How to correct the difference of phase because without delay?

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• determine the difference in phase between a reference signal and measure

  Hello

  I use a PXI-1000 b with two cards DAQ, PXI-6133 and I need to measure the difference in phase between a reference sinusoid, acquired on a map and an acquis of the sinusoid measured on the other card.  So far, my idea is simply to acquire samples of N of these two signas as waveform data, then compare.  My problem is that I see a way to extract the information from the relative phase.  How would I do that?  Is there a better way to achieve this end?

  Hey GlenS

  Check out this link. Use it a Subvi spend an entry as the data acquisition card entry and the other your reference wave. It should work.

  Good luck

  -laboratory

• How to tell the difference between recommended, and optional updates long after they have installed bene?

  I have a Vistaprogram of the window running on my Toshiba laptop.

  In the past, I've confirmed that optional udates be installed. Please help: now I want to uninstall optional updates because my computer is slow.  How to tell the difference between recommended, and optional updates long after they have installed bene?

  Hey monkey 44,

  I suggest you view the history in Windows Update:

  http://Windows.Microsoft.com/en-us/Windows-Vista/see-which-Windows-updates-are-installed

  Those listed as recommended is technically optional.

  Before you delete updates the computer, I suggest you try the steps from the following link to improve performance and check if that helps:

  http://Windows.Microsoft.com/en-us/Windows-Vista/ways-to-improve-your-computers-performance

  I hope this helps.

• The best way to draw the difference of phase vs. time of two signals

  I have three channels (time, force, displacement) of approximately 1 000 seconds of a sinusoidal test load test data (sampling rate was 100 Hz).  I would draw the difference in phase between the force and displacement (perhaps using a second window 30) according to time.  I tried using a few different analysis functions, but I get what looks like random noise (phase difference between force and displacement is very small and the difference in amplitude is very fantastic - 4 orders of magnitude).  Any suggestion would be appreciated! -Jim

  Hi Jim,.

  The phase channel resulting, that you get with the function FFT DIAdem is in the frequency domain.  If you select a channel data and time in the FFT dialog box, you will get a frequency channel that results as well as the Phase channel resulting.  If you select only a weather channel of waveform data in the FFT dialog box, you will get a Phase of waveform frequency channel resulting.

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• How to make the difference in percentage between two matrices?

  Hello everyone, I just want to ask how to make the difference in percentage between two binary matrices. This is to compare two images converted to matrices in LabView. Thank you.

  Well, in the current image interesting pixels are zero in the reference image. Here is a small example that would take all the zero 100% pixel, then look at the pixels of same in the other image to see how are always 0.

  Modify if needed.

  

• How to measure the difference in time between the passage by zero of a sine wave and the rise time of a pulse on a same graphic?

  I have a sine wave of 50 Hz and a pulse of the signal on the same chart. The difference in phase between the two is between 0-90 degrees.

  Now I need to calculate the time difference between (when the sinusoidal wave passes through zero volts) and (when the pulse increases). The frequency will remain about even for the two signals.

  The request is for a three-phase generator. In simple terms, when the difference in time between the passage to zero of the sine wave and pulse increases increases, it means that the load on the generator has increased.

  I am a novice user of LabView (version 9, 2009), maybe it's a very simple problem but I was pulling on my hair for the past few days and couldn't understand anything. Any help would be greatly appreciated. I use DAQ USB-6008 to measure these tensions and the impulse of the generator and a sensor

  I have attached a jpg file (a graphic that I just did with excel to explain). The time 't' is what I'm trying to measure

  

  See you soon

  Zdzislaw

  Awais.h,

  For problems of this kind I recommend start writing the granular steps you would take to manually fix this problem.  You can't say LabVIEW (or any programming language) If you can't succinctly describe the solution to your problem.

  The I want to address this problem is to:

  1. find all the zero crossing points and edges on the rise
  2. for every rising edge find the difference between the timestamp and previous passage by zero

  Here is an implementation of this algorithm LabVIEW:

  

• How to correct the bad image applesynofer.exe

  How to correct the bad image of apples synotifer.exe

  Contact apple.

• How to find the difference between standard edition and standard edition one

  How to find the difference between oracle database standard edition and standard edition one 64 bit
  
  (a) using sql
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  How to find the difference between oracle database standard edition and standard edition one 64 bit

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  Select * the option of $ v;

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• How to tell the difference between two dates

  Hello:
  
  I have a question on how to get the difference in quantities for two dates in the replies and dashboard.
  
  This is the scenario. I have two guests date and three columns. The first column must be the sum of the amounts for the first quick date. The second column should be the sum of the amounts for the second fast date. And the third column is the difference between the first two columns.
  
