How do good group when the join of two tables?

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• How it warns Oracle to use an index for the join of two tables...

  How to prevent the Oracle to use an index for the join of two tables to get a view online that is used in an update statement?
  
  O.K. I think I should explain what I mean:
  
  When you join two tables that have many entries sometimes there're better is not to use an index on the column that is used as a criterion to join.
  
  I have two tables: table A and table B.
  
  Table A has 4,000,000 entries and table B has 700,000 entries.
  
  I have a join of two tables with a numeric column as join criteria.
  
  There is an index on this column in A table.
  
  So I instead of
  

    where (A.col = B.col)

  I want to use
  

    where (A.col+0 = B.col)

  in order to avoid Oracle using the index.
  
  When I use the join in a select query, it works.
  
  But when I use the join as inline in an update statement I get the error ORA-01779.
  
  When I remove the '+ 0' the update statement works. (The column is unique in table B).
  
  Any ideas why this happens?
  
  Thank you very much in advance for any help.
  
  Hartmut cordially

  You plan to use a NO_INDEX hint as shown here: http://www.psoug.org/reference/hints.html

• help the join of two tables

  Hello
  
  I need your help in the script below:
  
  I have two tables.
  
  My "table1" table contains the data below:
  
  Code:
  
  Name, Value
  ------------
  12 A, 1
  12 B, 1
  12 C, 1
  
  
  
  Table2 contains the following data:
  
  Code:
  
  value, result
  ------------
  1.12
  1.24
  1.56
  1 423
  1.32
  1, 3
  
  
  
  
  I need to join based on a field value.
  
  My result is:
  
  Code:
  
  
  NAME, VALUE, RESULT
  -------------------------
  12 A, 1, 12
  12 B, 1: 24
  12 C, 1, 56
  12d, 1, 423
  12TH, 1, 32
  12F, 1, 3
  
  
  
  
  
  Based on the number of records in the second table, it must add A to Z at the end of the name field. The number of records exceeds no more than 26. How can we achieve this?
  
  
  _________________
  
  Thank you
  Pocard

  OK, now you give other useful information - that there always will be combinations of amounts in table2 to match values in table1. (It is difficult to help when you say the specs one both :-))

  But it is not easy, because the code should really try to consider all combinations and then 'choose the right' - it's easy for us humans, but not easy to code in the programming logic.
  I made an attempt:

  SQL> set linesize 120
  SQL> with table1 as (
    2     select 'A1' name, 123 id, 150 value from dual union all
    3     select 'A2' name, 123 id, 200 value from dual union all
    4     select 'A3' name, 123 id, 300 value from dual
    5  ), table2 as (
    6     select 123 id, 100 value from dual union all
    7     select 123 id, 100 value from dual union all
    8     select 123 id, 50  value from dual union all
    9     select 123 id, 100 value from dual union all
   10     select 123 id, 100 value from dual union all
   11     select 123 id, 100 value from dual union all
   12     select 123 id, 100 value from dual
   13  )
   14  --
   15  -- End of test data
   16  --
   17  select
   18  t1.id, t1.name, t1.value, t2.value,
   19  t1.rn, t1.minval, t1.maxval,
   20  t2.rn, t2.sumval
   21  from (
   22     select
   23     tab1.*,
   24     nvl(sum(tab1.value) over (
   25        partition by tab1.id
   26        order by tab1.rn
   27        rows between unbounded preceding and 1 preceding
   28     ),0) minval,
   29     sum(tab1.value) over (
   30        partition by tab1.id
   31        order by tab1.rn
   32        rows between unbounded preceding and current row
   33     ) maxval
   34     from (
   35        select
   36        table1.*,
   37        row_number() over (
   38           partition by table1.id
   39           order by table1.value desc
   40        ) rn
   41        from table1
   42     ) tab1
   43  ) t1
   44  join (
   45     select
   46     tab2.*,
   47     sum(tab2.value) over (
   48        partition by tab2.id
   49        order by tab2.rn
   50     ) sumval
   51     from (
   52        select
   53        table2.*,
   54        row_number() over (
   55           partition by table2.id
   56           order by table2.value desc
   57        ) rn
   58        from table2
   59     ) tab2
   60  ) t2
   61  on (t2.id = t1.id)
   62  where t2.sumval > t1.minval
   63  and t2.sumval <= t1.maxval
   64  order by
   65  t1.id,
   66  t1.rn,
   67  t2.rn
   68  ;
  
