How to choose a listItem from outside the list!
Hello guys! I'm developing an application on the meetings, and I am experiencing a small problem. The thing is: in the application I need a list to respond to music. Explain better: I want the list to automatically change the selection when the music reaches a predetermined point. As in its stars, the first element should be selected and then when it gets to 10 seconds, It shoud jump to the next, and so. To do the checks on the position of the music, I use OnPositionChanged. It's the portion of code:
onPositionChanged: {}
> console.log ("BBBBBBBBBB")
> >
> var i = myModel.data (myModel.find(["topic1","1"]))
> If (mediaPlayer.position > = {i.startTime})
> listView.select (i, true)
> console.log ("AAAAAAAAAAAAAAAAAAAAAAAAAAAA")
> >
> > }
In this case, the list takes the data of the dataModel, and the first has the title Topic1 and a property named startTime which in this case, that I set to 1. If I launch the app, when the stars of the music and the first signal from the position has changed is sent, the console displays "BATH", then the check is effective, because the console displays "ADRAR", but nothing happens on the list and the point is not to get selected. I thought it might be an error in the "var I = myModel.data (myModel.find(["topic1","1"]))" part, but then I called console.log ("i.startTime") and the console.displays 1... so the only thing left is the listView.select part... Someone knows how to call a selection of items from outside the component list view?
Welcome on the support forums.
I suggest you re-read the API ListView/DataModel carefully.
to call select, you need the path of the index.
Data() returns the list item associated with the path of the index.
Find() returns the index path, you must call select.
Use a var to store the row, and then use that data() and select().
and if I can offer a unrelated suggestion, 'i' use only for counter variables, use speaking names for others, for example "row".
Tags: BlackBerry Developers
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