Hierarchy parent child scenario

Similar Questions

• Get the parent-child hierarchy of column delimited

  I've been on this forum once before, and someone helped me, so I hope I can get help again!

  4-15-5987');

  Thus, the hierarchy is divided on the hyphen. first parent being 4245, then the next value is-4 (including the hyphen) and what follows is - 1, for example

  CREATE TABLE REGEXTEST
    ( ITEM VARCHAR(20)); 
  
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-1');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-10');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-11');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-12');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-13');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-14');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15-59A7');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15-59D7');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15-59F7');
    INSERT INTO REGEXTEST (ITEM) VALUES ('4245-
  
  

  I have to be able to bind-1, -4, 4245. Perhaps the simplest is to build a new table with a primary key where it is assigned the id of the parent to the child.
  I just can't understand how to divide the individual elements and maintain the hierarchy. As previously mentioned, someone helped me with another part of the problem before where I needed to maintain the entire path of each child with the following query:

  select  nvl(prior item,item) parent,
          nvl2(prior item,item,null) child
    from  REGEXTEST
    connect by substr(item,1,instr(item,'-',-1) - 1) = prior item
    order by child,parent
  
  

  Now, if I could extrapolate that into a new table:

  CREATE TABLE FileHierarchy
  (ItemID INT NOT NULL PRIMARY KEY,
  ItemName varchar(50) NOT NULL,
  ParentID INT NULL);
  
  

  ItemName is the 4245 or - 4 or - 1 (only) - Yes, including the hyphen.

  The ID of the parent-1 would be the ID-4, etc...

  Thank you very much in advance!

  J.F. Larente

  Solution for not having stored the high level:

  SQL > select *.
  regextest 2
  3.

  POINT LEV
  -------------------- ----------
  4245 4
  4245 4-1
  4245 4-10
  4245 4-11
  4245 4-12
  4245 4-13
  4245 4-14
  4245 4-15
  4245 4-15-59 A 7
  4245 4-15-59 D 7
  4245-4-15-59F7

  11 selected lines.

  SQL > with t1 as)
  2. Select item
  regextest 3
  4 Union all the
  5 select distinct substr (item, 1, instr(item,'-',1))
  6 of regextest
  7             ),
  8 t2 as)
  9. select element,
  10 row_number() on id (order by article)
  11 from t1
  12              )
  13. select id,
  14 regexp_substr (rtrim (point,'-'), case level when 1 then ' [^-] + $' other '-[^-] + $' end) child.
  parentID 15 prior id,
  16 regexp_substr (prior rtrim (point,'-'), case level - 1 when 1 then ' [^-] + $' other '-[^-] + $' end) parent
  17 of t2
  beginning 18 with substr(item,-1) = '-'
  19 connect by substr (item, 1, instr(item,'-',-1) - 1) = prior rtrim(item,'-')
  20 and article! point prior =
  21.

  ID PARENTID PARENT CHILD
  ---------- -------------------- ---------- --------------------
  1 4245
  2 -4                            1 4245
  3 -1                            2 -4
  4 -10                           2 -4
  5 -11                           2 -4
  6 -12                           2 -4
  7 -13                           2 -4
  8 -14                           2 -4
  9 -15                           2 -4
  10-59A 7 9-15
  11 59 D 7 9 - 15

  ID PARENTID PARENT CHILD
  ---------- -------------------- ---------- --------------------
  12 59F7 9-15

  12 selected lines.

  SQL >

  SY.

• in the query and parent/child relationship

  WITH the data AS

  (

  SELECT '213NY1' lfrom, NULL, '215ZVD' mi lto, "215ZV9 ' id, 1 January 2014' sdate, January 2, 2014' edate, 3 January, 2014 'mdate' January 5, 2014 medate double UNION ALL.

