get the name of the data with scsi CanonicalName store
Hello
I need name of data store that we define when adding LUN... I have that... with the same canonical name scsci in need of the cluster name, host name, and virtual machine running on this Lun.
This sample script:
Get-data-center "testdt" | Get-cluster "tstclu" | Get-Vmhost | Get-ScsiLun - CanonicalName * 6006016010122900 *.
Try like this
New-VIProperty -Name lunDatastoreName -ObjectType ScsiLun -Value { param($lun) $ds = $lun.VMHost.ExtensionData.Datastore | %{Get-View $_} | where {$_.Summary.Type -eq "VMFS" -and ($_.Info.Vmfs.Extent | where {$_.DiskName -eq $lun.CanonicalName})} if($ds){ $ds.Name }} -Force | Out-Null
I've updated the code on VIProperties as well.
Thanks for finding this 'feature '.
Tags: VMware
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Khaldiuser601042 wrote:
I want to get the date with milliseconds in table format in the variable. How to get there?SQL > create table test_date (col1 date);
Your data col1 type should be TIMESTAMP.
See you soon
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Hello
I need to shoot the records with one value of 'Other' more on delivery days fields.
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Scott@my11g SQL>with sampledata as ( 2 select 123 cust_id, 'newspaper' item, 'Home' mon, 'Work' tue, 'Other' wed, 'Home' thu, 'Other' fri, 'Other' sat from dual 3 union all 4 select 456, 'newspaper' item, 'Home' mon, 'Work' tue, 'Home' wed, 'Home' thu, 'Home' fri, 'Other' sat from dual 5 ) 6 --#### True query starts here #### 7 select * 8 from sampledata 9 where ( 10 decode(mon,'Other',1,0) 11 +decode(tue,'Other',1,0) 12 +decode(wed,'Other',1,0) 13 +decode(thu,'Other',1,0) 14 +decode(fri,'Other',1,0) 15 +decode(sat,'Other',1,0) 16 )>1 ; CUST_ID ITEM MON TUE WED THU FRI SAT ---------- --------- ---- ---- ----- ---- ----- ----- 123 newspaper Home Work Other Home Other Other
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Hello everyone,
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Hello
The WHERE clause controls the lines will appear.
If your needs change, change the WHERE clause to reflect their.For example:
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This will work as long as you want the first & yes_cnt lines to display (assuming that there are many) and the following lines & no_cnt don't step to display, and then another & yes_cnt lines to display and the other & no_cnt lines not to display and so on.
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This is how Java has shaped the date in Spanish. It is not specific to the WebCenter Sites.
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__________________________________________________________________________________________ _____________________________
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I have two tables TableA and TableB. I struggle to write a query to get the dates of TableB (instead of TableA dates) where TableA dates don't coincide with the tableB (beginning and end).
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Use TableB start and end date and combine number two rows from TableA for this account
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Use TableB start and end date and combine number three rows from TableA for this account.
ACCOUNT TableB_BEGIN TableB_END AMOUNT D5555 08/08/2014 10/09/2014 1100.0000000000 Example 4: To account E6666.
