go to random frame without repetition

Similar Questions

• 6 random numbers without repetition

  I'm doing a generator of 6 random numbers between 1 and 48. When the user clicks a button randomly 6 numbers appear in 6 different textFeilds. The problem is that I don't want the same number twice. How can I generate 6 different random numbers without using back and out of the service?

  import flash.events.Event;

  Stop();

  btn.addEventListener (MouseEvent.CLICK, random1);

  function random1 {(evt:Event)}

  display1. Text = "";

  Display2.text = "";

  Display3.text = "";

  display4. Text = "";

  display5. Text = "";

  display6. Text = "";

  var r1 = Math.floor (Math.random () *(1+48-1)) + 1;

  var r2 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A3 = Math.floor (Math.random () *(1+48-1)) + 1;

  var r4 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A5 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A6 = Math.floor (Math.random () *(1+48-1)) + 1;

  If (r2 = r1 | r3 == r2 | r4 == r3 | r5 == r4 | r6 = r5) {}

  return;

  }

  var list: Array = new Array();

  Liste.push (R1, R2, R3, R4, R5, R6);

  Liste.sort (Array.Numeric);

  display1. Text = String (list [0]);

  Display2.Text = String (list [1]);

  Display3.Text = String (list [2]);

  display4. Text = String (list [3]);

  display5. Text = String (list [4]);

  display6. Text = String (list [5]);

  }

  Here is the code for the approach mentioned with your included textfields

  btn.addEventListener (MouseEvent.CLICK, random1);

  function random1 {(evt:Event)}

  var nums:Array = new Array();

  Complete the table of numbers

  for (var i: uint = 1; i<=48;>
  Nums.push (i);
  }

  Shuffle (NUMS);

  Take the first six of the mixed table

  var list: Array = nums.splice (0.6);

  assign values to the textfields

  for (var j: uint = 1; j<=6;>
  This ["Display" + String (j)] .text = String (list [j]);
  }
  }

  function shuffle(a:Array) {}
  var p:int;
  var t: *;
  var ivar:int;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

• Error #2007: HitTestObject parameter must be non-null error comes if I'm going to another frame without success

  Error #2007: HitTestObject parameter must be non-null

  at flash.display::DisplayObject/_hitTest()

  at flash.display::DisplayObject/hitTestObject()

  but my hitTestObject works well in the frame 4 displays error when I goto another frame without hitting the object

  If I touched the subject, then I goto frame 1 this error does not appear. This means that the code made mandatory hit error otherwise. How to get rid of this

  var live: myscrew = new myscrew();

  addEventListener (Event.ENTER_FRAME, checkCollision);

  function checkCollision(event:Event) {}

  star test against crescent

  If (keys.hitTestObject (chest)) {}

  Screw.x = 100;

  Screw.y = 100;

  addChild (screw);

  removeChild (chest);

  }

  }

  This code used to goto frame 1.

  arrowtwo.addEventListener (MouseEvent.CLICK, fl_MouseClickHandler_two222);

  function fl_MouseClickHandler_two222(event:MouseEvent):void

  {

  gotoAndStop (1);

  }

  Remove the event listener before you change settings.

  removeEventListener (Event.ENTER_FRAME, checkCollision);

• How to set a picture FRAME without the picture?

  Before the new version of 2015.1, when I placed a picture on a page, then I could adjust the size of the frame without at the same time, adjusting the actual image. THEN double-click on and adjust the image without changing the framework... it has changed... Please help!

  Use the crop tool.

• Images often open bridge in the form of black frames without content.

  Images often open bridge in the form of black frames without content. The image may appear when enlarged or reduced, but in normal view, the framing will be black. The only way I am able to fix this problem is to restart photoshop. What can I do to prevent this?

  Have you tried turning off your GPU in Photoshop and perhaps also Bridge preferences?

• Random frame appearing

  I I have a random frame appearing in my video. I have video is worth a thousand words so check it out.

  http://youtu.be/__mt86Zecvs?HD=1 & t = 10s
  

  It starts at the first image of the item highlighted. There is no ther above it.

  The video is a. MOV my t2i. Cs5.5 running on Lion.

  Capture MPEG Streamclip; It's free, does not require a facility, and the latest beta version is fine.

  Open the awkward element in MPEG Streamclip. Go to file > save as and save a new copy of the file as a MOV - can - be give it a slightly different name. It's just repackaging of the file, do not re - encode.

  Back in Pr, right-click on the item in the project Panel, and then select replace sequences. Access the new MOV, you created, then select it. Click OK and look at the item in the sequence.

