how she did it? "Pointing out every line of a paragraph.

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  Hello
  
  I have the following simple query:
  

  select empno,
         ename,
         sal,
         sum(case
               when rn = 1 then sal
               else -sal
             end) over (order by sal, empno) as running_diff
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       EMPNO ENAME             SAL RUNNING_DIFF
  ---------- ---------- ---------- ------------
        7934 MILLER           1300         1300
        7782 CLARK            2450        -1150
        7839 KING             5000        -6150

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  select a.empno,
         a.ename,
         a.sal,
         (select case
                   when a.empno = min(b.empno) then sum(b.sal)
                   else sum(-b.sal)
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    from emp a
   where a.deptno = 10;

  but the result is
  

       EMPNO ENAME             SAL RUNNING_DIFF
  ---------- ---------- ---------- ------------
        7782 CLARK            2450         2450
        7839 KING             5000        -7450
        7934 MILLER           1300        -8750

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  Rephrase the question above:
  
  Is it possible, using plain vanilla SQL (which is the aggregate functions and operations such as joins and unions) to create a query that produces the same result as the first?
  
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  Thank you for your help,
  
  John.
  
  Published by: 440bx - 11 GR 2 on July 18, 2010 12:50 AM - correct ' ho w "to"how ".
  
  Published by: 440bx - 11 GR 2 on July 18, 2010 01:42 - struck all references to row_number and windowing being features of Oracle functions.
  
  Published by: 440bx - 11 GR 2 on July 18, 2010 03:51 - pointed out that my essay is terribly wrong and it had reaffirmed the goal to make it clearer.

  Hi, John,.

  A way to get a total operating (which is essentially what you want) must make a self-join. Join each line (let's call it the current line, or c) for himself and everything that preceded it (call this the previous line or p), and do a regular lump SUM, like this:

  WITH     got_base_sal     AS
  (
       SELECT       deptno
       ,       2 * MIN (sal)     AS base_sal
       FROM       scott.emp
       GROUP BY  deptno
  )
  SELECT       c.deptno
  ,       c.empno
  ,       c.ename
  ,       c.sal
  ,       b.base_sal - SUM (p.sal)     AS running_diff
  FROM       scott.emp     c
  JOIN       scott.emp     p     ON     c.deptno     = p.deptno
                      AND     (     c.sal     > p.sal
                           OR     (     c.sal     =  p.sal
                                AND     c.empno     >= p.empno
                                )
                           )
  JOIN       got_base_sal     b     ON     c.deptno     = b.deptno
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  GROUP BY  c.deptno
  ,       c.empno
  ,       c.ename
  ,       c.sal
  ,       b.base_sal
  ORDER BY  c.deptno
  ,       running_diff     DESC
  ;
  

  Output:

      DEPTNO      EMPNO ENAME             SAL RUNNING_DIFF
  ---------- ---------- ---------- ---------- ------------
          10       7934 MILLER           1300         1300
          10       7782 CLARK            2450        -1150
          10       7839 KING             5000        -6150
  

  I said you basically want a total runninng. There are two differences between a cumulative and your needs
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  You don't say what you want to do in the case of a tie (two or more lines having the same sal). The above query uses empno as a tiebreaker, so all sals are calculated as if they were separate. This is similar to what the analytical functions do when the window comes from the ranks. If you want something similar to windowing by scope, which could actually be simpler.

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  You can also get these results by using a WITH recursive clause. Which meets the criteria to avoid analytical functions and features specific to Oracle, but not on the use of the only clear and simple SQL features.

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