How to find the interface using the table name target

Similar Questions

• How to find the table in a schema, if I only have a particular column name

  Hi all
  
  Ideal if some1 could help me, I know not a column name and I need to find the table that actually holds this column paricular name I know.
  
  is it possible to find this particular table with SQL?
  
  Thank you
  Rahul

  Select the table TABLE_NAME from user_tab_columns where column_name = 'COLUMN_NAME '.

• How to find the tables that are used in a procedure

  Hello
  I need to write a SQL to find (user_source) procedures or triggers (from user_triggers), whose code contains the registerd tables in a table X.
  In other words, I have a table X with files having a column containing tables. I want to write a SQL to obtain these (proc, package and triggers) container objects or use the tables inside
  Can you help me?
  Thank you!

  Mark1970 wrote:
  Hello
  I need to write a SQL to find (user_source) procedures or triggers (from user_triggers), whose code contains the registerd tables in a table X.
  In other words, I have a table X with files having a column containing tables. I want to write a SQL to obtain these (proc, package and triggers) container objects or use the tables inside
  Can you help me?
  Thank you!

  I don't know if I understand your problem, but have you had a glance at the data dictionary views USER_DEPENDENCIES or ALL_DEPENDENCIES?

  It has classified hard dependencies of objects.
  If a table is used directly (not in dynamic SQL code in a string) in an object PL/SQL, the dependency is available in the stated points of view.

• How to find the tables placed only on pages.

  Hi experts,

  I find all the tables in the document (no XML Indd file.) .indd There is only a certain number of tables. And a table in the master page also. Now I'm trying to get back only the tables except the master page. How can I got it?

  I used the following code. But it is not working properly.

  var myTables is app.activeDocument.stories.everyItem () .tables;.

  App.Select(mytables[0]);

  var myTableCount = myTables.length;

  Alert (myTableCount);

  for (var i = 0; i < myTableCount; i ++) {}

  var myTableObj = myTables [i];

  Alert (myTableObj.parent);

  Try

  {

  var myTableObj.parent.parentPage.name = XXX;

  If (xxx.match("^[0-9]+$"))

  {

  Alert ('table');

  myTableObj.label = 'table' +(i+1);

  }

  on the other

  {

  Alert ("Master Page table");

  }

  }

  catch (e)

  {

  Alert (e.message);

  }

  }

  Always throw catch loop...

  Can someone guide me...!

  Thank you and best regards,

  Vel.

  Hi Peter,.

  Finally, I close with the codes below. It make me fight a lot...

  var pagelen = app.activeDocument.pages.length;

  Alert (pagelen);

  for (var i = 0; i)<>

  {

  var pageitemlen = app.activeDocument.pages [i].pageItems.length;

  for (var j = 0; j)<>

  {

  v var = app.activeDocument.pages [i] .pageItems [j] .tables;

  Alert (v.Length);

  for (var x = 0; x)<>

  {

  App.Select (v [x]);                                                      Here, I can select.

  App.Selection [0] .label = "table" + count;

  Count ++;

  myTables.push (v [i]);

  }

  }

  }

  Peter, thank you very much for your time in Golden for my problem...

  With respect,

  Vel.

• How to find the table?

  Hello
  
  I have a java Apps to connect to a database of GR 11, 2.
  When I clicked on a "billing" module, I don't 'a number' 1,641.00 error in java logs that cause billing does not be generated.
  I don't even enter this value. I don't know if this error at the level of the table or during analysis on the coast of java it fetch a numeric variable placeholder.
  I simply assume that it is at the database level. And assuming that I am the only user in the database.
  How can I get this operation with the 1,641.00 value and determine which table was is inserted to the error? In V$ SQLAREA maybe?
  

