How to do an INNER JOIN subquery?

Can't seem to find anything that could help out me with this.
My prototype query goes like this but its gives me an ORA-00905: lack of keyword


SELECT Poker_Site.site_name, bonus.sign_up_bonus
OF poker_site
INNER JOIN bonus
WHERE Poker_site.site_name = 'Poker Stars'
WE Poker_Site.site_name = bonus.site_name;

Join INNER JOIN must be immediately followed by ONE and only then, where:

SELECT Poker_Site.site_name, bonus.sign_up_bonus
FROM poker_site
INNER JOIN bonus
ON Poker_Site.site_name = bonus.site_name
WHERE Poker_site.site_name = 'Poker Stars';

SY.

Tags: Database

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    I don't know what you mean by "select sub", or what exactly is the PS limitation.
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           ledger,
           fund_code,
           account,
           foreign_amount,
           open_item_key
      from ps_open_item_gl a
     where (business_unit, ledger, fund_code, account) in
           (
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               from      ps_open_item_gl b
               where     b.open_item_status = 'O'
               and           business_unit  not in ('4110', '5301', '6501', '6602')
               group by  business_unit, ledger, fund_code, account
               having    sum (foreign_amount) = 0
           )
       and open_item_status = 'O'
     order by 1, 2, 3, 4, 6
    

    I move the condition 'and business_unit not in ('4110', '5301', '6501', 6602') ' in the subquery just for efficiiency.

    I think you would need a subquery, even if you don't re - he writes as a join.

    Perhaps using a view would work?

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    INSERT INTO CT VALUES ('987654','7ASDF654987');
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    XREF_CT_ID VARCHAR2(15)  
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    INSERT INTO CXRF VALUES ('987654','1','14WXYZ');
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    Published by: GMoney on 9 may 2013 08:49

    Thanks for posting examples of data and version, however, as said, it would be better if you can test, DDLS is full of typos.

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    {message: id = 9360005}

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      7  group by ct.design_id, ct.ct_id ;
    
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  • inner join is not eliminating duplicates!

    Name of the table is customers

    VALUE CITY SIDE NUMS CNAME
    1 2001 Hoffman 100 1001 London
    2 Rome 2002 200 1003 Giovanni
    3 2003 Liu San Jose 200 1002
    4 2004 grass Berlin 300 1002
    5 2006 Clemens 100 1001 London
    6 2008 Cisneros San Jose 300 1007
    7 2007 perish Rome 100 1004

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    4 Giovanni Liu
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    6 perira Clemens
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    Ideally, it should up to 5 rows, but it does not return these lines for an e.g. Hoffman perish since I'm Perira Hoffman already. Your answers will be appreciated.

    Thank you
    Vaibhav

    Hi, Vaibhav,

    914683 wrote:
    Name of the table is customers

    VALUE CITY SIDE NUMS CNAME
    1 2001 Hoffman 100 1001 London
    2 Rome 2002 200 1003 Giovanni
    3 2003 Liu San Jose 200 1002
    4 2004 grass Berlin 300 1002
    5 2006 Clemens 100 1001 London
    6 2008 Cisneros San Jose 300 1007
    7 2007 perish Rome 100 1004

    Query is
    To find all pairs of customers having the same side

    I tried:

    SELECT c.cname, cb.cname FROM customers c INNER JOIN customers cb WE cb.rating AND c.cname = c.rating! = cb.cname

    Perhaps what you want is

    SELECT      c.cname
    ,         cb.cname
    FROM          customers  c
    INNER JOIN  customers  cb  ON   c.rating  = cb.rating
                                       AND  c.cname       < cb.cname     -- not !=
    ;
    

    CNAME CNAME
    1 perish Hoffman
    2 Clemens Hoffman
    3 Liu Giovanni
    4 Giovanni Liu
    5 Cisneros grass
    6 perira Clemens
    7 Hoffman Clemens
    8 grass Cisneros
    Clemens 9 perish
    10 Hoffman perish

    The title you chose for this thread is "inner join is not eliminating duplicates!
    Inner joins (or other types of joints) are not supposed to remove duplicates. Use SELECT DISTINCT to remove duplicates, which is exactly the same lines.
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    `        CNAME     CNAME
    1     Perira     Hoffman
    10     Hoffman     Perira
    

    are not identical; Indeed, the two columns are different.

