How to create Cross Tab using Desktop

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  I see you want to create the shortcut on the desktop and pin it in the tool in windows 7. I'll help you with this problem.

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  Hello
  
  I'm using the version of oracle 11g.
  
  I have a requirement where I have to produce a cross-tab as explained below. Please help me write a SQL query to do this. Thank you very much.
  
  
  Sample data:
  ------------------
  

  Customer             product type
  --------------------------------------------
  AAA                           DVD
  AAA                           Tape
  BBB                           Tape
  CCC                                 DVD
  CCC                           Bluray
  DDD                           DVD
  DDD                           Tape
  DDD                           Bluray

  Logic
                                                                                  
       AAA                                              BBB                         CCC                         DDD          
       DVD     Tape     Bluray                    DVD     Tape     Bluray               DVD     Tape     Bluray               DVD     Tape     Bluray
  DVD          1                    DVD                         DVD               1          DVD          1     
  Tape     1                         Tape          1               Tape                         Tape     1          1
  Bluray                              Bluray                         Bluray     1                    Bluray          1     

  Final Output
  No. of customers who purchased the products across all product types
                      
       DVD     Tape     Bluray               
  DVD          2     1               
  Tape     2     1     1               
  Bluray     1     1                    

  Scripts:
  -------------------------
  create table cust_product(customer varchar2(5), product_type varchar2(10));
  
  insert into cust_product values('AAA','DVD');
  insert into cust_product values('AAA','Tape');
  insert into cust_product values('BBB','Tape');
  insert into cust_product values('CCC','DVD');
  insert into cust_product values('CCC','Bluray');
  insert into cust_product values('DDD','DVD');
  insert into cust_product values('DDD','Tape');
  insert into cust_product values('DDD','Bluray');

  Hello

  858747 wrote:
  ... Sample data:
  ------------------

  Customer             product type
  --------------------------------------------
  AAA                           DVD
  AAA                           Tape
  BBB                           Tape
  CCC                                 DVD
  CCC                           Bluray
  DDD                           DVD
  DDD                           Tape
  DDD                           Bluray
  

  ...
  Final output
  N ° of guests who have purchased products for all types of product

  `     DVD     Tape     Bluray
  DVD          2     1
  Tape     2     1     1
  Bluray     1     1                    
  

  Sorry, I don't follow the logic. Try to explain in words, with specific examples.
  Doesn't have 2 separate clients, 'CCC' and 'DDD', buy 'DVD' and 'Bluray '? Why aren't the results

  `     DVD     Tape     Bluray
  DVD          2     2
  Tape     2     1     1
  Bluray     2     1                    
  

  with 2 in the corners?

  Assuming it was just error, you can do something like this:

  WITH     got_pairs     AS
  (
       SELECT       a.product_type               AS product_a
       ,       NVL (b.product_type, a.product_type)     AS product_b
       FROM            cust_product     a
       LEFT OUTER JOIN     cust_product     b  ON  a.customer     = b.customer
                              AND     a.product_type != b.product_type
  )
  SELECT       *
  FROM       got_pairs
  PIVOT       (     COUNT (*)
         FOR     product_b
         IN     ( 'DVD'
            , 'Tape'
            , 'Blueray'
            )
         )
  ORDER BY  CASE  product_a
            WHEN  'DVD'     THEN  1
            WHEN  'Tape'     THEN  2
            WHEN  'Bluray'     THEN  3
         END
  ;
  

  This assumes that the combination (customer, product_type) is unique, as in your example of data., and that only product_types is 3 in your sample data.
  If these assumptions are not true, then after a few revised sample data and results, which show what you want in these cases.

  Sorry, I don't have an Oracle 11 database now to test this.
  I can (and has) test the outer join, which combines a product_type with him that if he can not be combined with any other thing.

  Using a technique of 11 pivot before Oracle, the following works:

  WITH     got_pairs     AS
  (
       SELECT       a.product_type               AS product_a
       ,       NVL (b.product_type, a.product_type)     AS product_b
       FROM            cust_product     a
       LEFT OUTER JOIN     cust_product     b  ON  a.customer     = b.customer
                              AND     a.product_type != b.product_type
  )
  SELECT       product_a     AS product_type
  ,       COUNT (CASE WHEN product_b = 'DVD'    THEN 1 END)     AS dvd
  ,       COUNT (CASE WHEN product_b = 'Tape'   THEN 1 END)     AS dvd
  ,       COUNT (CASE WHEN product_b = 'Bluray' THEN 1 END)     AS dvd
  FROM       got_pairs
  GROUP BY  product_a
  ORDER BY  CASE  product_a
            WHEN  'DVD'     THEN  1
            WHEN  'Tape'     THEN  2
            WHEN  'Bluray'     THEN  3
         END
  ;
  

  Note that the got_pairs of the subquery is identical in the two motions.

  Thanks for posting the CREATE TABLE and INSERT statements; It's very useful!

  Published by: Frank Kulash, may 29, 2011 16:05
  Oracle 9 append query.

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  || INITCAP ('FORMULA DESC')

  || ','

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  || ','

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  || ','

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  || ','

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  || ch.formula_status

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  || ch.ingrediant

  || ','

  || ch.by_product

  || ','

  || ch.by_product_type

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  EXCEPTION

  WHILE OTHERS

  THEN

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  || SQLERRM

  );

  END;

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  Thank you

  Rambeau

  Hi Christian,

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