Help Rex Exp
Im trying to find an exp reg which will match everything between 2 string matches... The two strings themselves are not a problem, but just between ... I can't use the indicator/m multiline or can I? I've seen using [\s\S], but this doesn't seem to work for me? I never thought of this... So, this is the beginning of what Im after... and it works fine...
Info = str.match / (%! PS-Adobe-3\.0/);
This is the end game...
Info = str.match (/%%EndComments/);
The only two work and the game is not null...
Is the closest I've been able to manage myself...
Info = str.match / (%! PS-Adobe-3\.0[\s\n\r]+.+/);
But I'll be shot if I can find a way to get the last part to repeat? Is it easy or do I look of string instead methods... Oh btw can you get the offsets of a match exp? Mood swings or what?
Edit... UM has played a bit longer and now I have it but slooowly is until a bad exp and is there a more specific method to do the same thing...
Info = str.match / (%! PS-Adobe-3\.0(.+[\s\n\r]+) {0}, %%EndComments/); Get a little happier now...
Would this be something like this work for you, Mark?
var str="!PS-Adobe-3.0This is the text I want%EndComments"; alert(str.match(/Adobe-3.0[^%]*/).toString().substr(9));
Or even this...
var str="!PS-Adobe-3.0This is the text I want%EndComments!\r\r\r"; str +="PS-Adobe-3.0This is the second lot of text I want%EndComments"; var parts = str.match(/Adobe-3.0(.*?)%EndComments/g); for(var a=0;a
Tags: Photoshop
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Registry WARNING: This section, method, or task contains steps that tell you how to modify the registry. However, serious problems can occur if you modify the registry incorrectly. Therefore, make sure that you proceed with caution. For added protection, back up the registry before you edit it. Then you can restore the registry if a problem occurs. For more information about how to back up and restore the registry, see this link: http://windows.microsoft.com/en-US/windows7/Back-up-the-registry
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Hi Experts,
I need help to use the regular Expression-
WITH t AS)
SELECT ' 1234 Angel Villa, House 420 | Detroit | WE | 700129' double txt
)
----------------
SELECT
txt,
SUBSTR (txt, InStr(txt,'||') + 2, (INSTR(txt,'|',1,3)-INSTR(txt,'||')-2)) val1,
REGEXP_REPLACE (txt '([^ ||] *||) (.*)', '\2') val2
T;
I want to extract the text entry "Detroit" - going between the two. (begins - with that) and a. (ends - with that).
txt - 1234 Angel Villa, House 420 | Detroit | WE | 700129
val1 - Detroit
val2 | Detroit | WE | 700129
My regex is not appropriate somewhere. Please provide any suspicion in this regard (and not the exact solution - want to try)
The backreference is very interesting but am very bad at writing regular expressions. Help much appreciated.
Thank you and best regards,
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(on Oracle 11.2.0.3.0 - Exadata)
Published:
Tried this now.
REGEXP_REPLACE (txt '([^ ||] *||) ([^|] *) (|. *)', '\2') val2Output-
||||
Nordine Hello B
Yes, because you have more sign like | in this case you must use the non-greedy option for your star: *?
I would use the REGEXP_SUBSTR.
You must use the escape character \ and must be given to the * that you don't want to have the sign | Once again...
It's a little hard to explain. If you want the solution tell me.
Best regards, David
P.S.: Because nobody didn't read you just wish that you do not want to have the right solution only just advice... And you already know the solution, so I post my solution too
WITH t AS)
SELECT ' 1234 Angel Villa, House 420 | Detroit | WE | 700129' double txt
)
----------------
SELECT
txt,
SUBSTR (txt, InStr(txt,'||') + 2, (INSTR(txt,'|',1,3)-INSTR(txt,'||')-2)) val1,
REGEXP_REPLACE (txt '([^ ||] *||) (.*)', '\2') val2
REGEXP_SUBSTR (txt '(\|) {2} ((.| ^(\|)) *?) (\|)', 1, 1, NULL, 2) LIKE REGEXP_RESULT --> Chris227 Correction
T;
Where:
(Results): take this sign | but don't interpret as the OR operator.
(\|) {2}: take the sign. twice
. : Take any character
. *: Take among these characters, as you can
.*? : Take one of these characters, not the longest chain you will find (NON-greedy option:?)
(.*?) : Consider backreference in parentheses. REGEXP_SUBSTR last option is 2, because we want only the name of the city without sign.
Last (-|) : The name of the city must be accompanied by a sign.
I hope it helps.
The SQL above has been fixed-> reason: Chris227 noticed a mistake. Thanks Chris277!
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Hello
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Remove the ';' after the exp command. Otherwise it translate in
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Have you noticed ';' before does not exist.
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Hello
Check with the router manufacturer support, their books online and ask in their forums (if any).
Most have excellent online help. Reset the router and write down the password and paste
on the bottom of the router or in another safe place.I hope this helps.
Rob Brown - Microsoft MVP<- profile="" -="" windows="" expert="" -="" consumer="" :="" bicycle="">-><- mark="" twain="" said="" it="">->
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Visit our Microsoft answers feedback Forum and let us know what you think.
[If this post can help solve your problem, please click the 'Mark as answer' or 'Useful' at the top of this message.] [Marking a post as answer, or relatively useful, you help others find the answer more quickly.]
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