help with functional overall

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• 2 parallel while loops with functional overall to share data

  Hello

  I'm having a problem with the sharing of functional with globals data between two parallel while loops:

  1. One of the loop (bottom) generates a random number periodically and write the total functional sample.
  2. Another loop (above) has a structure of event and when it expires, he would read the functional global and intrigue, a chart data point.

  The problem is sometimes the functional overall seems to be 'locked' and the output becomes zero constant. It also seems that whenever I first open the VI, it works fine. But for the second time running, he begins to have the problem.

  

  You must initialize your VI stop FGV FRONT of your lower loop begins.  Even if you use a global variable that is functional, you have a race condition.  FGV is read in the lower loop until it had a chance to be initialized with a value of false in the upper loop.  Functional global variables do not forget their data between executions of the VI.  So it is always set on stop the last time that you ran the VI.  This works your VI the first time it's because VI does not have in memory, so when it loads, it loads with the default value False in the shift register.

• [8i] help with function with parameters (for the calculation of the work)

  Let me start by saying, I've never written a function before, and I do not have access to create a feature in my database (that is, I can't test this feature). I am trying to achieve a function I can ask my IT Department to add for me. I hope that someone can take a look at what I wrote and tell me if this should work or not, and if it's the right way to go to solve my problem.
  
  I'm creating a function to make a very simple calculation of work (add/subtract a number of days to a date in the calendar).
  
  The database, I work with has a table with the schedule of work. Here is a sample table and sample data, representative of what is in my work table calendar:
  

  CREATE TABLE caln
  (     clndr_dt     DATE,
       shop_days     NUMBER(5)
       CONSTRAINT caln_pk PRIMARY KEY (clndr_dt)
  );
  
  INSERT INTO     caln
  VALUES (To_Date('01/01/1980','mm/dd/yyyy'),0);
  INSERT INTO     caln
  VALUES (To_Date('01/02/1980','mm/dd/yyyy'),1);
  INSERT INTO     caln
  VALUES (To_Date('01/03/1980','mm/dd/yyyy'),2);
  INSERT INTO     caln
  VALUES (To_Date('01/04/1980','mm/dd/yyyy'),3);
  INSERT INTO     caln
  VALUES (To_Date('01/05/1980','mm/dd/yyyy'),3);
  INSERT INTO     caln
  VALUES (To_Date('01/06/1980','mm/dd/yyyy'),3);
  INSERT INTO     caln
  VALUES (To_Date('01/07/1980','mm/dd/yyyy'),4);
  INSERT INTO     caln
  VALUES (To_Date('01/08/1980','mm/dd/yyyy'),5);
  INSERT INTO     caln
  VALUES (To_Date('01/09/1980','mm/dd/yyyy'),6);
  INSERT INTO     caln
  VALUES (To_Date('01/10/1980','mm/dd/yyyy'),7);
  INSERT INTO     caln
  VALUES (To_Date('01/11/1980','mm/dd/yyyy'),8);
  INSERT INTO     caln
  VALUES (To_Date('01/12/1980','mm/dd/yyyy'),8);
  INSERT INTO     caln
  VALUES (To_Date('01/13/1980','mm/dd/yyyy'),8);
  INSERT INTO     caln
  VALUES (To_Date('01/14/1980','mm/dd/yyyy'),9);

  The table includes since 01/01/1980 but 31/12/2015.
  
  I have written (and validated) this parameter query that performs the calculation of my working day (mday):

  SELECT     cal.clndr_dt
  FROM     CALN cal
  ,     (
       SELECT     cal.shop_days+:mdays     AS new_shop_days
       FROM     CALN cal
       WHERE     cal.clndr_dt     =:start_date
       ) a
  WHERE     cal.shop_days     = a.new_shop_days
  AND     ROWNUM          =1
  ORDER BY     cal.clndr_dt;

  Based on this request, I created the following function (and I have no idea if it works or if the syntax is right, etc..):

  CREATE OR REPLACE FUNCTION add_mdays 
       (start_date     IN DATE,
       mdays          IN NUMBER(5))
  RETURN     DATE 
  IS
       new_date DATE;
  BEGIN
  
       SELECT     cal.clndr_dt
       FROM     CALN cal
       ,     (
            SELECT     cal.shop_days+mdays     AS new_shop_days
            FROM     CALN cal
            WHERE     cal.clndr_dt     =start_date
            ) a
       WHERE     cal.shop_days     = a.new_shop_days
       AND     ROWNUM          =1
       ORDER BY     cal.clndr_dt;
  
       RETURN     new_date;
  
  END add_mdays;  //edit 9:31 AM - noticed I left off this bit

  I'm also not sure how to do to have the function handle results that would return a date outside the range of dates that appear in the table (prior to 01/01/1980 or after until 31/12/2015 - or, another way to look at what was, before the caln.clndr_dt or the caln.clndr_dt MAX value MIN value).
  
