Hang partitioned index text on construction

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• deletion of a partitioned index

  Hi friends,

  I use 10.2.0.4 oracle on solaris.

  I have several partitioned index with the 2011 created on a daily basis. I tried to drop one of the indexes and got the below error.

  SQL > ALTER INDEX QOSDEV. PK_RATE_CISCOMEMORYPOOL DROP PARTITION 'OCTOBER 5, 2012 '.

  ALTER INDEX QOSDEV. PK_RATE_CISMEPOOL DROP PARTITION 'OCTOBER 5, 2012 '.

  Error on line 2

  ORA-14076: submitted alter index partition/subpartition operation is not valid for local partitioned indexes

  Script done on line 2.

  I ask you how to remove these partitions.

  Thank you

  DBApps

  Hello

  Try-

  ALTER drop partition table RATE_CISCOMEMORYPOOL 'October 5, 2012;

  Anand

• Partitioned index

  Using Oracle 11.2.0.3
  
  We are evalauating partitiong stragetegies with a view to the realization of gains from perfomnace in reports in particular.
  
  How effeicient are partitioned indexes in this by example anti-terrorism just partitioned index aan table is not partitioned.
  
  One big fact to durrogate keys that have bitmpa indxese table which link to accentuate associated key dimensions.
  
  Patitioning given bitmap index which links to the largest dimension and partitiong Kay dimesnion dimension laregts.
  
  Reflections on partitioned indexes would be particularly useful.
  
  Thank you

  user5716448 wrote:
  Using Oracle 11.2.0.3

  We are evalauating partitiong stragetegies with a view to the realization of gains from perfomnace in reports in particular.

  How effeicient are partitioned indexes in this by example anti-terrorism just partitioned index aan table is not partitioned.

  One big fact to durrogate keys that have bitmpa indxese table which link to accentuate associated key dimensions.

  Patitioning given bitmap index which links to the largest dimension and partitiong Kay dimesnion dimension laregts.

  Reflections on partitioned indexes would be particularly useful.

  Thank you

  It is not possible to create a partitioned index bitmp on a non-partitioned table. Bitmap indexes can be local partitioned only.
  --
  John Watson
  Oracle Certified Master s/n
  http://skillbuilders.com

• Local partitioned indexes

  Hi all
  
  I created 2 local partitioned index. The indexes are indexes of function. the table size is 2.3 T.
  I created the first clue that it took 14 hours to create, and even to analyze and it works fine now. Then, I created second index. But now it does not.
  What should I do?
  
  version 11.1.0.6
  RAC, ASM
  
  Thanks in advance
  
  Published by: disaster on April 10, 2011 21:43
  
  Published by: disaster on April 10, 2011 21:51

  Dear Sir

  ----------------------------------------------------------------------------------------------------------
  | Id  | Operation              | Name         | Starts | E-Rows | A-Rows |   A-Time   | Buffers | Reads  |
  ----------------------------------------------------------------------------------------------------------
  |   1 |  PARTITION RANGE SINGLE|              |      1 |      1 |     82 |00:03:37.92 |     534K|    534K|
  |*  2 |   TABLE ACCESS FULL    | TBL          |      1 |      1 |     82 |00:03:37.92 |     534K|    534K|
  ----------------------------------------------------------------------------------------------------------
  

  It is the plan of the real explanation followed by the SQL engine to run your query

  The Oracle optimizer is the estimate (based on the statistics that you have collected about index and table) that your query will return only 1 rank (E-lines = 1) while in reality (when the query has been executed) it's return of 82 lines (A-Rows = 82) within 3 minutes and 37 seconds (A-Time = 00:03:37.92)

  It is clear that your index function that is not used.

  You should be aware that when you create a function based index, oracle will create a virtual column that is hidden behind the scene.

  Try to gather statistics on this column using dbms_stats.

  Please, try first to TEST

  BEGIN
     DBMS_STATS.gather_table_stats
                   (ownname             => user,
                    tabname             => 'TBL',
                    CASCADE             => TRUE,
                    method_opt         => 'FOR ALL HIDDEN COLUMNS SIZE 1'
                           );
  END;
  /
  

  and re - run your query and post once again the new plan explain him like you did before

  Best regards

  Mohamed Houri

• Global partitioned index hash

  Is it possible to create an index of global partitioned hash on the columns of the primary key of a table that is not partitioned itself?
  If a table has a PK constraint there an index generated automatically on the PK columns.
  Y at - it a syntax to make the overall index partitioned hash when creating the constraint of PK,.
  or syntax to MODIFY the indexes after the creation of the constraint?

