For Each loop

Similar Questions

• TestStand blocks by "for each" loop

  TestStand crashes from time to time for unknown reasons. We believe that 'foreach' loops could be the reason. By replacing the "for each" loop with a loop and iterate using the index, the problem is solved.

  Is this a known problem in Teststand? Is it possible that this is resolved in Teststand 4.1 (we use 4.0.1)?

  Kind regards

  Jeroen Coulembier

  This looks exactly like a previous problem (98902) report, which has been fixed in 4.1.

• write 1 d digital table in a binary file and start a new line or insert a separator for each loop writing file

  Hello:

  I'm fighting with digital table of 1 d writeing in a binary file and start a new line or insert a separator for each loop writing file. So for each loop, it runs, LABVIEW code will collect a table 1 d with 253 pieces of a spectrometer. When I write these tables in the binay file and the following stack just after the previous table (I used MATLAB read binary file). However whenever if there is missing data point, the entire table is shifted. So I would save that table 1-d to N - D array and N is how many times the loop executes.

  I'm not very familiar with how write binary IO files works? Can anyone help figure this? I tried to use the file position, but this feature is only for writing string to Bodet. But I really want to write 1 d digital table in N - D array. How can I do that.

  Thanks in advance

  lawsberry_pi wrote:

  So, how can I not do the addition of a length at the beginning of each entry? Is it possible to do?

  On top of the binary file write is a Boolean entry called ' Prepend/chain on size table (T) '.  It is default to TRUE.  Set it to false.

  Also, be aware that Matlab like Little Endian in LabVIEW by default Big Endian.  If you probably set your "endianness" on writing binary file as well.

• For each loop - Urgent

  Hello
  
  I try to use for each loop:
  
  FE Agreement_No
  Customer
  0.00
  0.00 <? end foreach? >
  
  It does not work. The FE code should be grouped?
  
  Can anyone help?
  
  Thank you

  Can you send me the files?

• for each loop works not

  My instructions of tracing inside ma for each loop will not appear. Please someone check my code. I'm no errors in flex builder. When I debug all vars are holding data prober. Thank you very much
  
  
  

  "essa tkinen" wrote in message
  News:gr27rt$3SB$1@forums. Macromedia.com...
  > Yes there are data there is a list of comma delimited keywords that are
  > catagorys. the selectedCatArray holds to a list item. I want to
  > returns true if the item is in this list

  On the one hand, you will leave this function in the first round,
  because you return the result inside the loop. Return immediately leave him
  function. On the other hand, I am tempted to move on to something more like
  this:

  for (var i = 0; i)<_item.cats.length; i++)="">
  iCat var = item.cats ;
  do your business here
  }

  I had really bad luck to get for each to work the way I think that it
  expected.

  HTH;

  Amy

• for each loop to print the values in the same line?

  
  Hi guys,.

  For our customer, I create a RTF file.

  In one line, I use this:

  Internal req. Ref #: <? for-each: G_2? > <? SEGMENT1? > <? end foreach? >

  Now when I run this report this part of line shows the values in separate lines

  Output:

  -----------------------------------------------

  Inside Ref No. DDE:

    226

  230

  ------------------------------------------------

  How can I make it back in the same line. Like this and separated by commas

  -----------------------------------------------

  Internal req. Ref #: 226 230

  ------------------------------------------------

  You can use inline grouping, please take a look at these posts:

  https://blogs.Oracle.com/XmlPublisher/entry/inline_grouping

  Re: Using conditional output

  Re: Display data from a list in a single field with values separated by commas

• Table row with loop for each group to set the variable.

  HI: There is probably a simple answer for this, but I don't the have not found...
  
  I have a single row table to move through a group to set a variable containing a sum running. I'm not display the amount in the table but when I saw the report, I see that the table is expanding (add lines) for each loop.
  
  The only line table has 3 columns.
  