  Lfrom SELECT NULL, '215ZVD' mi, id "213NY1", "215ZV9" lto 4 January 2014 'sdate', 6 January 2014 edate, January 7, 2014 'mdate', 8 January 2014 medate double UNION ALL

  SELECT '216TVZ' lfrom, NULL, "213JW7" e "217LVQ" id lto, 21 January, 2014 'sdate' January 9, 2014 edate, 10 January 2014 'mdate', 11 January 2014 medate double UNION ALL

  SELECT lfrom "215Y71", "217LVQ" lto, mi, "216TVZ" id "213JW7", 22 January, 2014 'sdate' January 23, 2014 edate, 24 January, 2014 'mdate' January 25, 2014 medate double UNION ALL

  SELECT '234IJF' lfrom, NULL, "234YU" e "3IUED" id lto, 26 January 2014 'sdate', 27 January 2014 edate, 28 January 2014 'mdate', 29 January 2014 medate OF double

  )

  some lines have parent/child relationship and some does not. for example, the first two query (data) are link together. online, the value of lto (215ZV9) corresponds to the id value

  in line 1.  the value of lfrom in row1 (213NY1) corresponds to the value of online id.

  the same scenario occurs in rows 3 and 4.  5th doesn't have any line which is a child. tier 5 is a single parent

  I want to WRITE a query that gives the following result.

  Mid id initial_date final_date

  =======================================

  215ZVD 215ZV9 1 January 2014 "January 5, 2014"

  "215ZVD 213NY1 7 January 2014" January 6, 2014 "

  "213JW7 217LVQ 21 January 2014 ' 11 January 2014"

  "213JW7 216TVZ 24 January 2014 ' 23 January 2014"

  "234YU 3IUED 26 January 2014 ' 27 January 2014"

  ONLY WHEN there is a parent/child relationship, initial DATE AND follow the final data WHAT such as

  FIRST date of deadline DATE

  < Mdate > < EDate > - for child

  < SDate > < MEDate > - for parent

  WHEN there is no relationship of parent/child (e.g. ONLY a parent ROW) THEN

  FIRST date of deadline DATE

  < SDate > < EDate-> parent

  can someone help me write a query for the above output

  with tt AS

  (SELECT a.*,

  ROW_NUMBER () ON LV (MIDDLE ORDER BY SDATE PARTITION),

  CASE

  WHEN ID = NVL (ADVANCE (lto, 1) OVER (PARTITION BY Middle ORDER BY sdate), LAG (lfrom) OVER (ORDER BY sdate Middle PARTITION))

  THEN 1

  END flg

  DATA one

  )

  SELECT THE MIDDLE,

  ID,

  CASE

  WHEN flg IS NOT NULL

  THEN

  CASE

  WHAT LV = 1

  THEN SDATE

  WHAT LV = 2

  THEN mDATE

  END

  Of ANOTHER sdate

  END INITIALDATE

  CASE

  WHEN flg IS NOT NULL

  THEN

  CASE

  WHAT LV = 1

  THEN mEDATE

  WHAT LV = 2

  THEN EDATE

  END

  Of ANOTHER edate

  END FINALDATE

  TT;

  Output:

  -------------

  MID ID INITIALDATE FINALDATE

  213JW7 217LVQ 21 January 2014 January 11, 2014

  213JW7 216TVZ 24 January 2014 23 January 2014

  215ZVD 215ZV9 January 1, 2014 5 January 2014

  215ZVD 213NY1 January 7, 2014 6 January 2014

  234YU 3IUED 26 January 2014 January 27, 2014

• Navigation in Parent child Hiearachy is a bug in OBIEE 11.1.1.6?

  Hi all
  
  Look in one of my previous posts
  
  OBIEE 11g - Navigation in the Parent child hierarchy does not
  
  One of my friends Ram told me that it is a Bug of Oracle in 11.1.1.6. It's that I just wanted to know if someone has faced the same problem and this was reported as a bug in Oracle. Unfortunately, I do not have the privileges to log a bug or review the information in bug, can someone please provide any information on that?
  