• How to sort a random number without using the command by

  Hello
  
  How must be sorted, 5 random number without the use of order by in PLSQL
  for example.
  amount of ID
  1 2
  2 9
  3 3
  4 5
  5 7
  
  Edited by: sake1 1-dec-2010 08:16

  I used Altavista and found an example, how is it?

  DECLARE
  
    /* there is no built array in oracle, you must declare
    your own */
    TYPE Numarray IS TABLE OF NUMBER INDEX BY BINARY_INTEGER;
  
    /* the array of numbers - using assoc array because I can start
    with zero like traditional arrays */
    Nums Numarray;
  
    n NUMBER := 0;
  
    Temp NUMBER;
  
  BEGIN
  
    /* load up the array, put 20 random values in the array,
    in array indicies 0 to 19 */
    FOR i IN 0 .. 19
  
     LOOP
      Nums(i) :=  Round(Dbms_Random.Value(1, 1000));
    END LOOP;
  
    /* get the array size */
    n :=  Nums.Count();
  
    /* display the unsorted values - loop through the whole array and
    print out the values */
    Dbms_Output.Put_Line('unsorted:');
    FOR i IN Nums.First .. Nums.Last LOOP
      Dbms_Output.Put_Line(Nums(i));
    END LOOP;
  
    /* bubble sort - using two loops, compare each value with the one
    after it
    if the one after the current one is smaller , then
  
    switch their locations in the array, this is just like standard
    bubble sorts
    in other languages. The only real diff is the syntax.
    */
  
    FOR i IN 0 .. n - 1 LOOP
      FOR j IN 0 .. n - (i + 1) - 1 LOOP
  
        IF (Nums(j) > Nums(j + 1)) THEN
          Temp := Nums(j);
          Nums(j) :=  Nums(j + 1);
          Nums(j + 1) :=  Temp;
        END IF;
  
      END LOOP;
    END LOOP;
  
    /* display the values sorted */
    Dbms_Output.Put_Line('sorted');
    FOR i IN Nums.First .. Nums.Last LOOP
      Dbms_Output.Put_Line(Chr(9) || Nums(i));
    END LOOP;
  END;
  /*
  unsorted:
  155
  909
  795
  977
  942
  214
  105
  269
  283
  820
  108
  594
  784
  921
  856
  736
  802
  457
  951
  411
  sorted
       105
       108
       155
       214
       269
       283
       411
       457
       594
       736
       784
       795
       802
       820
       856
       909
       921
       942
       951
       977
  
  */
  

  In the code the first comment is wrong in fact, I think, this one:
  "There is no table built in oracle, you must declare your own."
  I remember there are some types of collection of the system, if I not mix with something, I remember there was a sort of like they were undocumented, so we can say legally that the comment in the code has always been right.

• Random table without sequential repetitions

  Hello

  Continue to build the practice of e-Learning (lots of help from kglad). Came across a problem with sequential repetitions in the table randomly, which need a solution. The AS3 script (a lot of help here from kglad) to generate and then mix the table, often (since there are only 9 potential elements for a length of array of 70) product of the sequential repetitions. For example, you use 1,2,3,4,5,6,7,8,9 as elements, the mixed final table may produce 2,2,2, 1,4,5,9,3.3...

  Problem is that when these repetitions are used as textbox.text, there is no transition between same (repeated) "words." If a Word change (for example, 5-3), the user sees a visiable change. However, with these sequences repeated (for example, 02:57), there is no transition: repetition seems to remain the same for extended periods of time. Then, the user is not sure if they have already chosen this word.

  In any case it would be preferable, since I can't add a visible transition for rehearsals, to simply avoid sequential repetitions, if possible. But can not find a way to add to the script.

  Any help appreciated.

  The scripts array and shuffle random current:

  var index:int = 0;
  var numToDisplay:int = 10;
  var groupA:Array = ["1","2","3"]
  var groupB:Array = ["4","5","6"]
  var groupC:Array = ["7","8","9"]
  var word_array:Array = [];
  var i:int;
  for(i=0;i<3;i++){
  word_array.push(groupA[Math.floor(groupA.length*Math.random())]);
  }
  for(i=0;i<3;i++){
  word_array.push(groupB[Math.floor(groupB.length*Math.random())]);
  }
  for(i=0;i<3;i++){
  word_array.push(groupC[Math.floor(groupC.length*Math.random())]);
  }
  
  shuffle(word_array);
  
  function shuffle(a:Array) {
          var i:int;
          var j:int;
          var e:*;
          var len:int = a.length;
          for (i = len-1; i>=0; i--) {
              j=Math.floor((i+1)*Math.random());
              e = a[i];
              a[i] = a[j];
              a[j] = e;
          }
  }
  

  You are welcome and if you are willing, please mark the thread as answered so we can filter the questions unanswered. Good luck!

