go to the next iteration of loop for and continue execution of the previous iteration

Similar Questions

• using 'next' in a loop for?

  Hello!
  
  can you just explain in an example how to use 'next' in the loop 'for '? I think that's exactly what I need, but I can't find examples of how to use it.

  TKS. O

  Just write the line of code below the for loop

  for (var I...) {

  No matter what

  }

  var instance: ClassName = new ClassName()

• loop for and while loop with empty table entry

  Hello

  I have a question with loop and loop.

  When a constant empty array (zero element) is connected to the loop For with "allowing the index", there are no interactions performed in loop For. But, if the loop is replaced by any loop, no problem.

  LabVIEW 2010

  Hello

  It is ok. I have no problem at all.

  For the 'loop' For when you connect the table thanks to indexing, the number of iterations is set to the size of the array. The iteration number assigned to N (in your case 10) is ignored.

  For the 'While' loop the number of iteration is defined by the Boolean Condition and the size of the array is ignored.

  Paul

• How to stop and start a loop for

  I got the code and a loop running in a while loop.  What I need to do, is simply to suspend the processing of the loop until a condition is met, but retains its position of iteration throughout each pause time (not necessarily time, just paused until the following condition is met).  I tried wiring of a Boolean value to "continue if true" terminal of the for loop, but the reboot of the iteration count to 0 when the loop is restarted.  Is there a way to stop the loop for and continue to the particular iteration, it is in?

  Breakpoints, conditional, or normal are intended just for debugging your code.  I had the sense of your question as you want make a break is part of the normal operation of your code.  I would NOT recommend using a breakpoint for this situation.  It would make it appear the diagram showing the breakpoint when it occurs.  A user not to mention that the programmer wouldn't know what to do in this case.

  Yes, both the inner and outer loops would shift registers.

  Implementation of a structure dealing with a small loop inside the "case of a break" is feasible.  Depends on what you are or wait while the operation of the program is "paused."

• synchronization of two loops for...

  HII...

  I am using two loops for and I want each iteration for both loops start at the same time...

  in fact I want to sync between these two loops...

  so when the each iteration of the two loops will start at the same time then these will be synchronized...

  also if a loop takes more time in an iteration the other loop should suspend until the end of the iteration of the other...

  please me... thanks hlp...

  Hi samir,.

  two options:

  1: when both FOR loops should have same time iteration why not just put all the code in a loop FOR?

  2nd: when 1 is not possible/wanted, you can use a notification utility. Set the notifier early iteration of the first for a loop and wait for the signal in the second loop...

  3rd: use call loops and synchronize them...

• How to stop a flat sequence (or timed sequence) which is inside a loop for

  The problem is this, I have a loop that repeats 10 times and inside this loop, I have a flat sequence (or timed sequence) with four images, each of this chassis to evaluate a different condition of a vector that I introduce.

  What I woud like for example is:

  I'm a fifth County of the loop for and in the case that part 2 does not meet the condition, the sequence of dish (or timed sequence) stops and starts the loop again but this time for the number of number 6.

  I would appreciate your response.

  You can't stop a sequence structure.  This is how they are made.

  What you should consider to get rid fo structures sequence and to change a state machine architecture.  There are many examples in LabVIEW, as well as on the Forums.  The big advantage of the state machine is that at the end of each State, it examines the conditions and determines which State then run. And that is exactly the description of the problem you are experiencing.

  Lynn

• How to stop a loop "for".

  Hello

  Do you know how I can stop a loop for? because when I click on the stop switch on my front, the VI didn't stop and continue to perform the loop.

  If you have a newer version of LabVIEW, you can right click on your loop For and show the terminal stop.  This will allow you to stop the execution of the loop For the earlier that you would otherwise based on the N or the number of items in an array of automatic indexation.

• for and while loops

  Hello, im new to java, and now I have an assignment. I need to analyze a phone number like this-> (656) 345 6544 to 6563456544. I wrote the following code which works very well with a while loop. Now, I would like to know how can I make it work with a loop for.
  
  and the code is

  import java.io.*;
  public class Tema
  {
  
    public static String removeChar(String str, int i)
    {
      String first= str.substring(0,i);
      String last= str.substring(i+1,str.length());
      str=first+last;
      return str;
    }
    public static String cautaTrimite(String str)
    {
       /*for(int i=0; i<str.length(); i++)
      {
         if ((str.charAt(i)==' ')  ||(str.charAt(i)=='5')  ||(str.charAt(i)=='(')
            ||(str.charAt(i)==')') ||(str.charAt(i)=='-'))
            {
            str = removeChar(str,i);
            }*/
         int i=0;
          while(i<str.length())
           {
               if(( str.charAt(i)== ' ' )||( str.charAt(i)== '8' )
                       ||(str.charAt(i)==')')||(str.charAt(i)=='('))
        {
          str = removeChar(str,i);
        }   
              
        else
        {
          i++;
        }
  
           }
      
    return str;}
    public static void main (String [] args)
    {
    try{
       BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
       System.out.println("Introduceti un numar de telefon oarecare: ");
       String str= in.readLine();
       
       str= cautaTrimite(str);
       System.out.println(str);
    