  My goal is to be able to use the function in a situation similar to the following:
  
  First of all, here is a sample table and data:

  CREATE TABLE orders
  (     ord_no          NUMBER(5),
       plan_start_dt     DATE,
       CONSTRAINT orders_pk PRIMARY KEY (ord_no)
  );
  
  INSERT INTO orders
  VALUES (1,To_Date('01/08/1980','mm/dd/yyyy'));
  INSERT INTO orders
  VALUES (2,To_Date('01/09/1980','mm/dd/yyyy'));
  INSERT INTO orders
  VALUES (3,To_Date('01/10/1980','mm/dd/yyyy'));

  And here's how I would use my function:

  SELECT     orders.ord_no
  ,     orders.plan_start_dt
  ,     add_mdays(orders.plan_start_dt, -3) AS prep_date
  FROM     orders

  Thus, the function would allow me to come back, for each command in my table of orders, the date is 3 days working (mdays) before the start of the plan of each order.
  
  I go about it the right way? I have to create a function to do this, or is there a way for me to integrate my request (which makes my mday calculation) in the example query above (eliminating the need to create a function)?
  
  Thank you very much in advance!
  
  Published by: user11033437 on February 2, 2010 08:55
  Fixed some typos in the last insert statements
  
  Published by: user11033437 on February 2, 2010 09:31 (fixed some syntax in the function)

  Hello

  Ah, referring to Oracle 8 and is not not able to test your own code makes me nostalgic for the good old days, when you have entered your cards and led to a window to the computer center and waited an hour for the work to be performed and then seen printing to find that you had made a typo.

  If you write functions, you should really test yourself. Like all codes, functions forge be written small not: write a line or two (or sometimes just a part of what would later become a single line), test, make sure it is running properly and repeat.
  Ideally, your employer must create a pattern of development in a development database that you can use.
  You can legally download your own instance of Oracle Express Edition free; just be careful not to use features that are not available in the database where the code will be deployed.

  You need a function to get the desired results:

  SELECT       o.ord_no
  ,       o.plan_start_dt
  ,       MIN (e.clndr_dt)     AS prep_date
  FROM       orders     o
  ,       caln          l
  ,       caln          e
  WHERE       l.clndr_dt     = o.plan_start_dt
  AND       e.shop_days     = l.shop_days - 3
  GROUP BY  o.ord_no
  ,            o.plan_start_dt
  ;
  

  It would be more effective (and somewhat simpler) If you've added a column (let's call it work_day) identified whether each line represents a work_day or not.
  For each value of shop_days, exactly 1 row will be considered as a working day.
  Then, the query may be something like:

  SELECT       o.ord_no
  ,       o.plan_start_dt
  ,       e.clndr_dt          AS prep_date
  FROM       orders     o
  ,       caln          l
  ,       caln          e
  WHERE       l.clndr_dt     = o.plan_start_dt
  AND       e.shop_days     = l.shop_days - 3
  AND       e.work_day     = 1
  ;
  

  You can use the analytic LAG function to populate the work_day column.

  A function would certainly be useful, although perhaps slower.

  The function you have posted has some errors:
  an argument can be stated under NUMBER (5); Just NUMBER.
  (b) when you SELECT in PL/SQL, as you do, you must SELECT a variable to store the results.
  (c) ROWNUM is arbitrary (making it useless in this problem) unless you draw a neat subquery. I don't think you can use ORDER BY in subqueries in Oracle 8. Use the ROW_NUMBER analytic function.
  (d) the service must end with an END statement.

  Given your current caln table, here's how I would write the function:

  CREATE OR REPLACE FUNCTION add_mdays
       ( start_date     IN           DATE          DEFAULT     SYSDATE,
         mdays          IN           NUMBER          DEFAULT     1
       )
  RETURN     DATE
  DETERMINISTIC
  IS
       --     add_mdays returns the DATE that is mdays working days
       --     after start_date.  (If mdays < 0, the DATE returned
       --     will be before start_date).
       --     Work days do not include Saturdays, Sundays or holidays
       --     as indicated in the caln table.
  
       new_date     DATE;          -- to be returned
  BEGIN
  
       SELECT     MIN (t.clndr_dt)
       INTO     new_date
       FROM     caln     f     -- f stands for "from"
       ,     caln     t     -- t stands for "to"
       WHERE     f.clndr_dt     = TRUNC (start_date)
       AND     t.shop_days     = f.shop_days + TRUNC (mdays)
       ;
  
       RETURN     new_date;
  END     add_mdays;
  /
  SHOW ERRORS
  

  Production code forge be robust (which includes "fool-proofing").
  Try to anticipate what people errors might appeal to your function and correct for them where possible.
  For example, if it only makes sense for start_date at midnight, mdays to be an integer, use TRUNC in the function where soembody passes a good value.
  Allow default arguments.
  Comment of your function. Put all comments within the service (i.e. after CREATION and before the END) so that they will remain in the data dictionary.
  If, given the same arguments, the function always returns the same value, mark it as DETERMINISTIC, for efficiency. This means that the system will remember the values transmitted rather than to call the function whenever it is said to.

  I wish I could score questions such as 'Correct' or 'useful '; you get 10 points for sure.
  You posted CREATE TABLE and INSERT statements (without even be begged).
  You gave a clear description of the problem, including the expected results.
  The code is well formatted and easy to read.
  All around, one of the more thoughtful and well written questions I've seen.
  Play well! Keep up the good work!