    Ideally, it should up to 5 rows, but it does not return these lines for an e.g. Hoffman perish since I'm Perira Hoffman already.

    Please report the exact output of the sample data you want. (As said by Hoek, post CREATE TABLE and INSERT statements for the sample data too.)

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    values(2,'hotel2','hotel2 address2');
    insert into hotel(hotel_id, hotel_name, hotel_address)
    values(3,'hotel3','hotel3 address3');
    insert into hotel(hotel_id, hotel_name, hotel_address)
    values(4,'hotel4','hotel4 address4');
    
    insert into people_type (people_type_id, type_des)
    values (1,'Baby');
    insert into people_type (people_type_id, type_des)
    values (2,'Young');
    insert into people_type (people_type_id, type_des)
    values (3,'Adult');
    
    insert into hotel_people (hotel_id, people_type_id, age_min, age_max)
    values (1,1,0,2);
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    values (1,2,3,10);
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    values (2,3,18,200);
    
    insert into hotel_people (hotel_id, people_type_id, age_min, age_max)
    values (3,3,18,200);
    
    insert into hotel_people (hotel_id, people_type_id, age_min, age_max)
    values (4,1,0,2);
    insert into hotel_people (hotel_id, people_type_id, age_min, age_max)
    values (4,2,3,10);
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    values (1,10,2,1);
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    values (1,5,4,0);
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    values (2,6,2,1);
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    values (2,12,3,1);
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    values (3,10,2,1);
    insert into hotel_service (hotel_id, qty_room, qty_people,qty_people_extra)
    values (3,5,4,0);
    insert into hotel_service (hotel_id, qty_room, qty_people,qty_people_extra)
    values (4,6,2,1);
    insert into hotel_service (hotel_id, qty_room, qty_people,qty_people_extra)
    values (4,12,3,1);
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    I'm trying to get the records that match my condition as:
    1. I want to get the hotels that can accommodate 4 pieces with adults of 3 for each room.
    2 get hotels that can accommodate 6 rooms 2 where 2 of the bedrooms can have 1 young (3 people per room) and young people 9 years.

    For 1:
    select h.hotel_id, h.hotel_name, ss.qty_room, t.type_des, ss.qty_people, p.age_min, p.age_max
    from hotel h
    inner join hotel_service ss on h.hotel_id = ss.hotel_id
    inner join hotel_people p on h.hotel_id = p.hotel_id
    inner join people_type t on p.people_type_id = t.people_type_id
    where ss.qty_room >= 4
    and t.people_type_id = 3
    and ss.qty_people >= 3
    For 2:
    select h.hotel_id, h.hotel_name, ss.qty_room, t.type_des, ss.qty_people, p.age_min, p.age_max
    from hotel h
    inner join hotel_service ss on h.hotel_id = ss.hotel_id
    inner join hotel_people p on h.hotel_id = p.hotel_id
    inner join people_type t on p.people_type_id = t.people_type_id
    where ss.qty_room >= 6
    and ss.qty_people >= 3
    and t.people_type_id in (2,3)
    and 9 between p.age_min and p.age_max
    This does not work, the start of the query becomes more complex if I try to search for multiple rooms with a different number of people and children of different ages.
    Can anyone help with this?
    Thank you

    Published by: user9542267 on April 3, 2012 22:26

    Hello

    user9542267 wrote:
    ... Yes, what I need is a hotel that can accommodate TWO adults and youth. What do you mean by two copies?

    Right now I read something on the Grand Duke by Gilbert. I also have a book with the complete works of Gilbert, so I can leave it open, and when I see a reference in the commentary, I see exactly what the author is talking about in the book. However, when the comment compares some parts of this game to the other plays of Gilbert, The Yeomen of the Guard , it gets hard, because I have to keep changing the pages in the complete works, and I can't see both at the same time. It would be much easier if I could get a full second copy of the work; then I could leave a copy of the Grand Duke and leave the other copy open to The Yeomen of the Guard . This is similar to what you should do with the table of hotel_people, and what I do with the table scott.emp below.

