How to get the first day of the week on the calendar?

Similar Questions

• How to get the date for the first Monday of each month

  Dear members,
  
  How to get the date for the first Monday of each month.
  
  I wrote the following code
  
  SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL
  
  But he looks at complex bith.
  
  Abhishek
  
  Published by: 9999999 on 8 March 2013 04:30

  Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

  select  sysdate current_date,
          trunc(trunc(sysdate,'mm') + 6,'iw') first_monday_the_month
    from  dual
  /
  
  CURRENT_D FIRST_MON
  --------- ---------
  08-MAR-13 04-MAR-13
  
  SQL> 
  

  Here is the list of the first Monday of the month of this year:

  with t as(
            select  add_months(date '2013-1-1',level-1) dt
              from  dual
              connect by level <= 12
           )
  select  dt first_of_the_month,
          trunc(dt + 6,'iw') first_monday_the_month
    from  t
  /
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-JAN-13 07-JAN-13
  01-FEB-13 04-FEB-13
  01-MAR-13 04-MAR-13
  01-APR-13 01-APR-13
  01-MAY-13 06-MAY-13
  01-JUN-13 03-JUN-13
  01-JUL-13 01-JUL-13
  01-AUG-13 05-AUG-13
  01-SEP-13 02-SEP-13
  01-OCT-13 07-OCT-13
  01-NOV-13 04-NOV-13
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-DEC-13 02-DEC-13
  
  12 rows selected.
  
  SQL> 
  

  SY.

• How to get the 'DAY' based on the territory of current account held a number between

  Hi all
  
  Looks like I'm at the end of my intelligence here but how to get the 'DAY' based on the territory of current account with a number between 1 and 7? Oracle has functions to extract the day of the week, but I can't find the other way around.
  

  SQL> select * from v$version;
  
  BANNER
  --------------------------------------------------------------------------------
  Oracle Database 11g Release 11.2.0.3.0 - 64bit Production
  PL/SQL Release 11.2.0.3.0 - Production
  CORE    11.2.0.3.0      Production
  TNS for Linux: Version 11.2.0.3.0 - Production
  NLSRTL Version 11.2.0.3.0 - Production
  
  SQL> alter session set nls_territory=AMERICA;
  
  Session altered.
  
  SQL> select to_char (sysdate, 'D') from dual;
  
  T
  -
  3
  
  SQL> alter session set nls_territory=GERMANY;
  
  Session altered.
  
  SQL> select to_char (sysdate, 'D') from dual;
  
  T
  -
  2

  I need a way to know that the number '3' on the database with NLS_TERRITORY = AMERICA means a 'Tuesday' or the number '2' on a database with NLS_TERRITORY = GERMANY means "Tuesday" as well.
  
  Hope I am clear enough.
  
  And wish you all a happy new year :)
  
  Kind regards
  Smail

  Use the format "IW" to get the date of Monday and the format "DAY" to get the "first day of the week. Then compare dates to see if they are identical.

  ALTER SESSION SET NLS_TERRITORY = 'AMERICA';
  
  SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday",
  TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week",
  MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON"
  FROM DUAL CONNECT BY LEVEL <= 7;
  
  Monday    NLS First day of week 1 if day 1 = SUN, 0 if MON
  --------- --------------------- --------------------------
  31-DEC-12 30-DEC-12                                      1
  24-DEC-12 30-DEC-12                                      1
  24-DEC-12 23-DEC-12                                      1
  24-DEC-12 23-DEC-12                                      1
  24-DEC-12 23-DEC-12                                      1
  24-DEC-12 23-DEC-12                                      1
  24-DEC-12 23-DEC-12                                      1
  
  alter session set nls_territory = 'FRANCE';
  
  SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday",
  TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week",
  MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON"
  FROM DUAL CONNECT BY LEVEL <= 7;
  
