Split partition - index / local
Hi friends,I'm trying to divide a table partition.
Please let me know if the syntax below are correct.
If the local index used
ALTER TABLE SNYT. PART_ESTD
ESTD_M13_S22 PARTITION SPLIT TO ('IS', 13, '22')
IN (ESTD_M13_S21 PARTITION, PARTITION ESTD_M13_S22)
update of the index;
(by http://asktom.oracle.com/pls/asktom/f?p=100:11:0:::P11_QUESTION_ID:1401247200346349807)
=================================================================
If used Global indexes
ALTER TABLE SNYT. PART_ESTD
ESTD_M13_S22 PARTITION SPLIT TO ('IS', 13, '22')
IN (ESTD_M13_S21 PARTITION, PARTITION ESTD_M13_S22)
UPDATE GLOBAL INDEXES;
Concerning
KSG
Published by: KSG on 23 August 2012 18:27
Published by: KSG on 23 August 2012 18:51
http://docs.Oracle.com/CD/E11882_01/server.112/e26088/statements_3001.htm#i2131218
http://docs.Oracle.com/CD/E11882_01/server.112/e26088/statements_3001.htm#i2151566
Tags: Database
Similar Questions
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Dear experts,
I do the following:
SQL > create table tab (an integer, whole b)
2 partition () range (a)
3 partition p10 values less than (10),
4 partition p20 values less than (20).
5 partition pmax values less than (10000)
6 );
Table created
SQL > alter table tab add constraint tab_pk key primary (b);
Table changed
SQL > insert into tab values (1, 1);
1 row inserted
SQL > insert into tab values (19: 2);
1 row inserted
SQL > insert into tab values (9999, 3);
1 row inserted
SQL > commit;
Validation complete
SQL > select index_name, status of user_indexes where index-name = "TAB_PK";
INDEX_NAME STATUS
------------------------------ --------
VALID TAB_PK
SQL > tab table split partition of alter
2 pmax (30) into (partition, partition pmax p30);
Table changed
SQL > select index_name, status of user_indexes where index-name = "TAB_PK";
INDEX_NAME STATUS
------------------------------ --------
VALID TAB_PK
Could you explain please why the overall index of tab_pk was not marked UNUSABLE? The partmax of the partition was not empty.
It looks like you were the beneficiary of an optimization: Maintenance of Partitions
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Hi all
I created 2 local partitioned index. The indexes are indexes of function. the table size is 2.3 T.
I created the first clue that it took 14 hours to create, and even to analyze and it works fine now. Then, I created second index. But now it does not.
What should I do?
version 11.1.0.6
RAC, ASM
Thanks in advance
Published by: disaster on April 10, 2011 21:43
Published by: disaster on April 10, 2011 21:51Dear Sir
---------------------------------------------------------------------------------------------------------- | Id | Operation | Name | Starts | E-Rows | A-Rows | A-Time | Buffers | Reads | ---------------------------------------------------------------------------------------------------------- | 1 | PARTITION RANGE SINGLE| | 1 | 1 | 82 |00:03:37.92 | 534K| 534K| |* 2 | TABLE ACCESS FULL | TBL | 1 | 1 | 82 |00:03:37.92 | 534K| 534K| ----------------------------------------------------------------------------------------------------------
It is the plan of the real explanation followed by the SQL engine to run your query
The Oracle optimizer is the estimate (based on the statistics that you have collected about index and table) that your query will return only 1 rank (E-lines = 1) while in reality (when the query has been executed) it's return of 82 lines (A-Rows = 82) within 3 minutes and 37 seconds (A-Time = 00:03:37.92)
It is clear that your index function that is not used.
You should be aware that when you create a function based index, oracle will create a virtual column that is hidden behind the scene.
Try to gather statistics on this column using dbms_stats.