    Imagine (using tables in the scott schema) you have to find the departments where both an analyst and a clerk to work.
    This:

    SELECT DISTINCT
              d.*
    FROM       scott.dept     d
    JOIN       scott.emp     e  ON     d.deptno     = e.deptno
    WHERE       job          IN ('ANALYST', 'CLERK')
    ORDER BY  d.deptno
    ;
    

    product

    DEPTNO DNAME          LOC
    ------ -------------- -------------
        10 ACCOUNTING     NEW YORK
        20 RESEARCH       DALLAS
        30 SALES          CHICAGO
    

    because all these departments have either an analyst or a clerk. However, only deptno = 20 a time .
    If, instead of a single table of big job, you have a separate table for each Olympic Games, then you might do something like this:

    SELECT DISTINCT
              d.*
    FROM       scott.dept     d
    JOIN       analyst     a  ON     d.deptno     = a.deptno
    JOIN       clerk          c  ON     d.deptno     = c.deptno
    ORDER BY  d.deptno
    ;
    

    Of course, you don't have tables separated like that, but you could generate result sets who behaved as separte tables, for example:

    WITH     analyst          AS
    (
         SELECT  *
         FROM     scott.emp
         WHERE     job     = 'ANALYST'
    )
    ,     clerk          AS
    (
         SELECT  *
         FROM     scott.emp
         WHERE     job     = 'CLERK'
    )
    SELECT DISTINCT
              d.*
    FROM       scott.dept     d
    JOIN       analyst     a  ON     d.deptno     = a.deptno
    JOIN       clerk          c  ON     d.deptno     = c.deptno
    ORDER BY  d.deptno
    ;
    

    Note that the main request is exactly what I posted earlier.
    What produces the right output:

    DEPTNO DNAME          LOC
    ------ -------------- -------------
        20 RESEARCH       DALLAS
    

    There is no need to actually generate separate result sets, however. You can use two copies of the table scott.emp in the same query, as follows:

    SELECT DISTINCT
              d.*
    FROM       scott.dept     d
    JOIN       scott.emp     a  ON     d.deptno     = a.deptno
    JOIN       scott.emp     c  ON     d.deptno     = c.deptno
    WHERE       a.job          = 'ANALYST'
    AND       c.job          = 'CLERK'
    ORDER BY  d.deptno
    ;
    
  • Help with Inner join problem

    The following query works fine as long as there is a value in the subID field, which is the end of the inner join statement. If the subID is empty then no data is output, even if it is there. Try as I may, I can't do the right solution in which the statement to get the data to show without the subID. What Miss me?

    < name cfquery = "getInfo" datasource = "#application.database #" >

    Select page_id, pageName, pages.content, pages.cat_id, pages.seo_title, pages.seo_desc, pages.seo_words, pages.h1_title, pages.pic, pages.brochure, pa ges.video, catagories.catagory, subcat.subID, subcat.sub_category

    (page INNER JOIN categories ON pages.cat_id = catagories.cat_id) INNER JOIN subcat ON pages.subID = subcat.subID

    where pages.page_id = #page_id #.

    < / cfquery >

    Rick,

    Looks like you need a LEFT OUTER join to the table "subcat", so that all the records for the 'pages' and 'categories' are returned, even if no records matching "subcat" doesn't exist.  Joins INTERNAL returns only the selected records when both sides of the join statement tables have matching values, while you will get a join OUTER LEFT (sometimes also known simply as a LEFT JOIN) * everything * selected records from the table on the left side of the join statement, no matter if he adapt records from the table on the right side of the join statement.  When there is no corresponding record in the table on the right side of the join statement, all the columns in your SELECT clause that come from the table on the right side of the join statement will contain NULL values.

    HTH,

    -Carl V.