  1st column
  <? for-each: AC_GROUP? >
  
  2nd column
  <? xdoxslt:set_variable ($_XDOCTX, 'xAmtVar', xdoxslt:get_variable($_XDOCTX,'xAmtVar') + CURRENT_AMOUNT)? >
  
  3rd column
  <? end foreach? >
  
  Can I use <? for each group? > or something else. My requirement is to set the value of the variable with the total running, but because the loop is adding lines for each value he travels (though not displayed), it's also affecting other areas of the presentation of the page.
  
  Hope it makes sense. Thanks in advance.

  You can do it many ways.

  No need to loop
  You can create a variable and specify the amount of the sum directly to that.

  or

  loop through, then add as you do.

  give any space or enter characters in a word between them, just put it in a single form field will be

  But as I said, I'd definitely go with the first option.

• Procedure of work for each OSB.

  Hello
  I'm new to OSB, can someone explain how it works for everyone. I am totally confused with java for each. Please explain with an example xml or what ever iterate.
  
  Thank you
  Raj.

  Hisaak he explained here-

  For each loop in OSB

  Let us know if you are looking for something specific.

  Kind regards
  Anuj

  Published by: Anuj Dwivedi on December 27, 2010 18:00

• How can I clear the shift registers of sub for loop for each iteration of a larger loop?

  Hello

  I write a program to concatenate multiple text files.  However, I need to treat each column individually before they are concatenated.  I use one for a loop at normalze 6 columns choice the largest loop of concatenation.  However, the shift registers store data from previous iterations of the larger loop.  How can I clear the shift registers of the void loop based on the iteration of the larger loop?

  Thanks in advance!

  OK, that's fine. are there headers?

  In all cases, all you need to do is to place all of the 2D array in the shift register of the inner loop, iterate over the columns relevant to be normaized (use 'index array' to get the column it normalize, put it to help to "replace the subset of table".) You probably want to initialize the outer loop shift register. Use then "building the table" added to the beginning or the data of each file sets.

• loops through the sections XML &lt; RecieptDetails &gt; and for each record found...

  My input XML file is...
  I get this XML using file adapter...
  
  <? XML version = "1.0" encoding = "UTF-8"? >
  -< root xmlns:ns2 = "http://www.w3.org/2001/XMLSchema" >
  -< ns2:ReceiptBatch >
  < ns2:FileID > "99999" < / ns2:FileID >
  < ns2:Warehouse > in THE < / ns2:Warehouse >
  'L' < ns2:Revision > < / ns2:Revision >
  < ns2:DocID > A4 < / ns2:DocID >
  -< ns2:Receipt >
  < ns2:DeliveryNo > 123 - OP < / ns2:DeliveryNo >
  < ns2:ProcessDate > 112138 < / ns2:ProcessDate >
  < ns2:ContainerNo > 98765 < / ns2:ContainerNo >
  < ns2:Instructions > TREKAU < / ns2:Instructions >
  < ns2:ReceiptType > 1 < / ns2:ReceiptType >
  < ns2:SuppCustCode > 111 < / ns2:SuppCustCode >
  TREK-Cycle < ns2:SuppCustName > < / ns2:SuppCustName >
  -< ns2:ReceiptDetails >
  < ns2:Line > 1 < / ns2:Line >
  < ns2:ProductCode > 1000 < / ns2:ProductCode >
  < ns2:QuantityAdvised > 1 < / ns2:QuantityAdvised >
  < ns2:QuantityReceived > 1 < / ns2:QuantityReceived >
  < / ns2:ReceiptDetails >
  -< ns2:ReceiptDetails >
  < ns2:Line > 2 < / ns2:Line >
  < ns2:ProductCode > 2000 < / ns2:ProductCode >
  < ns2:QuantityAdvised > 2 < / ns2:QuantityAdvised >
  < ns2:QuantityReceived > 2 < / ns2:QuantityReceived >
  < / ns2:ReceiptDetails >
  -< ns2:ReceiptDetails >
  < ns2:Line > 3 < / ns2:Line >
  < ns2:ProductCode > 2000 < / ns2:ProductCode >
  < ns2:QuantityAdvised > 3 < / ns2:QuantityAdvised >
  < ns2:QuantityReceived > 3 < / ns2:QuantityReceived >
  < / ns2:ReceiptDetails >
  < / ns2:Receipt >
  < / ns2:ReceiptBatch >
  < / root >
  
