How to find the sql query by using the hash value

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  Hi all
  
  I'm using Oracle 11 g 2. I need to know the maximum value in a collection of items.
  
  When I run the following, I get the maximum number of collection as '5' but I need the max value itself which is 8, please help.
  
  
  DECLARE
  type v_number1 is table of number of directory indexes;
  
  v_number v_number1;
  
  IDX NUMBER.
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  LOOSE COLLECTION v_src_file_string_array
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  /
  
  
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  Harinath Arasu says:
  Hi all

  I'm using Oracle 11 g 2. I need to know the maximum value in a collection of items.

  When I run the following, I get the maximum number of collection as '5' but I need the max value itself which is 8, please help.

  DECLARE
  type v_number1 is table of number of directory indexes;

  v_number v_number1;

  IDX NUMBER.
  psrc_file VARCHAR2 (10): = '1,2,4,8,6';
  v_src_file_string_array v_number1;
  number of max_temp;

  BEGIN

  SELECT regexp_substr (psrc_file, "[^,] +', 1, level") coll
  LOOSE COLLECTION v_src_file_string_array
  FROM (SELECT psrc_file FROM dual)
  CONNECT BY LEVEL<= length(regexp_replace(psrc_file,="" '[^,]+'))="" +="">

  -Set up some test values:
  BECAUSE me IN v_src_file_string_array. FIRST... v_src_file_string_array. COUNTING LOOP

  It should be-online 1... v_src_file_string_array. COUNTY

  -v_numbers (i): = v_src_file_string_array (i);
  v_number (i): = i;

  This should be-online v_numbers (i): = v_src_file_string_array (i);

  Can't do you all just...

  DECLARE
       type v_number1 is table of number index by binary_integer;
       v_number v_number1;
       idx NUMBER;
       psrc_file VARCHAR2(10) := '1,2,4,8,6';
       v_src_file_string_array v_number1;
       max_temp number;
  BEGIN
       SELECT regexp_substr(psrc_file, '[^,]+', 1, level) coll
       BULK COLLECT INTO v_src_file_string_array
       FROM (SELECT psrc_file FROM dual)
       CONNECT BY LEVEL <= length(regexp_replace(psrc_file, '[^,]+')) + 1;
  
       FOR i IN 1..v_src_file_string_array.COUNT LOOP
         if max_temp is null or
                  v_src_file_string_array(i) > max_temp then
              max_temp := v_src_file_string_array(i);
            end if;
       END LOOP;
       dbms_output.put_line ('Max: ' || max_temp);
  end;
  

  Or more simply...

  DECLARE
       type v_number1 is table of number index by binary_integer;
       v_number v_number1;
       idx NUMBER;
       psrc_file VARCHAR2(10) := '1,2,4,8,6';
       v_src_file_string_array v_number1;
       max_temp number;
  BEGIN
           SELECT to_number(regexp_substr(psrc_file, '[^,]+', 1, level))
        BULK COLLECT INTO v_src_file_string_array
           FROM (SELECT psrc_file FROM dual)
                CONNECT BY LEVEL <= length(regexp_replace(psrc_file, '[^,]+')) + 1
           order by 1 desc;
       dbms_output.put_line ('Max: ' || v_src_file_string_array(1));
  end;
  

  Published by: JAC on April 3, 2013 18:56
  Unhandled exception...

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  Hello friends,
  
  I want to find the first and second maximum items in a pl/sql table.
  
  Here's the code...
  
  DECLARE
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  max_earnings_tab max_earnings_type: = max_earnings_type();
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  number of v_max_earnings;
  
  
  Can someone give me how to find the maximum first max and second in the type of the given table.
  
  appreciate your help.
  
  Thank you/kumar
  
  Published by: kumar73 on October 21, 2010 09:42

  kumar73 wrote:

  When I tried to implement your logic in my application, I get the following error...

  PL/SQL: digital or value error: NULL index key value table

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      TYPE max_earnings_sorted_type IS TABLE OF NUMBER
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        INTO  max_earnings_tab
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  PL/SQL procedure successfully completed.
  
  SQL> SELECT  sal + comm
    2    FROM  emp;
  
    SAL+COMM
  ----------
  
        1900
        1750
  
        2650
  
        1500
  
    SAL+COMM
  ----------
  
  14 rows selected.
  
  SQL>
  

  SY.

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  Hi Yogi,

  Thanks for posting your query in Microsoft Community.

  According to the description of the issue, I recommend you post your query in the TechNet Forums. TechNet is watched by other computing professionals who would be more likely to help you.

  TechNet Forum

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