Groups with overlapping intervals
HelloI need help on a problem of mind-boggling overlap, or perhaps overlap problem.
The data in the example below, I need to set up different subcodes in groups with overlapping
[MIN_VAL intervals; [MAX_VAL
I have this table:
SQL>create table t (product varchar2(1) not null
2 ,subcode number(1) not null, constraint subcode_chk check (subcode >= 0)
3 ,min_val number(2) not null, constraint min_val_chk check (min_val >= 0)
4 ,max_val number(2) not null, constraint max_val_chk check (max_val >= 0)
5 ,constraint t_pk primary key (product, subcode)
6 ,constraint t_val_chk check (min_val < max_val));
Table created.
SQL>
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 0, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 1, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 2, 18, 67);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 3, 20, 65);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 4, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 5, 45, 60);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 6, 20, 40);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 7, 0, 99);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 8, 60, 65);
1 row created.
SQL>insert into t (product, subcode, min_val, max_val) values ('A', 9, 0, 99);
1 row created.
SQL>commit
2 /
Commit complete.
SQL>
SQL> select product, subcode, min_val, max_val
2 from t
3 where product = 'A'
4 order by product, subcode;
PRODUCT SUBCODE MIN_VAL MAX_VAL
------- ---------- ---------- ----------
A 0 0 99
A 1 0 99
A 2 18 67
A 3 20 65
A 4 0 99
A 5 45 60
A 6 20 40
A 7 0 99
A 8 60 65
A 9 0 99
10 rows selected.
SQL>It's OK, that a record MAX_VAL = MIN_VAL from any other folder. The main thing is that the sous-codes
within a group are reciprocal to disclose on MIN_VAL, MAX_VAL.
SQL> select product, subcode, min_val, max_val
2 from t
3 where product = 'A'
4 and subcode in (5,6,8)
5 order by min_val;
PRODUCT SUBCODE MIN_VAL MAX_VAL
------- ---------- ---------- ----------
A 6 20 40
A 5 45 60
A 8 60 65
SQL>Then I came up with this hierarchical query, but I don't understand it myself and bothers me!
SQL> select distinct -- This, distinct, bothers me!
2 product
3 ,subcode
4 ,min_val
5 ,max_val
6 -- ,connect_by_isleaf
7 -- ,connect_by_root subcode
8 from t
9 where connect_by_isleaf = 1 -- Why does this help me?
10 start with -- This, start with, seems "clumpsy"
11 min_val in ( select min_val
12 from t
13 group by product, subcode, min_val)
14 connect by nocycle -- This, nocycle, really bothers me!
15 min_val > prior min_val
16 and max_val <= prior max_val
17 and product = prior product
18 and subcode <> prior subcode
19 order by product
20 ,subcode
21 ,min_val
22 ,max_val;
PRODUCT SUBCODE MIN_VAL MAX_VAL
------- ---------- ---------- ----------
A 5 45 60
A 6 20 40
A 8 60 65
SQL>PRODUCT SUBCODE MIN_VAL MAX_VAL GROUP_FLAG
------- ---------- ---------- ---------- ----------
A 0 0 99
A 1 0 99
A 2 18 67
A 3 20 65
A 4 0 99
A 5 45 60 1
A 6 20 40 1
A 7 0 99
A 8 60 65 1
A 9 0 99PRODUCT SUBCODE MIN_VAL MAX_VAL ROOT_SUBCODE
------- ---------- ---------- ---------- ------------
A 0 0 99 0
A 1 0 99 1
A 2 18 67 2
A 3 20 65 3
A 4 0 99 4
A 5 45 60 6
A 6 20 40 6
A 7 0 99 7
A 8 60 65 6
A 9 0 99 9Concerning
Peter
BANNER
----------------------------------------------------------------
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi-Change line 15 of hierarchical query
Hi, Peter,.
I'm not sure that understand what you're trying to do.