Please, try first to TEST
BEGIN DBMS_STATS.gather_table_stats (ownname => user, tabname => 'TBL', CASCADE => TRUE, method_opt => 'FOR ALL HIDDEN COLUMNS SIZE 1' ); END; /
and re - run your query and post once again the new plan explain him like you did before
Best regards
Mohamed Houri
-
Question about "split partition" command
Hello
I have the following partitioned table...
CREATE TABLE trans_tab
(
TRANS_ID number (10),
DATE OF TRANS_DATE,
CONSTRAINT PK_TRNS_ID PRIMARY KEY (TRANS_ID))
PARTITION BY RANGE (TRANS_DATE)
(PARTITION TRANS_2010 VALUES LESS THAN (TO_DATE ("2010-10-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '")) TABLESPACE TRANS_2010,)
PMAX VALUES LESS THAN (MAXVALUE) TABLESPACE TRANS_MAX PARTITION);
Now, I intend to add a partition, as shown below...
ALTER table split partition pmax trans_tab at (TO_DATE (' 2012-10-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN ')) in (2012 partition, partition pmax);
The command above split partition worked well and ended quickly in the TEST environment which had only 100 records. I now intend to do in the production, which has about 90 MM records in the table. Here are my questions...
(1) I will try to find how long would the "split partition" command to run into a table that has ~ 90 mm record table the command "split partition" to physically move the records or just logically to remap the records to the appropriate partition? If it is logical remapping, I guess that the split command would complement quickly even against a huge table... Could check you?
(2) in the TEST environment, I checked the non partitioned status of the global and the local index after splitting the partiton and they look good? Should I be rebuild the index after splitting the partition?
Thanks for your time...Assuming he has no line of 2012 year in partition PMAX, the SPLIT would create a vacuum PMAX anew. However, it has the maximum value of TRANS_DATE in the PMAX partition - so he must sweep the partition (or use a LOCAL index on the partition, if available). Therefore, depending on how it can identify lines, it may take a little time.
I think that the current PMAX partition is not empty (that is, it has lines of 2011). As a result, a SPLIT will cause GLOBAL Indexes to score UNUSABLE unlesss you use the UPDATE GLOBAL INDEXES.
Was your test with the actual number of lines to PMAX?
Hemant K Collette
-
partitioning and partitioned index
I created 1 table with partitions.
CREATE TABLE SAMPLE_ORDERS
(NUMBER OF ORDER_NUMBER,
ORDER_DATE DATE,
NUMBER OF CUST_NUM
NUMBER OF TOTAL_PRICE
NUMBER OF TOTAL_TAX
NUMBER OF TOTAL_SHIPPING)
PARTITION OF RANGE (ORDER_DATE)
(
SO99Q1 PARTITION VALUES LESS THAN (TO_DATE (APRIL 1, 1999 ',' MON-DD-YYYY "")),
SO99Q2 PARTITION VALUES LESS THAN (TO_DATE (1 JULY 1999 ',' MON-DD-YYYY "")),
SO99Q3 PARTITION VALUES LESS THAN (TO_DATE (OCTOBER 1, 1999 ',' MON-DD-YYYY "")),
SO99Q4 PARTITION VALUES LESS THAN (TO_DATE (JANUARY 1, 2000 ',' MON-DD-YYYY "")),
SO00Q1 PARTITION VALUES LESS THAN (TO_DATE (APRIL 1, 2000 ',' MON-DD-YYYY "")),
SO00Q2 PARTITION VALUES LESS THAN (TO_DATE (JULY 1, 2000 ',' MON-DD-YYYY "")),
SO00Q3 PARTITION VALUES LESS THAN (TO_DATE (OCTOBER 1, 2000 ',' MON-DD-YYYY "")),
SO00Q4 PARTITION VALUES LESS THAN (TO_DATE (JANUARY 1, 2001 ',' MON-DD-YYYY ""))
)
;
Few questions is now.
1. How can I create indexes on the table.
2. How can I rebuild the index if it is partitioned index?
3. What is the impact of the reconstruction of indexes on the table (all table locks or just locks partitioned index)
4. If I want to create partition for future purposes, for example for each month do I need to partition manually created for the same thing?
