get the number of layer of selectedLayers array

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• Get the number of frame composition before

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  "In Action script 3, I can easily get image number of the layer type"mcA.currentFrame "" "

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  Dan

• Get the number of CountItems by group in CS5 extended

  I have a collection of photos with count items created with the count tool in CS5 extended version. Each element of the county belongs to one of the 5 county groups created with the count tool. Using the Photoshop COM, I can get the total picture count items (Document.CountItems.Count ()). However, I can not get the number of items count by County group, or the group a County element belongs to. Someone managed to access groups of count? I use c#, but a solution to any language would be useful.

  Hi here are some features on how to get the length of the charges for a group:

  examples: =.

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  // ===================================

  function getCountsInGroup (idx) {}

  cArr var = listCountsArr();

  return of cArr [idx];

  }

  function getCurrentGroup() {/ / find the index of the selected group}

  var firstArr = listCountsArr(); / / make a list with tables like grpoups and inside these objects for each count

  addTempCount(); / / create a temp cont

  var listCountsArr() = secArr; / / make a second list

  theCGroup = 0;

  for (i = 0; i

  {If (firstArr [i] .length! = {secArr [i] .length)}

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  break;

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  var / / desc = new ActionDescriptor();

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  var / / desc = new ActionDescriptor();

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  cArr var = new Array();

  Var ref = new ActionReference();

  ref.putEnumerated (charIDToTypeID ("Dcmn"), charIDToTypeID ('Ordn'), charIDToTypeID ("Trgt'));

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  var crntG = 0;

  var grpArr = new Array();

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  itX var = desc1.getObjectValue (i) .getUnitDoubleValue (charIDToTypeID ("X"));

  itY var = desc1.getObjectValue (i) .getUnitDoubleValue (charIDToTypeID ("Y"));

  var cntObj = {x: itX, y: itY, grpIDX:gr, idx:itI, domI: I};

  if(crntG == gr) {}

  grpArr.push (cntObj);

  }

  If (crntG! = size) {}

  cArr.push (grpArr);

  grpArr = new Array();

  grpArr.push (cntObj);

  crntG = gr.

  }

  }

  cArr.push (grpArr);

  return of cArr;

  }

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  system variable 'PROCESSOR_ARCHITECTURE '?

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• Get the number of elements in the header in GroupDataModel

  Hey everybody!

  I wonder how to get the number of items in each topic in a GroupDataModel. Here's a code, where headerCount would be the number of items in each section:

  ListView {
              dataModel: _app.dataModel
  
              layout: StackListLayout {                    headerMode: ListHeaderMode.Sticky            }
  
              listItemComponents: [
                  ListItemComponent {
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                      Container {
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                  ListItemComponent {
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                      Container {
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              ]
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  Also here is the code of applicationui.cpp, where it defines the datamodel. It's using GroupDataModel.

  void ApplicationUI::initDataModel()
  {
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  Hope that makes sense. If you have any questions, let me know!

  This will help you

  https://developer.BlackBerry.com/native/reference/Cascades/bb__cascades__GroupDataModel.html#functio...

  Your header looks like this

  ListItemComponent {
      type: "header"
  
      Container {
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          Label {
              text: ListItemData + " " + rootItem.ListItem.view.dataModel.childCount(rootItem.ListItem.indexPath)
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      }
  }
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  It may be useful

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• Get the number of files in the folder

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• get the number in the declaration of DBMS

  Hello everyone,

  my friend, I create the following code, but I've always faced a problem to display the result of County all the

  the code is:

  ------------------------------

  I insert a count (*) to get the number of employees

  but he keep get only '1' to the last of the result in the following way:

  DETAILS OF THE EMPLOYEE:

  YJOSEPH5 | YOUSEFJOSEPH | 15 NOVEMBER 15

  HYOUSEF10 | HASSANYOUSEF | 15 NOVEMBER 15

  HYOUSEF17 | HASSANYOUSEF | 15 NOVEMBER 15

  HYOUSEF14 | HASSANYOUSEF | 15 NOVEMBER 15

  HYOUSEF16 | HASSANYOUSEF | 15 NOVEMBER 15

  COUNT: 1

  the code

  ------------------------------------

  DECLARE
  V_USER_ID VARCHAR2 (50);
  NUMBER OF V_EMP_NO;
  V_FIRST_NAME VARCHAR2 (30);
  V_LAST_NAME VARCHAR2 (30);
  DATE OF V_REG_DATE;
  NUMBER OF V_COUNT;
  V_SQL_SATEMENTS VARCHAR2 (1000);
  NCOUNT THE NUMBER;
  CURSOR C IS SELECT USER_ID, EMP_NO, FIRST_NAME, LAST_NAME, REG_DATE, COUNT (*) FROM EMP
  USER_ID, FIRST_NAME, LAST_NAME, EMP_NO, REG_DATE GROUP;
  BEGIN
  OPEN C;
  SELECT COUNT (*) FROM NCOUNT FROM USER_TABLES WHERE TABLE_NAME = 'EMP ';
  IF (NCOUNT < = 0) THEN
  V_SQL_SATEMENTS: =' CREATE TABLE EMP)
  USER_ID VARCHAR2 (40) PRIMARY KEY,.
  NUMBER OF EMP_NO,
  FIRST NAME VARCHAR2 (30),
  VARCHAR2 (30) LAST_NAME,.
  DATE OF REG_DATE)';
  
  RUN IMMEDIATELY "DROP TABLE EMP;
  IMMEDIATELY RUN V_SQL_SATEMENTS;
  END IF;

  SELECT NVL (MAX (EMP_NO), 0) + 1
  IN V_EMP_NO
  YOUSEF. EMP;
  INSERT YOUSEF. EMP (USER_ID, EMP_NO, FIRST_NAME, LAST_NAME, REG_DATE)
  VALUES (SUBSTR (: LAST NAME, 1, 1) |: LAST_NAME |) V_EMP_NO, V_EMP_NO,:FIRST_NAME,:LAST_NAME,TO_DATE(SYSDATE,'DD-MON-YY'));
  DBMS_OUTPUT. PUT_LINE (' DETAILS OF THE EMPLOYEE: "");
  LOOP
  EXTRACT THE C IN V_USER_ID, V_EMP_NO, V_FIRST_NAME, V_LAST_NAME, V_REG_DATE, V_COUNT;
  WHEN THE EXIT %C NOTFOUND;

  DBMS_OUTPUT. PUT_LINE (V_USER_ID |'|) ' || V_FIRST_NAME | V_LAST_NAME |' | ' || V_REG_DATE);
  END LOOP;
  DBMS_OUTPUT. PUT_LINE ("COUNT:" | "|") V_COUNT);

  CLOSE C;
  END;
  /

  ALL FRIENDS,

  THANKS FOR EVERY BODY,

  I JUST FOUND THE RIGHT WAY TO DO

  FOR THOSE WHO WANT TO SEE:

  -----------------------------------------------------------

  DECLARE
  V_USER_ID VARCHAR2 (50);
  NUMBER OF V_EMP_NO;
  V_FIRST_NAME VARCHAR2 (30);
  V_LAST_NAME VARCHAR2 (30);
  DATE OF V_REG_DATE;
  NUMBER OF V_COUNT;
  V_SQL_SATEMENTS VARCHAR2 (1000);
  NCOUNT THE NUMBER;
  CURSOR C IS SELECT USER_ID, FIRST_NAME, LAST_NAME, EMP_NO FROM EMP REG_DATE;
  BEGIN
  SELECT COUNT (*) IN THE EMP V_COUNT;
  OPEN C;
  SELECT COUNT (*) FROM NCOUNT FROM USER_TABLES WHERE TABLE_NAME = 'EMP ';
  IF (NCOUNT<=0)>
  V_SQL_SATEMENTS: =' CREATE TABLE EMP)
  USER_ID VARCHAR2 (40) PRIMARY KEY,.
  NUMBER OF EMP_NO,
  FIRST NAME VARCHAR2 (30),
  VARCHAR2 (30) LAST_NAME,.
  DATE OF REG_DATE)';
                                           