  Thank you
  Ronny

  Hello

  This problem is fixed in Version 11.1.1.7.0 Obiee (here next year released Q1: currently his patch not published)

  Thank you
  Deva

• Error with BIEE11.1.1.5 Parent-child hierarchies

  Hello
  
  I use BIEE11.1.1.5, I created a logic Dimensions with Parent-child hierarchies.
  
  In response, I move named 'H5 Sales Rep' hierarchies, and then display the results,
  
  There error, the following error message:
  
  ODBC driver returned an error (SQLExecDirectW).
  Error details
  Error codes: OPR4ONWY:U9IM8TAC:OI2DL65P
  State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error occurred. [nQSError: 43113] The message returned by OBIS. [nQSError: 43119] Query Failed: [nQSError: 22056] to use the line functions, you must associate a Table close Source logical Table "LTS1 Sales Rep. (HY000)
  Publ. SQL: SELECT 0 s_0, "Sample Sales". "" Sales Rep ". "" Sales Rep Name ' s_1, CASE WHEN ISLEAF ("Sample Sales" "." ") Sales Rep. ("' H5 Sales Rep") THEN 1 ELSE 0 END s_2, IDOF ("Sample Sales" "." ") Sales Rep. ("' S_3 H5 Sales Rep"), PARENT ("" Sample Sales "". "") Sales Rep. ("' S_4 H5 Sales Rep") OF "Sample Sales" WHERE ISROOT ("" Sample Sales "". "") Sales Rep. ("' H5 sales representative")
  
  someone knows why?
  Thank you!

  Hi Leo,

  You have configured table of closing? http://www.rittmanmead.com/2010/11/Oracle-BI-EE-11g-parent-child-hierarchies-multiple-modeling-methods/

  Also, be sure to make the changes to hierarchy in offline mode.

  Kind regards
  DpKa

• Parent-child dimension

  Hello
  
  I try to use Essbase Studio to build dimension with the source table already has the parent-child structure, how do I specify parent-child in essbase studio?
  
  Thank you

  In your minischema, making a join between the parent and the child, and then when you create the hierarchy, just put the company name mother colum with the child column as his child

  a bit like
  Parent
  -child

  then get an overview of the hierarchy, and you should see that it takes up the structure. If you don't do the join and save it, then the preview will look funny

• Add an object 3d without parent/child relationship.

  Hello

  I have a scene of 3d picture control, I have two objects in there, but when I created the scene I had to use the add object invoke node objects in the scene, so there is a parent/child relationship between the objects, which means that if I move the parent, I also move the child object. Is there a way to create a scene with several objects without the parent/child relationship.

  Thank you.

  -Luis

  Hello, I solved it by first moving the objects and then adding them to the scene. -Luis

• Blockages with parent/child tables

  Guys,

  We have a parent-child of tables in our database with the DDL below:

  CREATE TABLE 'ACCOUNT '.

  (SELECT 'ACCOUNT_ID' VARCHAR2 (32 BYTE) NOT NULL,)

  X, Y, Z,...),

  'XPK_ACCOUNT' CONSTRAINT PRIMARY KEY ('ACCOUNT_ID');

  CREATE TABLE ACCOUNT_PARTITION ".

  (SELECT 'ACCOUNT_ID' VARCHAR2 (32 BYTE) ENABLE NOT NULL, "BALANCE" NUMBER (5.0) NOT NULL,)

  X, Y, Z,...),

  'XPK_ACCOUNT_PARTITION' CONSTRAINT PRIMARY KEY ('ID_COMPTE', 'BALANCE')

  KEY FOREIGN CONSTRAINT 'ACCOUNT_PARTITION_FK1' ('ACCOUNT_ID')

  SELECT THE 'ACCOUNT' ('ACCOUNT_ID') REFERENCES);

  "Lately, we cross " ""ORA-00060: Deadlock detected while you wait for resources ' errors while DELETING in the tables above. Please note that the tables of the child is not any clue except KP index.

  
  

  Could someone please suggest resolution for us to minimize the error of blocking?