Thank youWhen you create an Index with the keyword LOCAL and do not specify the names of each partition, Oracle uses the default Partition of Table name.
For example, to rebuild the index corresponding to the first partition of the table, partition
alter index sales_orders_ndx_l rebuild partition SO99Q1 ;
DML may continue to run against the other partitions of the table (and their corresponding indices).
When you do the maintenance of the score as the addition of a new Partition or split an existing Partition, for each Partition of the 'new' Table, a corresponding Index Partition will be automatically created.
In order to ensure that the affected Index partitions are not left in a State UNUSABLE but are also rebuilt with maintaining the Table Partition, add the clause INDEX of UPDATE of the ALTER TABLE statement you use. -
deletion of a partitioned index
Hi friends,
I use 10.2.0.4 oracle on solaris.
I have several partitioned index with the 2011 created on a daily basis. I tried to drop one of the indexes and got the below error.
SQL > ALTER INDEX QOSDEV. PK_RATE_CISCOMEMORYPOOL DROP PARTITION 'OCTOBER 5, 2012 '.
ALTER INDEX QOSDEV. PK_RATE_CISMEPOOL DROP PARTITION 'OCTOBER 5, 2012 '.
Error on line 2
ORA-14076: submitted alter index partition/subpartition operation is not valid for local partitioned indexes
Script done on line 2.
I ask you how to remove these partitions.
Thank you
DBApps
Hello
Try-
ALTER drop partition table RATE_CISCOMEMORYPOOL 'October 5, 2012;
Anand
-
Using Oracle 11.2.0.3
We are evalauating partitiong stragetegies with a view to the realization of gains from perfomnace in reports in particular.
How effeicient are partitioned indexes in this by example anti-terrorism just partitioned index aan table is not partitioned.
One big fact to durrogate keys that have bitmpa indxese table which link to accentuate associated key dimensions.
Patitioning given bitmap index which links to the largest dimension and partitiong Kay dimesnion dimension laregts.
Reflections on partitioned indexes would be particularly useful.
Thank youuser5716448 wrote:
Using Oracle 11.2.0.3We are evalauating partitiong stragetegies with a view to the realization of gains from perfomnace in reports in particular.
How effeicient are partitioned indexes in this by example anti-terrorism just partitioned index aan table is not partitioned.
One big fact to durrogate keys that have bitmpa indxese table which link to accentuate associated key dimensions.
Patitioning given bitmap index which links to the largest dimension and partitiong Kay dimesnion dimension laregts.
Reflections on partitioned indexes would be particularly useful.
Thank you
It is not possible to create a partitioned index bitmp on a non-partitioned table. Bitmap indexes can be local partitioned only.
--
John Watson
Oracle Certified Master s/n
http://skillbuilders.com -
Split partitions in number of partitions
I have a partitioned table. Score is based on the Date column, and each partition is for the period of 1 month. I want to split a partition into 4 smaller partitions.
I tried split partition but split partition can be used to split the existing partition into 2 partitions. I tried to add sub partitions in an existing table, which failed, because this isn't a composite partition.
That's what I tried.
alter table activity set subpartition template ( subpartition SP_1_NEWNAME values less than (TO_DATE('07-JAN-2007 00:00:00', 'DD-MON-YYYY HH24:MI:SS')), subpartition sp_2_NEWNAME values less than (to_date('15-JAN-2007 00:00:00', 'DD-MON-YYYY HH24:MI:SS')), subpartition SP_3_NEWNAME values less than (to_date('15-JAN-2007 00:00:00', 'DD-MON-YYYY HH24:MI:SS')) );
Any suggestions?
Thank you
you would have to hit the score several times. You can recreate the object with the Assembly of partitions or dbms_redefinition allows you to change the definition of the object.
-
Is it possible to create an index of global partitioned hash on the columns of the primary key of a table that is not partitioned itself?
