Helps the complex expression to Group By
Hi allI use a BPM opensource to store variables in a Workflow process. Variables are stored in an Oracle 10 database and can be retrieved using the native Api of BPM (Java) or by using Sql. For performance reasons, I use simple SQL to collect a list filtered workflow variables.
Here is a simplified version of the BPM_INSTANCE Table:
[NAME] [VALUE] [PROCESS_INSTANCE]
=====================================
AREA IN ADDITION TO 1 125
ACME CUSTOMER 125
ID_WO 500 125
2 200 FIELD
200 TEST CLIENT
ID_WO 501 200
1 225 FIELD
CUSTOMER MODEL 225
ID_WO 502 225
Each PROCESS_INSTANCE has a set of variables that have a NAME and a VALUE.
My need is to collect the list of all (500,501,502) ID_WO, PROCESS_INSTANCE belongs to a DOMAIN (ex. 1) and one client (e.g. ACME)
I started coding the SQL:
Select VALUE from BPM_INSTANCE where NAME = 'ID_WO' and PROCESS_INSTANCE in
(select PROCESS_INSTANCE from BPM_INSTANCE, whose NAME = "CUSTOMER" and VALUE = "ACME"
)
However, I am not able to meet several conditions (for example I need also the PROCESS_INSTANCE also contains an AREA = 1).
Can someone help me?
Thank you
Frank
Hello
Would this work:
with data as (
select 'AREA' as name, '1' as value, '125' as pi from dual union all
select 'CLIENT' , 'ACME', '125' from dual union all
select 'ID_WO', '500', '125' from dual union all
select 'AREA', '2', '200' from dual union all
select 'CLIENT', 'TEST', '200' from dual union all
select 'ID_WO', '501', '200' from dual union all
select 'AREA', '1', '225' from dual union all
select 'CLIENT', 'DUMMY', '225' from dual union all
select 'ID_WO', '502', '225' from dual)
select o.value, i.value, ii.value from data o
inner join data i on ( o.pi = i.pi )
inner join data ii on ( o.pi = ii.pi ) where o.name = 'ID_WO' and i.name = 'AREA' and ii.name = 'CLIENT';
HtH
Johan
Tags: Database
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Help of the complex select query (Group by)
Hello
I am in need of your help to create a unique select query for the data in the table below and whose output requies. I use oracle 10g on RHEL 5 version.
create table bustour (number of bussno (4), start_date date, number (2)) passenger;
ALTER session set nls_date_format = "dd-mm-yyyy";
insert into bustour values (4123, April 10, 2009 ", 20);
insert into bustour values (4123, may 10, 2009 ", 25);
insert into bustour values (4123, may 10, 2009 ', 18);
insert into bustour values (4123, June 10, 2009 ', 15);
insert into bustour values (6138, March 10, 2009 ', 16);
insert into bustour values (' 6138, March 10, 2009 ", 19);
insert into bustour values (6138, April 10, 2009 ', 22);
insert into bustour values (' 6138, April 10, 2009 ", 13);
insert into bustour values ("4123, July 10, 2009 ', 23);
insert into bustour values (4123, August 10, 2009 ", 27);
insert into bustour values (4123, November 10, 2009 ', 15);
insert into bustour values (6138, may 10, 2009 ', 16);
insert into bustour values (6138, may 10, 2009 ', 13);
insert into bustour values (6138, may 10, 2009 ', 18);
insert into bustour values (' 6138, may 10, 2009 ", 24);
insert into bustour values (6138, July 10, 2009 ", 20);
insert into bustour values (6138, August 10, 2009 ", 18);
So that we can know on what particular travel calendar, we have obtained maximum passengers and the date. (For calculating % of bonus driver)SQL> select * from bustour; BUSSNO START_DATE PASSENGERS ---------- ---------- ---------- 4123 04-10-2009 20 4123 05-10-2009 25 4123 05-10-2009 18 4123 06-10-2009 15 6138 03-10-2009 16 6138 03-10-2009 19 6138 04-10-2009 22 6138 04-10-2009 13 4123 07-10-2009 23 4123 08-10-2009 27 4123 11-10-2009 15 BUSSNO START_DATE PASSENGERS ---------- ---------- ---------- 6138 05-10-2009 16 6138 05-10-2009 13 6138 05-10-2009 18 6138 05-10-2009 24 6138 07-10-2009 20 6138 08-10-2009 18 17 rows selected. I want query output as below : Bussno start_date end_Date totalpassengers maxpessenger maxpassdate 4123 04-10-09 06-10-09 78 25 05-10-09 6138 03-10-09 04-10-09 70 22 04-10-09 4123 07-10-09 11-10-09 65 27 08-10-09 6138 05-10-09 08-10-09 109 24 05-10-09
Please help me to write the query.