It may be useful to know
(1) what is your concept of 'group' to this problem? In what sense subcodes 5, 6 and 8 form a group? This is what they have in common the quality of not overlapping with a few rows with the same product? In other words, there will be no more than two groups by product: the lines that overlap with all other ranks and the lines which are not?
(2) what you mean by "disclosing each other?" Is that what the max_val min_val beaches do not overlap?
If you want to identify the subcodes for which there is an another product with the same subcode but non-overlapping min_val and max_val, then:
SELECT *
FROM t m
WHERE EXISTS (
SELECT NULL
FROM t
WHERE product = m.product
AND ( min_val > m.max_val
OR max_val < m.min_val
)
);
This requires that min_val<= max_val="" on="" each="">
The rest of this message is the request CONNECT BY you posted, in case you want to understand it better.
When I run the CONNECT BY query you posted, I get these results:
P SUBCODE MIN_VAL MAX_VAL
- ---------- ---------- ----------
A 0 0 99
A 1 0 99
A 4 0 99
A 5 45 60
A 6 20 40
A 7 0 99
A 8 60 65
A 9 0 99
The START WITH clause includes all lines: you might as well not have a START WITH clause:
10 start with -- This, start with, seems "clumpsy"
11 min_val in ( select min_val
12 from t
13 group by product, subcode, min_val)
Since you are grouping OF min_val, the subquery produces a list of all the min_vals of the table.
The clause CONNECT BY esteem line x to be the parent of line y if y min_val max_val beach is a subset of x:
14 connect by nocycle -- This, nocycle, really bothers me!
15 min_val >= prior min_val
16 and max_val <= prior max_val
17 and product = prior product
18 and subcode <> prior subcode
It's a kind of overlap, but much more strict.
Is there a particular reason why NOCYCLE you mind here? As SEPARATE, NOCYCLE is often a sign of something that is awkward, but not an indicator course. Somehow, they are like tape canvas: most of the time when you see led piece of tape is used inappropriately, but that does not mean the appropriate uses do not exist.
Because I'm not sure what you're trying to do, I'm not sure whether or not the WHERE clause allows:
9 where connect_by_isleaf = 1 -- Why does this help me?
It is certainly important. Without the WHERE clause, the output includes all lines. With the WHERE clause, the lines with the sous-codes 2 and 3 are excluded. Why? Because they always have children. Sub 2 (67-18) is the parent of 3 (20-65), and 3 is the parent of 5 (45-60), 6 (20-40) and 8 (60-65). (2 is also the parent of 5, 6 and 8, as well as their grandparents.)
You can ask: what about the subcodes 0, 1 and 7: they still do not have children? Why they spend the WHERE clause? 0, 1 and 7 (ranging from 0 to 99) are the parents of all the other lines, including one from the other. Therefore, they will all be invloved in cycles and whenever CONNECT_BY_ISCYCLE = 1, CONNECT_BY_ISLEAF will also be 1, while 0, 1 and 7 have children, they do not always have children.
Published by: Frank Kulash, May 19, 2009 13:07
Tags: Database
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BANNER
--------------------------------------------------------------------------------
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NLSRTL Version 3.4.1.0.0 - Production
Now for the sample data. I took an order of my real data set and cut a few columns to illustrate how the previous solution didn't find work. My real DataSet still has thousands of orders, similar to this one.
