cross tab using sql
HelloI'm using the version of oracle 11g.
I have a requirement where I have to produce a cross-tab as explained below. Please help me write a SQL query to do this. Thank you very much.
Sample data:
------------------
Customer product type
--------------------------------------------
AAA DVD
AAA Tape
BBB Tape
CCC DVD
CCC Bluray
DDD DVD
DDD Tape
DDD BlurayLogic
AAA BBB CCC DDD
DVD Tape Bluray DVD Tape Bluray DVD Tape Bluray DVD Tape Bluray
DVD 1 DVD DVD 1 DVD 1
Tape 1 Tape 1 Tape Tape 1 1
Bluray Bluray Bluray 1 Bluray 1 Final Output
No. of customers who purchased the products across all product types
DVD Tape Bluray
DVD 2 1
Tape 2 1 1
Bluray 1 1 Scripts:
-------------------------
create table cust_product(customer varchar2(5), product_type varchar2(10));
insert into cust_product values('AAA','DVD');
insert into cust_product values('AAA','Tape');
insert into cust_product values('BBB','Tape');
insert into cust_product values('CCC','DVD');
insert into cust_product values('CCC','Bluray');
insert into cust_product values('DDD','DVD');
insert into cust_product values('DDD','Tape');
insert into cust_product values('DDD','Bluray');Hello
858747 wrote:
... Sample data:
------------------Customer product type -------------------------------------------- AAA DVD AAA Tape BBB Tape CCC DVD CCC Bluray DDD DVD DDD Tape DDD Bluray...
Final output
N ° of guests who have purchased products for all types of product` DVD Tape Bluray DVD 2 1 Tape 2 1 1 Bluray 1 1
Sorry, I don't follow the logic. Try to explain in words, with specific examples.
Doesn't have 2 separate clients, 'CCC' and 'DDD', buy 'DVD' and 'Bluray '? Why aren't the results
` DVD Tape Bluray
DVD 2 2
Tape 2 1 1
Bluray 2 1
with 2 in the corners?
Assuming it was just error, you can do something like this:
WITH got_pairs AS
(
SELECT a.product_type AS product_a
, NVL (b.product_type, a.product_type) AS product_b
FROM cust_product a
LEFT OUTER JOIN cust_product b ON a.customer = b.customer
AND a.product_type != b.product_type
)
SELECT *
FROM got_pairs
PIVOT ( COUNT (*)
FOR product_b
IN ( 'DVD'
, 'Tape'
, 'Blueray'
)
)
ORDER BY CASE product_a
WHEN 'DVD' THEN 1
WHEN 'Tape' THEN 2
WHEN 'Bluray' THEN 3
END
;
This assumes that the combination (customer, product_type) is unique, as in your example of data., and that only product_types is 3 in your sample data.
If these assumptions are not true, then after a few revised sample data and results, which show what you want in these cases.
Sorry, I don't have an Oracle 11 database now to test this.
I can (and has) test the outer join, which combines a product_type with him that if he can not be combined with any other thing.
Using a technique of 11 pivot before Oracle, the following works:
WITH got_pairs AS
(
SELECT a.product_type AS product_a
, NVL (b.product_type, a.product_type) AS product_b
FROM cust_product a
LEFT OUTER JOIN cust_product b ON a.customer = b.customer
AND a.product_type != b.product_type
)
SELECT product_a AS product_type
, COUNT (CASE WHEN product_b = 'DVD' THEN 1 END) AS dvd
, COUNT (CASE WHEN product_b = 'Tape' THEN 1 END) AS dvd
, COUNT (CASE WHEN product_b = 'Bluray' THEN 1 END) AS dvd
FROM got_pairs
GROUP BY product_a
ORDER BY CASE product_a
WHEN 'DVD' THEN 1
WHEN 'Tape' THEN 2
WHEN 'Bluray' THEN 3
END
;
Note that the got_pairs of the subquery is identical in the two motions.
Thanks for posting the CREATE TABLE and INSERT statements; It's very useful!
Published by: Frank Kulash, may 29, 2011 16:05
Oracle 9 append query.
Tags: Database
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! http://blogs.Oracle.com/xmlpublisher/images/CTab2.jpg!