  Published by: Frank Kulash, February 2, 2010 13:10
  Added to my own version of the function.

• Help with packages and functions that it

  Hello, I need help with the package.
  I have two tables of the employee base (id, firstname, lastname, etc..) T1 and T2.
  What I need, it's a package and two features inside. First function reads the data from T1 and passes to the second function, where second function reads data from T2 and concatenates the data just read with data from function1 and data T1 + T2 function2 goes on the main program that displays this data.
  
  So far, I have:

  create or replace type emp_type as object
  (id number,
  firstname varchar(20),
  lastname varchar(20),
  salary number(9,2));
  
  create or replace type emp_type_table as table of emp_type;
  
  create or replace package my_package
  is emp_table emp_type_table:= emp_type_table();      -- *not sure if this line is correct*
  function get_T1_emp return emp_type_table;
  function get_T2_emp (T1_emp in emp_type_table) return emp_type_table;
  end my_package;
  
  -- *confusion begins*
  
  create or replace package body my_package as 
  function get_T1_emp
  return  emp_type_table as 
    emp_table emp_type_table:= emp_type_table();
  begin
       for i in (select * from T1) loop
           emp_table.extend;
           emp_table(emp_table.count):= (emp_type(i.id, i.firstname, i.lastname, i.salary));
        end loop;
      return emp_table; 
  end get_T1_emp; 

  - get_T1_emp function seems to be quite beautiful. At least it works separately
  

  function get_T2_emp (T1_emp in emp_type_table)
  return  emp_type_table  
    emp_table emp_type_table:= emp_type_table();
  begin
       for i in (select * from T2) loop
           T1_emp.extend;
           T1_emp(T1_emp.count):= (emp_type(i.id, i.firstname, i.lastname, i.salary));
        end loop;
      return T1_emp; 
  end get_T2_emp;
  end my_package;
  
  
  DECLARE
    v_Return emp_type_table;
    v_Return2 emp_type_table;
  BEGIN
    v_Return := get_T1_emp;
    v_Return2 := get_T2_emp(v_Return);
    for i in 1..2 loop
      DBMS_OUTPUT.PUT_LINE(v_Return2(i).id || ', ' || v_Return2(i).firstname || ', ' || v_Return2(i).lastname 
      || ', ' || v_Return2(i).salary || 'EUR');
    end loop;
  END;

  So basically I don't know about my tax package.
  Most important, I don't know how to write the get_T2_emp function. And also not very sure of my main function. Please can someone help my with my problem
  
  Published by: dber November 6, 2011 21:22
  
  Published by: dber November 6, 2011 23:38 added

  Hello

  Here you go

  SQL> DROP TABLE t1;
  
  Table dropped.
  
  SQL> DROP TABLE t2;
  
  Table dropped.
  
  SQL> CREATE TABLE t1 (id NUMBER,
    2                   firstname VARCHAR2(100),
    3                   lastname VARCHAR2(100) );
  
  Table created.
  
  SQL> CREATE TABLE t2 (id NUMBER,
    2                   firstname VARCHAR2(100),
    3                   lastname VARCHAR2(100) );
  
  Table created.
  
  SQL> INSERT INTO t1  (SELECT 1,'SURI','DAMA' FROM dual
    2                     UNION ALL
    3                     SELECT 2,'SRINU','DAMA' FROM dual);
  
  2 rows created.
  
  SQL> INSERT INTO t2  (SELECT 3,'ABC','XYZ' FROM dual
    2                     UNION ALL
    3                     SELECT 4,'DEF','PQR' FROM dual);
  
  2 rows created.
  

  Package code

  
  SQL> CREATE OR REPLACE PACKAGE test_array_pkg
    2  AS
    3    TYPE test_array1 IS TABLE OF t1%rowtype  INDEX BY PLS_INTEGER;
    4    TYPE test_array2 IS TABLE OF t2%rowtype  INDEX BY PLS_INTEGER;
    5
    6    FUNCTION get_t1 RETURN test_array1;
    7    FUNCTION get_t2(p_t1 IN test_array1)
    8    RETURN test_array2;
    9
   10  END test_array_pkg;
   11  /
  
  Package created.
  

  Package body

   SQL> CREATE OR REPLACE PACKAGE BODY test_array_pkg
    2  AS
    3    t1_array1 test_array1;
    4    t2_array2 test_array2;
    5
    6    FUNCTION get_t1
    7    RETURN test_array1
    8    IS
    9
   10      n NUMBER :=0;
   11
   12    BEGIN
   13
   14     FOR i IN (SELECT * FROM t1)
   15     LOOP
   16
   17       t1_array1(n).id:= i.id;
   18       t1_array1(n).firstname := i.firstname;
   19       t1_array1(n).lastname := i.lastname;
   20
   21       n:=n+1;
   22
   23     END LOOP;
   24
   25     RETURN t1_array1;
   26
   27    END get_t1;
   28
   29    FUNCTION get_t2(p_t1 IN test_array1)
   30    RETURN test_array2
   31    IS
   32
   33      n NUMBER:=0;
   34
   35    BEGIN
   36
   37     FOR i IN p_t1.FIRST..p_t1.LAST
   38     LOOP
   39
   40       t2_array2(n).id:=p_t1(i).id;
   41       t2_array2(n).firstname:= p_t1(i).firstname;
   42       t2_array2(n).lastname := p_t1(i).lastname;
   43
   44       n:=n+1;
   45
   46     END LOOP;
   47
   48     FOR i IN (SELECT * FROM t2)
   49     LOOP
   50
   51       t2_array2(n).id:=i.id;
   52       t2_array2(n).firstname:= i.firstname;
   53       t2_array2(n).lastname := i.lastname;
   54
   55       n:=n+1;
   56
   57     END LOOP;
   58
   59     RETURN t2_array2;
   60
   61    END get_t2;
   62
   63
   64  END test_array_pkg;
   65  /
  
  Package body created.
  

