GROUP BY generating time slots more
Hello guys,.I have a small problem I worked on since this morning and I can't find a solution... So, I ask for your help!
I use Oracle 10 g, and I try to have a schedule full, even when documents are missing from the base table. For example, consider this scenario:
CREATE TABLE requests
(
code VARCHAR2(100),
request_time DATE
);
INSERT INTO requests(code, request_time) VALUES('A', TO_DATE('01/02/2012 13:50', 'DD/MM/YYYY HH24:MI'));
INSERT INTO requests(code, request_time) VALUES('A', TO_DATE('01/02/2012 16:35', 'DD/MM/YYYY HH24:MI'));
INSERT INTO requests(code, request_time) VALUES('A', TO_DATE('01/02/2012 19:11', 'DD/MM/YYYY HH24:MI'));
INSERT INTO requests(code, request_time) VALUES('B', TO_DATE('01/02/2012 19:12', 'DD/MM/YYYY HH24:MI'));
INSERT INTO requests(code, request_time) VALUES('B', TO_DATE('01/02/2012 23:12', 'DD/MM/YYYY HH24:MI'));
INSERT INTO requests(code, request_time) VALUES('C', TO_DATE('03/02/2012 10:05', 'DD/MM/YYYY HH24:MI'));
It's a simple table with a code and a time of demand. Whenever a request is handled by a server, insert us a record into this table. I want to do is something like this:For each day where a request has been processed, I should have a result like this:
A 01/02/2012 00:00 NULL
A 01/02/2012 01:00 NULL
A 01/02/2012 02:00 NULL
A 01/02/2012 03:00 NULL
...
A 01/02/2012 13:00 1
A 01/02/2012 14:00 NULL
A 01/02/2012 15:00 NULL
A 01/02/2012 16:00 1
A 01/02/2012 17:00 NULL
A 01/02/2012 18:00 NULL
A 01/02/2012 19:00 1
A 01/02/2012 20:00 NULL
A 01/02/2012 21:00 NULL
A 01/02/2012 22:00 NULL
A 01/02/2012 23:00 NULL -- 24 records per code and per day with requests.
-- same for B
B 01/02/2012 00:00 NULL
B 01/02/2012 01:00 NULL
B 01/02/2012 02:00 NULL
...
B 01/02/2012 19:00 1
B 01/02/2012 20:00 NULL
...
B 01/02/2012 23:00 NULL -- 24 records for the 01/02
-- no request the 02/02 so no records for that day
C 03/02/2012 00:00 NULL
C 03/02/2012 01:00 NULL
...
C 03/02/2012 10:00 1
...
C 03/02/2012 22:00 NULL
C 03/02/2012 23:00 NULL
I have 24 records by code (per day) where a request has been registered. So, if we have 2 different codes, I should have 48 records. The problem is that I have not made throughout the day. Sometimes, certain lines are empty and I need these empty beaches in the final result.Can anyone help? Honestly, I tried but I can not find a solution...
Thank you
Hello
Here is a more intuitive approach.
Instead of the cross join and then by the GROUP BY and the COUNTER, we will make the GROUP BY and COUNT first (in the subquery got_request_cnt) and then join with the table for hours.
WITH all_hours AS
(
SELECT (LEVEL - 1) / 24 AS start_hour
, TO_CHAR ( LEVEL - 1
, 'FM00'
) || ':00' AS hour_txt
FROM dual
CONNECT BY LEVEL <= 24
)
, got_request_cnt AS
(
SELECT code
, TRUNC ( TRUNC (request_time, 'HH')) AS request_day
, TO_CHAR ( TRUNC (request_time, 'HH')
, 'HH24:MI'
) AS request_hour_txt
, COUNT (*) AS request_cnt
FROM requests
GROUP BY code
, TRUNC (request_time, 'HH')
)
SELECT r.code
, r.request_day
, h.hour_txt
, r.request_cnt
FROM all_hours h
LEFT OUTER JOIN got_request_cnt r PARTITION BY (r.code, r.request_day)
ON r.request_hour_txt = h.hour_txt
ORDER BY r.code
, r.request_day
, h.hour_txt
;
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Published by: zhxiangxie on April 26, 2012 14:41 fixed the grouping expected dataThere was an article about a similar problem in Oracle Magazine recently:
http://www.Oracle.com/technetwork/issue-archive/2012/12-Mar/o22asktom-1518271.html
See the section on the 'grouping beaches '. They needed a total cumulative who started once the total reaches a certain amount.
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Here is a solution-based 'code listing 5', the solution MODEL, which is recommended in the article.
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