• AppleScript, random items in list, without repetitions?

  Hello

  First of all it is what I have so far:

  the value myList {"Bob", "Brian", "Mark", "Joshua", "Sarah", "George"} as list

  Repeat

  the value of some element of myLIst randomChoice

  randomChoice2 the value of some element of myList

  display the dialog randomChoice & return & randomChoice2

  end repeat

  If you run this script, you will notice that sometimes there will be two of the same name (Bob Bob or Mark Mark).

  I want to be able to make sure the two random elements are not the same. So that once that a name is chosen as a randomChoice, it can not be chosen for the randomChoice2.

  Here:

  the value myList {"Bob", "Brian", "Mark", "Joshua", "Sarah", "George"} as list

  the value myList2 {"", ""}

  Repeat

  point 1 of the myList2 the value of some element of myList

  point 2 of myList2 the value of some element of myList

  Repeat until that point 1 of the myList2 is not point 2 of myList2

  point 2 of myList2 the value of some element of myList

  end repeat

  value {randomChoice, randomChoice2} myList2

  display the dialog randomChoice & return & randomChoice2

  end repeat

  (137457)

• Expression of remapping the colors at the moment of the random frame

  I work with a lot of hand-drawn loops and I am curious about the expressions that can make random display of a view of image sequences using the time remap property.

  For example, in hand-drawn traditional animation when you want to hold a pose without looking at static animation, you create what is called a trace, which means that you would trace physically at least 8 frames of the same design and then shoot over and repeatedly at random for as long, you need to ask.  In this way, you don't get the exact model of executives bike again and again as you would if you just loop it.

  Of course, you can manually rearrange frames in After Effects, but it takes a long time and I wonder if an expression can be written which could be easily changed for different sequences in different lengths and different.  For example, I found this expression by Filip Vandueren on the site Web of Creative Cow http://forums.creativecow.net/thread/227/12413 , she was destined to randomize a sequence of 5 images, however, the sequence and the model must be at the same frame rate in order to make it work.  Therefore, I have to work to a sequence of 12 IPS in a 12 fps model, if I want the animation to look like he was shot the 2s.  Usually a sequence of 12 fps without time remapping of expressions will play on 2 s if it is in a model of 24 frames per second and I can tell using time stretch or posterize time does not work.  Stretch time does nothing and posterize time crashes after effects when I add it to the when of image with the expression applied to the time remap property.  This probably has something to do with a conflict of expressions that happens once the time remapping effect is applied to the image sequence.  In any case, I ask if there is a way to change this expression so that I could put my pictures in a model at a different rate and use the expression itself to tell him to play 8 VPS, 12 FPS or any other cadence.

  This is expression of Filip Vandueren

  seedRandom(1,true);

  var t = timeToFrames ();

  var r1 = - 3;

  var r2 = - 2;

  var A3 = - 1;

  for (var i = 0; t > = i; i ++) {}

  var A3 = Math.floor (random (5));

  If (r1 = r3: r2 = r3) {}

  t ++ ;

  continue;

  }

  R1 = r2;

  R2 = r3;

  }

  framesToTime (r3);

  
  

  It is an expression based on Vandueren I tried to change to a sequence of images of 8 frame.  Any way, it worked, but it didn't really achieve what I was looking for.

  timeRemap

  seedRandom(2,true);

  var t = timeToFrames ();

  var r1 = - 6;

  var r2 = - 5;

  var A3 = - 4;

  var r4 = - 3;

  var A5 = - 2;

  var A6 = - 1;

  for (var i = 0; t > = i; i ++) {}

  var A3 = Math.floor (random (8));

  If (r1 = r3: r2 = r3) {}

  t ++ ;

  continue;

  }

  R1 = r2;

  R2 = r3;

  }

  framesToTime (r3);

  The image sequence played all 8 frames randomly without overlapping, but I could not yet understand how playing the fps 8 or 12 fps without consistent with rate of comp at the rate of the image sequence.  Ideally, I would like the expression to determine the frame rate so that I can have in a model with other frame rates and are not afraid to disturb the expression.

  Reorganization of the random images is a common thing for 2D animators to do this, I will also file a feature request After Effects to add this feature to an existing plug-in or create a standalone plugin.