If a table has a PK constraint there an index generated automatically on the PK columns.
Y at - it a syntax to make the overall index partitioned hash when creating the constraint of PK,.
or syntax to MODIFY the indexes after the creation of the constraint?When you add a Pk to a table, you can choose a place already in the index. Something like
alter table t1 add constraint T_PK primary key (col1) using index T_IDX;
Create the partitioned index as you like with the same columns as the primary key and use the foregoing.
-
Is - a can split a partition in addition to 2?
Example:
TOalter table HISTORY split partition HIST_MAX at (TO_DATE(' 2010-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')) into ( PARTITION HIST_10Q1 STORAGE(FREELISTS 1 FREELIST GROUPS 1) TABLESPACE HIST_DATA_1 LOGGING, PARTITION HIST_MAX_NEW STORAGE(FREELISTS 1 FREELIST GROUPS 1) TABLESPACE HIST_DATA_4 LOGGING );
Our MAX partition has grown too great and fast that we must divide and add more partitions to cover what we have in the MAX and also for the future. I know we can do it one by one (divided by 2), but I was wondering if we can do all of a sudden.alter table HISTORY split partition HIST_MAX at (TO_DATE(' 2010-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')) into ( PARTITION HIST_10Q1 STORAGE(FREELISTS 1 FREELIST GROUPS 1) TABLESPACE HIST_DATA_1 LOGGING, PARTITION HIST_10Q2 STORAGE(FREELISTS 1 FREELIST GROUPS 1) TABLESPACE HIST_DATA_1 LOGGING, PARTITION HIST_10Q3 STORAGE(FREELISTS 1 FREELIST GROUPS 1) TABLESPACE HIST_DATA_1 LOGGING, PARTITION HIST_10Q4 STORAGE(FREELISTS 1 FREELIST GROUPS 1) TABLESPACE HIST_DATA_1 LOGGING, PARTITION HIST_MAX_NEW STORAGE(FREELISTS 1 FREELIST GROUPS 1) TABLESPACE HIST_DATA_4 LOGGING );
Version is 9.2.0.7No, you must do the split of recursively.
Divide HIST_MAX by (HIST_10Q4, HIST_MAX)
Then, divided HIST_10Q4 (HIST_10Q3, HIST_10Q4)
Then, divided HIST_10Q4 (HIST_10Q2, HIST_10Q3)
and so on.Hemant K Collette
-
I have a table of 20 GB which has been partitioned by range (quarterly of the years of annual basis basis).
And most of the data have been stored in the max score and the segment size more quickly.
Now, I want to get rid of max partition and divide the table with more music that would capture data each year. This way I can have only 2 years worth of data on production and partition can be removed easily after moving to datawarehouse.
Please suggest. I want to divide partitions is each year as
""2008"PARTITION VALUES LOWER THAN (TO_DATE (' 2009-01-01 00:00:00 ',))".
TABLESPACE "LLS_DATA01" NOCOMPRESS.
Here is the table / / desc
«CREATE TABLE «THEY'RE "» test. "
("STARTDATE" DATE NOT NULL ACTIVATE,)
ACTIVATE THE "CALLID' CHAR (9 BYTES) NOT NULL,
NUMBER OF "CUSTOMERLLSID."
NUMBER OF "CRCLIENTLLSID."
NUMBER OF "EAPLLSID."
NUMBER OF "EAPCOMMROOMID."
'LANGID' VARCHAR2 (5 BYTE),
VARCHAR2 (20 BYTE) "CRCLIENTID."
VARCHAR2 (255 BYTE) "PERSONALCODE."
"PIN."
VARCHAR2 (4 BYTE) "SPECIALPROMOCODE."
NUMBER OF "PREBILLESTIMATE."