  There are 2 tables in the database.
  Table 1 = T1743512
  Table 2 = T2743002
  
  table - structure
  
  T1743512-
  
  DOCO KCOO DTCO LNID LNIX LITM NOTICE USR JOBN UPMJ PID'M CKNU UREC
  123 00026 1 1 1000 1 1 123 - OP OP
  124 00026 1 1 1000 1 1 124 - OP OP
  123 00026 2 2 1000 2 2 123 - OP OP
  123 00026 3 3 1000 3 2 123 - OP OP
  
  
  
  Things to do are:--
  
  1. Research Notice T1743512 (table) with the following keys:
  1.T1743512. CKNU = < DeliveryNo > XML
  2.T1743512. LNIX = XML < row >
  II. write a record in the T2743002 table for each < RecieptDetails >. (See map below)
  
  Mapping of the records in the table T2743002 to < ReceiptDetails >
  
  EDU - "SABSSV".
  EDBT - < EDBT > (the same for all records)
  EDTN - < DeliveryNo > (from the section < reception > XML)
  EDLN - < row > (from < ReceiptDetails > section in XML format)
  EDSP - white
  DOCO - white
  DCTO - white
  KCOO - white
  LNID - white
  LITM - < ProductCode > < ReceiptDetails > section
  UORG - < QuantityAdvised > < ReceiptDetails > section
  UREC - < QuantityReceived > < ReceiptDetails > section
  USER - "SABSSV".
  JOBN - "SOA - 3PL".
  PID - 'PO-ENTRANTS ".
  UPMJ - current Date Julian
  - Hour current HHMMSS
  
  
  
  Please suggest the solution.
  
  Published by: Prashant_AP on June 22, 2012 12:24 AM

  Hello

  Solution by using a loop in BPEL;
  1 count the number of nodes for ReceiptDetails.
  2 create a counter for loop through each node ReceiptDetails. Use a while loop in BPEL
  3 search T1743512 (table) with DeliveryNo and the line. Make sure that you select the correct line from the ReceiptDetails node element node. This can be done using the counter example of xpatch ns2:ReceiptBatch / ns2:Receipt / ns2:ReceiptDetails [counter] / ns2:Line. Please use the DB adapter.
  I guess that the DeliveryNo can only appear once in the document following your example.
  4. for each receiptDetails you write a record in table too T2743002. Please use the DB adapter.
  5. Since the time increment the counter. This is to ensure that the while loop stops at the point where the counter is greater then the number of nodes to ReceiptDetails.

  I think a better solution is to make the loop in PL/SQL. It will be faster. You specify an input of type of collection in your pl/sql package parameter. Assign all items receiptDetails and DeliverNo line to the PL/SQL package. Within PL/SQL unravel you the closure. With a little luck, you have the T2743002 in the same schema to create the record too. Otherwise create synonyms of the database or database links.

  Good luck

  Thank you

  Sander

• For each does not properly in the XSLT file to two loops on a single node

  Hi all
  
  I'm transforming 2 inputs to a single target using XSLT. Both of the target entry of the same pattern and have the child element.
  In the XSLT, I gave this condition.
  "< xsl: for each select="$Variable1.payload/ns1:BookStore/ns1:Books ">
  < xsl: for-each select = "/ ns1:BookStore / ns1:Books" >
  "< xsl: if test="$Variable1.payload/ns1:BookStore/ns1:Books/ns3:BookId = ns3:Books / ns3:BookId ">
  
  My second for each does not work and in the target, I'm getting double elements. Help, please. Here are two xml source and xml desired target.
  1 XML source:
  