  When you add a Pk to a table, you can choose a place already in the index. Something like

  alter table t1 add constraint T_PK primary key (col1) using index T_IDX;
  

  Create the partitioned index as you like with the same columns as the primary key and use the foregoing.

• ORA-14086: a partitioned index cannot be reconstructed as a whole

  Hello
  
  I'm trying to rebuld index had error below.
  
  SQL > alter index rms12. PRICE_HIST_I1 regeneration;
  ALTER index rms12. PRICE_HIST_I1 rebuild
  *
  ERROR on line 1:
  ORA-14086: a partitioned index cannot be reconstructed as a whole
  
  Select index_name, separated from dba_indexes where table_name = 'PRICE_HIST '.
  
  o/p
  
  Index_name partitioned
  
  PRICE_HIST_I2 YES
  PRICE_HIST_I1 YES
  
  Thank you

  If you need to find the names of partition in dba_ind_paritions.

  ------
  Sybrand Bakker
  Senior Oracle DBA

• Indexed text view Oracle is possible

  Indexed text view Oracle is possible?

  Looks like you are indexing the file as part of a multi_column_datastore name but expected to read the contents of the file. How do you know that filename is a file that must be read, where the other columns are text indexing Oracle text directly?

  To index the content of a file, you must use the FILE_DATASTORE. There is no direct way to concatenate the contents of a file with columns of simple text - if you need to do this you need to use USER_DATASTORE, you read the contents of the file in the procedure of data store and filter it with CTX_DOC. POLICY_FILTER.

• partitioning and partitioned index

  I created 1 table with partitions.
  
  CREATE TABLE SAMPLE_ORDERS
  (NUMBER OF ORDER_NUMBER,
  ORDER_DATE DATE,
  NUMBER OF CUST_NUM
  NUMBER OF TOTAL_PRICE
  NUMBER OF TOTAL_TAX
  NUMBER OF TOTAL_SHIPPING)
  PARTITION OF RANGE (ORDER_DATE)
  (
  SO99Q1 PARTITION VALUES LESS THAN (TO_DATE (APRIL 1, 1999 ',' MON-DD-YYYY "")),
  SO99Q2 PARTITION VALUES LESS THAN (TO_DATE (1 JULY 1999 ',' MON-DD-YYYY "")),
  SO99Q3 PARTITION VALUES LESS THAN (TO_DATE (OCTOBER 1, 1999 ',' MON-DD-YYYY "")),
  SO99Q4 PARTITION VALUES LESS THAN (TO_DATE (JANUARY 1, 2000 ',' MON-DD-YYYY "")),
  SO00Q1 PARTITION VALUES LESS THAN (TO_DATE (APRIL 1, 2000 ',' MON-DD-YYYY "")),
  SO00Q2 PARTITION VALUES LESS THAN (TO_DATE (JULY 1, 2000 ',' MON-DD-YYYY "")),
  SO00Q3 PARTITION VALUES LESS THAN (TO_DATE (OCTOBER 1, 2000 ',' MON-DD-YYYY "")),
  SO00Q4 PARTITION VALUES LESS THAN (TO_DATE (JANUARY 1, 2001 ',' MON-DD-YYYY ""))
  )
  ;
  
  
  Few questions is now.
  1. How can I create indexes on the table.
  2. How can I rebuild the index if it is partitioned index?
  3. What is the impact of the reconstruction of indexes on the table (all table locks or just locks partitioned index)
  4. If I want to create partition for future purposes, for example for each month do I need to partition manually created for the same thing?
  
  Thank you

  When you create an Index with the keyword LOCAL and do not specify the names of each partition, Oracle uses the default Partition of Table name.

  For example, to rebuild the index corresponding to the first partition of the table, partition

  alter index sales_orders_ndx_l rebuild partition SO99Q1 ;
  

  DML may continue to run against the other partitions of the table (and their corresponding indices).

  When you do the maintenance of the score as the addition of a new Partition or split an existing Partition, for each Partition of the 'new' Table, a corresponding Index Partition will be automatically created.
  In order to ensure that the affected Index partitions are not left in a State UNUSABLE but are also rebuilt with maintaining the Table Partition, add the clause INDEX of UPDATE of the ALTER TABLE statement you use.