Best regards
NishaOK, something like this:
with my_tab as (select 1 id, 4123 busno, to_date('04/10/2009', 'dd/mm/yyyy') start_date, 20 passengers from dual union all select 2 id, 4123 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 25 passengers from dual union all select 3 id, 4123 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 18 passengers from dual union all select 4 id, 4123 busno, to_date('06/10/2009', 'dd/mm/yyyy') start_date, 15 passengers from dual union all select 5 id, 6138 busno, to_date('03/10/2009', 'dd/mm/yyyy') start_date, 16 passengers from dual union all select 6 id, 6138 busno, to_date('03/10/2009', 'dd/mm/yyyy') start_date, 19 passengers from dual union all select 7 id, 6138 busno, to_date('04/10/2009', 'dd/mm/yyyy') start_date, 22 passengers from dual union all select 8 id, 6138 busno, to_date('04/10/2009', 'dd/mm/yyyy') start_date, 13 passengers from dual union all select 9 id, 4123 busno, to_date('07/10/2009', 'dd/mm/yyyy') start_date, 23 passengers from dual union all select 10 id, 4123 busno, to_date('08/10/2009', 'dd/mm/yyyy') start_date, 27 passengers from dual union all select 11 id, 4123 busno, to_date('11/10/2009', 'dd/mm/yyyy') start_date, 15 passengers from dual union all select 12 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 16 passengers from dual union all select 13 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 13 passengers from dual union all select 14 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 18 passengers from dual union all select 15 id, 6138 busno, to_date('05/10/2009', 'dd/mm/yyyy') start_date, 24 passengers from dual union all select 16 id, 6138 busno, to_date('07/10/2009', 'dd/mm/yyyy') start_date, 20 passengers from dual union all select 17 id, 6138 busno, to_date('08/10/2009', 'dd/mm/yyyy') start_date, 18 passengers from dual) -- end of mimicking your data; use SQL below: select busno, min(start_date) start_date, max(start_date) end_date, sum(passengers) total_passengers, max(passengers) max_passengers, max_pass_date from (select id, start_date, busno, passengers, distance, max(start_date) keep (dense_rank first order by passengers desc) over (partition by distance, busno) max_pass_date from (select id, start_date, busno, passengers, -- using tabibitosan method, borrowed from Aketi Jyuuzou dense_rank() over (order by id) - row_number() over (partition by busno order by id) distance from my_tab)) group by busno, distance, max_pass_date order by min(id) BUSNO START_DATE END_DATE TOTAL_PASSENGERS MAX_PASSENGERS MAX_PASS_DATE ---------- ---------- ---------- ---------------- -------------- ------------- 4123 04/10/2009 06/10/2009 78 25 05/10/2009 6138 03/10/2009 04/10/2009 70 22 04/10/2009 4123 07/10/2009 11/10/2009 65 27 08/10/2009 6138 05/10/2009 08/10/2009 109 24 05/10/2009 -
In the book of Marcus Geduld "AfterEffectsExpressions" it is an example (p.145) which reads:
Effect ("4-Color gradient"). Param (propertyIndex - 2).valueAtTime(time-.5)
It is an expression is applied to one of the points in a gradient effect 4 colors. It returns an error message:
Bad method arguments: propertyIndex cannot be used in this property. It seems strange that this book has a whole section that uses this expression is not valid.
