FIRST, LAST, COUNTY collection

Hello

I need to know how these values are coming to Arry.FIRST, Arry.LAST and Arry.COUNT.

SQL > DECLARE

Arry_t TYPE 2 IS the TABLE OF THE PLS_INTEGER;

3 Arry Arry_t: = Arry_t();

4 BEGIN

5. FOR i IN 1.10 LOOP

6 Arry.EXTEND (i + 3);

7 Arry(i+3): = - 100 + 2 * i;

8 END OF LOOP;

9 DBMS_OUTPUT. Put_line ("FIRST value" |) Arry.FIRST);

10 DBMS_OUTPUT. Put_line (' LAST value ' |) Arry.LAST);

11 DBMS_OUTPUT. Put_line (' COUNT value ' |) Arry.COUNT);

12 DBMS_OUTPUT. Put_line ("FIRST value" |) Arry.FIRST);

13. FOR I IN 1.10 LOOP

14 DBMS_OUTPUT. Put_line (' value to the index ' |) I |' is ' | Arry (i));

15 END LOOP;

16 END;

17.

FIRST value 1

LAST value 85

Value of COUNT 85

Value at index 1 is

Value at index 2 is

Value at index 3 is

Value at index 4 is - 98

Value at index 5 is - 96

Value at index 6 is - 94

Value at index 7 is - 92

8 index value is - 90

Value at index 9 is - 88

Value to the index 10 is - 86

PL/SQL procedure successfully completed.

Arry.FIRST should be 4, Arry.LAST and COUNT must be 10 and 7 respectively. So how is it random values are to come.

Hello

When you create arry, its NUMBER is 0.

Then you throw in the loop (beginning on line 5) 10 times.

When the 1st time in the loop, I = 1, you add 1 + 3 = 4 points and put the 1 + 3 = a 4th.

The 2nd time in the loop, when I = 2, you add 2 + 3 = 5 points more and put the 2 + 3 = 5.

When the 3rd time in the loop, I = 3, you add 3 + 3 = 6 points more and put the 3 + 3 = 6 a.

...

The 10th time through the loop, when I = 10, you add 10 + 3 = 13 points more and set them 10 + 3 = a 13th.

The other inputs (i.e., 1-3 and 14-85) never get assigned to all values.

4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 = 85.

Tags: Database

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