  
  

  Respect,

  Bugs

  Imagine you remove account, Oracle must verify there is no record of the child in ACCOUNT_PARTITION, this is because as your FK is restrict the deletions (do not allow the removal if there are child records).  As ACCOUNT_PARTITION. Account_id is indexed so it will be an exclusive table lock to find this, locks the table.

  Another way of thinking is, imagine that you have performed the following query without and ACCOUNT_ID index:

  Select *.

  of ACCOUNT_PARTITION

  where ACCOUNT_ID =

  He SHOULD do a full table scan right?  Well well, even on a deletion of the parent. It attempts to identify lines for the purpose of blocking,

  As a general rule, it is always a good idea to index FKs.

• Parent - child relationship constraint Unique 5.0 apex oracle

  Oky so I will try to avoid duplicate values get inserted in the parent-child node.

  So basically when there's a node parent (Mobile) I can't create same node with the same name.

  Even for the child node, if there is a child node name there may be another named A.

  Structure:

  Mobile (parent) /Android (Child) /KitKat (subchild) (allowed)

  Mobile/apple/ios(Now allowed Same Parent name)

  Win7/Windows/win7(not allowed same child)

  So a big child and the parent must be unique at any time.

  

  create an index of single "TEST_UK" on tablename (parent_id, upper (child_name));

  see this too for a case-insensitive unique constraint

  Case-insensitive unique constraint

• Oracle query convert recursive parent-child level columns

  Dear gurus,

  I have a Hyperion extracted dimension table with my COA in a parent/child layout:

  parent, child

  Acc01, acc001

  acc001, acc0001 etc.

  I need to convert to the:

  level 2, level 1, Level0

  Acc01, acc001, acc0001 etc.

  Please advise, need to feed table table schema for reporting.

  Concerning

  Yannis

  with

  data in the form of

  (select "C01" parent, child 'C001' Union double all the)

  Select 'C001', 'C0001' from dual union all

  Select 'C001', 'C0002"dual union all

  Select "C01", "C002' from dual union all

  Select "C0001', 'C00001' from dual union all

  Select "C00001', 'C000001' from dual union all

  Select 'C000001', 'C0000001' from dual

  )

  Select leve1_1, level_2, level_3, level_4, level_5, level_6

  from (select root0, lvl0, regexp_substr(path,'[^,]+',1,level) VAC, level lvl

  of (lvl0 level select,

  connect_by_root parent root0,

  parent connect_by_root | path of SYS_CONNECT_BY_PATH (Child, ',')

  from the data

  where connect_by_isleaf = 1

  Start with parent (select parent

  data d

  If not exists (select null

  from the data

  where child = d.parent

  )

  )

  connect by prior child = parent

  )

  connect by level<=>

  and prior root0 = root0

  and prior lvl0 = lvl0

  and prior sys_guid() is not null

  )

  Pivot (max (VAC) for lvl 1 as leve1_1, 2 level_2, 3 level_3, 4 level_4, 5 level_5, 6 level_6)

  LEVE1_1	LEVEL_2	LEVEL_3	LEVEL_4	LEVEL_5	LEVEL_6
  C01	C002	-	-	-	-
  C01	C001	C0002	-	-	-
  C01	C001	C0001	C00001	C000001	C0000001

  Concerning

  Etbin

• ADF Parent-child tables of rules

  Hello

  I use JDeveloper and ADF 12.1.3. Now, I have a set of related tables, and each of them have only a child table.

  I have a jsf page master / detail for each child table. Inside it, I can insert a row in the parent table and several rows in the child table. Commit the button is clicked validate monkey for the booth tables. Link between the master (parent table) and retail (child table) is done via the partnership link and view for the user interface.

  Now, here's the rule I would apply: I can't commit newly created at the table parent without at least a new inserted row in child table.

  Because I have several parent-child tables in this case of use, I wanted to replace the EntityImpl class and add newly created to each parent table class, so I bussines logic in one place for this tables.