       }
    catch(IOException e){System.out.println("S-a produs o eroare de IO");}
    }
  }

  Published by: 1002443 on 30-Apr-2013 05:17

  In the while loop, you have full control on when you increment the i and when not, and what you're doing is correct.
  Do this with the because the loop always increments the i. To avoid this, you can discover that when you removeChar, you decrement the i, just to increment the loop right after.
  Everything in that this would mean by code more obscure all loop, so I wouldn't use it.

  Edit: Why you remove 8 in the while loop and 5 in the loop remains a great mystery.

  Published by: baftos on April 25, 2013 11:56

• while loop: delay enforcement and continuous updated: VI back to fake out of time?

  Hi all

  I want to control the time of execution of a while loop. I want the user to have the ability to decide how long he wants to run the while loop. The while loop is used to update certain values, then it should run continuously, not only run once and wait (that I could easily using the synchronization functions).

  I used the time up VI as suggested in this post:

  http://forums.NI.com/T5/LabVIEW/how-to-create-a-time-control-for-while-loop/m-p/2530212/highlight/FA...

  and works well, but the while loops are integrated into another loop for and when Goes to the next iteration, the elapsed time Boolean result is set to true and it does not run at all (I think that's the problem).

  Can I return the Boolean result of the elapsed time VI to false, after reaching the target of time? That would solve my problem, I think that...

  I attach some of my VI, although I don't know that it could be useful for you...

  Thanks for your help

  Use the iteration for while loops count and an equal to zero? node.  Then the output of the comparison at the entrance to reset the elapsed time functions.  The idea is that reset you on the first iteration (when I = 0).

• stop a loop without waiting for its next iteration

  I wonder if there is a good way, or still anyway to stop a while loop without waiting for its next iteration. Lets say you have a timer in the loop so he iterates once evey 10 seconds, and then you have to wait 10 seconds for him to stop after you press a stop button that could be a problem.

  Thank you!

  
  

• In any case, to use transform activity with a loop for storage of the iterative purpose?

  Hi all
  
  
  I have a question about the processing activity. As I am new to BCI, I want to learn more about the processing activity. If we use a transformation inside a loop activity, all other records other than the last ones will be overwritten. I want to avoid this situation and s output
  
  Scenario of
  -------------------------------
  
  (1) inside a loop for, I keep a DB adapter that will choose 1 row of table. So in each loop iteration for, we will get a line.
  
  (2) in the same loop, we maintain another DB adapter which will retrieve multiple records.
  
  (3) these values, I need to map it to an output variable (output xsd is able to contain multiple records) in the following order.
  < 1Adaptateur out >
  < data1 > < / data1 >
  < data2 > < / data2 >
  < 2 adapter output >
  < data > < / data >
  < data > < / data >
  < / 2 adapter output >
  
  for example)
  < Person > - 1 adapter Db I st iteration
  < name > xx < / name >
  < 23 > < / Age >
  < address > - 2nd iteration of st adapter 1 DB
  home address < address > < / address >
  address of the < address > < / address >
  permanent address < address > < / address >
  < address >
  < / person >
  
  
  < Person > - 1 adapter Db iteration nd II
  yy < name > < / name >
  < 23 > < / Age >
  < address > - 2nd iteration of st adapter 1 DB
  home address < address > < / address >
  address of the < address > < / address >
  permanent address < address > < / address >
  < / book >
  < / person >
  How can I pass the data that we have read from the db adapter in the above format
  
  Pls suggest a solution for this.
  
  Published by: user_ds on June 15, 2011 02:38
  
  Published by: user_ds on June 15, 2011 02:47

  HI'.

  1.) initialize a new variable 'counter' of type int, and assign inside initialize counter = 1
  2.) put the card1 DB and DB map2 invoke the of inside a while loop, then put it
  condition (that you want to use) for the number of times you want to hit the DB again and again
  3.) use affect the activity and inside this use Add and put the [$counter] on the expression of xsl to map to the next node
  4.) now use a beneficiary within an Assign activity where increment you counter + 1

  Yatan-

• repeating nodes using loop but when XML string concating then concating only last iteration of the loop FOr?