• Table partition and no partition indexes

  Hello
  
  I have the partition table that contains about 1 ml recods and he have daily score.
  This partition table have only a unique index that is a partition No.
  
  CREATE UNIQUE INDEX xxxxxx WE yyyyyy
  (ITEM_GUID, IMAGE_SIDE)
  LOGGING
  TABLESPACE zzzzzz
  PCTFREE 10
  INITRANS 2
  MAXTRANS 255
  STORAGE)
  INITIAL 170M
  ACCORDING TO 1 M
  MINEXTENTS 1
  MAXEXTENTS 2147483645
  PCTINCREASE 0
  DEFAULT USER_TABLES
  )
  NOPARALLEL;
  
  I drop very first partition of
  
  Fall of ALTER TABLE wwww.yyyyy SCORE PT_20080706;
  
  But this isn't my unique INVALID index.
  
  Is it normal to have a VALID unique index after the fall of any partition?
  
  Do I have to rebuild a unique index again?
  
  DB: oracle 10.2.0.3
  platform: solaris
  
  Thanks in advance

  According to the Oracle doc, if you drop the bulkhead with an overall index,.

  All index global, or all partitions of global partitioned indexes are marked UNUSABLE unless one of the following are true:

  You specify the UPDATE INDEX (cannot be specified for tables organized by index. Use GLOBAL updating INDEXES.)

  The dropped partition or its subparts are empty

  more info here
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14231/partiti.htm#sthref2751

  Check ALL_PART_INDEXES and ALL_INDEXES to check the State of your indexes.

• Count (*) using partitioned index gives incorrect results

  I have a table partitioned by hash with 4 index the.

  Table name: store_assortment

  clues the: idx1 (master_id), idx2 (store), idx3 (item), idx4 (request_id)

  When I run this query result is 13649:

  SELECT COUNT (*)

  OF store_assortment

  WHERE to store = 6010

  ORDER BY point;

  When I run this query result is 13648:

  SELECT COUNT (*)

  OF store_assortment

  WHERE store = 6010;

  I rebuild all indexes, but the results are the same. Can anyone point to a bug or something that can explain this?

  I dropped and recreated the indices and values are correct now. Reconstruction did not work.

  Thanks for all the help.

• After splitting partition index was not marked UNUSABLE. Oracle 11.1.0.6.0

  Dear experts,

  I do the following:

  SQL > create table tab (an integer, whole b)

  2 partition () range (a)

  3 partition p10 values less than (10),

  4 partition p20 values less than (20).

  5 partition pmax values less than (10000)

  6  );

  Table created

  SQL > alter table tab add constraint tab_pk key primary (b);

  Table changed

  SQL > insert into tab values (1, 1);

  1 row inserted

  SQL > insert into tab values (19: 2);

  1 row inserted

  SQL > insert into tab values (9999, 3);

  1 row inserted

  SQL > commit;

  Validation complete

  SQL > select index_name, status of user_indexes where index-name = "TAB_PK";

  INDEX_NAME STATUS

  ------------------------------ --------

  VALID TAB_PK

  SQL > tab table split partition of alter

  2 pmax (30) into (partition, partition pmax p30);

  Table changed

  SQL > select index_name, status of user_indexes where index-name = "TAB_PK";

  INDEX_NAME STATUS

  ------------------------------ --------

  VALID TAB_PK

  Could you explain please why the overall index of tab_pk was not marked UNUSABLE? The partmax of the partition was not empty.

  It looks like you were the beneficiary of an optimization: Maintenance of Partitions

• Split partition - index / local

  Hi friends,
  
  I'm trying to divide a table partition.
  
  Please let me know if the syntax below are correct.
  
  If the local index used
  
  ALTER TABLE SNYT. PART_ESTD
  ESTD_M13_S22 PARTITION SPLIT TO ('IS', 13, '22')
  IN (ESTD_M13_S21 PARTITION, PARTITION ESTD_M13_S22)
  update of the index;
  
  (by http://asktom.oracle.com/pls/asktom/f?p=100:11:0:::P11_QUESTION_ID:1401247200346349807)
  =================================================================
  
  If used Global indexes
  
  ALTER TABLE SNYT. PART_ESTD
  ESTD_M13_S22 PARTITION SPLIT TO ('IS', 13, '22')
  IN (ESTD_M13_S21 PARTITION, PARTITION ESTD_M13_S22)
  UPDATE GLOBAL INDEXES;
  