  Monday   NLS First day of week 1 if day 1 = SUN, 0 if MON
  -------- --------------------- --------------------------
  31/12/12 31/12/12                                       0
  24/12/12 24/12/12                                       0
  24/12/12 24/12/12                                       0
  24/12/12 24/12/12                                       0
  24/12/12 24/12/12                                       0
  24/12/12 24/12/12                                       0
  24/12/12 24/12/12                                       0
  

  Or it could be simpler:

  ALTER SESSION SET NLS_TERRITORY = 'AMERICA';
  
  WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
  SELECT INPUT_DAY,
  TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
  from data;
  
  INPUT_DAY Day label
  --------- ------------------------------------
          1 SUNDAY
          2 MONDAY
          3 TUESDAY
          4 WEDNESDAY
          5 THURSDAY
          6 FRIDAY
          7 SATURDAY
  
  alter session set nls_territory = 'FRANCE';
  
  WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
  SELECT INPUT_DAY,
  TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
  from data;
  
  INPUT_DAY Day label
  --------- ------------------------------------
          1 MONDAY
          2 TUESDAY
          3 WEDNESDAY
          4 THURSDAY
          5 FRIDAY
          6 SATURDAY
          7 SUNDAY
  

• How to get the difference in dates in days

  Hi friends,
  
  How to get the date difference between two dates exactly
  
  date2-date1 days exactly... shouyld rounded to the nearest value of...
  
  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service
  
  This gives negative also result

  Hello

  776317 wrote:
  Hi friends,

  How to get the date difference between two dates exactly

  date2-date1 days exactly... shouyld rounded to the nearest value of...

  Date1 - date2 is the exact number of days is after date2 date1. (It is as accurate as possible, given that the DATEs do not have fractions of a second).

  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

  You want to probably get the exact number of days first, then ROUND this number:

  SELECT  ROUND (SYSDATE - TO_DATE (date_start, ...))   AS days
  FROM    per_periods_of_service; 
  

  Always pass arguments at least 2 to TO_DATE:
  (1) the string to be converted, and
  (2) a saying string how (1) is formatted

  This gives negative also result

  Right; If date1 is before date2 then date1 - date2 returns a negative number.
  If you want to never get a negative value, use ABS (date2 - date1). If it returns 4, then you know that one of the DATEs was 4 days before the other, but you won't know who was earlier.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

• How to get the maximum number of days in a month?

  How to get the maximum number of days in a month?

  I use a dateField. where I can get the month. Now, I want to get the maximum number of days in a month.

  How can I get it?

  Please help me. and thanks in advance... []

  NET. RIM. Device.API.util
  Class DateTimeUtilities

  getNumberOfDaysInMonth (int month, int year)
  Returns the number of days in the specified month

  It took me like 10 seconds to find it in the API, I guess you spent more time writing the post...

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• Win version first elements 14 rather than Mac version you downloaded. Serial number does not work. How to get the right serial number

  Win version first elements 14 rather than Mac version you downloaded. Serial number does not work. How to get the right serial number?

  It is unclear what problem you are facing... the wrong version or the wrong serial number.  The serial number is likely for the other version.  You don't want the serial number of Windows or the Mac version?

  One of the following conditions may be useful...

  You can exchange languages/platforms for a newer version product if you follow the instructions on the following link:

  l http://helpx.adobe.com/x-productkb/Policy-Pricing/Order-Product-Platform-Language-swap.htm

  To the link below, click on the still need help? the option in the blue box below and choose the option to chat...
  Make sure that you are logged on the Adobe site, having cookies enabled, clearing your cookie cache.  If it fails to connect, try to use another browser.

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  I don't know what you've done, but here are the instructions to install the PProCS6 and the callback with a cloud account

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• How to get the last day of the week?

  HII
  
  I can get the week number of calendar for a given date using
  
  SELECT to_char (to_date('04/04/2011','MM/DD/YYYY'), 'WW') FROM dual
  
  can any body tell me, how to get the last day of the week?
  
  and the answer should be: 04/08/2011(8th april)
  Thank you
  San
  
  Published by: sandeep9 on April 4, 2011 03:50

  Perhaps this...

