How to do a loop function?
I looked through the documentation on a loop, but I do not understand. I'm doing this function loop, until the user stops it:
function playMusic(evt:MouseEvent):void
{
Channel.Stop (); to prevent users to start the file several times above the other - is there a better way to do it?
Channel = myMusic.play (songPosition);
myTimer.start ();
}
I'm new to flash, as well as near terms of wailing as possible would be appreciated.
I have a crew a bit. The main thing was to listen to the SOUND_COMPLETE event. So, here's something that works mainly (I tested) - just pasted the code like this:
stop();
import flash.events.MouseEvent;
import flash.media.Sound;
import flash.net.URLRequest;
import flash.media.SoundChannel;
import flash.media.SoundTransform;
import fl.events.SliderEvent;
import flash.utils.Timer;
import flash.events.TimerEvent;
import flash.media.SoundLoaderContext;
import flash.events.Event;
var soundFile:URLRequest = new URLRequest("1.mp3");
var soundFile1:URLRequest = new URLRequest("2.mp3");
var song:Sound;
var channel:SoundChannel;
var s_Transform:SoundTransform = new SoundTransform();
var myTimer:Timer = new Timer(250);
myTimer.addEventListener(TimerEvent.TIMER, updateTime);
var songPosition:Number = 0;
var myContext:SoundLoaderContext = new SoundLoaderContext(5000);
// both buttons call the same function
btn_play.addEventListener(MouseEvent.CLICK, playMusic);
btn_play1.addEventListener(MouseEvent.CLICK, playMusic);
btn_stop.addEventListener(MouseEvent.CLICK, stopMusic);
sld_volume.addEventListener(SliderEvent.CHANGE, changeVolume);
btn_pause.addEventListener(MouseEvent.CLICK, pauseMusic);
function pauseMusic(e:MouseEvent):void {
myTimer.stop();
songPosition = channel.position;
channel.stop();
}
function onSoundComplete(e:Event):void {
channel = song.play(0);
}
function convertTime(ms:Number):String {
return new Date(ms).toUTCString().replace(/(\w+\s){2}+\d+\s{1}\d+\:|\s\d+\s\w+/g, "");
}
function updateTime(e:TimerEvent):void {
LBL_songtime.text = convertTime(channel.position);
}
function getSongLength(e:Event):void {
LBL_songtotal.text = convertTime(song.length);
}
function changeVolume(e:SliderEvent):void {
s_Transform.volume = sld_volume.value;
channel.soundTransform = s_Transform;
}
function stopMusic(e:MouseEvent = null):void {
myTimer.stop();
if(channel) channel.stop();
songPosition = 0;
}
function playMusic(e:MouseEvent):void {
stopMusic();
song = new Sound();
switch(e.currentTarget) {
case btn_play:
song.load(soundFile, myContext);
break;
case btn_play1:
song.load(soundFile1, myContext);
break;
}
channel = song.play(0);
channel.addEventListener(Event.SOUND_COMPLETE, onSoundComplete);
myTimer.start();
}
txt_area.htmlText = "testing
";
Tags: Adobe Animate
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Select f_pwd_encrypt ('password') of double
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My question is
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OK, after reviewing the, I don't think you'll be able to write a function of decryption for him.
The first thing he does is take the ascii value of each character in the password and converts them into a binary string. The code it uses is far too complex and can be simplified, but which is not a problem here.
I've recreated the first step of SQL like this...
SQL > ed
A written file afiedt.buf
1 with chr_val like)
2. Select level l
3, dump('password',10,level,1) in the dmp
4, to_number (substrb (dump('password',10,level,1), instr (dump('password',10,level,1),' ', 1) + 1)) as chr_val
5, ascii (substr('password',level,1)) as chr_val - equivalent of extraction of useless dump
6 double
7. connect by level<=>
8 )
9, r (l, b, ch, chr_val, result, vtemp) as
10 (select l, 0 b, chr (chr_val), chr_val)
11, cast (null as varchar2 (8)) as a result
12, chr_val as vtemp
13 of chr_val
14 union of all the
15 select l, b + 1, b, ch, chr_val
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17, trunc(vtemp/2) as vtemp
18 r
where the 19 b + 1<=>
(20) depth search first by l, defined b seq
21, as)
22 select l, ch, chr_val, str_to_bit result
23 r
where the 24 b = 8
25 arrested by l, seq
26 )
27 select listagg (ch) within the Group (order) as password
28, listagg (chr_val, ',') within the Group (order) byte_vals
29, listagg (str_to_bit) within the Group (order) bit_vals
30 sec.