BTW, I found a number of typos in the book which I like and that you have learned a lot from. I would contact him if there was a link in his book, but I can't find anything. If anyone can understand it that I would really appreciate it.
I think the problem is that when the book was written, thisProperty is implied when it relates to the housing property attributes the expression. Somewhere along the line it was changed so that now you have to include it explicitly. This should work:
Effect ("4-Color gradient"). Param (thisProperty.propertyIndex - 2).valueAtTime(time-.5)
Dan
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Hello
I have a MyCounter table that is used to get the sequence numbers after N.
For purposes of simplicity, let's just table MyCounter has 2 fields - maxNumber and currentNumber.
maxNumber is the maximum sequence number that can be allocated.
currentNumber is the last (current) sequence number.
Assuming maxNumber is 1000, currentNumber is 500. If N is 10, the sequence should I get numbers: From = To = 510, 501
I am new to Oracle. I had a first blow of dagger to write the SQL to update, but I am not convinced that it works.
Can anyone give me suggestions please? Thank you...
---------
DECLARE
v_origValue NUMBER (10,0): = 0;
v_allocated NUMBER (10,0): = 0;
V_quantity NUMBER (10,0): = 0;
BEGIN
V_quantity: = 10; -assuming that 10 is a constant at this stage
UPDATE MyCounter
SET v_allocated = box
When (currentNumber + v_quantity < = maxNumber) then restart
else (maxNumber-currentNumber)
end,
v_origValue = (currentNumber),
currentNumber = (currentNumber + v_allocated)
WHERE the currentNumber < maxNumber;
SELECT v_origValue + 1 as 'from', v_origValue + v_allocated 'to '.
FROM DUAL;
END;
---------
Kind regards
JudyHere is a small example of what you could do.
SQL> create table t(type varchar2(10),max_val number, curr_val number) 2 / Table created. SQL> insert into t values('type1',100,0) 2 / 1 row created. SQL> insert into t values('type2',1000,500) 2 / 1 row created. SQL> create or replace type my_seq as table of number 2 / Type created. SQL> create or replace procedure get_sequence(ptype in varchar2, pcount in number, pseq out my_seq) 2 as 3 lcurr_val t.curr_val%type; 4 lmax_val t.max_val%type; 5 max_seq_exception exception; 6 begin 7 update t 8 set curr_val = curr_val + pcount 9 where type = ptype 10 returning curr_val, max_val into lcurr_val, lmax_val; 11 12 if lcurr_val > lmax_val 13 then 14 rollback; 15 raise max_seq_exception; 16 else 17 select lcurr_val - (level-1) 18 bulk collect into pseq 19 from dual 20 connect by level <= pcount 21 order by level desc; 22 23 commit; 24 end if; 25 exception 26 when max_seq_exception then 27 raise_application_error(-20001,'Max sequence exceeded'); 28 end; 29 / Procedure created. SQL> declare 2 lseq my_seq; 3 begin 4 get_sequence('type1',10,lseq); 5 for i in 1..lseq.count 6 loop 7 dbms_output.put_line(lseq(i)); 8 end loop; 9 end; 10 / 1 2 3 4 5 6 7 8 9 10 PL/SQL procedure successfully completed. SQL> select * from t 2 / TYPE MAX_VAL CURR_VAL ---------- ---------- ---------- type1 100 10 type2 1000 500 SQL> declare 2 lseq my_seq; 3 begin 4 get_sequence('type1',100,lseq); 5 for i in 1..lseq.count 6 loop 7 dbms_output.put_line(lseq(i)); 8 end loop; 9 end; 10 / declare * ERROR at line 1: ORA-20001: Max sequence exceeded ORA-06512: at "SYSADM.GET_SEQUENCE", line 27 ORA-06512: at line 4But do not forget in a multiuser environment, there are many chances for you to get screwed!. Sequence is the best option in my opinion.
Published by: Karthick_Arp on November 30, 2008 21:14
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Cannot find the Airport Express Airport utility
Hello
I have a firmware running extreme Airport 7.6.7. 6.3.6 and one Airport utility Terminal Airport Express (model A1392). I have access to my system on a Macbook pro. Also have the app on my iPhone.
