How to get the last day of the weekend rather than a month

Hi all

Is the request appropriate and preferable to use to get the last business day of the month below?

SELECT to_date('13.08.2014','dd.mm.yyyy') + MAX(RNUM) LastDay(nonweekend)
   FROM   (SELECT ROWNUM RNUM
          FROM   ALL_OBJECTS where rownum <=31)
  WHERE   ROWNUM <= 31 ANd
     TO_CHAR(to_date('13.08.2014','dd.mm.yyyy') + RNUM, 'DY','NLS_DATE_LANGUAGE=ENGLISH' ) NOT IN ('SAT' , 'SUN')
     and to_date('13.08.2014','dd.mm.yyyy') + RNUM <= last_day(to_date('13.08.2014','dd.mm.yyyy'))

I have to use this motion for production.

East - recommended to use?

You can change your query this way:

WITH t AS (SELECT trunc (to_date ('& calc_date', 'dd.mm.yyyy'), 'mm') + level - 1 calc_date)

OF THE DOUBLE

CONNECT BY LEVEL<= last_day(to_date('&calc_date',="" 'dd.mm.yyyy'))="" -="" trunc(to_date('&calc_date',="" 'dd.mm.yyyy'),="" 'mm')="" +="">

)

Select max (calc_date)

t

where to_char (calc_date, 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') NOT IN ("SAT", "Sun");

Tags: Database

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How to get the second Monday of each month in a given date range?

In Oracle forms, how to get the second Monday of each month in a given date range?
I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?
WITH month_range AS
(
SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month
, TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month
OF the double
)
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, LEVEL - 1
)
, 'MONDAY '.
) AS second_monday
OF month_range
CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)
;
Thanks in advance.

Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

END AS second_day

FROM (SELECT SYSDATE startdate,

SYSDATE + 300 enddate

THE DOUBLE)

CONNECT BY LEVEL<=>

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Granniebiker

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How to get sales last day of the previous month

HELO guys
I have a question how do I get sales date last day of the previous month where my fact table is level. in fact I tried using Ago but it seems not working. for example, if I chose December 29, 2014 so if I used the function there are then the result will display data on November 29, 2014 (not the last day of November 2014).
Please guys if you have any solution and I really advise thanks to you.

Not exactly under what circumstances specific as you try to reach this goal, but suppose you have a few guest dashboard where you select a day and you have a report with a measure where you want to show the sales of the last day of the previous month based on the selected date in the dash prompt.

If you change the formula of this measure to something like:

FILTER (with the HELP of 'Sales' (DATE = TIMESTAMPADD (SQL_TSI_DAY-1, TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH(@{PV_DATE_SELECTED}) * (-1) + 1, @{PV_DATE_SELECTED}))))

How to get the desired result when subsequent month is not available

WITH T1
     AS (SELECT 'A' COL1,
                'B' COL2,
                'C' COL3,
                '01-Jan-2015' DT,
                10 QTY
           FROM DUAL
         UNION
         SELECT 'A' COL1,
                'B' COL2,
                'C' COL3,
                '01-feb-2015' DT,
                20 QTY
           FROM DUAL
         UNION
         SELECT 'A' COL1,
                'B' COL2,
                'C' COL3,
                '01-mar-2015' DT,
                30 QTY
           FROM DUAL
         UNION
         SELECT 'A' COL1,
                'B' COL2,
                'C' COL3,
                '01-may-2015' DT,
                40 QTY
           FROM DUAL
         UNION
         SELECT 'A1' COL1,
                'B1' COL2,
                'C1' COL3,
                '01-mar-2015' DT,
                40 QTY
           FROM DUAL
         UNION
         SELECT 'A1' COL1,
                'B1' COL2,
                'C1' COL3,
                '01-may-2015' DT,
                40 QTY
           FROM DUAL)
SELECT *
  FROM t1

Current output:

COL1	COL2	COL3	DT	QTY.
A	B	C	January 1, 2015	10
A	B	C	February 1, 2015	20
A	B	C	01-mar-2015	30
A	B	C	01-may-2015	40
A1	B1	C1	01-mar-2015	40
A1	B1	C1	01-may-2015	40

Expected results

COL1	COL2	COL3	DT	QTY.	DT	REQ_VAL
A	B	C	01/01/2015	10	01/01/2015	20
A	B	C	01/02/2015	20	01/02/2015	30
A	B	C	01/03/2015	30	01/03/2015	0
A	B	C	01/05/2015	40	01/05/2015	0
A1	B1	C1	01/03/2015	40	01/03/2015	0
A1	B1	C1	01/05/2015	40	01/05/2015	0

Logic:

If we COL1, COL2, COL3 combination for A, B, C, we have the quantity for 1 January, 1 February, 1 March, 1 may, and we don't have quantity for April 1 and June 1. I need following QUANTITY value as another column. If I use the lead, I'll get the value from May 1st to March 1st, but I want to value 0 because it is after March either.