  RUN IMMEDIATELY "DROP TABLE EMP;
  IMMEDIATELY RUN V_SQL_SATEMENTS;
  END IF;

  SELECT NVL (MAX (EMP_NO), 0) + 1
  IN V_EMP_NO
  YOUSEF. EMP;
  INSERT YOUSEF. EMP (USER_ID, EMP_NO, FIRST_NAME, LAST_NAME, REG_DATE)
  VALUES (SUBSTR (: LAST NAME, 1, 1) |: LAST_NAME |) V_EMP_NO, V_EMP_NO,:FIRST_NAME,:LAST_NAME,TO_DATE(SYSDATE,'DD-MON-YY'));
  DBMS_OUTPUT. PUT_LINE (' DETAILS OF THE EMPLOYEE: "");
  LOOP
  EXTRACT THE C IN V_USER_ID, V_EMP_NO, V_FIRST_NAME, V_LAST_NAME, V_REG_DATE;
  WHEN THE EXIT %C NOTFOUND;

  DBMS_OUTPUT. PUT_LINE (V_USER_ID |'|) ' || V_FIRST_NAME | V_LAST_NAME |' | ' || V_REG_DATE);

  END LOOP;

  CLOSE C;
  DBMS_OUTPUT. PUT_LINE ("COUNT:" | "|") V_COUNT);

  END;
  /

• How to get the number of entries in the navigation menu?

  

  How to get the number of entries in the navigation menu? Check the image. What it shows 8 number of customers and 10 products and 10 orders in the list. How to get it?

  --

  Thank you

  Hello

  Create items of the request saying, "CUSTOMERS", "PRODUCTS" and "ORDERS".

  Create the application process that defines these items when loading the page for example

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  loop

  : CUSTOMERS: = c1.cnt;

  end loop;

  C1 in select count (*) NTC (of products_table)

  loop

  PRODUCTS: = c1.cnt;

  end loop;

  C1 in select count (*) NTC (of orders_table)

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  Components shared Open-> Navigation bar and change:

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• Get the number of days in a month based on the month and year of fields

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  Found this on some forum javascript code:

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function daysInMonth(month,year) {
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}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

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  The code seems to be JavaScript and runs as needed by using the JavaScript console.

  I would like to consider making more general code, so if you have a date string that includes at least the month and year we could just call the function and get the number of days for that month.

  The following script will calculate the number of days in a month, by using at least the month and year values can display the result on the JavaScript console and all of the value field for the field that has this code as the custom calculation Script.

  function daysInMonth (oDate) {}
  return new Date (oDate.getFullYear (), oDate.getMonth () + 1, 0) .getDate ();
  }

  nMonth var = this.getField("Month").valueAsString; get the value of month;
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  Event.Value = "";

  If (nMonth! = "" & nYear!) = "") {}
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  Console.Open (); Open the JavaScript console;

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  }

• get the number of the day of the week - any national locale is used

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  I heard that some countries start the week of Sunday.

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  PL/SQL Release 11.2.0.1.0 - Production

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  2621671 wrote:

  Hi all

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  ...

  That's what you asked for, whatever your NLS settings:

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  I heard that some countries start the week of Sunday.

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• Get the number of CPU of the machine virtual and carrots

  Hello

  I tried the following, but failed to get the number of CPUS the VM and carrots. What I am doing wrong?

  

  Of course, try like this

  $myCol = @)

  foreach ($cluster Get-cluster)

  {

  foreach ($vmhost in ($cluster |)) Get - VMHost))

  {

  foreach ($vm in (Get-VM-location $vmhost)) {}

  $VMView = $vm | Get-View

  $VMSummary = "" | Select NOMCLUSTER, HostName, VMName, VMSockets, VMCores, CPUSockets, CPUCores

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  $VMSummary.HostName = $vmhost. Name

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