          ID NA      VALUE      VALUE         RN     MINVAL     MAXVAL         RN     SUMVAL
  ---------- -- ---------- ---------- ---------- ---------- ---------- ---------- ----------
         123 A3        300        100          1          0        300          1        100
         123 A3        300        100          1          0        300          2        200
         123 A3        300        100          1          0        300          3        300
         123 A2        200        100          2        300        500          4        400
         123 A2        200        100          2        300        500          5        500
         123 A1        150        100          3        500        650          6        600
         123 A1        150         50          3        500        650          7        650
  
  7 rows selected.
  

  It doesn't seem to work for your sample data, but it is much too simple a rule at work in general. My "rule" is simply of sorts data according to the value descending and adding up to what 'enough' of values have been added.

  Consider this example of data instead of this:

  SQL> with table1 as (
    2     select 'A1' name, 1 id, 100 value from dual union all
    3     select 'A2' name, 1 id, 200 value from dual union all
    4     select 'A3' name, 1 id, 300 value from dual union all
    5     select 'B1' name, 2 id, 100 value from dual union all
    6     select 'B2' name, 2 id, 200 value from dual
    7  ), table2 as (
    8     select 1 id, 25  value from dual union all
    9     select 1 id, 75  value from dual union all
   10     select 1 id, 50  value from dual union all
   11     select 1 id, 50  value from dual union all
   12     select 1 id, 175 value from dual union all
   13     select 1 id, 225 value from dual union all
   14     select 2 id, 25  value from dual union all
   15     select 2 id, 50  value from dual union all
   16     select 2 id, 75  value from dual union all
   17     select 2 id, 100 value from dual union all
   18     select 2 id, 50  value from dual
   19  )
   20  --
   21  -- End of test data
   22  --
   23  select
   24  t1.id, t1.name, t1.value, t2.value,
   25  t1.rn, t1.minval, t1.maxval,
   26  t2.rn, t2.sumval
   27  from (
   28     select
   29     tab1.*,
   30     nvl(sum(tab1.value) over (
   31        partition by tab1.id
   32        order by tab1.rn
   33        rows between unbounded preceding and 1 preceding
   34     ),0) minval,
   35     sum(tab1.value) over (
   36        partition by tab1.id
   37        order by tab1.rn
   38        rows between unbounded preceding and current row
   39     ) maxval
   40     from (
   41        select
   42        table1.*,
   43        row_number() over (
   44           partition by table1.id
   45           order by table1.value desc
   46        ) rn
   47        from table1
   48     ) tab1
   49  ) t1
   50  join (
   51     select
   52     tab2.*,
   53     sum(tab2.value) over (
   54        partition by tab2.id
   55        order by tab2.rn
   56     ) sumval
   57     from (
   58        select
   59        table2.*,
   60        row_number() over (
   61           partition by table2.id
   62           order by table2.value desc
   63        ) rn
   64        from table2
   65     ) tab2
   66  ) t2
   67  on (t2.id = t1.id)
   68  where t2.sumval > t1.minval
   69  and t2.sumval <= t1.maxval
   70  order by
   71  t1.id,
   72  t1.rn,
   73  t2.rn
   74  ;
  
          ID NA      VALUE      VALUE         RN     MINVAL     MAXVAL         RN     SUMVAL
  ---------- -- ---------- ---------- ---------- ---------- ---------- ---------- ----------
           1 A3        300        225          1          0        300          1        225
           1 A2        200        175          2        300        500          2        400
           1 A2        200         75          2        300        500          3        475
           1 A1        100         50          3        500        600          4        525
           1 A1        100         50          3        500        600          5        575
           1 A1        100         25          3        500        600          6        600
           2 B2        200        100          1          0        200          1        100
           2 B2        200         75          1          0        200          2        175
           2 B1        100         50          2        200        300          3        225
           2 B1        100         50          2        200        300          4        275
           2 B1        100         25          2        200        300          5        300
  
  11 rows selected.
  

  In this data set simple ranking by value won't work - it should have been A3: (225,75), A2: (175,25) and A1: (50.50).

