How to calculate an average for each quarter in a year

Similar Questions

• Many storage spaces and data for each quarter of the year files

  Hello

  I am junior DBA and I have a question about tablespace partitioning or data file sharing.

  I have a database of 10g in many storage spaces, for example:

  KER_DATA_2009_Q1

  KER_DATA_2009_Q2

  KER_DATA_2009_Q3

  KER_DATA_2009_Q4

  KER_INDX_2009_Q1

  KER_INDX_2009_Q2

  KER_INDX_2009_Q3

  KER_INDX_2009_Q4

  There is also a data file for each tablespace that is mentioned.

  But for this year 2013, only two big storage space I can get one and data KER_DATA, KER_INDX files.

  All tables and indexes in the whole database are KER_DATA, KER_INDX, tablespaces.

  I don't know any cut in two storage spaces and means of data files. Is this something like tablespace partitioning? This can be done automatically or someone needed to do it manually on the end of each quarter?

  This should be done to improve performance, several small files data instead a large?

  Can some admin explain this to me?

  The reason for this separation of database/tablespace was partitioning. There are a lot of tables partitioned by date column, and there are partitions for each quarter of the year. There are tablespace with a data file for each quarter (partition).

• calculate an average for each record

  Hello
  
  what I want is: I have a table
  
  SCHOOLBOY (id, first_name, last_name,...)
  
  and another table
  
  BRANDS (id, schoolboy_id, discipline_id, mark, mark_type). a schoolboy
  
  on a discipline (math, for example), a schoolboy may have more points. I want to calculate the average mark, but for every schoolchild. then, for example I want to generate a report that contains the first name, the family name of the schoolboy and nearby, the average of the marks.
  How can I calculate the average of all brands for every schoolchild ?
  
  Thank you!
  
  Edited by: Roger22 06.06.2009 at 01:43

  Maybe something like:

   SELECT   first_name, last_name, b1.avg_mark
     FROM   schoolboys a1, (  SELECT   schoolboy_id, AVG (mark) avg_mark
                                FROM   marks
                                WHERE   discipline_id = 4 -- specify whatever discipline_id you want
                            GROUP BY   schoolboy_id) b1
    WHERE   a1.id = b1.schoolboy_id
   /
  

  Kind regards
  JO

  Edit: Corrected the Code tags

• average for each contragentid

  Hi all! This code works great, it returns the average value for contragentid = 1. So correct result is LUAHPER = 14996837,94
  
  But when I add the values for contragentid = 2 (see commented strings), my statement returns incorrect result LUAHPER = 5497801,81
  
  How can I improve my code in order to calculate the average for each contragentid?
  

  with t as ( 
  
  select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual 
  union all
  select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual 
  union all
  select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual 
  union all
  select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15274795.50 as luah, 215274795.50 as lusd from dual 
  union all
  select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15431807.40 as luah, 215431807.40 as lusd from dual 
  union all
  select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual 
  union all
  select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual
  
  /*union all
  select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual 
  union all
  select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual 
  union all
  select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual 
  union all
  select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215274795.50 as luah, 215274795.50 as lusd from dual 
  union all
  select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215431807.40 as luah, 215431807.40 as lusd from dual 
  union all
  select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual 
  union all
  select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual*/
  ) 
  
  select contragentid, sum(luahper) / cnt as luahper 
  from ( 
   select contragentid, (lead(arcdate,1,date '2011-03-20' + 1) over(order by arcdate) - arcdate) * luah luahper, 
  date '2011-03-20' - date '2011-03-13' + 1 cnt 
  from ( 
  select arcdate, contragentid, luah, lusd 
  from 
  
  t 
  
  where arcdate > date '2011-03-13' 
  and arcdate <= date '2011-03-20' 
  union all 
  select greatest(arcdate,date '2011-03-13'), 
  contragentid, luah, lusd 
  from 
  
  t 
  
  where arcdate = (select max(arcdate) from 
  
  t 
  
  where arcdate <= date '2011-03-13') 
  ) ) 
  where contragentid = 1
  group by contragentid, cnt

  Edited by: 858774 14/06/2011 02:29

  Hello

  858774 wrote:
  But when I add the values for contragentid = 2 (see commented strings), my statement returns incorrect result LUAHPER = 5497801,81

  I guess that's because you don't join and partition on contragentid.
  This appears to do:

  Scott@my10g SQL>/
  
  CONTRAGENTID    LUAHPER
  ------------ ----------
             1 14996837.9
  
  Scott@my10g SQL>l
    1  with t as (
    2  select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual
    3  union all
    4  select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual
    5  union all
    6  select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,14275303.54 as luah, 214275303.54 as lusd from dual
    7  union all
    8  select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15274795.50 as luah, 215274795.50 as lusd from dual
    9  union all
   10  select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15431807.40 as luah, 215431807.40 as lusd from dual
   11  union all
   12  select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual
   13  union all
   14  select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 1 as contragentid,15480730.00 as luah, 215480730 as lusd from dual
   15  --
   16  union all
   17  select to_date('12.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual
   18  union all
   19  select to_date('14.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual
   20  union all
   21  select to_date('15.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,214275303.54 as luah, 214275303.54 as lusd from dual
   22  union all
   23  select to_date('16.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215274795.50 as luah, 215274795.50 as lusd from dual
   24  union all
   25  select to_date('17.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215431807.40 as luah, 215431807.40 as lusd from dual
   26  union all
   27  select to_date('18.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual
   28  union all
   29  select to_date('21.03.2011','dd.mm.yyyy') as arcdate, 2 as contragentid,215480730 as luah, 215480730 as lusd from dual
   30  --
   31  )
   32  select contragentid, sum(luahper) / cnt as luahper
   33  from (
   34   select contragentid, (lead(arcdate,1,date '2011-03-20' + 1) over(partition by contragentid order by arcdate) - arcdate) * luah luahper,
   35  date '2011-03-20' - date '2011-03-13' + 1 cnt
   36  from (
   37  select arcdate, contragentid, luah, lusd
   38  from
   39  t
   40  where arcdate > date '2011-03-13'
   41  and arcdate <= date '2011-03-20'
   42  union all
   43  select greatest(arcdate,date '2011-03-13'),
   44  contragentid, luah, lusd
   45  from
   46  t
   47  where arcdate = (select max(arcdate) from
   48  t t2
   49  where arcdate <= date '2011-03-13'
   50  and t.contragentid=t2.contragentid)
   51  ) )
   52  where contragentid = 1
   53* group by contragentid, cnt
  Scott@my10g SQL>/
  
  CONTRAGENTID    LUAHPER
  ------------ ----------
             1 14996837.9
  

  858774 wrote: How can I improve my code in order to calculate the average for each contragentid?

  When I remove the 'where contragentid = 1' seems to do with above query:

  Scott@my10g SQL>/
  
  CONTRAGENTID    LUAHPER
  ------------ ----------
             2  214996838
             1 14996837.9
  

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