CHECK CONSTRAINT 'LANID"ENABLE (LANID IN ('A', 'B', 'C', 'E', 'P')),
ENABLE CHECK CONSTRAINT 'TRUE_OR_FALSE_IC1' (InterpreterLunchAdjustmentMade IN (', 'F')),
ENABLE CHECK CONSTRAINT 'TRUE_OR_FALSE_IC2' (DontBillCustomer IN (', 'F')),
ENABLE CHECK CONSTRAINT 'TRUE_OR_FALSE_IC3' (DontPayInterpreter IN (', 'F')),
ENABLE CHECK CONSTRAINT 'TRUE_OR_FALSE_IC4' (RecordChanged IN (', 'F')),
ENABLE CHECK CONSTRAINT 'TRUE_OR_FALSE_IC5' (LogicalDelete IN (', 'F')),
KEY CONSTRAINT PRIMARY "XPKINTERPRETATIONCALLS" ("INTERPRETATIONSTARTDATE", 'CALLID')
TABLESPACE "LLS_INDX01" ENABLE
)
TABLESPACE "U12_DATA".
PARTITION BY RANGE ("STARTDATE")
(PARTITION '2007Q 3' VALUES LESS THAN (TO_DATE (' 2007-10-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN ')))
TABLESPACE "LLS_INTCALLS_DATA01" NOCOMPRESS,
PARTITION '2007Q 4' VALUES LESS THAN (TO_DATE (' 2008-01-01 00:00:00 ',))
TABLESPACE "LLS_DATA01" NOCOMPRESS,
PARTITION 'CALLSMAX' VALUES LESS THAN (MAXVALUE)
TABLESPACE NOCOMPRESS 'LLS_INTCALLS_DATA01');Go to the Morgan Library: www.morganslibrary.org/reference.html
Select the PARTITIONING
Search for "Split Partition".If you like the library... to bookmark the page.
-
ORA-14086: a partitioned index cannot be reconstructed as a whole
Hello
I'm trying to rebuld index had error below.
SQL > alter index rms12. PRICE_HIST_I1 regeneration;
ALTER index rms12. PRICE_HIST_I1 rebuild
*
ERROR on line 1:
ORA-14086: a partitioned index cannot be reconstructed as a whole
Select index_name, separated from dba_indexes where table_name = 'PRICE_HIST '.
o/p
Index_name partitioned
PRICE_HIST_I2 YES
PRICE_HIST_I1 YES
Thank youIf you need to find the names of partition in dba_ind_paritions.
------
Sybrand Bakker
Senior Oracle DBA -
NOLOGGING in alter table split partition...
Hi all
Please can tell me where I would add the NOLOGGING in the below statement, or any other means by which I can stop to redo being generated
ALTER table split partition EB_LOGS_082008 at (to_date('01-01-2010','DD-MM-YYYY')) NOLOGGING EB_LOGS into (partition EBLAST_TABLE, partition EB_LOGS_012010 tablespace EBLAST_TABLE tablespace EB_LOGS_082008) parallel;Wow... Grammar ALTER TABLE just constantly more and more complex, isn't?
According to this:
http://download.Oracle.com/docs/CD/E11882_01/server.112/e10592/clauses005.htm#CJAHABGF"For partitioned objects, the value specified for this clause is the physical attribute by default segments (and ALTER following... associated with all the partitions specified in the CREATE statement ADD PARTITION statements), unless you specify the logging attribute in the description of the PARTITION. »
If I read that correctly, so if you want the NOLOGGING keyword to indicate more than just the physical default attribute, then it must be in the description of the PARTITION.
So something like this, perhaps?
Totally not tested, BTW:
ALTER table EB_LOGS split partition EB_LOGS_082008 at (to_date('01-01-2010','DD-MM-YYYY')) into (partition EB_LOGS_082008 tablespace EBLAST_TABLE nologging, partition EB_LOGS_012010 tablespace EBLAST_TABLE nologging) parallel;Once again, this is an assumption and cannot yet pass the analysis.
