Form on SQL does not work

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• Why this SQL does not work?

  The following code does not work when I try to delete rows from a table of test. The test table has no unique or primary key on it and is defined as test (identification number). Can you explain to me why it doesn't work?
  

  
  

  delete from test a where a.rowid in (select b.rowid from test b where b.id = a.id and b.rowid != a.rowid);

  
  

  
  

  
  

  When I run the subquery (selection) with replacement of the actual values of a.rowid and the table queried a.id (IE.select b.rid from test2 b where b.id = 1 and b.rid != 'XXX'

  ), the subquery returns exactly as expected (that is to say, it gives the rowid is different from that which went from subquery). And as although I know the internal subquery must return the result for each row of the table in the outside circle delete statement, and only after that should execute the delete statement. For example, for the first row of the table in the external suppression, the delete statement must send the ID of the first row in the internal subquery and then wait the result which should return. And then runs the delete statement, in which case the subquery must return the rowid is different from that which went from subquery (ie.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.
  
  

  
  

  P.S. The sql is also not working if we replace remove it with the update or select
  

  in this case, the subquery must return the rowid is different from that which went from subquery (IE.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.

  You are right that this subquery should return other than past rowid thr. But you used the IN clause as well as below:

  where a.rowid in

  What States remove the line if rowid returned by the subquery contains the identifier for the row whose ID was passed. As the inner query is to return another rowid, therefore, no row is deleted.

  To remove duplicate lines, try the query (Replace tablename/columns with your) below:

  DELETE FROM emp A

  WHERE A.ROWID > ALL (SELECT B.ROWID

  PEM'S B

  WHERE A.empno = B.empno);

• reset_image_prefix. SQL does not work

  Hello

  My DB has two instances with two different versions of the top charge. One is the version 4.1.1 (works well) and I decided to upgrade the other 4.1.1 to 4.2. I created a new location in the httpd.conf file entry in my case of OSH to point to the new instance 4.2 referencing a new Alias image on the server. When I installed APEX 4.2 I showed the images the New Alias directory setting "i42' but it does not work. Applications always refer to is

  I ran the script reset_image_prefix.sql with /i42/ as an input parameter, but the applications are always reference/i /.

  There was a similar discussion in October 2012 and Patrick Wolf wrote on bug # 14785456.

  But the BUG seems to be fixed?

  After executeing the script Iget:

  SQL > select text from dba_source where owner = 'APEX_040200' and lower (name) = "wwv_flow_image_prefix";

  TEXT

  ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  package wwv_flow_image_prefix

  is

  constant g_image_prefix VARCHAR2 (255): = ' / i42 / ";

  end wwv_flow_image_prefix;

  4 selected lines.

  Is there a solution?

  Kind regards

  Carola

  Hi Carola,

  What exact version of APEX 4.2 do you use? Are you using the latest 4.2.2? Because it includes the hotfix that you referenced. After installation of this version or the patch installed, it will automatically erase all the prefixes image-level asks if they are identical to the current instance image prefix. So in your case, you should set the prefix image back to / i /, install the hotfix and then reset_image_prefix again to set the parameter instance/i42.

  Joel has some useful information on this blog (YABAOAE) yet another Blog about Oracle Application Express: prefix of Image Exchange in Oracle Application Express 4.2.2

  Some background info on reset_image_prefix.sql. Who has never changed the image prefix used in applications, only the prefix of image for our application Builder.

  Concerning

  Patrick

  Member of the APEX development team

  My Blog: http://www.inside-oracle-apex.com

  APEX Plug-Ins: http://apex.oracle.com/plugins

  Twitter: http://www.twitter.com/patrickwolf

  Post edited by: PatrickWolf

• help please former flash player does not work on the game apps

  Adobe Flash Player does not work how to fix it

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• SQL does not work

  I posted this already, but I can't so I'm posting again so apologies...
  
  I downloaded Oracle Express. I used the utilities tab and downloaded a file. I can see the file with "select * from all_tables ' and I can't
  see that I am the owner. I have s/n privs, and using the object browser, I can see the data and and I have granted all privileges to the public.
  Although I can see the table of the dictionary with SQL, and object browser, I am the owner; but, SQL will not allow me
  describe the table
  Select from the table
  even remove the table, so I can recreate another way.
  
  All I get never the SQL tab or BACK SQL command line is "ORA-00942: table or view does not exist '- but it does not exist under my ownership and all privileges have been granted on the table. What's wrong? Thank you... Richard ([email protected])

  You need to learn how to CUT & PASTE

  Select * from 'Movie '.

  has provided previously you & you still ignore it.

• If the default value in columns on slot form of table does not work.

  Hello
  
  I created a tabular form and I want to set some default values to columns that are based on the values of page elements.
  
  so I put the page element to the value of the column in the attributes in a table by selecting the value & P24_ISSUE_ID. default type as Expression PLSQL & DEFAULT function there but
  in the same way, I tried for the other column by selecting the type default as pl/sql expression and function by default the value & P24_CASE_NAME.
  
  but it throw an error of this type could not parse the SQL query: ORA-00904: "C254DB": invalid identifier
  
  I don't understand where I did wrong, I checked for the data types of columns, all right.
  
  so please help me out of this problem.

