How to generate random numbers from 1 to 5

Similar Questions

• Generate random numbers in BPEL

  I have a use case that requires I generate a random number of 2 digits, something similar to "math: random * 100. I noticed that this feature is not readily available in the SOA Composite Editor. Can anyone suggest how this can be done?

  [code]

  "targetNamespace ="http://xmlns.oracle.com/KIMServices/embedded_java/BPELProcess1"

  "xmlns ="http://schemas.xmlsoap.org/ws/2003/03/business-process/"

  "xmlns:client ="http://xmlns.oracle.com/KIMServices/embedded_java/BPELProcess1"

  "xmlns:ORA ="http://schemas.oracle.com/xpath/extension"

  "xmlns:bpelx ="http://schemas.oracle.com/bpel/extension"

  "xmlns:bpws ="http://schemas.xmlsoap.org/ws/2003/03/business-process/"

  "xmlns:bpel2 ="http://docs.oasis-open.org/wsbpel/2.0/process/executable"

  "container ="http://www.w3.org/2001/XMLSchema"

  "xmlns:XP20 ="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.Xpath20"

  "xmlns:oraext ="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.ExtFunc"

  "xmlns:kimbpel ="http://xml.ibridge.nl/nl/rsg/kim/bpel"

  "xmlns:DVM ="http://www.oracle.com/XSL/Transform/java/oracle.tip.dvm.LookupValue"

  "xmlns:HWF ="http://xmlns.oracle.com/bpel/workflow/xpath"

  "xmlns:IDS ="http://xmlns.oracle.com/bpel/services/IdentityService/xpath"

  "xmlns:BPM ="http://xmlns.oracle.com/bpmn20/extensions"

  "xmlns:XDK ="http://schemas.oracle.com/bpel/extension/xpath/function/xdk"

  "xmlns:XREF ="http://www.oracle.com/XSL/Transform/java/oracle.tip.xref.xpath.XRefXPathFunctions"

  xmlns:LDAP ="http://schemas.oracle.com/xpath/extension/ldap" >. "

  Language = "java" >

  try {}

  Random random = new Random();

  int abc = random.nextInt (100);

  setVariableData ("NombrAl", abc);

  }

  end generate random number java

  [[catch (Exception e) {}]] >

  Query = "" / client: processResponse / client: result "/ >"

  [/ code]

  That should do it

• Generating random numbers with format 18XX88YYYYY

  I've been tryig to generate random numbers with
  format 18xx88yyyyy
  here
  18, followed by two random number then 88 followed by five random number. Here 18 and 88 are set to place one, two, five and sixth position.
  
  but I am unable to get the logic.
  
  So please help
  
  
  Thanx
  
  Achyot

  Try this:

  SELECT    '18'
         || ROUND (DBMS_RANDOM.VALUE (1, 100))
         || '88'
         || ROUND (DBMS_RANDOM.VALUE (1, 100000))
    FROM DUAL
  

  - - - - - - - - - - - - - - - - - - - - -
  Kamran Agayev a. (10g OCP)
  http://kamranagayev.WordPress.com

• How LabVIEW can generate random numbers according to any pdf or histogram?

  I would like to know if there is a VI that generates a set of random numbers according to any probability density, the probability mass function or the graph histogram (this without explicitly knowing the function).

  Thank you.

  Acoustic wrote:

  I would like to know if there is a VI that generates a set of random numbers according to any probability density, the probability mass function or the graph histogram (this without explicitly knowing the function).

  If you have a given arbitrary distribution, you can simulate random data of thesholding mapping in the integral standard service with a simple random number 0... 1.

  This old post of mine should show you the General procedure and more details. (Is there even an former example). Of course, make sure that the desired function is all positive, of course.

  

  

• How can I randomly select from a set of number without that breed?

  Hello

  I am creating a module on randomization without replacement.

  I chose the size of the sample to 10. in other words, there will be ten trials. the number range is 1 to 10. It cannot be that then happen to pick random numbers. I am able to choose the number randomly. However, I can't avoid the repetition of several numbers. I've attached what I try to do to avoid the repetition, but failed.

  I'm new to using LabVIEW. I'd really appreciate your help on this problem.

  Thank you

  Samia

  Or you can make your own, for example as follows:

  

• How to make random numbers

  Please Dear Sirs,
  I would like to create random numbers
  is there any function in oracle to make random numbers?
  waiting reply
  Thanks for all the people here
  Yasser

  Yasser,

  You can use the DBMS_RANDOM package. For more details, look at the thread http://www.psoug.org/reference/dbms_random.html

  Kind regards

  Manu.

• How to generate random curves under image control?

  Hello

  I'm still in the learning process LV my current objective is to have a circle drawn in the image optimization to move everything in the path of a curved line. The problem is that whenever I run the VI a new different trajectory is programatically created for my circle.

  I don't know how to approach this problem.

  A similar VI, I had the balls moving linearly, so I simply added a speed component to the component of the position of my balls. I initially use the same design here, but I can't devise a set of rules that would make the change in the result of the position on a trajectory of curved line. I think that generate a picture of the whole trajectory before each execution would probably work here, but I can't think a function do it either. Play with basic trig led sinusiodal or curved trajectory, but nothing really random out of period and amplitude.

  Ideally, I want as much possible variance in the path (ex: a function that could give me S, U-shaped, in the shape of spiral, loop, etc.) while maintaining control of certain parameters (length, position, max dX, etc..)

  Someone has an idea?

  Thank you!

  Looks like a random Walker.  One that I just did.  At each time point (0.1 seconds in this example), he took of the unit step in one direction, with the changing direction by a random amount within an angular range.  It can get pretty wild...