In regards to the perceived dangers of NOLOGGING operations, well, it is certainly something that must be clearly understood, but not to fear. The disadvantage of an operation NOLOGGING is that if you need to recover from a backup taken before the NOLOGGING operation, until a point in time after the operation NOLOGGING objects in the database that were submitted to NOLOGGING operations will logically corrupted and must be rebuilt.
Finally, I fell on this can also be useful, regarding the optimization of SPLIT PARTITION operations:
http://download.Oracle.com/docs/CD/E11882_01/server.112/e10837/part_admin.htm#VLDBG00304Hope that helps,
-Mark
-
Table partition and no partition indexes
Hello
I have the partition table that contains about 1 ml recods and he have daily score.
This partition table have only a unique index that is a partition No.
CREATE UNIQUE INDEX xxxxxx WE yyyyyy
(ITEM_GUID, IMAGE_SIDE)
LOGGING
TABLESPACE zzzzzz
PCTFREE 10
INITRANS 2
MAXTRANS 255
STORAGE)
INITIAL 170M
ACCORDING TO 1 M
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
DEFAULT USER_TABLES
)
NOPARALLEL;
I drop very first partition of
Fall of ALTER TABLE wwww.yyyyy SCORE PT_20080706;
But this isn't my unique INVALID index.
Is it normal to have a VALID unique index after the fall of any partition?
Do I have to rebuild a unique index again?
DB: oracle 10.2.0.3
platform: solaris
Thanks in advanceAccording to the Oracle doc, if you drop the bulkhead with an overall index,.
All index global, or all partitions of global partitioned indexes are marked UNUSABLE unless one of the following are true:
You specify the UPDATE INDEX (cannot be specified for tables organized by index. Use GLOBAL updating INDEXES.)
The dropped partition or its subparts are empty
more info here
http://download.Oracle.com/docs/CD/B19306_01/server.102/b14231/partiti.htm#sthref2751Check ALL_PART_INDEXES and ALL_INDEXES to check the State of your indexes.
-
Size of the partition and Index Local
Hi all
Database information: 11.2.0.3 64-bit Linux. It is a 3 RAC Cluster node.
I recently partitioned a Parent and child tables as PARTITION of REFERENCE set. The parent table has been RANGE - partitioned. The first partition is on an integer column and the beaches are 0-1000, 10001-2000, 20001-30000 and so on. The secondary partition is on a date and it is partitioned for each quarter.
I created a local index as follows (faullt2vehicle, offboard_load_date, record_type, Column_Y).
Here's an example query I will carry out, where the date is covering 2 secondary partitions
select * from gets_tool_Fault t where fault2vehicle = 12195 and offboard_load_date BETWEEN TO_DATE('2015-04-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss') AND TO_DATE('2015-07-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss') AND record_type IN('FLT','STP','HC','EGU','EOAEQP','CEL')
When I generate the plan explain below is the output
Plan hash value: 2702285198 -------------------------------------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop | -------------------------------------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 386 | 76428 | 244 (0)| 00:00:03 | | | | 1 | PARTITION RANGE SINGLE | | 386 | 76428 | 244 (0)| 00:00:03 | 2 | 2 | | 2 | PARTITION RANGE ITERATOR | | 386 | 76428 | 244 (0)| 00:00:03 | 7 | 8 | | 3 | TABLE ACCESS BY LOCAL INDEX ROWID| GETS_TOOL_FAULT | 386 | 76428 | 244 (0)| 00:00:03 | 10 | 18 | |* 4 | INDEX RANGE SCAN | GETS_TOOL_FAULT_C7 | 386 | | 7 (0)| 00:00:01 | 10 | 18 | -------------------------------------------------------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 4 - access("FAULT2VEHICLE"=12195 AND "OFFBOARD_LOAD_DATE">=TO_DATE(' 2015-04-01 00:00:00', 'syyyy-mm-dd hh24:mi:ss') AND "OFFBOARD_LOAD_DATE"<=TO_DATE(' 2015-07-01 00:00:00', 'syyyy-mm-dd hh24:mi:ss')) filter("RECORD_TYPE"='CEL' OR "RECORD_TYPE"='EGU' OR "RECORD_TYPE"='EOAEQP' OR "RECORD_TYPE"='FLT' OR "RECORD_TYPE"='HC' OR "RECORD_TYPE"='STP')
If you observe the optimizer is currently to identify the partition, and then the secondary partition, but what is confusing to me, this is why the restricted PREMISES index scan scans all secondary partitions for a given partition. The partition should be not even as a value from PARTITION RANGE ITERATOR of 7 and 8.
