday) & the end of the week (Friday)

  DT	Period of the WEEK	Max Date in this week	Min Date this week
  June 16, 12	WEEK 24-2012	June 16, 12	22 June 12
  July 4, 12	WEEK 27-2012	30 June 12	July 6, 12
  January 4, 13	WEEK 01-2013	January 4, 13	29 December 12
  January 7, 13	WEEK 02-2013	5 January 13	January 11, 13
  January 8, 13	WEEK 02-2013	5 January 13	January 11, 13
  January 9, 13	WEEK 02-2013	5 January 13	January 11, 13
  January 10, 13	WEEK 02-2013	5 January 13	January 11, 13
  January 11, 13	WEEK 02-2013	5 January 13	January 11, 13
  June 4, 13	WEEK 23-2013	1 June 13	June 7, 13

  Indicate also if a function available in oracle for this one.

  Like this? I think in your required output, 3rd line data, MAX_DATE should be 29 December 12 and MIN_DATE should be January 4, 13.

  WITH TEM AS

  (SELECT 11 January 13 ' DT double Union)

  SELECT 16 June 12 ' Union double

  SELECT 4 July 12 ' Union double

  SELECT January 9, 13 ' Union double

  SELECT 10 January 13 ' Union double

  SELECT 4 January 13 ' Union double

  SELECT January 7, 13 ' Union double

  SELECT 4 June 13 ' Union double

  SELECT 8 January 13 ' double)

  SELECT D1 DT,

  WK WEEK_PERIOD,

  BOX WHEN (TRIM (TO_CHAR (D1, 'DAY')) = 'SATURDAY') THEN D1

  ANOTHER NEXT_DAY(D1,'SATURDAY')-7

  END AS MAX_DATE_IN_THIS_WEEK,

  BOX WHEN (TRIM (TO_CHAR (D1, 'DAY')) = 'FRIDAY') THEN D1

  OF OTHER NEXT_DAY(D1,'FRIDAY') END AS MIN_DATE_IN_THIS_WEEK

  DE)

  SELECT TO_DATE (DT) D1,' WEEK ' | To_char (to_date (DT), 'IW-YYYY') tem WK)

  ORDER BY DT;

  OUTPUT:

  DT WEEK_PERIOD MAX_DATE_ MIN_DATE_

  --------- ------------ --------- ---------

  JUNE 16, 12 WEEK 24-2012 16 JUNE 12 22 JUNE 12

  4 JULY 12 WEEK 27-2012 JUNE 30, 12 6 JULY 12

  4 JANUARY 13 WEEK 01-2013 29 DECEMBER 12 JANUARY 4, 13

  JANUARY 7, 13 WEEK 02-2013, JANUARY 5, 13 JANUARY 11, 13

  JANUARY 8, 13 WEEK 02-2013, JANUARY 5, 13 JANUARY 11, 13

  JANUARY 9, 13 WEEK 02-2013, JANUARY 5, 13 JANUARY 11, 13

  10 JANUARY 13 WEEK 02-2013, JANUARY 5, 13 JANUARY 11, 13

  JANUARY 11, 13 WEEK 02-2013, JANUARY 5, 13 JANUARY 11, 13

  4 JUNE 13 WEEK 23-2013, JUNE 1, 13 JUNE 7, 13

  9 selected lines.

• It is possible to select more than one layer by selecting the first and the last layers?

  I frequently get Illustrator files which are individual objects such as the paths on separate layers that can be grouped together to make the shorter layers. I find that I have to change click on each individual layer to select it to finally bring together them. Sometimes, I have 25 or so layers that I need to select. Is there a way to select the first and the last layer in the layers palette and have Illustrator select all the layers in the meantime?

  Don't know about the selection of layers of first/last, but to select several consecutive layers in the layers palette...

  Option-click on (Mac) on a layer to select it and, with the option always pressed key, drag to the bottom of the list - DO NOT slip on as logical target icons you like.  When you drag to the bottom of the list of layers, the icons of the target will become selected.

  Shift + Option-click allows you to ignore the layers and continue to select consecutive additional layers on the bottom of the palette.

  Note: Drag slowly or some layers would not choose.

  Strange, I know.  It took me years to come across this.

• First day/last day of each month

  Hello
  y at - it sql/script to get the first day/last day of each month.new to bi do not know the syntax
  
  If a point on the link to get these things will be highly appreciated

  Hello
  I suggest that you go through the following link

  (1) http://oracle.ittoolbox.com/groups/technical-functional/oracle-bi-l/obiee-date-comparison-1726677#M1729534

  Toget first/last day of the month

  (2) http://www.obinotes.com/2010/02/tip-to-get-firstday-lastday.html

  New to OBIEE---> http://obiee101.blogspot.com/2009/07/obiee-how-to-get-started.html

  Thank you
  Saichand.V