  SYSUSER - 263293-40-1 2012-07-10 11:08:25,578 [http-6700-1] INFO  (support.context.CacheManager) Registering cache 'BusinessObjectInfoCache'
  SYSUSER - 263293-41-1 2012-07-10 11:08:25,859 [http-6700-2] ERROR (api.service.ServiceExecutionPolicy) Rollback: Read failed
  java.lang.NumberFormatException: Not a number: 1,641.00
       at com.ibm.icu.math.BigDecimal.bad(BigDecimal.java:3894)

  Thank you very much
  Kins

  >
  apps itself has no problem.
  >
  I have to disagree. If the application is to throw an exception and the journal contains her not the information necessary for you tell what is causing the exception, and then the application has ALSO a problem.

  java.lang.NumberFormatException: Not a number: 1,641.00
       at com.ibm.icu.math.BigDecimal.bad(BigDecimal.java:3894)
  

  Add additional record to the app to catch the exception and discover the connection, the request and the record that causes the error.

  Troubleshoot, to gather information when the problem actually occurs and work your way backwards.

  If you say that the problem did not exist before the developer made the change then prove it by running the old code against the same data. If it works then the problem is with the change that made the developer.

• How to find the table - is - this normal table or external table?

  Hello
  
  
  Regardless of DML operations in normal and reading tables only access tables outside, is there a way to find the specified table is regular table or the external table?
  
  Thanks in advance.
  
  Suresh.

  One possibility would be to query the ALL_EXTERNAL_TABLES data dictionary view. If there is a line in ALL_EXTERNAL_TABLES to the table, wondering (I assume you know that you query a table, a view, or a synonym), it is an external table. Otherwise, it's an ordinary table.

  Justin

• Windows FAX and SCAN error reports - request server name. How to find the server name?

  How can I find the name of the server to send e-mail using Windows FAX and SCAN.

  Hi DonaldCombes,

  1. are you able to use it earlier?
  2. What is the exact error message you get?
  3. don't you make changes occur the computer before the show?

  Try to use the full name of your Pc name of the server.

  Configure your computer to send and receive faxes
  http://Windows.Microsoft.com/en-us/Windows-Vista/set-up-your-computer-to-send-and-receive-faxes

  Solve fax problems
  http://Windows.Microsoft.com/en-us/Windows-Vista/troubleshoot-fax-problems

• How to give the table name as input for the insertion procedure parameter

  Hello
  Could a little help in this scenario,
  Here is an example of how to insert,
  where the 'b' table name will change at each
  is there a possible way to keep the name of the table as an input parameter
  
  SQL > CREATE or REPLACE PROCEDURE PROC_INSERT as
  BEGIN 2
  3 INSERT INTO A
  4 (ID, NAME, LOC)
  5. SELECT ID, NAME, B LOC;
  6 VALIDATION;
  7 END;
  
  Kind regards
  Vikram

  If you need to pass the object name to a SQL running, you must use dynamic SQL statements.

  A simpler way is the following

  create or replace procedure proc_insert
  (
       pTableName varchar2
  )
  as
  begin
       execute immediate 'insert into a (id, name, loc) select id, name, loc from ' || pTableName;
       commit;
  end;
  

• cannot find the table name of the multiple tables which has more columns.

  Hello
  
  I'm trying to find the NAME of the TABLE from multiple tables which has more columns. I can't count the number of columns in the table, but cannot find the name of the table that has larger columns in other tables.
  
  SELECT TABLE_NAME, COUNT (*) FROM THE USER_TAB_COLUMNS WHERE TABLE_NAME LIKE '% LOC' GROUP TABLE_NAME
  
  
  Thank you.

  in SQL, you can try this:

  var v_name varchar2(40)
  
  begin
     with
        subq1 as ( select table_name, count(*) as column_count from user_tab_columns where table_name like 'FIBER%'
                       group by table_name
                       order by count(*) desc )
     select table_name
       into :v_name
      from subq1
     where rownum = 1;
  end;
  

  To get the result:

  select :v_name from dual
  

  The clause "with" brings together all the tables and ordered them all first, by the greatest number of columns
  The final query uses the rownum restriction so that it takes the first name from the table of results of the subquery.