  		I stuck with a problem that I use FOR loop to generate expandable nodes. Now when I concat the node generated in the primary node and then I only last iteration of the loop FOR. can someone suggest me a way to manage this error... BECAUSE me IN 1.pl_phone_tab. County LOOP SELECT xmlelement ("phone" , xmlelement ("PHONETYPE", xmlattributes ('01' AS "dmnADRP_PHONETYPE"), pl_phone_tab (i) .p_phtype_tab) , xmlelement ("PHONENUM", pl_phone_tab (i) .p_phnum_tab) , xmlelement ("PRIMARY_CONTACT", pl_phone_tab (i) .p_prcon_tab) ) IN p_phone_xml DOUBLE; END LOOP; SELECT xmlelement ("PhoneInfo" xmlconcat (p_phone_xml)) IN p_phone_info_xml DOUBLE; Here, I'm a single node, but there must be two nodes for node of PHONE

• loop for iterator goes from 0 to random number?

  Hi all

  I have a loop with a tunnle auto-indexé coming out of it.  The for loop is defined to run 240 times (4 x / sec.), then the table when he went from the loop is on average and data is played from there on out.

  It works fine except for the first round which is shake more data on the entire line.  It will run across the 20ish seconds seconds to 50ish.

  If I put a flag on the index it will increase from 0 to a number between 7 and 160 randomly as soon as the program starts.  From there on, after the first iteration it fires every minute.  However the timestamps on all data are not at the minute, for example. 01:00, 02:00, 03:00, etc.  They are at a different interval, for example: 01:16, 02:16, 03:16 etc.

  Why would he do that?

  My guess is that the output array has some kind of memory of the previous races and is the first notches n fill with data stored and accessible to the general public starting the iterator to the next index, and continues from there.

  Is there a way to reset the data stored in the tunnle?  I do not use a shift register.

  If I change a shift register and try to transmit data to the output function of summons since the shift register, there is an error on the output and gives me a bad connection.

  If I change a shift register and try to transmit data to the service of summons since the input shift register, it will work but continues to count arbitrary point.

  If I change a shift register and try to intitialize the table by connecting a constant to 0, it continues to count arbitrary point.

  Any help would be greatly appreciated.

  Thank you.

  What is the format of the data being sent?  Should I use jump as end of line character? It sends all the time?

  If she is using jump for line termination, your configuration is correct (well that count = 50 byte may not be the best). You should not use bytes on Port when the characters of endpoints are enabled. With the characters of endpoint read VISA sets the calendar to match the received data.

  With the default settings of the configuration, it will take about 50 ms to 50 characters. If messages are less than 50 characters, the delay will be less. Two examples: 1. device sends continuous and date never has a line break character. Read return 50 characters around every 50 m 2. Message consists of 8 data characters more line break. The device stops between messages, then send 4 messages per second. Read return 8 characters 4 times per second.

  My guess is that your device sends permanently and that something else in the program allows some data accumulate occasionally, so that at the start of this VI a batch of messages are in the buffer and treated quickly enough that you do not see the loop counter increment.

  Lynn

• next iteration during the click on

  Hello

  I'm doing a loop (as or) I'll be able to control so that he won't be at the next iteration until I click.

  I tried to use a combination with case-control and has not found a solution.

  I need the loop because I need move node registry/feedback.

  would appreciate help.

  Here's an example for you

• Create a table in a loop 'for' (reset the number of loops)

  Hello

  I try to incorporate a signal of acceleration from an analog input CRIO to get speed and then further integrate to get the moving of a vibration system.

  I understand that to achieve integration, a table must be fed in. My problem is that I could not buffer the signal in a buffer block, as I couldn't find buffer blocks. so I decided to create my data table by using a loop "for". The nests of the loop 'for' inside a timed loop. The problem that I'm stuck on is how to reset the loop 'for' in order to fill the buffer with each iteration of the outer loop timed.

  I enclose the code if that helps. Note that I use labview in 2013.

  If anyone who has encountered a similar problem before can help me, I would be gratefull.

  Concerning

  Ali

  You can use a shift register initialized as inputs to your curls, to build your table of one. However, you realize, don't you, that the execution of your program as written loops as soon as the computer can spit out responses, then the output array may contain several points that took place before the entry has updated? Assuming that your thing cRIO (I've not worked with these) has integrated into its routine acquisition of calendar data, I suggest you put that inside the loop to get a data point by reading.

  And do you really want your graph to distance for update only every thousand points (points of acceleration million) speed?

  Cameron