My Airport Express and extreme talked to each other and have been broadcast on the Airport utility. However, I had to change my wifi password and the network password. After that, the Airport extreme restarted. After the reboot, my Express was no longer recognized by my network. The Express has a light orange and blinks repeatedly. I can't connect to the express to address the issue of amber light.
I have read many posts on the forum. However, I still have to find a solution. How to connect the airport utility to the Airport express?
Thanks for any help, you can make it,
You have changed the password for WiFi on AirPort Extreme... but... the AirPort Express Terminal was previously programmed to connect by using your password in the "old". The Express is lost, unable to find the network at all and doesn't know what to do.
You can help the AirPort Express by doing a hard reset on the AirPort Express to clear the old network settings and passwords, and then configure the Express again to connect to your network 'nine' with the 'new' password.
After the back if you don't know how to proceed.
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Help in regular Expression for the beaches of limitation
Hi, I'm working on the provision of a text field is limited to dates, it's just a part of the code. I already have the validation of the dates, but I am now limiting what the user enters using a regular expression. This code works a little however, it does not limit me for example I can enter more than 2 digits, but then he limits based on the total amount allowable so for example 8 digits are allowed if I just type. I need to stop after 2 digits then have a - then 2 other numbers then one - and then followed by 4 digits. I tried to limit each section and grouping as well. Any help would be greatly appreciated. Thank you.
It is in the format code and I am the appellant in the key sequence.
function DateKS () {}
var value = AFMergeChange (event);
If (! event.willCommit) {}
Allow only characters that match the regular expression
Event.RC = /^([0]{0,1}[1-9]{0,1}|[_1]{0,1}[012]{0,1}) ([-] {0,1}) ([0] {0,1} [1-9] {0,1} |) [12] {0,1} [0-9] {0,1} | ([3] {0,1} [01] {0,1}) ([-] {0,1}) ([0-9] {0,4}) $/ .test (value);
}
}
I decided that control for 100 and 400 was not necessary because this event does occur that all 400 years. But I'm working on it further and changed even more. Here is my code to work.
function isLeapYear (year) {}
year return % 4 = 0;
}function checkDaysInMonth (day, month, year) {}
daysInMonth var = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];If (month = 2) {}
If (isLeapYear (year)) {}
daysInMonth [1] += 1;
}
}return daysInMonth [month - 1] > = day;
}function checkDateFormat (dateStr) {}
var errorMsg = ",
maxYear = (new Date()) .getFullYear (),
minYear = maxYear - 1,.
match = dateStr.match(/^(\d{2})-(\d{2})-(\d{4})$/),
months,
day,
year;If {(matches)
month = parseInt (matches [1], 10);
day = parseInt (matches [2], 10);
year = parseInt (matches [3], 10);If (month < 1="" ||="" month=""> 12) {}
errorMsg = "invalid value for the month: ' + matches [1];"
} ElseIf (day = 0) {}
errorMsg = "invalid value for the day:" + match [2];
} else if (! checkDaysInMonth (day, month, year)) {}
errorMsg = "number of days for invalid month: ' + match [2];"
} ElseIf (year < minyear="" ||="" year=""> maxYear) {}
errorMsg = "invalid value for the year:" + match [3] + "-must be between" + minYear + "and" + maxYear;
}
} else {}
errorMsg = "invalid date format: ' + dateStr + ' \r\nPlease use format: dd-mm-yyyy ';"
}return errorMsg;
}function checkReceivedDate() {}
var value = AFMergeChange (event),
errorMsg = ";
ignore control if the value is blank, because this field is not mandatory
If (! value) {}
return;
}If {(event.willCommit)
errorMsg = checkDateFormat (value);If (errorMsg) {}
App.Alert (errorMsg, 0, 0, "error");
Event.value = ";Returns false;
}
} else {}
Allow only characters that match the regular expression
Event.RC = /^(?:0) [1-9]? 1 [012]?) ? -? ( ? : 0 [1-9] ? | [12] [0-9]? 3 [01]?) ? - ? 2? 0? [0-9] {0,2} $/ .test (value);
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} -
in windows 7 in sharing network, sometimes an error "the dependency service or group could start.