  SQL> select trunc(sysdate,'WW')+6 from dual;
  
  TRUNC(SYSDATE,'WW')+
  --------------------
  08-APR-2011 00:00:00
  
  SQL>
  

• How to get the date in the exact day in the field when another?

  Hello
  
  Please help me how to get the day of the week using another date field.
  
  In fact, a field (week_day) has 1,2,3,4,5,6,7 here 1-, 2 - KILL like this.
  another field has the date. After this date, go to this particular week and need to pick up the date of the Etiquettemois above. It should be this week there himself.
  
  Thanks in advance!
  
  Kind regards
  Florian...
  
  Published by: Florian on October 29, 2010 03:07

  Maybe it's

  select trunc(date_field,'D') + week_field - 1 from table
  

• How to get the second Monday of each month in a given date range?

  In Oracle forms, how to get the second Monday of each month in a given date range?

  I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?

  WITH month_range AS

  (

  SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month

  , TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month

  OF the double

  )

  SELECT NEXT_DAY (6 + ADD_MONTHS (first_month

  , LEVEL - 1

  )

  , 'MONDAY '.

  ) AS second_monday

  OF month_range

  CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)

  ;

  Thanks in advance.

  Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

  SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

  THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

  END AS second_day

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to get the text have the same effect as the video?

  Hello

  For the first time post here, but I wonder how to get the text of the titles have the same effect as the video behind her.

  For my video, I use 'bad tv' and other effects such as Gaussian that obviously changes the appearance of video, creating the look of VHS. However, I then inserted text via the title, but it normally appears. How can I make this text have the same effects as the video behind it?

  A friend told me I might need to add text to the video first, then do the effects, I have not tried, but wonder if there is an easier way, as this would require me to restart.

  EDIT: That's what I'm looking for. https://youtu.be/7_2PHQI89dI?t=24s The text has the same effect as the video.

  Thank you

  One way is to create a clip made up based on the title and the original clip. Then apply the effect.

  Another way is to use an adjustment layer.

  Good luck.

  Russ

• Re: How to get the Tempo to work properly?

  Hello

  I have problems with the service of Tempo.

  I don't get updates via this application (all the settings of this application are accurate, i.e. "full control"). I know this because there are updates available online to my laptop via the pilot site of toshiba.

  When I installed first Tempo, updates for about a month, I received, and then all of a sudden, no update came through. My firewall is blocking either of this application.

  I tried to reinstall the application, but no change in the situation.

  Does anyone know if ALL updates are available via the website of driver toshiba out tempo? Because, in the month that this service worked, I got an update of the bios, but I recently saw a bios update online and Tempo has not always reports that it is available.

  Any ideas on how to get the Tempo to work properly?

  Thank you.

  I saw in your other thread you have installed SP1 on your Vista laptop.
  There may be some compatibility problems between SP1 and Tempo

  And Yes, as far as I know Tempo bring all available updates!

• Satellite A500 PSAM3A - how to get the HARD market under Vista 64-bit disk Protection System

  Hello

  I would like to know how to get the HARD drive Protection system up and running under Vista Home Premium 64 bit operating system. I downloaded the program 64 bit of Toshiba for this program and install it I tried but doesn't seem to work. I have uninstalled and try to install the program, but still does not work.

  Unable to find the problem, why it won't work. If anyone knows how to solve this problem it would be a great
  help for me. If anyone knows how to solve this problem please answer me as soon as possible.

  Thank you for your time.

  Kind regards
  Nigel.

  Hello!

  What you downloaded exactly on the Toshiba site?

  As written Akuma you must install first added value Package you will find also on the Toshiba site. Check this box!

  An interesting thing: it does not work if you are using the preinstalled operating system? It should have everything installed for your laptop.

  Good bye