  Main script

   SQL> declare
    2
    3     t1_result test_array_pkg.test_array1;
    4     t2_result test_array_pkg.test_array2;
    5
    6  begin
    7
    8    t1_result:= test_array_pkg.get_t1;
    9    t2_result:= test_array_pkg.get_t2(t1_result);
   10
   11    FOR i IN t2_result.first..t2_result.last
   12    LOOP
   13
   14      dbms_output.put_line(t2_result(i).id||' '||t2_result(i).firstname||' '||t2_result(i).lastname);
   15
   16    END LOOP;
   17
   18  end;
   19  /
  1 SURI DAMA
  2 SRINU DAMA
  3 ABC XYZ
  4 DEF PQR
  
  PL/SQL procedure successfully completed.
  

• I'm suddenly needing help with my browser Firefox (6.0.2)

  Hello
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  (OS: I use Windows XP).

  When I open the browser, I don't see is a totally white screen of white, with all the toolbars at the top.

  I know that my physical connections are very good: I have tested the modem, turned the pc market etc and I can also receive/send emails.

  This problem started today, September 8, 2011 and has never happened before.

  Is it a coincidence that Firefox itself to day before I disconnected yesterday evening? Could this be something to do with this particular new update?

  I also noticed that just before I "opened" Firefox, I now get a small box indicating:

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  Handl exc in Ev: TypeError: this oRoot.enable is not a function

  This never appeared before - I hope that it offers a clue has what is wrong.

  The browser not be stuck in Mode safe, said by the way.

  Of course, I can't find solutions to the problem on the internet, I don't physically see all Web sites!
  (A friend sends this request in my name from their pc)

  Any light you can throw on this problem of confusion would be much appreciated. I'd rather not have to uninstall and reinstall Firefox if possible.

  If the only option is to uninstall Firefox and reinstall from your site, I'm also in trouble (I can not see the internet or download).
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  Thanks in advance.

  One possible cause is security software (firewall) that blocks or limits Firefox or plugin-container process without informing you, possibly after the detection of changes (update) for the Firefox program.

  Delete all rules for Firefox in the list of permissions in the firewall and leave your firewall again ask permission to get full unlimited access to the internet for Firefox and the plugin-container and the update process.

  See:

  • https://support.Mozilla.com/kb/server+not+found
  • https://support.Mozilla.com/kb/firewalls

  Start Firefox in Firefox to solve the issues in Safe Mode to check if one of the extensions of the origin of the problem (switch to the DEFAULT theme: Firefox (Tools) > Add-ons > appearance/themes).

  • Makes no changes on the start safe mode window.
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• HP Deskjet 3051 a J611: help with Windows 10 drivers? Incompatibility problem?

  Hello, I had to get help with a problem with my printer HP Deskjet 3051 a J611.

  I was always able to properly scan using my printer until I installed the update for Windows 10.

  I use a Sony VAIO computer Fit portable (may 2013 model) originally shipped with Windows installed Pro 8.1.

  After I installed Windows 10 and I tried to use my scanner two weeks later (it prints very well), I can't seem to use the same program I was using before 10 Windows to use my scanner. I tried to use printing HP and doctor Scan to fix my problem, and he told me that my printer had an unknown driver error that it could not solve. I also tried to reset my laptop (and power cycling the printer) and to uninstall and reinstall the driver for my printer.

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  ~ Miguel G

  Hello
  
  Thank you for using the HP Forums.

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  https://support.microsoft.com/en-us/help/17588/fix-problems-that-block-programs-from-being-installed...
  
  Please download and install the software FULL of printing to HP for your operating system (Win 10) features:

  http://support.HP.com/us-en/drivers/selfservice/HP-DeskJet-3050a-e-all-in-one-printer-series-j611/4311836/model/5096936#Z7_3054ICK0K8UDA0AQC11TA930O2

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  I would like to get the return tech to help you to...

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• I have a mess of error. about microsoft Isatap adapter... plug and play id root\ * Isatap\0002 error tv-configmgrerr31 need help with drivers

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  Hello

  (1) what is the complete error message you receive?

  (2) when exactly you get this error message?

  (3) how long have you been faced with this problem?

  You can ignore this error message. This error message does not indicate a problem with the adapter. The adapter will continue to function correctly.

  See the article below

  On a Windows Vista-based computer or on a Windows Server 2008-based computer, the Microsoft ISATAP map appears with a yellow exclamation mark next to it in Device Manager, and you also receive an error message
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• Help with error message: "Windows Vista Home Premium product key you typed in is invalid for activation.