Help me solve this problem...Hi Nick,
Welcome to the Microsoft Community Forums.
According to the description, it seems like you get an error "the dependency service or group could start" while turning on the network share. I will certainly help you fix this problem.
(1) did you do changes on the computer before this problem?
Method 1: I suggest you follow the steps to enable services and check if it helps.
(a) click Start and type services.msc , and then press enter.
Make sure that all the following services are enabled. Don't forget that its Startup Type is set to Automatic , and then click OK.
To activate a service, click to select the check box.
. Application Layer Gateway Service
. Network connections
. Knowledge of the network (NLA) locations
. Plug-and-Play
. Remote Access Auto Connection Manager
. Remote Access Connection Manager
. Remote procedure call (RPC)
. Telephony
(b) click OK, and then click restart.
Method 2: If the problem persists, I suggest you to follow the steps from the link and check if it helps.
Some services do not start in Windows Vista and Windows 7
http://support.Microsoft.com/kb/943996
To do: Important This section, method, or task contains steps that tell you how to modify the registry. However, serious problems can occur if you modify the registry incorrectly. Therefore, make sure that you proceed with caution. For added protection, back up the registry before you edit it. Then you can restore the registry if a problem occurs. For more information about how to back up and restore the registry, click on the number below to view the article in the Microsoft Knowledge Base:
322756 (http://support.microsoft.com/kb/322756/)
How to back up and restore the registry in Windows
I hope this helps. Try the above steps and get back to us for further assistance if you have questions about Windows. We will be happy to help you.
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Need help to make the complex calculation "period of coverage"...
Published by: W Nicloei on June 10, 2011 12:54 AMdear team, I am stuck up at one point where i cant seem to be finding any logic to implement the following piece of request... I hope i can come assistance from the forum members,here... any idea would be helpful :-) The situation is explained below... 1..The data set... Select * From (SELECT 25048189 ITEM_NO, '2011_35' DEL_WEEK, 352811.406 FINISH_ON_HAND, 7188.621 DEMAND, 5.654 POC from dual union all SELECT 25048189, '2011_36', -83977.656, 436789 , 0 from dual union all SELECT 25048189, '2011_37', -448155, 64177.406 , 0 from dual union all SELECT 25048189, '2011_38', 2012206, 430095.406, 0 from dual union all SELECT 25048189, '2011_39', 1612299, 399907.094, 0 from dual union all SELECT 25048189, '2011_40', 1612516, 402966.406, 0 from dual union all SELECT 25048189, '2011_41', 1612732, 402966.406, 0 from dual union all SELECT 25048189, '2011_42', 1615767, 403183 , 0 from dual union all SELECT 25048189, '2011_43', 2837452, 403183 , 0 from dual union all SELECT 25048189, '2011_44', 2434269, 403183 , 0 from dual union all SELECT 25048189, '2011_45', 2031086, 403183 , 0 from dual union all SELECT 25048189, '2011_46', 1624869, 406217.594, 0 from dual union all SELECT 25048189, '2011_47', 1563112, 1624868 , 0 from dual union all SELECT 25048189, '2011_51', 1605986, 1563112 , 0 from dual union all SELECT 25048189, '2012_03', 1976204, 1605986 , 0 from dual union all SELECT 25048189, '2012_07', 0.25 , 1976204 , 0 from dual union all SELECT 25048189, '2012_08', 1568796, 0 , 0 from dual union all SELECT 25048189, '2012_12', 1647070, 1568796 , 0 from dual union all SELECT 25048189, '2012_16', 1971510, 1647070 , 0 from dual union all SELECT 25048189, '2012_20', 0.25 , 1971510 , 0 from dual union all SELECT 25048189, '2012_21', 1613356, 0 , 0 from dual union all SELECT 25048189, '2012_25', 1564118, 1613356 , 0 from dual union all SELECT 25048189, '2012_29', 1983125, 1564118 , 0 from dual union all SELECT 25048189, '2012_33', -0.125, 1983125 , 0 from dual ); Now if you notice carefull the POC (Period of cover) = 0 which i need to calculate... 