  1243 Tulasi wrote:
  for the first column

  I chose
  The DEFAULT TYPE as PL/SQL Expression & FUNCTION

  As the default * & P24_ISSUE_ID.* it is a number data type column

  2nd column

  The default Type as PL/SQL Expression & function

  As the default * & P24_CASE_NAME.* it's column of type Varchar2.

  Element (name of the page element or application) for the default Type and the name of the default item ( P24_ISSUE_ID, P24_CASE_NAME etc.) options appropriate for a default value for a page element.

  * & P24_ISSUE_ID.* is not a "PL/SQL Expression or function.

  but it throws an error, because this guy could not parse the SQL query: ORA-00904: "C254DB": invalid identifier

  What you're doing results in the engine of the APEX, P24_CASE_NAME 'C254DB' value in the default value and then try to assess this string as a piece of PL/SQL. Outside a block in which it is defined as a variable, constant, or a function 'C254DB' is not a valid expression of PL/SQL.

• Form of muse does not work on godaddy and no error message indicating a php error occurs. Perhaps wrong? I have to manually set once charged form for Go Daddy to lead through their form of mail system?

  I read in several places on the forum that muse forms are now supported on third party platforms. However, I have great difficulty to pretend to work on Godaddy. They seem to no longer have the option 'form mailer' and told me to look at this PHP: Mail - Manual to forms of work. Muse is not give error messages indicating that there is a problem on the end of go daddy, the form appears to work but no message is received at the e-mail address. can anyone help solve this for me.

  Thank you.

  Hello

  Please check the email that is in use, try to change it and check if the notification is received that would isolate the issue.

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  Thank you

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• Contact form of muse does not work with the e-mail address of the Yahoo customer. Any solution yet?

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• the form validation (Checkbox) does not work for the interactive report

  Hello
  
  I use the oracle apex 4.0 and oracle 11g.
  
  I wrote a under select query on interactive report
  
  Select
  apex_item. CheckBox(1,RESIDD) | apex_item. Hidden(2,RESIDD) row_selector.
  apex_item. Text(3,RESNUM) as resnum
  of 'PDRRES '.
  
  and written validation to display the error message ( error of function return text ) as
  
  DECLARE
  vRow directory;
  BEGIN
  -apex_application.g_print_success_message: = NULL;
  
  BECAUSE me in 1... apex_application.g_f01. COUNTY
  LOOP
  vRow: = apex_application.g_f01 (i);
  apex_application.g_print_success_message: = apex_application.g_f01 (i) | » -'|| apex_application.g_f03 (vRow) ;
  END LOOP;
  END;
  
  Output: No data available error message
  
  As long as it works for sql report with above logic because apex built in line selector
  but it fails in the case of interactive report for some reason any.
  
  Please suggest.

  Saroj Nayak

  Saroj Nayak says:

  DECLARE
  vRow BINARY_INTEGER;
  BEGIN
  --  apex_application.g_print_success_message := NULL;
  
  FOR i IN 1 .. apex_application.g_f01.COUNT
  LOOP
  vRow := apex_application.g_f01(i);
  apex_application.g_print_success_message := apex_application.g_f01(i)||'-'|| apex_application.g_f03(vRow) ;
  END LOOP;
  END;
  

  You have set the value of vRow to the value of the number box i which is checked. There is probably nothing in the apex_application.g_f03 with RESIDD as index table

  What you want is hollow loop all the hidden objects g_f02
  and with in this loop through all verified elements checkbox g_f01
  and if the values of these in the game, you have your line for checking f03

  for k in 1 .. apex_application.g_f02.count
  loop
    for p in 1 apex.application.g_f01.count
    loop
      if   apex_application.g_f01(p) =  apex_application.g_f02(k)
      then
        apex_application.g_print_success_message := apex_application.g_f01(p)||'-'|| apex_application.g_f03(k) ;
      end if;
    end loop;
  end loop;
  

  Nicolette
  PS your NPA between

  { code }Your code { code } without the spaces between {, } and code 
  

• My treatment in my web form credit card does not work!

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• Plu SQL does not work with suse 11

  Hello
  
  I am trying to oracle 11 g and when I try to run sqlplus it tell me:
  
  Error 6 initialization sqlplus
  SP1 file < lang > .msb not found message
  SP2-0750: you may need to set ORACLE_HOME in your Oracle software directory.
  
  After I run oraenv, I write the sid... but sqplus shows the same message.
  
  Any idea?
  
  Thank you

  user648940 wrote:
  Hello
  Any idea?
  Thank you

  Yes.
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• Contact the Forum does not work on the accommodation of third party (former title now

  I created a site in muse with a simple contact form. When I write the site to a third party host the email filed does not work unless I use my creative cloud email any other email gives me a "the server has encountered an error" when the submit button

  

  Work with your hosting provider.

  Something is change the generated files from Muse.

  There is more information on troubleshooting the forms here <> .

  The script form_check.php on your site returns the following:

  

  This strongly implies that something changes the generated files from Muse.

  This page should contain display three lines of text, where at least the first two have green check marks indicating PHP and a sender are configured correctly (as far as Muse can tell). The third green check mark or a red x can be ignored. It refers to SQL, which is optional. The form will work without it.

• Is it possible to return to the synchronization of the former in Firefox, as new synchronization does not work.

  As new synchronization does not work for me, despite the setting it in total compliance with the Mozilla Web site and no one took the trouble to answer the previous post today, is it possible to return to the synchronization of the former?

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