  Basically, I'm trying to do something similar to a function of sum of two lines but trying to get the difference between the two rows. Any help to solve this problem would be appreciated.

  Use the COLUMN FILTERS level...

  the first column with the first variable of date quick presentation of the filter

  Similarly, the second column in the second variable of quick overview of date filter

  Kind regards
  Rambeau

• How to remove the live windows messaging account without deleting messages

  How to remove the live windows messaging account without deleting messages

  If you mean Windows Live Hotmail, or Outlook.comm messages are stored on their servers, if you delete the account, you also delete the mail.

  Did you mean something else?

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• How to get the difference of two dates in months

  Dear friends,

  I have 4 items on my page.

  2 entered message text (value of loan, monthly deduction)

  2 are message style fields (start date, end date)

  I need to get the difference from above 2 dates in no.. of months. (for example say N)

  So with N, loanvalue should be divided and populated as monthly deduction.

  I tried this way, but not able to get the difference of dates

  {if ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))}

  System.out.println ("enter populateMonthlyDeduction loop1");

  String xxDeductionStartDate = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  System.out.println ("xxDeductionStartDate is:" + xxDeductionStartDate);

  TXN OADBTransaction = am.getOADBTransaction ();

  java.sql.Date DeductionSDate = null;

  java.sql.Date DeductionEDate = null;

  if(xxDeductionStartDate!=null)

  {

  java.sql.Date startDate = txn.getOANLSServices () .stringToDate (xxDeductionStartDate);

  DeductionSDate = startDate;

  System.out.println ("DeductionSDate is:" + DeductionSDate);

  }

  String xxDeductionEndDate = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  if(xxDeductionEndDate!=null)

  {

  java.sql.Date endDate = txn.getOANLSServices () .stringToDate (xxDeductionEndDate);

  DeductionEDate = endDate;

  System.out.println ("DeductionEDate is:" + DeductionEDate);

  }

  int difInDays = xxDeductionEndDate-xxDeductionStartDate; -Please correct me

  How reach it .plz help.

  Thank you

  Aravinda

  I used a custom like this method and calls this method daysBetween PFR.

  I got it. Thanks to you all.

  public int daysBetween(As Date, Date etDate)

  {

  return (int) ((etDate.getTime () - stDate.getTime (()) / (1000 * 60 * 60 * 24));

  }

  If ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))

  {

  System.out.println ("enter populateMonthlyDeduction loop1");

  String dedStDt = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  String dedEndDt = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  If (! dedStDt.Equals (null) &! dedEndDt.equals (null))

  {

  SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");

  Date sdate = new Date();

  Date edate = new Date();

  String sdate1 = null;

  String edate1 = null;

  try {}

  sdate = dateFormat.parse (dedStDt);

  EDATE = dateFormat.parse (dedEndDt);

  SimpleDateFormat dateFormat1 = new SimpleDateFormat("dd-MMM-yyyy");

  sdate1 = dateFormat1.format (sdate);

  edate1 = dateFormat1.format (edate);

  int days = daysBetween(sdate, edate);

  int diffInMonths = days/30;

  System.out.println ("days is:" + days);

  System.out.println ("diffInMonths is:" + diffInMonths);

  String sTotValueTuitionFees = vom.getCurrentRow ().getAttribute("TotValueTuitionFees").toString ();//pageContext.getParameter("LoanValue").toString();

  int iTotValueTuitionFees = Integer.parseInt (sTotValueTuitionFees);

  int iMonthlyDeduction = iTotValueTuitionFees/diffInMonths;

  String sMonthlyDeduction = String.valueOf (iMonthlyDeduction);

  System.out.println ("iMonthlyDeduction is:" + sMonthlyDeduction);

  OAMessageStyledTextBean bMonthlyDeduction = (OAMessageStyledTextBean) webBean.findChildRecursive ("MonthlyDeduction");

  bMonthlyDeduction.setValue (pageContext, sMonthlyDeduction);

  }

  catch (ParseException exception) e

  {

  }

  }

  }

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• How to tell the difference between default programs downloaded vs programs

  How can I tell the difference between my default that is already installed on my computer and programs that were downloaded on my computer that I need to uninstall? I'm very nervous about to enter Control Panel and then try to decide what programs or downloads that need to be uninstalled by fear of uninstalling vital programs in need of my computer.

  Hi AnitaJackson,

  What operating system is installed on your computer?

  Built-in applications on Windows will not appear in the control panel of Windows. The programs you have downloaded only appears in the Panel. If you want to uninstall any program downloaded, you can uninstall it from Control Panel.

  Hope the helps of information.

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.