2..Logic for POC... (tried hard to format :-( ) Now forumula for calculaing POC = FOH (FINISH ON HAND) of current week - DEMAND (next week) IF THIS IS -ve then POC = FOH / NEXT WEEK DMD * 7.... IF FOH -VE then POC = 0 IF FOH (FINISH ON HAND) of current week - DEMAND (next week) > 0 then use this balance to satisfy the next week demand...and so on... Once balance qty - next week demand = 1 or 0 then stop there....count the no of weeks in between...the current week is always 0, next week 1, the week after next week, 1 and so on... if balance qty - next week demand = 1 -->> take current FOH / NEXT week demand + count the no of weeks in between... I have given one example which shows this situation...for weeks 2011_35 and 2011_38 ITEM_NO DEL_WEEK FINISH_ON_HAND DEMAND POC = FOH (curr wee ) - Demand (next week) formula value 25048189 2011_35 352811.406 7188.621 5.654 -83977.594 = FOH / NEXT WEEK DMD * 7 5.654171332 25048189 2011_36 -83977.656 436789 0 0 """'---" """'---" 25048189 2011_37 -448155 364177.406 0 0 """'---" week counter 25048189 2011_38 2012206 430095.406 7 1612298.906 current week 38 0 25048189 2011_39 1612299 399907.094 6 1209332.594 current week + 1 = 39 1 25048189 2011_40 1612516 402966.406 0 1209549.594 current week + 2 = 40 1 25048189 2011_41 1612732 402966.406 0 1209549 week 41 1 25048189 2011_42 1615767 403183 0 1212584 week 42 1 25048189 2011_43 2837452 403183 0 2434269 week 43 1 25048189 2011_44 2434269 403183 0 2031086 week 44 1 25048189 2011_45 2031086 403183 0 1624868.406 week 45 1 25048189 2011_46 1624869 406217.594 0 1 week 46 6.15435E-07 25048189 2011_47 1563112 1624868 0 0 week 47 7.000000615 -->total 25048189 2011_51 1605986 1563112 0 n/a n/a n/a 25048189 2012_03 1976204 1605986 0 n/a n/a n/a 25048189 2012_07 0.25 1976204 0 n/a n/a n/a 25048189 2012_08 1568796 0 0 n/a n/a n/a 25048189 2012_12 1647070 1568796 0 n/a n/a n/a 25048189 2012_16 1971510 1647070 0 n/a n/a n/a 25048189 2012_20 0.25 1971510 0 n/a n/a n/a 25048189 2012_21 1613356 0 0 n/a n/a n/a 25048189 2012_25 1564118 1613356 0 n/a n/a n/a 25048189 2012_29 1983125 1564118 0 n/a n/a n/a 25048189 2012_33 -0.125 1983125 0 n/a n/a n/a TOTAL POC OF WEEK 2011_35 = 5.65 TOTAL POC OF WEEK 2011_38 = 7.000000615 I know this is complex issue and may not be correct to post here also...but any kind of inputs as how to achieve this..would be help full... let me know i am clear in my question...i tried to format. but no use :-(
Published by: W Nicloei on June 10, 2011 01:11Hello
There is something you can do with analytic functions, but it's a little complicated.
Howevere, I have always not understant why POC is 0 2011_40 of the week?
Kind regards
Sylvie -
Form validation helps with the regular Expression [a-zA-Z]
I'm trying to use the regular expression [a-zA-Z] to allow only upper or lowercase WITHOUT SPACES. With the help of [a-zA-Z] allows space and numbers.
Could someone give me a point in the right direction?
Thank you!
RGNelson wrote:
I'm trying to use the regular expression [a-zA-Z] to allow only upper or lowercase WITHOUT SPACES. With the help of [a-zA-Z] allows space and numbers.
Could someone give me a point in the right direction?
Please try with the following regular expression, which should work for text entry fields 'a line' well standard.