SQL > /.
PASSWORD BYTE_VALS BIT_VALS
--------------- ---------------------------------------- ----------------------------------------------------------------------------------------------------
password 0111000001100001011100110111001101110111011011110111001001100100 112,97,115,115,119,111,114,100
Then he takes this string binary ("bit_vals" in my example) and does the following:
1. take the first 3 bits of left and to transpose on the right end of the string.
2 chops the resultant bit string upward into sections of 4 bits (which is known as a 'nibble' inside)
3. for each bit in the nibble, he treats the bits in binary reverse to normal and gives them a value of 1,2,4 or 8 from left to right for each bit set to 1
4. for each nibble it adds the value of 1,2,4,8 bits to give a value from 0 to 15
To show that the use SQL...
SQL > byte (select ' 0111000001100001011100110111001101110111011011110111001001100100' as pieces of double)
2, swap3bit as (-take the binary string and put the first bits (high) 3 as a (low) bit of the right hand side)
3. Select bytes.bits
4, substr (bit 4) | substr (bits, 1, 3) as init_substr
5 bytes
6 )
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9, substr (init_substr, ((level-1) * 4) + 1, 4) as a nibble
swap3bit 10
11. connect by level<=>
12 )
13, bitpowers (select l
14, snack
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16, to_number (substr(nibble,2,1)) * power (2, 2-1) as bitval2
17, to_number (substr(nibble,3,1)) * power (2, 3-1) as bitval3
18, to_number (substr(nibble,4,1)) * power (2, 4-1) as bitval4
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22 to_number (substr (nibble, 4, 1)) * power (2, 4-1) as total_val
23 of split4
24 )
25 select * from bitpowers
26.
L NIBB BITVAL1 BITVAL2 BITVAL3 BITVAL4 TOTAL_VAL
---------- ---- ---------- ---------- ---------- ---------- ----------
1 1000 1 0 0 0 1
2 0011 0 0 4 8 12
3 0000 0 0 0 0 0
4 1011 1 0 4 8 13
5 1001 1 0 0 8 9
6 1011 1 0 4 8 13
7 1001 1 0 0 8 9
8 1011 1 0 4 8 13
9 1011 1 0 4 8 13
10 1011 1 0 4 8 13
11 0111 0 2 4 8 14
12 1011 1 0 4 8 13
13 1001 1 0 0 8 9
14 0011 0 0 4 8 12
15 0010 0 0 4 0 4
16 0011 0 0 4 8 12
16 selected lines.
These final values are then re-combination as strings in reverse order so that you get then:
'12' |' 4'||' 12' |' 9'||' 13'... and so on.
In SQL...
SQL > byte (select ' 0111000001100001011100110111001101110111011011110111001001100100' as pieces of double)
2, swap3bit as (-take the binary string and put the first bits (high) 3 as a (low) bit of the right hand side)
3. Select bytes.bits
4, substr (bit 4) | substr (bits, 1, 3) as init_substr
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6 )
7, split4 as (-chop the string of bits nibbles (half bytes - 4 bits))
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11. connect by level<=>
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17, to_number (substr(nibble,3,1)) * power (2, 3-1) as bitval3
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23 of split4
24 )
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27.
PWD
-------------------------------------------------------------------------------------------------------------------
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Now, the problem of decryption is that these numbers are concatenated without padding for a fixed number of digits by value, so you don't know if it was
'12' |' 4'||' 12' |' 9'||' 13'... and so forth as we did it, or whether he was
'1'||' 2'||' 4'||' 12' |' 9'||' 1'||' 3'... and so on, or any other combination of values from 0 to 15
There is essentially no information to allow you to divide the string upwards in the correct components to allow the whole process be reversed.
So, you are out of luck... no chance of decrypting it.
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Tree var;
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Stop();
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var exconem = 100;
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Tree var;
var tec;
power of the var;
var fvis;
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{
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}
on the other
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MVT = (CET + MVT) * fvis; now that we're here the MVT auto perpetuates on himself
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