  Original title: help with error message... Please...!

  I use a desktop PC of HP Pavilion a6202.uk with Windows Vista Home Premium & Microsoft Office 2003.  When I am back from vacation & turned on my PC, my password was OK, but rather to raise Windows, I received the following message: "Windows Vista Home Premium product key you typed in is invalid for activation.  He then listed the following options: "access your computer with reduced functionality (this will allow you to buy a product online key)" or "Type a different product key" or "contact HP to help solve this problem."

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  I'm quite desperate, I travel docs to print and e-mail to answer and I don't have any idea what is happening.  Please can someone help with this not very IT clued-up DTP...!

  Moved from Vista programs Forum.

  You should have a sticker with the product key on your computer, on the bottom, or under the battery cover.  I try to type this key in and see if it accepts it.  If this isn't the case, you might not have an authentic version of Windows installed.

• can someone help with the following code plsql errors...

  Hello

  If anyone can help with the following code... to get a successful outing.

  create or replace package lib_01 as

  procedure lib_proc01 (p_user_id in numbers, p_user_name in varchar2);

  end lib_01;

  create or replace package body lib_01 as

  procedure lib_proc01 (p_user_id in numbers, p_user_name in varchar2) as

  number of v_user_id;

  v_user_name varchar2 (50);

  number of v_avl_books;

  number of v_avl_days;

  date of v_end_date;

  date of v_return_date;

  Start

  dbms_output.put_line ('Enter User Name');

  dbms_output.put_line (' username :'|| p_user_name);

  Select user_id, user_name in v_user_id v_user_name of user_registration where user_name = p_user_name;

  If v_user_name <>p_user_name then

  dbms_output.put_line (' username is not.) Please submit full name ');

  end if;

  If v_user_id is null or v_user_name is null then

  dbms_output.put_line ("' user not found");

  validate_userLogin;

  on the other

  validate_issuedbooks (p_issuecount);

  end if;

  If v_issuecount < v_avl_books then

  issuebooks;

  on the other

  Number of return of late_fee (p_mem_id, p_extradays, p_latefee_total);

  end if;

  If paid_flag = "Y" then

  issuebooks;

  on the other

  dbms_output.put_line ("' book may be issued due to its maximum reached late fees");

  end if;

  end lib_proc01;

  procedure validate_userLogin is

  procedure reg_proc is

  procedure user_validate (p_id_proof in varchar2, p_id_no out varchar2) is

  v_id_proof varchar2 (20);

  v_id_no varchar2 (20);

  Start

  Select user_name, id_proof, id_no, v_user_name, v_id_proof, v_id_no of user_registration where id_proof = p_id_proof;

  If v_id_proof = "Adhar_Card" then

  dbms_output.put_line ('user a valid proof of ID');

  dbms_output.put_line (' and the id no. :'|| is p_id_no).

  on the other

  dbms_output.put_line ('Invalid ID evidence.) Please submit valid proof of ID ');

  end if;

  exception

  When no_data_found then

  dbms_output.put_line ('No Data found');

  end user_validate;

  procedure member_validate (p_mem_id series)

  v_mem_flag char (1);

  curr_date date: = sysdate;

  date of v_mem_enddate;

  Start

  dbms_output.put_line('Mem_flag:'|| v_mem_flag);

  Select mem_flag in the v_mem_flag of user_login where user_id = v_user_id;

  If v_mem_flag = 'n' or v_mem_flag is null then

  dbms_output.put_line ('The User do not have membership');

  on the other

  Select mem_id in the v_mem_id of user_login where user_id = v_user_id;

  dbms_output.put_line ('the user has membership');

  v_mem_id: = p_mem_id;

  Select mem_enddate in the member_login v_mem_enddate where mem_id = v_mem_id;

  If v_mem_enddate < curr_date then

  dbms_output.put_line ('Membership has expired' | v_mem_id |' on ' | v_mem_enddate);

  on the other

  dbms_output.put_line ('User a validity again' | v_mem_enddate);

  end if;

  end if;

  exception

  When no_data_found then

  dbms_output.put_line ("' no data found");

  while others then

  dbms_output.put_line (' another error.) Please find");

  end member_validate;

  Start

  insert into user_registration values ('& first_name ',' & last_name', null, ' & user_type',)

  address_ty ("& bldg_no",

  '& bldg_name',

  '& Street',

  ' & city ",

  '& State',

  '& zip'

  ),

  user_phone ',' & user_mail ',' mem_idproof', ' & id_no');

  Dbms_output.put_line ('user is properly registered');

  exception

  When no_data_found then

  dbms_output.put_line ("' data not found");

  end reg_proc;

  Start

  Dbms_output.put_line (' enter ID or user name ');

  Dbms_output.put_line (' username: ' | p_user_name);

  If v_user_name is null then

  Dbms_output.put_line ('user not found');

  reg_proc;

  Insert user_login SELECT user_id_seq. NEXTVAL, user_name, NULL, mem_id_seq. NEXTVAL, user_type FROM user_registration WHERE user_name is lower (p_user_name);

  Dbms_output.put_line (' because the user wants to have the membership? ");

  Dbms_output.put_line ('If Yes, please pay dues");

  INSERT INTO member_login SELECT mem_id_seq. CURRVAL, SYSDATE, SYSDATE + avl_days, 500, 'Y' of user_login ul, bl book_loan WHERE ul.mem_type = bl.mem_type AND user_name = p_user_name;

  END IF;

  exception

  When no_data_found then

  dbms_output.put_line ("' no data found");

  When too_many_rows then

  dbms_output.put_line (' too many lines).