  • Urgent help please.  Inner join caused the error ora-00933

    I ran it, works great:
    SELECT DIFFERENT EXP. EXP_ID,
    EXP. DATU_EXP_WIRE_CENTER_CLLI,
    EXP. DATU_EXP_IP,
    EXP. DATU_EXP_CLLI,
    EXP. DATU_EXP_PORT,
    EXP. DATU_EXP_NAME,
    EXP. DATU_EXP_CITY,
    EXP. DATU_EXP_STATE,
    EXP. DATU_EXP_SW_VERSION,
    DECODE (LAST_ALARM. LAST_ALARM_DATE, NULL, TO_CHAR (SYSDATE, ' YYYY/MM/DD HH24:MI:SS'),
    TO_CHAR (LAST_ALARM. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS STATUS_DATE,
    DECODE (LAST_ALARM. ALARM_NAME, NULL, "disconnected", LAST_ALARM. ALARM_NAME) AS DATU_STATUS,
    DECODE (LAST_ALARM. ALARM_CLASS, NULL, 'OTHER', LAST_ALARM. ALARM_CLASS) AS IS_ERROR_STATUS,

    DECODE (LAST_RESOURCE. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_RESOURCE. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS RESOURCE_STATUS_DATE,
    DECODE (LAST_RESOURCE. RESOURCE_CODE_NAME, NULL, ", LAST_RESOURCE. RESOURCE_CODE_NAME) AS RESOURCE_STATUS,
    DECODE (LAST_RESOURCE. RESOURCE_CODE_CLASS, NULL, ", LAST_RESOURCE. RESOURCE_CODE_CLASS) AS IS_RESOURCE_ERROR_STATUS,
    DECODE (LAST_OPER. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_OPER. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS OPER_STATUS_DATE,
    DECODE (LAST_OPER. OPER_CODE_NAME, NULL, ", LAST_OPER. OPER_CODE_NAME) AS OPER_STATUS,
    DECODE (LAST_OPER. OPER_CODE_CLASS, NULL, ", LAST_OPER. OPER_CODE_CLASS) AS IS_OPER_ERROR_STATUS,