Instead of grouping all sequential steps with 'OUTPR' station, I am gathering all the sequential steps with "S9%" station, then here is the solution changed to this:CREATE TABLE test_data ( item_id CHAR(25) , ord_id CHAR(10) , step_id CHAR(4) , station CHAR(5) , act_hrs NUMBER(11,8) , q_comp NUMBER(13,4) , q_scrap NUMBER(13,4) ); INSERT INTO test_data VALUES ('abc-123','0001715683','0005','S509',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0010','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0020','A501',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0026','S011',0.58,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0030','S970',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0040','S970',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0050','S003',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0055','S600',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0060','Z108',6.94,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0070','Z108',7,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0080','Z310',4.02,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0085','Z409',2.17,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0090','S500',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0095','S502',1.63,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0110','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0112','S011',0.15,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0117','S903',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0118','S900',0,9,1); INSERT INTO test_data VALUES ('abc-123','0001715683','0119','S950',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0120','S906',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0140','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0145','S950',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0150','S906',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0160','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0170','S900',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0220','S902',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0230','S906',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0240','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0250','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0260','S006',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0270','S012',0.95,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0280','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0285','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0290','Z426',1.78,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0300','Z426',2.07,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0305','Z426',1.23,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0310','Z402',3.97,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0315','Z308',8.09,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0410','Z409',4.83,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0430','S500',3.6,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0435','S502',0.43,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0450','S002',0.35,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0460','S001',1,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0470','Z000',2.6,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0476','S011',1,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0478','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0480','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0490','S003',1.2,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0500','S500',1.37,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0530','B000',0.28,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0536','S011',0.65,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0538','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0540','S923',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0560','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0565','S001',0.85,0,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0570','S012',2.15,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0575','S509',0,0,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0580','B000',3.78,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0590','S011',0.27,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0600','S510',0,9,0);
If just run the subquery to calculate grp_id, you can see that it sometimes affects the same number of group in two stages that are not side by side. For example, the two step 285 and 480 are they assigned group 32...SELECT item_id , ord_id , MIN (step_id) AS step_id , station , SUM (act_hrs) AS act_hrs , MIN (q_comp) AS q_comp , SUM (q_scrap) AS q_scrap FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station LIKE 'S9%' THEN NULL ELSE step_id END ORDER BY step_id ) AS grp_id , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) AS r_num1 , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station LIKE 'S9%' THEN NULL ELSE step_id END ORDER BY step_id ) AS r_num2 FROM test_data ) -- End in-line view to compute grp_id GROUP BY item_id , ord_id , station , grp_id ORDER BY item_id , step_id ;
I don't know if it's because my orders have many more steps that the orders of the sample I provided, or what...
I tried this version too (by replacing all the names of the stations "S9%" by "OUTPR"):
and it shows the same problem.INSERT INTO test_data VALUES ('abc-123','0009999999','0005','S509',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0010','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0020','A501',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0026','S011',0.58,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0030','OUTPR',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0040','OUTPR',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0050','S003',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0055','S600',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0060','Z108',6.94,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0070','Z108',7,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0080','Z310',4.02,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0085','Z409',2.17,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0090','S500',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0095','S502',1.63,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0110','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0112','S011',0.15,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0117','OUTPR',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0118','OUTPR',0,9,1); INSERT INTO test_data VALUES ('abc-123','0009999999','0119','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0120','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0140','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0145','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0150','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0160','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0170','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0220','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0230','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0240','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0250','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0260','S006',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0270','S012',0.95,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0280','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0285','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0290','Z426',1.78,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0300','Z426',2.07,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0305','Z426',1.23,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0310','Z402',3.97,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0315','Z308',8.09,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0410','Z409',4.83,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0430','S500',3.6,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0435','S502',0.43,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0450','S002',0.35,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0460','S001',1,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0470','Z000',2.6,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0476','S011',1,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0478','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0480','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0490','S003',1.2,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0500','S500',1.37,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0530','B000',0.28,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0536','S011',0.65,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0538','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0540','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0560','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0565','S001',0.85,0,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0570','S012',2.15,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0575','S509',0,0,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0580','B000',3.78,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0590','S011',0.27,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0600','S510',0,9,0); SELECT item_id , ord_id , MIN (step_id) AS step_id , station , SUM (act_hrs) AS act_hrs , MIN (q_comp) AS q_comp , SUM (q_scrap) AS q_scrap FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station = 'OUTPR' THEN NULL ELSE step_id END ORDER BY step_id ) AS grp_id , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) AS r_num1 , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station = 'OUTPR' THEN NULL ELSE step_id END ORDER BY step_id ) AS r_num2 FROM test_data ) -- End in-line view to compute grp_id GROUP BY item_id , ord_id , station , grp_id ORDER BY item_id , step_id ;
Help?Hello
I'm glad that you understood the problem.