  END validate_userLogin;

  procedure validate_issuedbooks (p_issuecount series)

  number of v_issuecount;

  Start

  Select user_login u, bl book_loan, avl_days, avl_books in v_avl_days, v_avl_books where bl.mem_type = u.mem_type and user_id = p_user_id;

  SELECT count (case when end_date < end return_date then p_mem_id) as invalidcount in v_issuecount from book_count where mem_id = p_mem_id;

  v_issuecount: = p_issuecount;

  dbms_output.put_line (' no. books that the user contains the :'|| p_issuecount);

  end validate_issuedbooks;

  procedure issuebooks is

  procedure book_avl (p_avl_now_flag in p_avl_date Boolean, date) is

  v_avl_now_flag char (1);

  date of v_avl_date;

  procedure reader_bookissue is

  Start

  insert into values drive (p_user_id, v_book_id, sysdate, sysdate, null);

  insert into book_count values(p_mem_id,v_book_id,sysdate,sysdate,null);

  Update book_availability set issued_to is "Reader" where book_id = v_book_id;.

  end reader_bookissue;

  Start

  Select book_name, b.book_id avl_now_flag v_book_name, v_book_id, v_avl_now_flag of the book b, book_availability b where b.book_id = ba.book_id and ba.book_id = p_book_id;

  If v_avl_now_flag = "Y" then

  dbms_output.put_line ('the book is available for issuance' | v_book_id);

  on the other

  Select mem_type in the v_mem_type of user_login where user_id = (select user_id from book_availability where avl_now_flag = 'n' and book_id = p_book_id);

  If v_mem_type = "Reader" then

  reader_bookissue;

  dbms_output.put_line (' the book is with Reader.) Please try tomorrow.') ;

  on the other

  dbms_output.put_line ('the book is member');

  end if;

  Select avl_date in the book_availability v_avl_date where book_id = p_book_id;

  v_avl_date: = p_avl_date;

  dbms_output.put_line (' the available date is: ' | p_avl_date);

  end if;

  end book_avl;

  Start

  insert into book_count values(p_mem_id,p_book_id,sysdate,sysdate+v_avl_days,v_return_date);

  Update book_availability set book_id = p_book_id, avl_now_flag = 'n', avl_date is to_date (sysdate + v_avl_days,' dd-mm-yyyy ""), issued_to = v_mem_type, user_id = p_user_id where mem_id = p_mem_id;

  commit;

  dbms_output.put_line ("' the book published successfully");

  end issuebooks;

  Number of function return late_fee (p_mem_id in number, p_extradays series, p_latefee_total number) is

  number of v_extradays;

  number of v_latefee_total;

  number of v_latefee_per_book;

  number of v_latefee_per_day;

  number of v_book_count;

  Start

  Select trunc (sysdate) - v_end_date in v_extradays from book_received where mem_id = p_mem_id and book_id = p_book_id;

  p_extradays: = v_extradays;

  v_latefee_per_book: = v_latefee_per_day * v_extradays;

  v_latefee_total: = v_latefee_per_book * v_book_count;

  p_latefee_total: = v_latefee_total;

  dbms_output.put_line ('The total AMT for not returned books' | p_latefee_total);

  end late_fee;

  end lib_01;

  Hello

  I checked the first 10 lines after the beginning and I could count already several errors.

  Is it an exercise or a real code, you must provide?

  Kind regards.

  Alberto

• Need help with a SQL query

  Hello

  I have a data in table (raj_table) with columns (char11) raj_id, raj_number (varchar2 (15)), raj_format (NUMBER), Primary_ID (identity with the values of the primary key column)

  Primary_ID raj_id Raj_number Raj_format

  1                            raj                 rajvend                      1

  2                            raj                 rajvend                      1

  3                            raj                 rajvendor1                 2

  4                            raj                 rajvendor1                 2

  5                            raj                 rajvendor1                 2

  6                            raj                 rajvendor2                 3

  I used under SQL to get query output as below, but has not achieved the required result:

  Select client_id vendor_number, vendor_format, primary_id, row_number() on sl_no (client_id partition, primary_id, vendor_format order of client_id primary_id, vendor_format, vendor_number, vendor_number)

  from raj_table by sl_no asc

  SL_NO raj_id raj_number raj_format primary_id

  1                   1                   raj              rajvendor                 1

  1                   2                  raj              rajvendor                 1

  2                   3                   raj              rajvendor1                2

  2                   4                   raj              rajvendor1                2

  2                   5                  raj               rajvendor1                2

  3                   6                    raj              rajvendor2                3