  The restriction of rownum also exactly guarantees a result each time so that it will work with the variable binding.

  RP

• How to find the JSFF name in managed bean

  Hi gurus,

  I'm new in the adf and the use of 11.1.2.3. I'm looking for the name of page jsff managed bean.  For example, if I have abc.jsf contains a fragment of xyz.jsff. I want when I click on the button in the jsff page, a pop shows me the name is xyz.jsff.

  Thank you

  Hello

  to get the page name, FacesContext.getCurrentInstance () .getViewRoot () .getViewId () (return abc.jsf). If you expose the page through a region of the ADF fragment, then the call is

  ControllerContext.getInstance () .getCurrentViewPort () .getViewId () (returns xyz if the activity view has the same name as the file xyz.jsff Physics)

  Frank

• How to find the middle name of any column NAME

  I wrote under request

  why this market not could you please help me?

  Select substr (ename, instr (ename,' ', 1, 1), instr (ename, ' ', 1.2)) of e1

  InStr, primary function must return the first position of the space and

  2 nd instr, function should return 2nd space

  so we can specify in substr function to extract the form position of string from this place to that place

  It would be very useful that you explain the reason

  Best regards

  Prem kumar

  Select

  -case when length (substr (ename, instr (ename,' ', 1.2))) = length (ename) then

  (case when length (substr (name, instr (ename,' ', 1.1))) = length (ename) then null)

  of another substr (ename, instr (ename,' ', 1, 1) + 1) end)

  of another substr (ename, instr (ename,' ', 1, 1) + 1, instr(ename,' ',1,2)-instr(ename,' ',1,1)-1)

  end middle_name

  of e1;

  Select

  -case when length (substr (ename, instr (ename,' ', 1.2))) = length (ename) then

  (case when length (substr (ename, instr (ename,' ', 1.1))) = length (ename) then null)

  of another substr (ename, instr (ename,' ', 1, 1) + 1) end)

  of another substr (ename, instr (ename,' ', 1, 1) + 1, instr(ename,' ',1,2)-instr(ename,' ',1,1)-1)

  end middle_name

  from (select 'asw nag raj' ename of double)

  Union

  Select "raj asw ght" double

  Union

  Select 'raj asw dfjadf Tom' from dual) e1;

• How to find the user name and a name indatapump import tablespace

  I have a datapump without the export log file. I would like to import it into a database. Before you begin the import, I would like to know the schema and the tablespace which exported so that I can remap the schema and the tablespace to others. Is there anyway that I can do

  You can run your import command, but add this:

  include tablespace, sqlfile = look.sql user =

  The look.sql file will have the tablespace create orders and orders for the user to create.

  Edit look.sql to see what are the names of tablespace and user.

  Dean

• How to find the primary key columns in the tables in MS Access using SQL queries

  How to find the primary key columns in the tables in MS Access using SQL queries

  Hello

  This is the forum for Windows Vista programs related issues.

  For better assistance, please try instead the Forums in SQL Server .

  Thank you! Vincenzo Di Russo - Microsoft MVP Windows Internet Explorer, Windows Desktop Experience & security - since 2003. ~ ~ ~ My MVP profile: https://mvp.support.microsoft.com/profile/Vincenzo

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How to find the user Apex table

  Hello
  
  Please let me know, how to find the user apex table. I need validate the unique user based on the same, for which I use below function.
  
  DECLARE
  VAL A BOOLEAN;
  BEGIN
  VAL: = APEX_UTIL.IS_USERNAME_UNIQUE (p_username =
  (: P6_USERNAME);
  END;
  
  However, in this case, he always comes back "FALSE," saying new user exists.
  
  Kindly help me in fixing this problem.

  There is a view called apex_workspace_apex_users.

  Details under Home > utilities > Application Express views

  André