  Concerning
  KSG
  
  Published by: KSG on 23 August 2012 18:27
  
  Published by: KSG on 23 August 2012 18:51

  http://docs.Oracle.com/CD/E11882_01/server.112/e26088/statements_3001.htm#i2131218

  http://docs.Oracle.com/CD/E11882_01/server.112/e26088/statements_3001.htm#i2151566

• Index text fuzzy vs utl_match.jaro_winkler_similarity

  Dear all,
  
  I try with the utl_match.jaro_winkler_similarity function in my code to search scenarios.
  I tried the function utl_match.jaro_winkler_similarity by replacing oracle index contains - fuzzy function.
  

  utl_match.jaro_winkler_similarity (string1, string2) >= 77

  gives more possible values as text fuzzy oralce index. It gives quick result comparing to blurry text indexes. More important, it gets the tuples that are not recovered by the text index fuzzy oracle with a default score of 60. Fuzzy does not work for numeric values, rather utl_match.jaro_winkler_similarity retrieves the numeric values successfully.
  
  I have two questions.
  1. can I use function utl_match.jaro_winkler_similarity instead of the oracle text index - blurred? Are there restrictions when using this feature of utl_match?
  2. can I create a function based on utl_match.jaro_winkler_similarity index to improve performance?
  
  Kind regards
  Suresh.

  1. can I use function utl_match.jaro_winkler_similarity instead of the oracle text index - blurred? Are there restrictions when using this feature of utl_match?

  You can use it, but it will be probably slow by itself. I would use Oracle Text contains and blurred in a subquery to limit the lines, using an index first, then use utl_match.jaro_winkler in an external query to further limit. I would not use the default values for fuzzy, but could ensure that it would not remove everything that should not be eliminated. Fuzzy is destined to find similar spellings. Jaro_Winkler is destined to find similar names. If you have strings that include a number, then I would use utl_match.edit_distance_similarity instead of Jaro_Winkler.

  2. can I create a function based on utl_match.jaro_winkler_similarity index to improve performance?

  Yes, if the two strings that you compare are in the same table in the same line. You can also create a view and an index on the view.

• Table partitioning/indexing strategy

  Hello
  
  I have a data warehouse containing medical data. Normally, we develop queries against a small number of patients (e.g. where patient_id < 100) and adjust upward to run on a greater number (usually the entire base of 26 000 patients least some due to exclusion criteria).
  
  The largest table contains about 200 million lines, and I'm working on the question of whether I can change the partitioning and indexing in order to improve the performance of queries.
  
  The table contains 'patient_id', 'visit_id', 'item_id', 'chart_time', 'value' and 'valuenum' column and a variety of other columns that are rarely used. The id id columns are integers, pointrefers to the type of value is saved and value (varchar2) and valuenum (number) contain the data. chart_time is a "timestamp with time zone '.
  
  Currently, there are clues on patient_id, visit_id and item_id and a composite index on (visit_id, itemid). There is no partitioning for the moment.
  
  1. is the current index redundent? that is visit_id, item_id and composite (visit_id, item_id) do I need?
  2. we started to run queries of time based for specific patients. that is, we want data for specific items, for a specific set of visits, in the first day. An index on (visit_id, chart_time, item_id) would help with that?
  3. the table of patient_id partitioning help? We "never" queries between patient and therefore the data of each patient are independent. The database is running on 2 raid controllers, one for data, one for the index, perhaps it would be better to put half of patients on a single controller, and the other half on the other?
  
  Thank you
  
  Dan Scott

  Hello

  1. the index on visit_id sounds redundant as it is the main column in the composite index (visit_id, itemid).
  2. added chart_time to the composite index could be useful that the pair of columns (visit_id, item_id) is not quite selective. You must put in place a realistic model of your data distribution, choose some queries that you intend to run often watch their performance. It is not possible to predict performance in function purely thereotical reasoning.
  3 bear partitioning functions: maintenance of data (for example truncating, deleting or moving old partitions) and eliminating the irrelevant data in queries (partition size). You imagine you having to truncate, delete, or move a partition that is defined by a range of patient_id? Probably not. Can you imagine the need to restrict your query to a certain range of patient_id? Unlikely. That answers your question.

  Best regards
  Nikolai

• partitioning index.

  Hi all
  Is it possible to partition the partion of maxvalue index created using index range partitioning.

  Hello

  If you talk to split a partition into several smaller, then Yes, you can do, see:

  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:660224234238

  If not, please clarify what you mean.

  Best regards
  Nikolai