  I need help with a SQL query to get the result as above without using the group by clause. I want to bring together the combination of separate line of the three columns (raj_id, raj_number, raj_format) and add a unique serial number for each online game (SL_NO column below). So, above there are 3 unique set of (raj_id, raj_number, raj_format) I can get in a group by clause, but I can not add prmiary_id, SL_NO values if I group by clause. I used the analytical functions like row_number() but no luck. Need solution for this.

  with t as)

  Select 'raj' raj_id, 'rajvend' raj_number, 1 raj_format, 1 primary_id Union double all the

  Select option 2, 'raj', 'rajvend', 1 double Union all

  Select 3, 'raj', 'rajvendor1', 2 double Union all

  Select 4, 'raj', 'rajvendor1', 2 double Union all

  Select 5, 'raj', 'rajvendor1', 2 double Union all

  Select 6, 'raj', 'rajvendor2', 3 double

  )

  Select dense_rank() over (order of raj_id, raj_number, raj_format) sl_no,

  t.*

  t

  order by primary_id

  /

  PRIMARY_ID RAJ RAJ_NUMBER RAJ_FORMAT SL_NO
  ---------- ---------- --- ---------- ----------
  1 1 raj rajvend 1
  1 2 raj rajvend 1
  2 3 raj rajvendor1 2
  2 4 raj rajvendor1 2
  2 5 raj rajvendor1 2
  3 6 raj rajvendor2 3

  6 selected lines.

  SQL >

  SY.

• Help with the query to select only one record from the result set in double

  Hello

  Please help with the query. Version of Oracle database we use is 10g R2.

  I have a vision that is duplicated IDS, but they are used across the different functions. See below examples of data. Please help me with a query to select only one record (based on ID regardless of the area) from the bottom of the result set of duplicate records. For what is the point of view is there unique records, given the combination of the fields ID, Org, DF, dry, Sub-Sec

  ID	Org	DF	Sec	Sub-Sec

  
  (163)CQCPDMCPDMHD(163)PCENGENGENG(163)CQASICASICIS8888TSTACTACTAC(163)TSHEHESW6789CQINFOINFOFOS6789PCSECSYSSECSYSINFO16789TSSECSYSSECSYSINFO29009PCBMSBMSBMS1

  My result set must eliminate the duplicate identifiers regardless of whoever we choose of the result set. (I mean without distinction Org, DF, s, Sub-s). My expected result set should be.

  ID	DSB

  
  DF
  SEC
  Sub-Sec
  (163)CQCPDMCPDMHD8888TSTACTACTAC6789CQINFOINFOFOS9009PCBMSBMSBMS1

  
  

  Thank you

  Orton
  

  Hello

  This sounds like a job for ROW_NUMBER:

  WITH got_r_num AS

  (

  SELECT id, DSB, df, s, sub_sec org

  ROW_NUMBER () OVER (PARTITION BY ID.

  ORDER BY org

  ) AS r_num

  OF view_x

  )

  SELECT id, DSB, df, sub_sec s,

  OF got_r_num

  WHERE r_num = 1

  ;

  He is a Top - N query example, where you choose the elements of N (N = 1 in this case) from the top of an ordered list.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and INSERT, only relevant columns instructions) to your sample data and the results desired from these data.  (I know that you said that you were a view selection.  Just for this thread, pretending it is a picture and post simple CREATE TABLE and INSERT statements to simulate your point of view).
  Point where the above query is to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in these places.  (I didn't quite understand the explanation above.  I don't know why you want to

  ID ORG DF DRY SUB_SEC

  --      ---     --      ---     -------

  1234 CQ DPRK DPRK HD

  and is not

  1234 IS CQ ASIC, ASIC

  or

  TS 1234 IT IT SW

  or

  1234 CQ ASIC ASIC HD

  )
  If you change the query at all, post your modified version.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002

• Help with conditional display and Validation

  Version 4.1.1.00.23

  Hello

  I'm having a difficult time with a conditional display and validation, I hope someone can help with.

  Requirements:

  When (Datepicker) Start Date or the end Date (Datepicker) change can display the reason for change (select list) and change Description (Textbox)
  If the page is saved without entering a reason change display an error message of validation that the reason for the change cannot be empty (NULL)

  What I tried

  Create a dynamic Action on the Start Date

  Event: Change

  Selection type: Article (s)

  Items (s): P51_START_DATE

  Condition: no

  Real Action Section:

  Action: Show

  Fire on Page load: Checked

  Display all the elements of the page on the same line: NO.

  Section of the elements concerned:

  Selection type: Article (s)

  Product (s): P51_CHANGE_REASON, P51_CHANGE_DESC

  I also created a dynamic Action with similar settings for the P51_END_DATE.

  I created a Validation for the P51_CHANGE_REASON as a function return error text:

  DECLARE
      v_start_date    work_items.start_date%TYPE;
      v_end_date      work_items.end_date%TYPE;
  BEGIN
      SELECT start_date
            ,end_date
      INTO   v_start_date
            ,v_end_date
      FROM   work_items
      WHERE  work_items_id = :P51_WORK_ITEMS_ID;
      IF ( (v_start_date != TO_DATE(:P51_START_DATE,'DD-MON-YYYY') OR v_end_date != TO_DATE(:P51_END_DATE,'DD-MON-YYYY') ) AND
            :P51_CHANGE_REASON IS NULL ) THEN
          RETURN 'Change Reason must have a value';
      END IF;
  END;
  
  
  

  The question

  I tried to create another dynamic Action to hide the P51_CHANGE_REASON and P51_CHANGE_DESC fields during the loading of the page, but when the date fields are changed and the validation is fired the P51_CHANGE_REASON and the P51_CHANGE_DESC are hidden again.