Here's a little explanation of the approach of the fixed difference. I can refer to this page later, so I will explain some things you obviously already understand, but I jump you will find helpful.
Your problem has additional feature that, according to the station, some lines can never combine in large groups. For now, we will greatly simplify the problem. In view of the CREATE TABLE statement, you have posted and these data:INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0010', 'Z417'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0011', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0012', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0140', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0170', 'Z417'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0175', 'Z417'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0200', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0205', 'S906');Let's say that we want this output:
` FIRST LAST _STEP _STEP ITEM_ID ORD_ID _ID _ID STATION CNT ------- ---------- ----- ----- ------- ---- abc-123 0001715683 0010 0010 Z417 1 abc-123 0001715683 0011 0140 S906 3 abc-123 0001715683 0170 0175 Z417 2 abc-123 0001715683 0200 0205 S906 2Where each line of output represents a contiguous set of rows with the same item_id, ord_id and station. "Contguous" is determined by step_id: lines with "0200" = step_id = step_id "0205' are contiguous in this example of data because there is no step_ids between '0200' and '0205". "
The expected results include the step_id highest and lowest in the group, and the total number of original lines of the group.GROUP BY (usually) collapses the results of a query within lines. A production line can be 1, 2, 3, or any number of lines in the original. This is obviously a problem of GROUP BY: we sometimes want several lines in the original can be combined in a line of output.
GROUP BY guess, just by looking at a row, you can tell which group it belongs. Looking at all the 2 lines, you can always know whether or not they belong to the same group. This isn't quite the case in this issue. For example, these lines
INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0140', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0200', 'S906');These 2 rows belong to the same group or not? We cannot tell. Looking at just 2 lines, what we can say is that they pourraient belonging to the same group, since they have the same item_id, ord_id and station. It is true that members of same groups will always be the same item_id, the ord_id and train station; If one of these columns differ from one line to the other, we can be sure that they belong to different groups, but if they are identical, we cannot be certain that they are in the same group, because item_id, ord_id and station only tell part of the story. A group is not just a bunch or rows that have the same item_id, ord_id and station: a group is defined as a sequence of adjacent to lines that have these columns in common. Before we can make the GROUP BY, we need to use the analytical functions to see two lines are in the same contiguous streak. Once we know that, we can store this data in a new column (which I called grp_id), and then GROUP BY all 4 columns: item_id, ord_id, station and grp_id.
First of all, let's recognize a basic difference in 3 columns in the table that will be included in the GROUP BY clause: item_id, ord_id and station.
Item_id and ord_id always identify separate worlds. There is never any point comparing lines with separate item_ids or ord_ids to the other. Different item_ids never interact; different ord_ids have nothing to do with each other. We'll call item_id and ord_id column 'separate world '. Separate planet do not touch each other.
The station is different. Sometimes, it makes sense to compare lines with different stations. For example, this problem is based on questions such as "these adjacent lines have the same station or not? We will call a "separate country" column of the station. There is certainly a difference between separate countries, but countries affect each other.The most intuitive way to identify groups of contiguous lines with the same station is to use a LAG or LEAD to look at adjacent lines. You can certainly do the job, but it happens to be a better way, using ROW_NUMBER.