Interestingly, when I provide a date range which is in single partition the pruning is happening correctly Plan hash value: 3457799067 -------------------------------------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop | -------------------------------------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 197 | 4 (0)| 00:00:01 | | | | 1 | PARTITION RANGE SINGLE | | 1 | 197 | 4 (0)| 00:00:01 | 2 | 2 | | 2 | PARTITION RANGE SINGLE | | 1 | 197 | 4 (0)| 00:00:01 | 7 | 7 | |* 3 | TABLE ACCESS BY LOCAL INDEX ROWID| GETS_TOOL_FAULT | 1 | 197 | 4 (0)| 00:00:01 | 16 | 16 | |* 4 | INDEX RANGE SCAN | GETS_TOOL_FAULT_N1 | 1 | | 3 (0)| 00:00:01 | 16 | 16 | -------------------------------------------------------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 3 - filter("RECORD_TYPE"='CEL' OR "RECORD_TYPE"='EGU' OR "RECORD_TYPE"='EOAEQP' OR "RECORD_TYPE"='FLT' OR "RECORD_TYPE"='HC' OR "RECORD_TYPE"='STP') 4 - access("FAULT2VEHICLE"=12195 AND "OFFBOARD_LOAD_DATE">=TO_DATE(' 2015-04-01 00:00:00', 'syyyy-mm-dd hh24:mi:ss') AND "OFFBOARD_LOAD_DATE"<=TO_DATE(' 2015-06-01 00:00:00', 'syyyy-mm-dd hh24:mi:ss'))
Thank you
Jayadeep
1. your index (faullt2vehicle, offboard_load_date, record_type, Column_Y), your query has a predicate based on a beach on the second column in this index, which means that the order of the index that must be examined is dictated by this predicate and each row in the range must be considered (filtered) to check the third predicate. Basic guideline on the column in the index you are ordering for more effective use: If you have columns where predicates are always equal put these columns at the beginning of the index, the columns where predicates are usually based on a beach go towards the end. You seem to have been misled by reviews 'the prefix local index' stick to your two columns of partitioning at the front of your index - which should NOT be an automatic choice for the local index: see this note ( https://jonathanlewis.wordpress.com/2011/02/28/prefixed/ ) comments that follow and OTN article it is linked to.
2 since you have two indexes that start the same way (this goes with the local prefix again) you made easy for the optimizer to choose the index (for you) is clearly evil. That's why behind the choice of the optimizer is probably another example of an issue that I spoke a few days ago: Re: Composite index + map selection N1 your index is probably greater than the index of C7, and the order of the entries in the C7 index probably makes the data much more dispersed that it really is (i.e. high clustering_factor).
Concerning
Jonathan Lewis
PS (update):
If there are many rows for each fault_id, then you must create an index from fault_id with 'compress 1' (or compress N if the first columns of the index N are repetitive).
When dealing with range partitions do not forget that the high value partition is never reached in the document, do so based in the form "date_col BETWEEN date1 and date2", use the form "date_col > = dateX and date_col»< datey"="" or="" you="" may="" find="" that="" you="" are="" accessing="" one="" more="" partition="" than="" you="" hope="" to,="" and="" in="" some="" cases="" that="" may="" mean="" "multiple"="" (i.e.="" 2)="" when="" you="" were="" expecting="" 1="" (and="" the="" optimizer="" is="" much="" better="" at="" estimating="" costs="" for="" a="" single="">
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