    EXP BEGIN_MAINT_WINDOW, RTU. RTU_NAME
    OF TT_DATU_EXP_UNIT_INFO EXP
    left outer join
    (SELECT distinct alarmed_datus. EXP_ID, c.ALARM_NAME, c.ALARM_TYPE, c.ALARM_CLASS and alarmed_datus. LAST_ALARM_DATE
    Of alarmed_datus (SELECT EXP_ID, MAX (ALARM_TIME) AS LAST_ALARM_DATE FROM TT_DATU_EXP_ALARM_INFO GROUP BY EXP_ID)
    inner join TT_DATU_EXP_ALARM_INFO b on b.EXP_ID = alarmed_datus. EXP_ID AND b.ALARM_TIME = alarmed_datus. LAST_ALARM_DATE
    inner join TT_DATU_EXP_ALARM_TYPES c on b.ALARM_TYPE = c.ALARM_TYPE
    ) LAST_ALARM on EXP.. EXP_ID = LAST_ALARM. EXP_ID
    left outer join
    (SELECT distinct a.EXP_ID, c.RESOURCE_CODE_NAME, c.RESOURCE_CODE_TYPE, c.RESOURCE_CODE_CLASS, a.LAST_ALARM_DATE
    FROM (SELECT EXP_ID, MAX (RESOURCE_CODE_TIME) AS LAST_ALARM_DATE
    OF TT_DATU_EXP_RESOURCE_CODE_INFO GROUP BY EXP_ID) a
    inner join TT_DATU_EXP_RESOURCE_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.RESOURCE_CODE_TIME = a.LAST_ALARM_DATE
    inner join TT_DATU_EXP_RESOURCECODE_TYPES c on b.RESOURCE_CODE_TYPE = c.RESOURCE_CODE_TYPE
    ) LAST_RESOURCE on EXP.. EXP_ID = LAST_RESOURCE. EXP_ID
    left outer join
    (SELECT distinct a.EXP_ID, c.OPER_CODE_NAME, c.OPER_CODE_TYPE, c.OPER_CODE_CLASS, a.LAST_ALARM_DATE
    FROM (SELECT EXP_ID, MAX (OPER_CODE_TIME) AS LAST_ALARM_DATE
    OF TT_DATU_EXP_OPER_CODE_INFO GROUP BY EXP_ID) a
    inner join TT_DATU_EXP_OPER_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.OPER_CODE_TIME = a.LAST_ALARM_DATE
    inner join TT_DATU_EXP_OPER_CODE_TYPES c on b.OPER_CODE_TYPE = c.OPER_CODE_TYPE) LAST_OPER on EXP.. EXP_ID = LAST_OPER. EXP_ID
    inner join TT_DATU_LRN_MAP on exp. EXP_ID = NAB NAB. EXP_ID AND TRIM (NAB. LRN) AS p_LRN
    inner join TT_RTU_TYPES on exp. RTU_TYPE_ID = RTU RTU. RTU_TYPE_ID
    WHERE THERE IS NOT (SOME SATELLITE_EXP_ID OF TT_HOST_SATELLITE WHERE EXP. EXP_ID = SATELLITE_EXP_ID)
    AND EXP.IS_PRIMARY_ADDRESS LIKE p_isPrimary;
    ON THE OTHER
    OPEN FOR V_cursor
    SELECT EXP. EXP_ID,
    EXP. DATU_EXP_WIRE_CENTER_CLLI,
    EXP. DATU_EXP_IP,
    EXP. DATU_EXP_CLLI,
    EXP. DATU_EXP_PORT,
    EXP. DATU_EXP_NAME,
    EXP. DATU_EXP_CITY,
    EXP. DATU_EXP_STATE,
    EXP. DATU_EXP_SW_VERSION,
    DECODE (LAST_ALARM. LAST_ALARM_DATE, NULL, TO_CHAR (SYSDATE, ' YYYY/MM/DD HH24:MI:SS'), TO_CHAR (LAST_ALARM. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS STATUS_DATE,
    DECODE (LAST_ALARM. ALARM_NAME, NULL, "disconnected", LAST_ALARM. ALARM_NAME) AS DATU_STATUS,
    DECODE (LAST_ALARM. ALARM_CLASS, NULL, 'OTHER', LAST_ALARM. ALARM_CLASS) AS IS_ERROR_STATUS,

    DECODE (LAST_RESOURCE. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_RESOURCE. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS RESOURCE_STATUS_DATE,
    DECODE (LAST_RESOURCE. RESOURCE_CODE_NAME, NULL, ", LAST_RESOURCE. RESOURCE_CODE_NAME) AS RESOURCE_STATUS,
    DECODE (LAST_RESOURCE. RESOURCE_CODE_CLASS, NULL, ", LAST_RESOURCE. RESOURCE_CODE_CLASS) AS IS_RESOURCE_ERROR_STATUS,
    DECODE (LAST_OPER. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_OPER. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS OPER_STATUS_DATE,
    DECODE (LAST_OPER. OPER_CODE_NAME, NULL, ", LAST_OPER. OPER_CODE_NAME) AS OPER_STATUS,
    DECODE (LAST_OPER. OPER_CODE_CLASS, NULL, ", LAST_OPER. OPER_CODE_CLASS) AS IS_OPER_ERROR_STATUS,