Help the ROW_NUMBER, we can take the irregular you are ordering step_id and turn it into a dial of nice, regular, as shown in the column of r_num1 below:` R_ R_ GRP ITEM_ID ORD_ID STEP STATION NUM1 S906 Z417 NUM2 _ID ------- ---------- ---- ------- ---- ---- ---- ---- --- abc-123 0001715683 0010 Z417 1 1 1 0 abc-123 0001715683 0011 S906 2 1 1 1 abc-123 0001715683 0012 S906 3 2 2 1 abc-123 0001715683 0140 S906 4 3 3 1 abc-123 0001715683 0170 Z417 5 2 2 3 abc-123 0001715683 0175 Z417 6 3 3 3 abc-123 0001715683 0200 S906 7 4 4 3 abc-123 0001715683 0205 S906 8 5 5 3We could also assign consecutive integers to the lines in each station, as shown in the two columns, I called S906 and Z417.
Notice how the r_num1 increases by 1 for each line to another.
When there is a trail of several rows of S906 consectuive (for example, step_ids ' 0011 'by '0140'), the number of s906 increases by 1 each line to another. Therefore, during the duration of a streak, the difference between r_num1 and s906 will be constant. For 3 lines of the first series, this difference is being 1. Another series of S906s contiguous started step_id = '0200 '. the difference between r_num1 and s906 for this whole series is set to 3. This difference is what I called grp_id.
There is little meaning for real numbers, and, as you have noticed, streaks for different stations can have as by chance the same grp_id. (it does not happen to be examples of that in this game of small sample data.) However, two rows have the same grp_id and station if and only if they belong to the same streak.Here is the query that produced the result immediately before:
SELECT item_id , ord_id , step_id , station , r_num1 , CASE WHEN station = 'S906' THEN r_num2 END AS s906 , CASE WHEN station = 'Z417' THEN r_num2 END AS Z417 , r_num2 , grp_id FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id, station ORDER BY step_id ) AS grp_id , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) AS r_num1 , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id, station ORDER BY step_id ) AS r_num2 FROM test_data ) -- End in-line view to compute grp_id ORDER BY item_id , ord_id , step_id ;Here are a few things to note:
All analytical ORDER BY clauses are the same. In most of the problems, there will be only an ording regime that matters.
Analytical PARTITION BY clauses include the columns of 'distinct from the planet', item_id and ord_id.
The analytical PARTITION BY clauses also among the column 'split the country', station.To get the results we want in the end, we add a GROUP BY clause from the main query. Yet once, this includes the columns of the 'separate world', column 'split the country', and the column 'fixed the difference', grp_id.
Eliminating columns that have been includied just to make the output easier to understand, we get:SELECT item_id , ord_id , MIN (step_id) AS first_step_id , MAX (step_id) AS last_step_id , station , COUNT (*) AS cnt FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id, station ORDER BY step_id ) AS grp_id FROM test_data ) -- End in-line view to compute grp_id GROUP BY item_id , ord_id , station , grp_id ORDER BY item_id , ord_id , first_step_id ;This prioduces the output displayed much earlier in this message.
This example shows the fixed difference indicated. Specific problem you is complicated a little what you should use an expression BOX based on station rather than the station iteself.
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Selection of layers in a group with Ctril + click
Hi all
I can't just do this thing works, or even know if this feature works in CS5.
I know for a fact that I'm not the only one in the world that creates groups with layers in them,
So here's my question.
Q: when a group has been created that contains layers. How do you choose the layers inside with the Ctrl + click on the layer or a function object.
It drives me crazy that I have to open the Group and manually pick the layer where the Ctrl + Click works perfectly well when the layers are not grouped.
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MTSTUNER
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Add the group with the ES2 Java API
Hi all
There is an example that shows how to create a new group using the ES2 API here:
http://help.Adobe.com/en_US/LiveCycle/9.0/programLC/help/index.htm
However, if you run the code to create a group, the code works fine and a new OID is returned. But if you go in the /AdminUI ES2 and the list of all groups, you don't see the 'AdobeGroup' group here! Also if you are looking to the /AdminUI for the group 'AdobeGroup' it is not found.
If the code does not work or the Admin UI does not show the newly created group.
What's not here?
Thank you.
Paul.After the code snippet should work for you
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