^ [A-Za-z] + $
See you soon,.
Günter
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Need help with the curve of a group of objects
Salvation Group;
This is my first post in this group. I'm quite new to Adobe Illustrator CS5, and I had to start using it to provide the type of file to a printer for Sublimation in the USA. They use CS5, and all colors are limited to the Pantone Solid Coated for their printing system. I'm swimsuit fabric printing.
However, my question is probably very basic. It is also frustrating, because I have already successfully did this that I ask, just do not remember how I did it.
In my image, the upper rectangle has curved shape finished (bottom). I've done this before, with in fact several objects together. They all have the curve with the rectangle.
I tried to do it again, using all kinds of transformation tools (shear), the tools of the effect and everything I could find, but nothing has worked. I thought that maybe to shear would work if I could fix in the middle of the rectangle and shear on both sides of the rectangle to the top, but it does not work. I think I'll start to take notes when I find something that works!
How this simple curves of single object or group of objects? It can be done, I know!
Thank you, Tom.
You can also use the Suspender Warp or distort the Emvelope > make with Warp Arc
How to apply it
as individual objects and the other as a group
As objectrs
As a group
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Impossible to replace and update a file in the client computers through Group Policy preferences
Hello
I am unable to replace and update a file in the client computers through Group Policy preferences.
For example,.
I am trying to replace and update a custom calendar file (c:\Program Files\Microsoft Office\Office12\1033\outlook.hol)to client computers through Group Policy ptreferences (political group: computer configuration\group policy setting \file preference\windows).) But it is not updated and replaced in client computers.
Could you please help me on this?
THnaks
Srinivasan
Hello
Your question of Windows 7 is more complex than what is generally answered in the Microsoft Answers forums. It is better suited for the public on the TechNet site. Please post your question in the following link for assistance:
http://social.technet.Microsoft.com/forums/en/winserverGP/threads
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I know by logic box to get the output using the regular expression?
Hello
I am now only study the notion of Regexp. I had seen the best of Mr. Blus. Can I know how it works. I need this logic of the functionality of wildcards in sting matching Regexp (wildcard string Matching).
Please help me in this matter.SQL> ed Wrote file afiedt.buf 1 WITH test_data AS ( 2 SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL 3 SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL 4 SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL 5 SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL 6 SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL 7 SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL 8 SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL 9 ) 10 select regexp_replace(t, '^.*[\]([^\]*)[\][^\]*$','\1') 11* from test_data SQL> / REGEXP_REPLACE(T,'^.*[\]([^\]*)[\][^\]*$','\1') ------------------------------------------------------------------ folderA temp A B C D folderE 7 rows selected. SQL>
IqbalSabrina wrote:
One last question what is the average ofThe final "\1" in
select regexp_replace(t, '^.*[\]([^\]*)[\][^\]*$','\1')Iqbal
It is a reference.
See here:
http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14251/adfns_regexp.htm#CHDHCIGHand in the middle of the table here:
http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14251/adfns_regexp.htm#CHDIEGEIMatches the nth previous subexpression, in other words, either grouped in parentheses, where n is an integer between 1 and 9. The parentheses cause > an expression be remembered; a backreference refers to him. A backreference account subexpressions from left to right, starting with the opening > bracket of each subexpression preceding. The expression is not valid if the source string contains less than n subexpressions preceding the \n.
Oracle supports the expression of backreference in the regular expression pattern and the replacement of the REGEXP_REPLACE function string.
The expression (abc: def) matches the strings abcxyabc and defxydef xy\1, but does not abcxydef or abcxy.A backreference allows you to search for a string repeated without knowing the actual string advance. For example, the expression ^(.*) \1$ > matches a line consisting of two adjacent instances of the same string.
As explained in table 4-2, backreferences store sub-expressions matched in a temporary buffer, which allows to reposition the characters. You access the pads with the notation \n, where \n is a number between 1 and 9. Each subexpression brackets and is numbered from left to right.
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Passing parameters to the EL Expression method
Hello
With the help of jdev 11g R1.