  I can't really think of a reasonably easy way to do this in SQL only. Maybe using the clause TYPE would be possible, but not negligible. It is possible, it would be easier to solve this problem in PL/SQL in iterating through a few tables and intelligently to try different combinations, rather than creating all combinations in a huge piece of brute force SQL.

  I'm sorry, Pandeesh, but I can't think a solution easily.
  I might be able to do something, if I fiddled with the problem for a few days, but that would be beyond the scope of this forum. It would be a consultation of employment rather than a little help from the forum :-)

• Delete rows in a table when the columns from two tables match

  Hello

  I have following two tables.

  ===========================================

  create the table empbooth as

  (

  Select 1 empid, 1 double cabin Union all the

  Select option 2, Union 1 double all the

  Select 3, Union 1 double all the

  Select option 4, Union 2 double all the

  Select option 5, 2 double

  );

  create the table attsht as

  (

  Select 1 empid, 240 reg, 0 unpaid all double union

  Select option 2, reg 200, 0 unpaid of all the double union

  Select 3, 240 reg, 0 unpaid all double them union

  Select 4 480 reg, 0 unpaid all double union

  Select 5 240 reg, unpaid double 0

  );

  =================================================

  I want to remove rows from attsht where corresponding booth (which is stored in the empbooth table) is 1.

  The condition is 'where attsht.empid = empbooth.empid and empbooth.booth = 1 '.

  I use oracle 10g.

  Help, please

  delete from attsht where a.empid in (select b.empid from empbooth b where b.booth = 1)

  or

  remove from attsht a

  where exists (select null

  of empbooth b

  where b.booth = 1

  and b.empid = a.empid)

• How will I know when the synchronization is complete?

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  I paired a device (smart phone Samsung) - it worked good 10 minutes, yet on my phone says sync is complete, but any of the bookmarks do not appear on my computer 'main '.

  Hello.

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• How will I know when the capsules are on?

  Original title: caps Inspiron 1545?

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• How can I detect when the last container in my stream is full?

  I have a bunch of related containers which I am flowing text through. How can I detect when the text has filled a container? There's an overflowPolicy then I guess it can be detected.

  Hello

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  {

  var zeComposer:IFlowComposer = textFlow.flowComposer;

  var iTextLen:int = textFlow.textLength;

  var iNoController:int = zeComposer.findControllerIndexAtPosition (iTextLen - 1);

  return (iNoController is-1);

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• problem with join of two tables

  Hi, consider the following data

  WITH data AS
  (
    SELECT 123 cid, 'aaa' isi, 'kkk' sud, 'ttt' ri FROM dual UNION ALL 
    SELECT 222 cid, 'bbb' isi, 'gggg' sud, 'hhh' ri FROM dual
  
  ) ,
  data2 AS 
  (
    SELECT 'aaa' isi, 'yyy' sud, 'ooo' ri FROM dual UNION ALL 
    SELECT 'qqq' isi, 'ggg' sud, 'ooo' ri FROM dual UNION ALL 
    SELECT 'uuu' isi, 'ppp' sud, 'ttt' ri FROM dual UNION ALL
     SELECT 'ppp' isi, 'mmm' sud, 'nnn' ri FROM dual 
  
  
  )

  what I want to do, is to join data2 with data by isi, ri or southern id table and produce this output.
  

   cid  txt
   ===  ====
   123  aaa
   222  ggg
   123  ttt

  It's how I got the above output:
  first try to join isi in database2 with isi in "features" and discover if line matches. If this is the case, display the cid of the data table and the use of the value to match.
  e.g. in the first line of table data2, we can see that isi = aaa matches line an isi data table. If the output displays 123 and value aaa.
  
  If the rank table two of the Data2 isi = qqq. When join them with the data table, we find not all isi with qqq. in this case, it must join with column of South. We can see that South = ggg data2 games
  the second line in the table of output so will bee 222 and value ggg.
  
  now, take a look at the third row in Database2. ISI = uuu is not found in the data table when join them. then try to join to the South. South = ttt is also not found in any row of the data table. so join with ri. We
  can see that ri = ttt data2 matches with ri = ttt in the table of data online 1. Therefore, we display the value.
  
  can someone help me write a sql query that joins these two tables by isi. If no line found then join South, if no found rows then join in ri? Thank you

  Hello

  elmasduro wrote:
  Hi Frank, data2.sud = 'Gay' (4 characters) assume to be South = "ggg". by mistake, I type extra g.

