How to choose the last rate in SQL?
Dear friends,
I have a table named pr_master
There are the item_id, pr_date, and item_rate fields in the table
data are as below
item_id pr_date item_rate
21 01/01/2014 50
21 01/05/2014 45
01/09/2014 21, 44
01/05/2014 25, 115
15/01/2014 25, 110
17/01/2014 25, 125
I want the maximum date through SQL for specific item rate.
Any1 can help. Thanking you.
Kind regards
with
pr_master as
(select 21 item_id, to_date('01-01-2014','dd-mm-yyyy') pr_date, 50 item_rate union double all the)
Select 21, to_date (May 1, 2014 "," dd-mm-yyyy ""), 45 union double all the
Select 21, to_date (September 1, 2014 "," dd-mm-yyyy ""), 44 Union double all the
Select 25, to_date (May 1, 2014 "," dd-mm-yyyy ""), 115 union double all the
Select 25, to_date (15 January 2014 "," dd-mm-yyyy ""), 110 union double all the
Select 25, to_date (January 17, 2014 "," dd-mm-yyyy ""), 125 of the double
)
Select item_id, pr_date, item_rate
of (item_id, pr_date, item_rate, row_number (select) on rn (partition by item_id arrested by pr_date desc)
of pr_master
)
where rn = 1
| ITEM_ID | PR_DATE | ITEM_RATE |
|---|---|---|
| 21 | 09/01/2014 | 44 |
| 25 | 17/01/2014 | 125 |
Concerning
Etbin
Tags: Database
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