  < bookStore >
  < book >
  Name1 < name > < / name >
  author1 < author > < / author >
  < ID > 1 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < book >
  name2 < name > < / name >
  Author2 < author > < / author >
  < ID > 2 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < book >
  < name > NAME3 < / name >
  author of 3 < author > < / author >
  < ID > 3 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < / book >
  
  XML source 2:
  
  < bookStore >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 1 < / BookId >
  < price > 100 < / price >
  < status > < / status >
  < book >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 2 < / BookId >
  < price > 200 < / price >
  < status > NA < / status >
  < book >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 3 < / BookId >
  < price > 300 < / price >
  < status > < / status >
  < book >
  < / book >
  
  Desired target XML:
  
  < bookStore >
  < book >
  Name1 < name > < / name >
  author1 < author > < / author >
  < ID > 1 < / BookId >
  < quantity > 2 < / quantity >
  < price > 100 < / price >
  < status > < / status >
  < book >
  < book >
  name2 < name > < / name >
  Author2 < author > < / author >
  < ID > 2 < / BookId >
  < quantity > 2 < / quantity >
  < price > 200 < / price >
  < status > NA < / status >
  < book >
  < book >
  < name > NAME3 < / name >
  author of 3 < author > < / author >
  < ID > 3 < / BookId >
  < quantity > 2 < / quantity >
  < price > 300 < / price >
  < status > < / status >
  < book >
  < / book >
  
  Thank you

  Hello

  It will not work like that... To do something like the following... Only one for each...

  
    
    
      ns1:Name
      ns1:Author
      ns1:BookId
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Quantity
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Price
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Status
    
  
  

  I don't have to check the syntax, but you get the idea...

  I hope this helps...

  See you soon,.
  Vlad

• loops for each: the type of the variable

  I see warning in the editor telling me that the type of the variables in my curls foreach was not specified. I use an XMLList type (such as the collection) and I can not understand what should be the type of each element.
  Here is a sample of my code.
  
  var xmlList:XMLList = xmlDoc.dataTable [0] .dataRow;
  for each {(var xmlList)
  }
  
  So what is the type of the variable "item" supposed to be? I tried the XMLNode, but it isn't like that. The debugger shows me the 'node', but does not show the type.
  
  Shiv
  
  
  

  Never mind. I realized that it should be of XML type.

• Loading the default limits for each execution

  Hello

  My situation is like this:

  I spend my sequence using the sequential model. Usually, the sequence is executed, 'in the loop', which means that when once the sequential model is launched, we can test unit after unit until we want to put an end for some reason any. The sequence is load dynamically by the sequential model and download after executing the step to discharge option.

  In the sequence, we use limits. Default TS limits similar to below.

  

  All our limitations change during execution depending on what unit we test and on what stage is the unit.

  Problem:

  I thought that if the sequence is loaded dynamically, it is unloaded when executing the next time that the next unit will be tested the default values of the container limits will be charged (in response to being dynamically loaded and unloaded at the step which called the main sequence is executed). Unfortunately, it seems that when we realize continous test the test limits have not returned to the default value, as expected, but they are a superposition of the limits assigned by previous executions. Of course

  Issues related to the:

  1 are my expectations about the behavior of TS are correct?

  2. how to impose default deadline to be 'reset', the default value for each run of the sequence, not only the first execution of sequential model?

  MimiKLM wrote: I am worry the speed of loading, you talked about associated to your solution, but potential problems with memory. Let say, I called the main sequence of 1000 times without breaking execution. So instead of having one copy of the sequence called with wiped/reset all variables and properties I have 1000 copies in the memory. I would call it a waste to have 1000 copies only because I need to have the properties and variables deleted.

  The copy exists only during the execution of the sequence. Once the execution of the sequence is complete, the copy will be destroyed/released. At least as long your code modules do not hold their own reference to it somewhere (which generally do not do).