  We will look and taste to the table of one of the parents (not overloaded class EntityImpl):

  The Interior has generated parent EO class

  @Override

  {} public void beforeCommit (TransactionEvent transactionEvent)

  TODO implement this method

  If (! validateParentChildNumber()) {}

  throw new local ("not allowed.");

  }

  super.beforeCommit (transactionEvent);

  }

  public boolean validateParentChildNumber() {}

  If (getParentChild (). GetRowCount() > 0)

  Returns true;

  on the other

  Returns false;

  }

  This works well. If I inserts a row in the parent table and one or more rows in the child table passes validation. But if I get a line inside the parent table and no line of children tables I'm not allowed message in my browser.

  So here's where problem read. Once I'm getting now authorized message, no matter if I insert the new line of Herald, I cannot commit until what I restar my app. Why? Because now, I constantly have this message:

  ORA-02291: integrity constraint (RE. FK_PAR_PAR_ID) violated - key parent not found

  It's like I can't hire the existing parent row I inserted before the child missing line. Why is this happening? I should replace postChanges method and what to put in it?

  Thx a lot

  Yes, you should do it in all cases, but point of my post is - put this code in the method of beforeCommit() of the primary entity. Only you need to do in beforeCommit(), is to count the child related entities.

  In your java master entity impl class, you will have the method which returns a RowIterator with associated children, entities, something like that

  public getChildsEO() {} RowIterator

  return (RowIterator)...;

  }

  then, just call this method in beforeCommit() and see if there is at least a child entity...

  You have a point?

• parent/child relationship hirarchy

  Hi everyone, consider the sample data

  SELECT LFROM '1TR1Y6', NULL LTO, MID '11ZFDD', '21XHK7' double UNION ALL TID-

  SELECT '1TR1YF' LFROM, LTO NULL, '11ZFDD' MI '21XHK5' TID FROM dual UNION ALL-

  SELECT '1TR1X1' LFROM, LTO NULL, '11ZFDD' MI '21XHK8' TID FROM dual UNION ALL-

  SELECT '1LSZX1' LFROM, LTO NULL, '11ZFDD' MI '1TR1YD' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZWQ", "21XHK7" LTO, MID '11ZFDD', '1TR1Y6' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZX2", "21XHK5" LTO, MID '11ZFDD', '1TR1YF' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZVG", "21XHK8" LTO, MID '11ZFDD', '1TR1X1' TID FROM dual UNION ALL-

  SELECT LFROM "4LSSVG", "21XHK9" LTO "11AAA' MI '1TR1X1' TID double UNION ALL

  SELECT "AAAAA" LFROM, LTO NULL, '11ABB' e, 'CCCCCC' double UNION ALL TID

  SELECT "BATH" LFROM, 'CCCCCC' LTO, MID '11ABB', 'AAAAA' double UNION ALL TID

  some of them have a parent/child releationship. for example, let take rank with LFROM = 1TR1Y6

  1TR1Y6 (lfrom) corresponds to the fifth line with TID 1TR1Y6.  TID 1TR1Y6 LTO COLUMN value corresponds to the first line TID (21XHK7)

  It before these two LINES are IN a parent/child relationship.

  lets take another example.  LINE two WITH LFROM = 1TR1YF matches sixth RANK WITH TID 1TR1YF.  the sixth LINE LTO COLUMN (21XHK5) corresponds to the SECOND TID of LINE.

  Once again the parent child relationship. There are two lines that do not have the relationship of parent/child (ex.  line 8)

  Im trying to write a query that can partition the data in the middle column and find the parent/child relationship. the output of the above data should be

  LTO LFROM MIDDLE TID FLAG

  1TR1Y6 NULL 11ZFDD 21XHK7 1

  1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1

  1TR1YF NULL 11ZFDD 21XHK5 1

  1LSZX2 21XHK5 11ZFDD 1TR1YF 1

  1TR1X1 NULL 11ZFDD 21XHK8 1

  1LSZVG 21XHK8 11ZFDD 1TR1X1 1

  1LSZX1 NULL 11ZFDD 1TR1YD 0

  4LSSVG 21XHK9 11AAA 1TR1X1 0

  ABDELKÉBIR 11ABB CCCCCC NULL 1

  CCCCCC 11ABB AAAAA BATH 1

  For simplicity, I posted the release with parent/child, side by side in the sequence.  the order does not matter as long as the flag column (pull the column) is set to an appropriate value (1 if parent/child, 0 no parent/child)

  the flag column value is derived from column to indicate the parent/child relationship was found.