  This should work:

  FR = 12; frame rate;

  numFrames = 8;

  seedRandom (index, true);

  SEG = Math.floor(time*fr);

  f = Math.floor (random (numFrames));

  for (i = 0; i< seg;="">

  f = (f + Math.floor (random(1,numFrames))) % numFrames;

  framesToTime (f);

  Dan

• iPhone 6s making random functions without touching.

  iPhone, 6, is random, making phone calls, for, people, list of contacts, or myself, with, touch, IT., he, too, plays, music, without touching, she and opening another, Lapps., all, have, been, made updates,., what, other solutions, can, any who do?

  Make an appointment at the genius bar to your Apple store. This is symptomatic of a damaged or, failing touch screen.

• T410 2516CTO random freezes without anything in the Windows Event Viewer. :(

  I used Update Retriever + slim Installer (practically system update 4.0 but a client version + server) to download the drivers and install Windows 7 Ultimate x 64 with SP1 on this machine. It takes a hard power off by pressing the button for 5 seconds

  Core i7 620M

  8 GB RAM

  320GB 7.2 k RPM HARD drive

  Optimus graphics

  Gobi2000 WWAN

  uPek Fingerprint reader

  The machine crashes without warning and did with the two installation (more common) factory and with the deleted HARD disk and using Windows 7 Ultimate SP1 from Microsoft x 64 slipstreamed (freezes much less often). Are there tools that I can use to help diagnose this problem?

  I also used an adapter 90W AC and 65W adapter on this machine. The random freezes occur on each adapter as well.

  I read other people who have the same frustrations on to freeze, but no other situation is exactly the same as mine unfortunately - most other occasions you can find something in the Windows Event Viewer!

  Hi again

  Discovered it was the 6300 WiFi Intel that was locking the machine. It disabled via switch h/w or BIOS does the gel to disappear.

  So he left. Once off the coast of the incident of a 6300 wireless card has failed.

• How to get to a stop and a random frame?

  Hello

  I have a little problem and I can't seem to find solutions.

  What I want is my symbol (= "pijl1" in which there are 4 images different keys on the timeline) to show one of the keyframes, randomly, then stop.

  (I'm trying to do a game like this http://www.youtube.com/watch?v=sYGJ0TRWdRM where my symbol would be one of the arrows randomly)

  I did this:

  import flash.events.Event;

  var pijl1:pijl = new pijl();

  pijl1.addEventListener (Event.ENTER_FRAME, randomdirect)

  function randomdirect (event: Event) {}

  var randomFrame:Number = (Math.floor (Math.random () * 4) + 1);

  trace (randomFrame);

  pijl1.gotoAndStop (randomFrame);

  addChild (pijl1);

  pijl1.x = 200

  pijl1.y = 200

  }

  but he won't stop. It takes just to go (the output becomes crazy).

  I don't know if I was clear. But if someone understands my problem, could you please help me?

  PIW

  Your frames loop entry constantly "replaces" your STOP function.

  You can simply remove the eventlistener after the stop funtion

  ....

  pijl1.gotoAndStop (randomFrame);

  pijl1. RemoveEventListener (Event.ENTER_FRAME, randomdirect)

  ....

• Loads of random MC without repeat

  I am loading a MC randomly using the following code:
  
  this.createEmptyMovieClip ("had", 1);
  bground._x = 0;
  bground._y = 0;
  
  var myClips:Array = new Array ("buzz_teamplay1.swf", "buzz_teamplay2.swf", "buzz_teamplay3.swf", "buzz_teamplay4.swf");
  
  var currentClip = random (myClips.length);
  bground.loadMovie ("buzz words /"+ myClips [currentClip] ");
  
  Stop();
  
  
  
  At the end of each MC, another is responsible for randomly using:
  
  this.loadMovie ("buzz words /"+ _root.myClips [random (_root.myClips.length)] ");
  
  Stop();
  
  
  This code can be modified to ensure that no MC is repeated twice?
  Thank you

  You are always welcome!
  Finally a small request, please my thread as answered this question.
  So that we can avoid other users to visit this thread here again without any needs.
  Thanks in advance!

• How can I transfer a photo library (raw and jpeg files) fram without loss of metadata and keywords?

  How can I transfer my favorite photos library on my MacBook to another library on an external hard drive without losing metadata and keywords?

  If you want to keep the metadata, you must export the images as the current versions, edited. File > export > export... images.  Then you can turn on the indicator "Tile, keys, descriptions words":

  

  Choose a high quality for JPEG, not to lose quality.  To the RAWs export them under like TIFF picture.

  You can export the RAWs as "file > export > export original unmodified" and keep it RAW, but which will not include the metadata.  And the Photos will allow you to export an XMP file with metadata, but when I tested, it did not apply the metadata when you import the RAW files again. So the best compromise for the RAW format would be to export as TIFF, another lossless format.