    EXP BEGIN_MAINT_WINDOW, RTU. RTU_NAME
    OF TT_DATU_EXP_UNIT_INFO EXP
    (in left outer join
    SELECT distinct alarmed_datus. EXP_ID, c.ALARM_NAME, c.ALARM_TYPE, c.ALARM_CLASS and alarmed_datus. LAST_ALARM_DATE
    Of alarmed_datus (SELECT EXP_ID, MAX (ALARM_TIME) AS LAST_ALARM_DATE FROM TT_DATU_EXP_ALARM_INFO GROUP BY EXP_ID)
    inner join TT_DATU_EXP_ALARM_INFO b on b.EXP_ID = alarmed_datus. EXP_ID AND b.ALARM_TIME = alarmed_datus. LAST_ALARM_DATE
    inner join TT_DATU_EXP_ALARM_TYPES c on b.ALARM_TYPE = c.ALARM_TYPE)
    LAST_ALARM on EXP.. EXP_ID = LAST_ALARM. EXP_ID
    left outer join
    (SELECT distinct a.EXP_ID, c.RESOURCE_CODE_NAME, c.RESOURCE_CODE_TYPE, c.RESOURCE_CODE_CLASS, a.LAST_ALARM_DATE
    FROM (SELECT EXP_ID, MAX (RESOURCE_CODE_TIME) AS LAST_ALARM_DATE
    OF TT_DATU_EXP_RESOURCE_CODE_INFO GROUP BY EXP_ID) a
    inner join TT_DATU_EXP_RESOURCE_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.RESOURCE_CODE_TIME = a.LAST_ALARM_DATE
    inner join TT_DATU_EXP_RESOURCECODE_TYPES c on b.RESOURCE_CODE_TYPE = c.RESOURCE_CODE_TYPE) LAST_RESOURCE on EXP.. EXP_ID = LAST_RESOURCE. EXP_ID
    left outer join
    (SELECT distinct a.EXP_ID, c.OPER_CODE_NAME, c.OPER_CODE_TYPE, c.OPER_CODE_CLASS, a.LAST_ALARM_DATE
    FROM (SELECT EXP_ID, MAX (OPER_CODE_TIME) AS LAST_ALARM_DATE
    OF TT_DATU_EXP_OPER_CODE_INFO GROUP BY EXP_ID) a
    inner join TT_DATU_EXP_OPER_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.OPER_CODE_TIME = a.LAST_ALARM_DATE
    inner join TT_DATU_EXP_OPER_CODE_TYPES c on b.OPER_CODE_TYPE = c.OPER_CODE_TYPE
    ) LAST_OPER on EXP.. EXP_ID = LAST_OPER. EXP_ID ORDER BY EXP. DATU_EXP_CLLI
    inner join TT_RTU_TYPES on exp. RTU_TYPE_ID = RTU RTU. RTU_TYPE_ID
    WHERE THERE is NOT (SOME SATELLITE_EXP_ID OF TT_HOST_SATELLITE WHERE EXP.. EXP_ID = SATELLITE_EXP_ID) AND EXP.IS_PRIMARY_ADDRESS love
    p_isPrimary;


    However this one:

    SELECT EXP. EXP_ID,
    EXP. DATU_EXP_WIRE_CENTER_CLLI,
    EXP. DATU_EXP_IP,
    EXP. DATU_EXP_CLLI,
    EXP. DATU_EXP_PORT,
    EXP. DATU_EXP_NAME,
    EXP. DATU_EXP_CITY,
    EXP. DATU_EXP_STATE,
    EXP. DATU_EXP_SW_VERSION,
    DECODE (LAST_ALARM. LAST_ALARM_DATE, NULL, TO_CHAR (SYSDATE, ' YYYY/MM/DD HH24:MI:SS'),
    TO_CHAR (LAST_ALARM. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS STATUS_DATE,
    DECODE (LAST_ALARM. ALARM_NAME, NULL, "disconnected", LAST_ALARM. ALARM_NAME) AS DATU_STATUS,
    DECODE (LAST_ALARM. ALARM_CLASS, NULL, 'OTHER', LAST_ALARM. ALARM_CLASS) AS IS_ERROR_STATUS,


    DECODE (LAST_RESOURCE. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_RESOURCE. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS RESOURCE_STATUS_DATE,
    DECODE (LAST_RESOURCE. RESOURCE_CODE_NAME, NULL, ", LAST_RESOURCE. RESOURCE_CODE_NAME) AS RESOURCE_STATUS,
    DECODE (LAST_RESOURCE. RESOURCE_CODE_CLASS, NULL, ", LAST_RESOURCE. RESOURCE_CODE_CLASS) AS IS_RESOURCE_ERROR_STATUS,
    DECODE (LAST_OPER. LAST_ALARM_DATE, NULL, ", TO_CHAR (LAST_OPER. LAST_ALARM_DATE, "YYYY/MM/DD HH24:MI:SS")) AS OPER_STATUS_DATE,
    DECODE (LAST_OPER. OPER_CODE_NAME, NULL, ", LAST_OPER. OPER_CODE_NAME) AS OPER_STATUS,
    DECODE (LAST_OPER. OPER_CODE_CLASS, NULL, ", LAST_OPER. OPER_CODE_CLASS) AS IS_OPER_ERROR_STATUS,