  I have another question about the request. What happens if I want to bring rows of data.2 even if they do not exist in the data table for the entire column was join?
  for example, I want to show this:

  cid  txt
  ===  ====
  123  aaa
  222  ggg
  123  ttt
  ppp  --row from data2
  

  the columns of the last row of data.2 does not match any column in the data table. in this case, I want to make but cid will be null. I tried outer join on your request, but it looks like I can not clause or with outer join

  SELECT     d1.cid
  ,     CASE
            WHEN  d1.isi = d2.isi  THEN  d2.isi
            WHEN  d1.sud = d2.sud  THEN  d2.sud
                                          ELSE  d2.ri
       END     AS txt
  FROM data     d1
  JOIN     data2     d2  ON     d1.is(+)i     = d2.isi
                OR     d1.sud(+)     = d2.sud
                OR     d1.ri(+)     = d2.ri
  ;
  

  How can I re - write the query for this case? Thanks again for your help

  Here is the outer join syntax:

  SELECT     d1.cid
  ,     CASE
            WHEN  d1.isi = d2.isi  THEN  d2.isi
            WHEN  d1.sud = d2.sud  THEN  d2.sud
            WHEN  d1.ri  = d2.ri   THEN  d2.ri
                                          ELSE  d2.isi
       END     AS txt
  FROM          data2     d2
  LEFT OUTER JOIN     data     d1  ON     d1.isi     = d2.isi
                         OR     d1.sud     = d2.sud
                         OR     d1.ri     = d2.ri
  ;
  

  The + sign for outer joins only works with the old join syntax, non-ANSI. Do not try to mix the two different ways to do joins.

  Not to mention that the outer join, don't forget to change the CASE expression, to include the new possibility of any columns 3 join matching.

• Join of two tables in two different schemas

  Hi all
  
  I have an obligation to join two tables on two different schemas. How to join these two tables in the object view.
  
  Thanks in advance.
  
  Concerning
  Kaushik Guillaumin

  You can do just that using schema name in the +' view object.table name ' + according to the query object and also grant select the another schema to this schema user

  ex
  you need schem is test and another Act you need to a view object based on the test to join a table on shcema Act

  you write semply object sql view code:

  Act.table name

  and you can also give him select statement on Bill schem table to test

  concerning

• display the data in two tables.

  Hi considers the following data

  WITH table1 AS
  (
    SELECT 111 userid,  To_Date('7/31/2010','mm/dd/yyyy') dt  FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/1/2010','mm/dd/yyyy') dt  FROM dual UNION all
    SELECT 111 userid,  To_Date('8/2/2010','mm/dd/yyyy') dt FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/3/2010','mm/dd/yyyy') dt  FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/4/2010','mm/dd/yyyy') dt FROM dual UNION ALL
    SELECT 111 userid,  To_Date('8/5/2010','mm/dd/yyyy') dt  FROM dual UNION ALL
  
    SELECT 222 userid,  To_Date('2/28/2010','mm/dd/yyyy') dt  FROM dual UNION all
    SELECT 222 userid,  To_Date('3/5/2010','mm/dd/yyyy') dt  FROM dual UNION all
  
  ),
   mydates AS
  (
   SELECT To_Date('7/31/2010','mm/dd/yyyy') dt1, To_Date('8/4/2010','mm/dd/yyyy') dt2 FROM dual  UNION ALL 
   SELECT To_Date('2/28/2010','mm/dd/yyyy') dt1, To_Date('3/5/2010','mm/dd/yyyy') dt2 FROM dual 
  )

  I want to join these two tables and result the following
  

  DT        DT2
  7/31/2010 8/04/2010
  8/01/2010  8/01/2010
  8/02/2010  8/02/2010
  8/03/2010  8/03/2010
  8/04/2010  8/04/2010
  8/05/2010  8/05/2010
  
  2/28/2010  3/5/2010
  3/5/2010   3/5/2010

  Basically, I join two tables, take dt from table1 and look into mydates. If the data match then display dt and DM2.
  If the date in table1 does not match date in t1d in mydates, then display the data but dt and DM2 there same date.
  
  for example,.
  