  There are two buttons to send the page: 'SAVE' will submit the page and stay on the page and 'SAVE_CHANGES' will present the page and creates a branch to the previous page (which is a relationship with the EDIT buttons to change recording).

  I can not loading the dynamic Action page for fires DO NOT when validation is triggered.

  I hope it is clear and if not what information can I provide?

  Thank you

  Joe

  Which the condition is failing and what browser? I tested it in Firefox and it works as it should. Can you confirm that?

• write a view with function in oracle

  Hi all

  I have a table named border, contains the borders of certain countries.

  and then I did notice, for symmetric data, which means that if I have a folder {ch, OF} I {, ch}.

  so I want another opinion, preferably with the help of functions, to show me that these results, the first view must be used, not the main table, to create this view.

  en, 1

  pl, 1

  UK, 2

  read, 2

  read, 3

  This means between these countries, we have these quantity of bordes, but we just want to see these up to 3 borders, not more.

  Thanks for your reply.

  IM using oracle 10 g and linux ubuntu 12.

  First of all, I have a table illustrating the countries

  {code}

  -File created - Sunday-November-24-2013

  --------------------------------------------------------

  --------------------------------------------------------

  -The DOF for Table BORDERS

  --------------------------------------------------------

  CREATE TABLE 'borders' ('Country1' CHAR (2), 'countries2"TANK (2), the NUMBER of 'LENGTH')

  INSERTION of REM in borders

  TOGETHER TO DEFINE

  Insert into borders (countries1, countries2, LENGTH) values ('from', 'fr', 381);

  Insert into borders (countries1, countries2, LENGTH) values ('from', 'ch', 494);

  Insert into borders (countries1, countries2, LENGTH) values ('from', 'pl', 148);

  Insert in borders (countries1, countries2, LENGTH) values ('ch', 'fr', 608);

  Insert in borders (countries1, countries2, LENGTH) values ('ch', 'it', 318);

  Insert into borders (countries1, countries2, LENGTH) values ("ch", "li", 240);

  Insert into borders (countries1, countries2, LENGTH) values ('he', 'if', 306);

  Insert into borders (countries1, countries2, LENGTH) values ('he', 'DM', 584);

  Insert into borders (countries1, countries2, LENGTH) values ('en', 'read', 549);

  Insert into borders (countries1, countries2, LENGTH) values ('en', 'of', 1000);

  Insert into borders (countries1, countries2, LENGTH) values ('pl', 'ru', 628);

  Insert in borders (countries1, countries2, LENGTH) values ('pl', 'sk', 126);

  Insert into borders (countries1, countries2, LENGTH) values ('UK', 'au', 1800);

  {code}

  and then I have a symmetrical data view:

  {code}

  SELECT B.COUNTRY1, B.COUNTRY2

  BORDERS B

  UNION

  SELECT B.COUNTRY2, B.COUNTRY1

  BORDERS B

  {code}

  Of course you can do it in a function. But why write a function where possible in SQL using the features of Oracle wrote to us ;-)

  'min way' is the key here sentence. You said... for example, we do not want {en, 3, 1000}

  Is it because that {en, a, 2} is already covering en-> of?

  In, this case may be something like this... I am sure that other members may provide the most effective solution.

  But please review these suggested solutions build further and learn SQL/capabilities in Oracle. After all, it's that you should maintain and build on this code. Play with this code and see what makes each step. You will be able to solve the problem that you encounter in yourself. Basically, it is the main objective of these forums.

  > col A30 path format

  > with t as)

  Select the Country1, countries2, lvl level length, SYS_CONNECT_BY_PATH (countries2, ' /') 'Path' of borders

  Start by Country1 = "of" connect by nocycle Country1 = countries2 prior)

  t2 as)

  Select t.*, min (lvl) on Pmin (partition by Country1, countries2) t where lvl<>

  Select * from t2 where Pmin = lvl

  Country1 countries2 LVL PMIN path LENGTH

  -------- -------- ---------- ---------- ------------------------------ ----------

  ch       fr                2        608 /ch/fr                                  2

  ch       it                2        318 /ch/it                                  2

  ch       li                2        240 /ch/li                                  2

  de       ch                1        494 /ch                                     1

  de       fr                1        381 /fr                                     1

  de       pl                1        148 /pl                                     1

  fr       de                2       1000 /fr/de                                  2

  fr       lu                2        549 /fr/lu                                  2

  it       si                3        306 /ch/it/si                               3

  it       sm                3        584 /ch/it/sm                               3

  pl       ru                2        628 /pl/ru                                  2

  pl       sk                2        126 /pl/sk                                  2

  ru       ua                3       1800 /pl/ru/ua                               3

  13 selected lines

  Elapsed time: 00:00:00.018

  I hope this helps.

  VR,

  Sudhakar