    EXP BEGIN_MAINT_WINDOW, RTU. RTU_NAME
    OF TT_DATU_EXP_UNIT_INFO EXP
    left outer join
    (
    SELECT distinct alarmed_datus. EXP_ID, c.ALARM_NAME, c.ALARM_TYPE, c.ALARM_CLASS and alarmed_datus. LAST_ALARM_DATE
    Of alarmed_datus (SELECT EXP_ID, MAX (ALARM_TIME) AS LAST_ALARM_DATE FROM TT_DATU_EXP_ALARM_INFO GROUP BY EXP_ID)
    inner join TT_DATU_EXP_ALARM_INFO b on b.EXP_ID = alarmed_datus. EXP_ID AND b.ALARM_TIME = alarmed_datus. LAST_ALARM_DATE
    inner join TT_DATU_EXP_ALARM_TYPES c on b.ALARM_TYPE = c.ALARM_TYPE) LAST_ALARM on EXP.. EXP_ID = LAST_ALARM. EXP_ID

    left outer join
    (SELECT distinct a.EXP_ID, c.RESOURCE_CODE_NAME, c.RESOURCE_CODE_TYPE, c.RESOURCE_CODE_CLASS, a.LAST_ALARM_DATE
    FROM (SELECT EXP_ID, MAX (RESOURCE_CODE_TIME) AS LAST_ALARM_DATE
    OF TT_DATU_EXP_RESOURCE_CODE_INFO GROUP BY EXP_ID) a
    inner join TT_DATU_EXP_RESOURCE_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.RESOURCE_CODE_TIME = a.LAST_ALARM_DATE
    inner join TT_DATU_EXP_RESOURCECODE_TYPES c on b.RESOURCE_CODE_TYPE = c.RESOURCE_CODE_TYPE) LAST_RESOURCE on EXP.. EXP_ID = LAST_RESOURCE. EXP_ID
    left outer join
    (SELECT distinct a.EXP_ID, c.OPER_CODE_NAME, c.OPER_CODE_TYPE, c.OPER_CODE_CLASS, a.LAST_ALARM_DATE
    FROM (SELECT EXP_ID, MAX (OPER_CODE_TIME) AS LAST_ALARM_DATE
    OF TT_DATU_EXP_OPER_CODE_INFO GROUP BY EXP_ID) a
    inner join TT_DATU_EXP_OPER_CODE_INFO b on b.EXP_ID = a.EXP_ID AND b.OPER_CODE_TIME = a.LAST_ALARM_DATE
    inner join TT_DATU_EXP_OPER_CODE_TYPES c on b.OPER_CODE_TYPE = c.OPER_CODE_TYPE
    ) LAST_OPER on EXP.. EXP_ID = LAST_OPER. EXP_ID ORDER BY EXP. DATU_EXP_CLLI
    inner join TT_RTU_TYPES on exp. RTU_TYPE_ID = RTU RTU. RTU_TYPE_ID
    WHERE the EXP.IS_PRIMARY_ADDRESS as p_isPrimary;

    It does not work kept send me errors:
    [ORA-00933: SQL not correctly completed command]


    Any guru can help? I need to have this resolved effect today.
    Thanks in advance.
  • Difference between Inner join and right outer join...

    Which is precisely the difference between an Inner join and right outer join...

    JOIN INTERNAL:-to return all rows from the two tables where there is a football game. That is to say. the table resulting from all the rows and columns will have values.

    AND

    RIGHT OUTER JOIN:-Returns all rows in the second table, even if there is no match in the first table.

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