Is it possible to pass parameters to a method in an expression EL located in a property of UIComponent?
something like: af:inputText label = 'asdf' id = "id1" disabled = "#{bean.check ['value']}" / >
You can do this by using SecurityContext userInRole (#{securityContext.userInRole ['admin']}, but I need to do in my own managed bean.) When I try to follow the same approach as securityContext (i.e. #{mybean.check ['value']}) and having a check (String) method in mybean, it gives me an error saying that there is no such thing as checking property.
I followed the post http://technology.amis.nl/blog/622/how-to-call-methods-from-el-expressions-pre-jsp-20-trick-for-jsps-with-jstl that shows something to do (the bean implements interface card), it works.
The question is if this will also work in future releases of the ADF.
Thank you
RogerHello
You are hard to figure out how to work the EL:
ValueExpression: solve the last part of the phrase as a property of the object resolved the previous expression. [So if you #{securityContext.userInRole\['admin'\}] or #{securityContext.userInRole.admin}, it really means "find the admin of the object property #{securityContext.userInRole}", now #{securityContext.userInRole} is a
MethodExpression: solve the last part of the phrase as a method with a specific context signature of the object resolved the previous expression. Now the specific context depends on the attribute being used, actionListener will seek public Sub method (ActionEvent) and nothing else. So, if you want to pass a parameter by using the same strategy, you do not disrupt the party, but you can influence the previous part, which is a ValueExpression. So, let's say you have actionListener = "#{foo.bar.method}" and must pass the parameter to the method, you can use instead of #{foo.bar\[parameter\].method}, where #{foo.bar\[parameter\}] resolve to an object with a public method (ActionEvent) Sub, but instantiated during the resolution of parameter passing the said parameter to the constructor of the object. " This way is quite complicated, however, and we never had to use it in the projects I've done (and some of them were / are very complex). I suggest to the contrary push settings in the object before calling the method. Let the example of listener to action:
public class MyController { private MyAction action; public ActionListener getAction() { if (action == null) { action = new MyAction(); } return action; } private static class MyAction implements ActionListener { private Object parameter; public void processAction(ActionEvent ev) { // do something } public String getParameter() { return parameter; } public void setParameter(String parameter) { this.parameter = parameter; } } }Then in the page:
Kind regards
~ Simon
Published by: Simon Lessard on December 11, 2009 10:57
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Can not update the settings on the Airport Express
Currently have a facility - two extremes and an Express network. I for the life of me can't update the Express settings. I always get an error message but I can update the settings on the two extremes very well. I can make changes to the Express with my Iphone but I can't with my Imac. I want to activate the function of 5 GHz but I can't do that via my Iphone - with the desktop app I think. Can someone help me?
Let's first check and make sure that on which Airport Express version you have.
Your version of the AirPort Express is there only 1 or 2 Ethernet ports?
The Express to connect to your network and extend it wireless? Alternatively, the Express connects to one of the extremes airport using a wired Ethernet cable connection.
Then, I would be not too concerned of not being able to 'see' the Express of the iMac as long as you can access the settings of the iPhone. You can make almost any change using the iPhone you can use a Mac.
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The AirPort Express Terminal is good enough for me?
I need a new wireless router to replace my Netgear WNDR4300 'antiques '. The network is only 2-3 laptops and iPhones 1-2 at a time, over a printer and Chromecast device. We occasionally video stream, but not often. Critics say the AirPort Express is best purchased as an add-on to an existing network, but I can't justify more expensive options from the airport. I don't need the 11ac 802 that offer other options, and it seems that margin would be a problem, because it is limited to 5 GHz. We have a two-storey house. Is the simple terminal AirPort Express good enough for my home network?
The AirPort Express, pourraient deliver similar performance to your old Netgear router in terms of signal strength and the beach... but the only way to know with certainty if the Express will be good enough for your needs is to try in your home.
Try to locate the Express up high on a shelf or Cabinet, if you can, to help in the dissemination of the signal.
Fortunately, if you buy through Apple, you have one day 14, no questions asked return privilege, so if the Express does not provide the performance you need, you can return the unit for Exchange or a refund.
Maybe you are looking for
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