  

  Bob Schor

• How to display random lines from txt file

  Good morning (or evening all). I am creating an application and want to display random lines of a text file. I know how to create a text file using file connections, but how can I read the random lines of her?

  OK I got it.

  For beginners like me to have a problem in the future, I was not specify my path correctly. It is not enough to land your .txt in the /res folder and wait for the Simulator to load. You must load from SD card or device memory.

  Use the method found here:

  http://www.weask.us/entry/J2ME-BlackBerry-read-write-text-file

  to use it's as simple as that

  StringfName = "file:///SDCard/Blackberry/text.txt";

  String printLine = readTextFile (fName);

  label.setText (printLine);

  Somewhere in your project directory create a directory called SDCard (I did in my res folder).

  In the Simulator go to switch SD card, then load Select Directory and select the new directory of the SD card. This will create the structure of the SD card in the Simulator. Simply move your .txt in the SDCard/Blackberry directory and run your application.

• Generate random numbers when the pdf file is opened

  I tried to write a script that generates a random 12-digit number when the PDF opens.  I need the number appears in a certain read only field on the pdf file.  I tried write the script in the script of the document and have failed.  (The number random and another part of the document will be used to extract information from it at a later date.)  Can someone help me with a script so that I can make this possible?

  Do you want a new random number whenever the file is opened? If Yes, enter

  Copy the following code as a script at the level of the document (not inside a function!):

  this.getField("fieldname").value =.

  Math.Floor (Math.Random () * Math.Pow (10,12));

• How to eliminate specific numbers from a digital controller based on bollean LEDs?

  I have a LED bollean table. When I turn on a specific number of Boolean values it should perform a digital output controller. For Ex: From the table of Boolean if I turn on the LED 1, 3 and 7, the digital controller should now only givce monia 1.3 and 7 numbers instead of all sequence numbers. Is there a way to do this?

  Here is a much simpler version of the example given above.

  

• How to generate random keystrokes on AppleScript?

  I want to say my Mac to press random letters and delays at random.

  Here what I have so far:

  value validChars to {'a', 'b', 'c', '', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', "m", "n", "o", "p", "q", "r", "s", "t", "u", 'v', 'w', 'x', 'y', 'z'}

  the value randomChar to some point of validChars

  say application "TextEdit".

  activate

  end say

  delay 2.0

  say application "System events".

  strike randomChar

  strike randomChar

  delay of 2.5

  strike randomChar

  1.3 of the delay

  strike randomChar

  strike randomChar

  strike randomChar

  strike randomChar

  delay 5.0

  strike randomChar

  delay 0.5

  strike randomChar

  strike randomChar

  strike randomChar

  strike randomChar

  delay of 1.7

  strike randomChar

  strike randomChar

  strike randomChar

  strike randomChar

  3.2 the delay

  strike randomChar

  strike randomChar

  strike randomChar

  strike randomChar

  delay 7.0

  strike randomChar

  strike randomChar

  delay 1.2

  strike randomChar

  strike randomChar

  end say

  But that only raises the same randomness each keystroke, while I'm after a different character to each keystroke.

  Any help appreciated.

  
  

  You set only randomChar once. You would need to change this quickly on the key.

• Generate random numbers

  Hi all

  I searched the forum and have understood, there are many ideas generation random number, however I have another question, better explained by the attachment.

  I want to have output unique.

  your contributions are appreciated.

  I have not seen your code because I use LV2009 but I think the attached vi will want you want.

  Ben64

• How to get the numbers from a string?

  Hi all
  
  I have a string Let's say
  '0a1b2c3d4e5f '.
  
  I want to retrieve all the numbers out of it.
  
  012345
  
  Please Guide Me.
  
  Thank you

  Try

  SELECT REGEXP_REPLACE ('0a1b2c3d4e5f','(*[^[:digit:]]) ', ") double;

• How to generate several lines from a single line

  Hi, using Oracle 11 g R2.

  Looking for a way to display the result of a query where a column value is a text similar to the following field. There is only 1 row.

  create table testlist (col1 varchar2 (50))

  insert into testlist values (' ' 845, 999, ABC ")

  The values are always separated by commas. Looking for display the result as follows

  845

  999

  ABC

  Hello

  Since you have only 1 row in the table, you can do this:

  SELECT REGEXP_SUBSTR (col1

  , '[^,]+'

  1

  LEVEL

  ), Element

  OF testlist

  CONNECT BY LEVEL<= regexp_count="" (="">

  , '[^,]+'

  )

  ;

  Output:

  AGENDA

  ------------

  845

  999

  ABC

• How the random numbers will be generated

  The "dice" in LabVIEW function is ised to generate random numbers between 0 and 1. If I create a [100000] array with random numbers between 0 and 100, the appearance of 1 to 100 is the same (about 1000 times each), but the appearance of the 0 is only 500.

  So my question is, on the basis of which will be generated random numbers?

  Mitu salvation,

  It is not a problem of the RNG, it's a problem of your function rounded!

  "To U8" allows you to convert the entire random DBL. ToU8 rounds up to the next integer. So all the number of 0-0.5 will get rounded to 0, but all the numbers from 0.5 to 1.5 will get rounded to 1. If you have twice the range of a number rounded to 1 at the beach of rounding to zero - the same goes for your "end of range" with rounding to 100. 100 should be also less likelihood (in your VI) to appear...

  To get the same probability, you should (explicitly) roundpupils before converting in U8!

  BTW. You can also search the forum to get the same answer by searching for "random"...