The fields are
! http://blogs.Oracle.com/xmlpublisher/images/CTab3.jpg!
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< TYPE_CODE > < / TYPE_CODE >
< MOST_RECENT_NOTE_DATE > 1 < / MOST_RECENT_NOTE_DATE >
< DD_CODE > visit - WDE Office < / DD_CODE >
< NOTE_DATE > 1321 < / NOTE_DATE >
< / ROW >
< ROW >
Product < NAME > < / NAME >
< DATE > 2008 - 05-01 T 00: 00:00.000 - 05:00 < / DATE >
< TYPE_CODE > < / TYPE_CODE >
< MOST_RECENT_NOTE_DATE > 1 < / MOST_RECENT_NOTE_DATE >
< DD_CODE > visit - WDE Office < / DD_CODE >
< NOTE_DATE > 1312 < / NOTE_DATE >
< / ROW >
< ROW >
Product < NAME > < / NAME >
< DATE > 2008 - 05-01 T 00: 00:00.000 - 05:00 < / DATE >
< TYPE_CODE > < / TYPE_CODE >
< MOST_RECENT_NOTE_DATE > 1 < / MOST_RECENT_NOTE_DATE >
< DD_CODE > visit - WDE Office < / DD_CODE >
< NOTE_DATE > 211 < / NOTE_DATE >
< / ROW >
< / LINES >
If I use the cross-tab Wizard... I get the following output...
The figures in each column are dynamic... I might have 2,3,4... (In this case, all are four)... I looked at the link below, but he had static 2 repeat columns... but in my case, the columns of repetition are unknown...-------------Call - Back Office-------Call - Monitoring-------Site Visit - Back Office-------Site Visit -Monitoring-----Visit - WDE Office product 12 121 11 1432 123 but I'm looking for output like... -------------Call - Back Office-----Call - Monitoring------Site Visit - Back Office------Site Visit -Monitoring-------Visit - WDE Office product-------12 11 14 112-----------121 122 131 111----------11 143 122 111------------------1432 112 121 123 ---------123 1321 1312 211
http://winrichman.blogspot.com/2008/09/crosstab-with-multiple-repeating.html
Is is possible to build a cross- like this tab... ?
Thanks in advance...Hello
Email me at colectionaru at gmail dot com
I'll watch your xml and post a solution here.Kind regards
Colectionaru -
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Hello
This is my first time on this forum so bear with my ignorance! I'll expose the background of my setup and then explain the error.
We have a small business with a server running SBS2011 and PC running Windows 8 and 8.1 connected to the server in a domain environment.
We use a CRM product called Emu Tall that uses SQL Server 2008 R2 on the server for the database and the PC run a local application that connects to this database.
On a daily basis, but completely randomly and sometimes several times a day, a user will try and open the application on a PC and get the following error message.
Could not load file or assembly 'Microsoft.SqlServer.SqlEnum, Version = 10.0.0.0, Culture = neutral, PublicKeyToken = 89845dcd8080cc91' or one of its dependencies. The system cannot find the specified file.
At first, I thought it must be a matter of waiting time as it seemed to happen every morning, but I've proved since that it occurs at any time of the day and is apparently unrelated to amount of users or idle time or something like that.
Here's another oddity that hopefully sheds some light on it. If I go to the server and open the CRM application on the server, it works very well since it is only the PC that have the connection problem. In addition, as soon as I connected to the server of any PC can connect immediately (until it happens again later in the day). I don't need to stay connected to the server, connect one time and close the session and he "fixed" it for a few hours for all PC users.
I contacted the CRM vendor, and they are completely confused and have no idea what to do.
We are trolling along at the moment with me opening a session on the server for launch launch whenever a user receives the error message but it is far from satisfactory.
A final observation is that it does not always. It used to work fine. The problem began just two months ago and seems to coincide with the increase in our user from 5 to 12 users license even if the CRM provider swear that it is nothing to do with the license. They may agree; I don't know enough to argue the point.
Any help will be appreciated! I'm sure it will be a simple solution and someone there will know why and the answer immediately but is elusive at this time.
This issue is beyond the scope of this site and must be placed on Technet or MSDN
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