How to get the Date format for a specific date?

May be it is inept to ask, but I'm aware of the Date.
which appear on client - it's just that the average customer treats the date.
Right?
So what happens if a need to check the format to set the server to date.
Or need to write common code indicating the date format
on the server, it is running.

This requirement came into my mind while using the extract method.
Actually, I wanted to date of manipulation of the side back end.
Let's say the time is 04:12:2012 03:05:16.
Now, if I add 100 minutes, the result will be.
04:12:2012 04:45:16.

It's the requirement. Maybe there may be best way to do
but it's the way I think now.

Thank you.

It's something that you don't need to know:
you have a string containing a date or timestamp, and then he must know the format of this string and not the fornat date used by the server.
or you have a date or timestamp, and then you can add minutes to it without knowing the format as described before.

Tags: Database

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Dear members,

How to get the date for the first Monday of each month.

I wrote the following code

SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL

But he looks at complex bith.

Abhishek

Published by: 9999999 on 8 March 2013 04:30

Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

select  sysdate current_date,
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CURRENT_D FIRST_MON
--------- ---------
08-MAR-13 04-MAR-13

SQL>

Here is the list of the first Monday of the month of this year:

with t as(
          select  add_months(date '2013-1-1',level-1) dt
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            connect by level <= 12
         )
select  dt first_of_the_month,
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FIRST_OF_ FIRST_MON
--------- ---------
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01-APR-13 01-APR-13
01-MAY-13 06-MAY-13
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01-AUG-13 05-AUG-13
01-SEP-13 02-SEP-13
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Hi, I am using the DateTimePicker.

There are several question about this command:

1. how to get the Date, month and year?

-With the help of myDateTime.value, I get this string ' Wed May 08 14:45 ICT 2013 '-> I have to manually analyze this? Because I need in format yyyy/mm/dd. Or can set the format of dateTimePicker.value?

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https://developer.BlackBerry.com/Cascades/reference/bb__cascades__datetimepicker.html#property-value

See more:

https://developer.BlackBerry.com/Cascades/reference/QDateTime.html#date

https://developer.BlackBerry.com/Cascades/reference/QDate.html

You can get
```
day = dateTimePicker.value.date().day()
month = dateTimePicker.value.date().month()
year= dateTimePicker.value.date().year()
dateYYYYMMDD = dateTimePicker.value.date().toString(Qt::ISODate)
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[[Garneau, 1990 #12]] » [9]
The good article can also be locally as text, e.g. [9]
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Currently, I read in the tables as "strings" (function GetText not shown):

var gaFmtCitsRaw  = [];                           // left column in processed RTF
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var gaBibliography= [];                           // bibliography lines from processed RTF
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  var nCits=0, nBib = 0, openParams, openReturnParams, newDoc, pgf, pgfText ;
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// --- read the temp/formatted citations  
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    pgfText = GetText (pgf, newDoc);
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Hello

Table [temp2]
 
   id          name        dt
  123        a             2-mar-2010
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This table how to get this line by id - name (id and the name of the composite key) whose date is the date of last weekend (last Saturday).
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Here's another option:

SELECT     *
FROM
(
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     ,     MAX(CASE WHEN TO_CHAR(DT,'DY','NLS_DATE_LANGUAGE=ENGLISH') = 'SAT' THEN DT END) AS DT
     FROM     TEMP2
     GROUP BY ID, NAME
)
WHERE DT IS NOT NULL

It is always useful to provide the following information:

1. oracle version (SELECT * FROM V$ VERSION)
2. examples of data in the form to CREATE / INSERT commands.
3. expected results
4 explanation of the expected results (alias "business logic")
5. use.

 tags for #2 and #3. See FAQ (Link on top right side) for details.

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If there is discontinuity in dates how we write the query...
I need to get the dates and the dates of discontinuity.
I / p:

item_no first_date second_date
1 January 1, 10 Aug 1, 10

1-01 - 7.-10 1er January 11

1 February 1, 11 1 July 11
"
"
"
o/p:

1 1 January 10 01 - aug - 10

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1 February 1, 11 1 July 11

'
'
'
Please let me know is possible

SQL> select  *
  2    from  tbl
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        ID FIRST_DAT SECOND_DA
---------- --------- ---------
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SQL> with t1 as (
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---------- --------- ---------
         1 01-JAN-10 01-AUG-10
         1 02-AUG-10 31-AUG-10
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How to get the date of Sunday of the week
Hello
I have a column date 'start_date', I need to create a report for all the weeks from Sunday, for example:

I need to get the dates of the week in the form:

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Help, please

Thank you...
Hello

To find the last Sunday before or equal to start_date:
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```
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It's not you NLS parameters. Always ISO weeks start on Monday. Your week begins 1 day earlier, that is why the above expression is the + 1 and -1.
(According to the parameters of the NLS)
```
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...
```
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I hope that answers your question.
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How to get the date in the exact day in the field when another?
Hello

Please help me how to get the day of the week using another date field.

In fact, a field (week_day) has 1,2,3,4,5,6,7 here 1-, 2 - KILL like this.
another field has the date. After this date, go to this particular week and need to pick up the date of the Etiquettemois above. It should be this week there himself.

Thanks in advance!

Kind regards
Florian...

Published by: Florian on October 29, 2010 03:07
Maybe it's
```
select trunc(date_field,'D') + week_field - 1 from table
```

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How to get the Date format for a specific date?

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