  7/31 in table1 is 7/31 in mydates so I show 7/31 dt and DM2 as 8/4(from mydates).
  now 8/01 does not match all lines in my dates so dt should be 8/01 and T2D should be 8/01. same logic applies to the other lines
  
  can someone write a query that gives the above result? Thank you

  Hello

  If you want all lines of table1 (attached to mydates when this is possible, but even when there is no match) then use an outer join:

  SELECT     t.dt
  ,     NVL (m.dt2, t.dt)     AS dt2
  FROM          table1     t
  LEFT OUTER JOIN     mydates     m     ON     t.dt     = m.dt1
  ORDER BY     t.dt
  ;
  

• Kindly help me with the request to find the data in two tables

  Hello Guru
  
  Kindly help me to recover the data from two tables-
  
  BASEBALL
  LEGAL_ENT_ID (PK)
  GAME_ID (FK)
  LEGAL_ENT_NM
  INACTIVE_DT
  DATE OF INS_TS
  INS_LOGIN
  DATE OF UPD_TS
  UPD_LOGIN
  
  
  FOOTBALL
  GAME_ID (PK)
  BRKR_NM,
  BRKR_ISR_ID
  BROKER_SYMBOL
  INACTIVE_DT
  BRKR_SWIFT_FLG
  BRKR_INTERNAL_FLG
  BRKR_CATEGORY
  UPD_TS
  MINORITY_FLG
  BROKER_TYP
  STATUS
  INS_TS
  INS_LOGIN
  UPD_LOGIN
  APP_USER
  ACTIVE_FLG
  
  and if I want fecth data from these two tables according to the following condition then it is fine with the suite of applications.
  
  1 select distinct values only table of BASEBALL by using the following query.
  
  SELECT DISTINCT B.GAME_ID as 'CLEARING GAME ID', B.BRKR_NM "NAME of THE GAME of COMPENSATION" OF BASEBALL A, FOOTBALL B WHERE A.BROKER_RELATION_CD IN ('FUTBRKR1', 'FUTBRKR2') AND A.GAME_ID = B.GAME_ID
  
  2 Select all the table BRKR_NM OF FOOTBALL as well by using the query - next
  
  SELECT GAME_ID "RUNNING GAME ID", 'NAME OF THE GAME OF EXECUTION' BRKR_NM SOCCER
  
  Now, my query is that--
  
  I want a query that gives me a combination of above mentioned queries... and if I tried to use Union or Union All, then she is not giving me the result as expected.
  
  I like the result to look like who has a few conditions such as -
  1 - the records in the table Football are high vs Baseball table because there is no condition to filter the records of the Football.
  2 - football is a superset of records and Baseball is a subset.
  3 - COMPENSATION NOM_JEU and RUNNING NOM_JEU may return the same values as well.
  
  I want the result to be in the following form-
  
  EXECUTION ID GAME | NAME OF THE GAME TO RUN. COMPENSATION ID GAME | DELETE THE NAME OF THE GAME.
  2123 test1 2345 test5
  2456 test10 2456 test10
  
  
  Thanks in advance. Kindly help me.
  
  Published by: user555994 on January 4, 2011 23:48

  In the output you want.
  All the values of baseball;
  Values of football that are matched;
  But on what condition you want to match?

• Freeze frame disappears when the join clips

  I have iMovie 10.1 on my new iMAC.    I have a video playing a few seconds of game my son lax.   Then I divide and added a stop on image - to stop the action for 2 seconds (I am also a PIP for him put an arrow).    Then I left the second clip continue.

  I'm trying 2 necklaces... so that it becomes a clip with the still image in the middle... but it won't work.    The still picture always disappears.      Any thoughts on how to stick around?

  I'm not quite clear why you want to join the clips.  They will be joined when you share the movie.

  The join function only to cancel a split of the previous.

  Geoff.

• How controls are grouped in the front pannel "write basic series and Read.vi.

  I wonder how the controls are grouped on the front. An example is the "basic series write and Read.vi. The rocker of Scripture and the 'rope to wirte' are grouped in a raised area. I couldn't move individual out of this box control when I tried to arrange the controls. How they are grouped and how do I move them individually?

  Thank you.

  

  Select the Group of controls you want to Group/Ungroup and select the option group/ungroup as shown above.no wonder in this