  I try using lead, the lag function but I have problem of sorting data from parent and child line could come at random order (they are not side by side).

  It is therefore difficult to use lead because you don't know how many lines to carry forward.

  can someone help me write a query that displays the output above

  SELECT T1. LFROM,

  T1. LTO,

  T1. ENVIRONMENT,

  T1. TID,

  (

  SELECT COUNT (*)

  OF TBL T2

  WHERE)

  T2. TID = T1. LFROM

  OR

  T2. LFROM = T1. TID

  )

  AND T2. MI = T1. MID

  ) FLAG

  OF TBL T1

  /

  LTO LFROM MIDDLE TID FLAG
  ------ ------ ------ ------ ----------
  1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1
  1LSZX2 21XHK5 11ZFDD 1TR1YF 1
  1LSZVG 21XHK8 11ZFDD 1TR1X1 1
  CCCCCC 11ABB AAAAA BATH 1
  1TR1X1 11ZFDD 21XHK8 1
  1TR1X1 11ZFDD 21XHK8 1
  1LSZX1 11ZFDD 1TR1YD 0
  1TR1Y6 11ZFDD 21XHK7 1
  ABDELKÉBIR 11ABB CCCCCC 1
  1TR1YF 11ZFDD 21XHK5 1
  4LSSVG 21XHK9 11AAA 1TR1X1 0

  11 selected lines.

  SQL >

  SY.

• Default filters that users can delete (in the parent/child Setup)?

  Is it possible in Latitude 2.2.2 to have filters (filters of the range, refinement filters etc.) applied by default (which means that users see these filters when they log-in), but they can also remove (using bread crumbs portlet) if they wanted to? We tried to use the source of data (JSON) filters (using 'baseFunctions' setting) where we have a parent/child Setup, but it seems these filters cannot be removed once applied. Note that filters can be removed if we do not have a parent/child relationship between the data sources, but as soon as we introduce a parent/child relationship between the data sources (which we need), the GET of sticky filters and cannot be deleted. Any reason why the parent/child relationship causes the filters becoming sticky? Any way (alternate) to reach what we want?

  I think that it is a known problem (LSTUDIO-5088) and there could be a fix for this. You can contact technical support to obtain the fix.

  Dave

• Fusion of data/result defines what are parent/child?

  Hello:
  
  I have seen a few examples to make a data model so that a BI report can have master-detail data. They are a set of Q1 data and a set of T2 data with a variable binding to connect the two in a parent/child relationship.
  
  But what I need, it is actually a UNION. I have the same table on multiple instances of database and I want to show the results grouped in a single report, as if it all happened to a table. Examples of master-detail have a section defining the grouping but they group Q1 (see here)
  
  http://blogs.Oracle.com/BIDeveloper/data_template/
  
  and I need to regroup in a column in Q1 and Q2 to "merge" the two sets of data.
  
  Does anyone do this?
  
  Thank you.

  If you define multiple SQL-queries/data models data sets, you can combine them into a single set of data by selecting the concatenated SQL Data Source.

  Choose concatenate them box, concatenation will result in the union.

  RTF again, you can use the two dataset and display as a single table.

• SmartView display parent.child members

  When using smartview, how can I do so that it displays only the name of base instead of parent.child member?

  The short answer is you can't. Financial reports has the ability to do it, but if you do a dynamic exercise against HFM, it cannot be changed.

  You can always make a formula that requires no parent.child format.