Table corresponds to a row with TableB and no additional lines in TableA, just display the data in A table
Tables and data:
create table TableA ( Account varchar2(10) not null, Begin date not null, End date not null, Amount number(19,10) not null ) ; create table TableB ( Account varchar2(10) not null, Begin date not null, End date not null, Amount number(19,10) not null ) ; TableA Data: insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('31-01-2014', 'dd-mm-yyyy'), 0.0000000000); insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('03-03-2014', 'dd-mm-yyyy'), 100.0000000000); insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('B7777', to_date('18-04-2013', 'dd-mm-yyyy'), to_date('06-05-2013', 'dd-mm-yyyy'), 120.0000000000); insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('C6666', to_date('25-06-2014', 'dd-mm-yyyy'), to_date('08-07-2014', 'dd-mm-yyyy'), 10.0000000000); insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('16-08-2014', 'dd-mm-yyyy'), 1000.0000000000); insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 0.0000000000); insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('D5555', to_date('16-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 100.0000000000); insert into tablea (ACCOUNT, BEGIN, END, AMOUNT) values ('E6666', to_date('01-01-2014', 'dd-mm-yyyy'), to_date('01-02-2014', 'dd-mm-yyyy'), 100.0000000000); TableB Data: insert into tableb (ACCOUNT, BEGIN, END, AMOUNT) values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('03-03-2014', 'dd-mm-yyyy'), 100.0000000000); insert into tableb (ACCOUNT, BEGIN, END, AMOUNT) values ('B7777', to_date('05-04-2013', 'dd-mm-yyyy'), to_date('06-05-2013', 'dd-mm-yyyy'), 200.0000000000); insert into tableb (ACCOUNT, BEGIN, END, AMOUNT) values ('C6666', to_date('06-06-2014', 'dd-mm-yyyy'), to_date('08-07-2014', 'dd-mm-yyyy'), 10.0000000000); insert into tableb (ACCOUNT, BEGIN, END, AMOUNT) values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 1100.0000000000); insert into tableb (ACCOUNT, BEGIN, END, AMOUNT) values ('E6666', to_date('01-01-2014', 'dd-mm-yyyy'), to_date('01-02-2014', 'dd-mm-yyyy'), 100.0000000000); SELECT A.ACCOUNT, A.BEGIN, A.END, A.AMOUNT, B.ACCOUNT, B.BEGIN, B.END, B.AMOUNT FROM TABLEA A LEFT JOIN TABLEB B ON A.ACCOUNT = B.ACCOUNT
Hello
SeshuGiri wrote:
Hi Frank,.
Your query/solution works very well, but I forgot to mention something in the first post...
Please insert these additional lines and try the request again.
TableA Additional lines:
- Insert into TABLEA (ACCOUNT, BEGIN, END, QUANTITY)
- values ('F9999', to_date (January 2, 2014 ',' dd-mm-yyyy ""), to_date (3 January 2014 ', 'dd-mm-yyyy'), 999.0000000000);
- Insert into TABLEA (ACCOUNT, BEGIN, END, QUANTITY)
- values ('A1234', to_date (March 3, 2014 ',' dd-mm-yyyy ""), to_date (4 March 2014 ', 'dd-mm-yyyy'), 999.0000000000);
TableB Additional lines:
- Insert into TABLEb (ACCOUNT, BEGIN, END, QUANTITY)
- values ('A1234', to_date (March 3, 2014 ',' dd-mm-yyyy ""), to_date (4 March 2014 ', 'dd-mm-yyyy'), 999.0000000000);
Question 1:
The table has a rows for A1234 account (i.e. the time period different than the ranks for the same account)
one is A1234 31/01/2014-03/03/2014, A1234 03/03/2014-03/04/2014
Your query that returns two rows for A1234 account (which is what I want), but the amount is messed up.
ACCOUNT BEGIN END TOTAL_AMOUNT 1 A1234 31/01/2014 03/03/2014 1100 2 A1234 03/03/2014 03/04/2014 1100 Except:
ACCOUNT BEGIN END TOTAL_AMOUNT 1 A1234 31/01/2014 03/03/2014 101 2 A1234 03/03/2014 03/04/2014 999 Question 2:
In some cases TableA will have an account (F9999), but the TableB don't. I can just this line by making the Left Join right join?
I don't get the results with additional data. I get 1099 for two lines where account = 'A1234 '. I get 1100 as the amount on the line with the account = "D5555. You did it other changes to data?
Except:
ACCOUNT BEGIN END TOTAL_AMOUNT 1 A1234 31/01/2014 03/03/2014 101 2 A1234 03/03/2014 03/04/2014 999 Still, I don't see why you want to 101 for the amount of the first row. Why not 100?
How can you know which rows from tablea should get attached to what rows from tableb, when the account is not unique?
Maybe you want something like this:
SELECT a.account
b.begin
b.end
SUM (a.amount) AS total_amount
FROM tablea a
ON a.account = b.account JOIN tableb B
AND a.begin BETWEEN b.begin
AND b.end
AND a.end BETWEEN b.begin
AND b.end
GROUP OF a.account, b.begin, b.end
ORDER BY a.account
;
but I guess just to your needs, and guessing is not a very good or reliable way to solve problems.
Question 2:
In some cases TableA will have an account (F9999), but the TableB don't. I can just this line by making the Left Join right join?
Yes, it looks that you want an outer join. What happened when you tried? As always, post your code, the exact results you want from the given sample data, as well as an explanation of how you get these results from these data.
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