  If you call from the main sequence 1000 times in a loop, you must still do not have a runtime copy into memory at once. The difference is a new copy is created (and destroyed once that the sequence is made running) each time, rather than create a copy only once and reuse. There is a performance hit in this call of your sequence which is somewhat proportional to the size of your sequence, but unless your sequence is really huge, or test you execution is extremely fast, you probably won't see the difference.

  Hope this helps to clear things up,

  -Doug

• Is it possible to draw the same color for each curve automatically

  Hello

  Is it possible to draw the same color for each curve automatically. I use graphic XY basis with data set.

  Lol you'll either need to set the properties through the dialog box.  Or use the nodes property of the graph to adjust the Active plot and then set the color of the plot.  This can be done in a loop For.

  

• How do I either set channel name of a graph of cluster or get a 1 d waveform chart to start different time (t0) for each line of the waveform?

  I have a chart single 2D out a conditional of a loop indexing output such that over the rows of the table are not the same size. -Basically, they have different starting and ending points and sizes. -Not so concerned by the endpoints, because as soon as I get correctly starting points, everything shows fall in place.

  The challenge is that when I try to have the variable t0 (start time) for each line, the wave of construction vi form would always keep each line at the same starting point.

  I used the approach bundled with success (the cluster approach ensures that each waveform starts at different times according to the guidelines of my t0 defined for each line) but then I'm not able to get in the channel names I could make using the graphical approach (wave generation) waveform.

  In essence what I get here, I'm losing here.

  Because I don't want one of my mentors, Bob and Altenbach have fed up with me I have attached a vi this time

  Attached VI shows a combination of the two attempts (first with the waveform graph) and then with the graph of cluster

  1. with the first (graphical waveform), I get my channel names as you wish, but the alignment of the wave is not correct.

  2. with the second (graphical cluster), the alignment is good, but I can't do the names of channel in the chart, even if they are present in the cluster.

  I read some reviews that mentions that attributes can be displayed with waveform and data Dynamics (not clsuters) so I guess that's why.

  I saw another report indicating the start time for a waveform 1 d will always remain the same for the rest lines defined for the first line even if changed for the following lines in a loop.

  So I guess my question is: what is the way around questions like that?

  First of all, let me be the first to the congratulate and thank you for finally posting a code!  I'm not 100% certain I understand your question or your code, but I have an idea, perhaps, of what you want to do, so I wrote a little VI who made something simple that could be relevant.

  You mention waveforms of different lengths and beginning at different times.  You also want everyone to have a unique attribute (although I'm not sure what you want to do with the attribute).  So, I did the following:

  1. Generated an array of 100-sample random to represent one second of a waveform.
  2. Created 4 waveforms on this 100-sample basis.  The first waveform (channel 0) is just these 100 points.  The second, 1 channel, is the concatenation of string 0 with the base of 100 samples, or a waveform "double".  Channel 2 is 1 string concatenated with the base, and channel 3 is 2 string concatenated with the base.
  3. In order to trace the four channels that they rest 'on' the other, the waveform has the number of the channel added to it.  Channel 3 is 3 + (4 copies of the basis of 100 points), a waveform 400-point random centered around a shift of 3.
  4. All channels have dt value 0.01 (but I guess I could have varied, as well).
  5. To make the channels start at different times, I started channel N N seconds before channel 0 (by subtracting the index of the loop, I, T0).
  6. For each channel, I created an attribute called "Chan" equal to "Channel N" (where N = 0, 1, 2 or 3, as the case may be).

  This is the plot that results. Scale X is the absolute time value (no Date) using the 24-hour HH: mmS format.  You can see that the plots are 1, 2, 3 and 4 seconds of time, and are offset from each other by a second.  I used the trace attributes to change the name to the respective attribute.

  

  The code to do this is very simple - I almost don't need to show it, because I think it is completely described by the text above, but this is here:

  

  Now, it was not that much faster that some of your previous posts, when you refused to your postcode, "guess us" what you wanted (but not to not correctly guess), you tried to "push" us in the right direction (still refuses to post code), and no one seemed very happy?

  Bob Schor