What I've tried so far:

SELECT *
  FROM (WITH T1
AS (SELECT 'A' COL1,
'B' COL2,
'C' COL3,
'01-Jan-2015' DT,
10 QTY
FROM DUAL
UNION
SELECT 'A' COL1,
'B' COL2,
'C' COL3,
'01-feb-2015' DT,
20 QTY
FROM DUAL
UNION
SELECT 'A' COL1,
'B' COL2,
'C' COL3,
'01-mar-2015' DT,
30 QTY
FROM DUAL
UNION
SELECT 'A' COL1,
'B' COL2,
'C' COL3,
'01-may-2015' DT,
40 QTY
FROM DUAL)
        SELECT COL1,
 COL2,
 COL3,
TO_DATE (T1.DT) DT,
NVL (QTY, 0) QTY,
 MONTHS.DT ALL_DATES,
 LEAD (NVL (QTY, 0), 1, 0) OVER (ORDER BY MONTHS.DT) REQ_VAL
          FROM T1,
(    SELECT ADD_MONTHS (TO_DATE ('01-jun-2015'), LEVEL - 6) DT
FROM DUAL
CONNECT BY LEVEL <= 12) MONTHS
         WHERE MONTHS.DT = T1.DT(+))
WHERE DT ISNOTNULL;

My query works for a set of COL1, COL2, COL3, am looking how we can achieve multiple COL1, COL2, COL3 (or) otherwise better query writing.

Thanks for your suggestions in advance.

Thank you

Now, to understand your condition: your additional column must indicate the amount of the next month, or zero if it is not a record for the month. How about this?

WITH T1

AS (SELECT 'A' COL1,)

'B' COL2,

COL3 'C ',.

To_date('01-Jan-2015','dd-mon-yyyy') DT,

QTY 10

OF THE DOUBLE

UNION

SELECT 'A' COL1,

'B' COL2,

COL3 'C ',.

To_date('01-Feb-2015','dd-mon-yyyy') DT,

QTY. 20

OF THE DOUBLE

UNION

SELECT 'A' COL1,

'B' COL2,

COL3 'C ',.

To_date('01-Mar-2015','dd-mon-yyyy') DT,

QTY 30

OF THE DOUBLE

UNION

SELECT 'A' COL1,

'B' COL2,

COL3 'C ',.

To_date('01-May-2015','dd-mon-yyyy') DT,

QUANTITY 40

OF THE DOUBLE

UNION

SELECT 'A1' COL1,

COL2 "B1."

COL3 "C1"

To_date('01-Mar-2015','dd-mon-yyyy') DT,

QUANTITY 40

OF THE DOUBLE

UNION

SELECT 'A1' COL1,

COL2 "B1."

COL3 "C1"

To_date('01-May-2015','dd-mon-yyyy') DT,

QUANTITY 40

THE DOUBLE)

X.Col1, x.col2, x.col3, x.dt, x.qty, NVL(y.qty,0) SELECT req_val

THE t1 x

LEFT OUTER JOIN t1 y

ON y.col1 = x.col1

AND y.col2 = x.col2

AND y.col3 = x.col3

AND y.dt = add_months(x.dt,1)

ORDER BY 1,2,3,4

My query works for a DFU, am looking how we can achieve multiple UTD

What is a DFU?

How to get the value less than 0 = 0

I'm trying to get a formula to do two operations of a field given something like:
Form1. #subform [0].yes1.qn1::calculate - (JavaScript, client)
(p1-s1)
Then, if the value is less than '0' the value '0 = '.
what I have so far does not work, any help is greatly appreciated.
If
(this.rawValue < 0)
this.rawValue
= 0;
Thank you.

I put the following code in the event the qn4 field Calculate... FormCalc language...

If this isn't what you're trying to do, then please explain in detail...

If ((p4-s4) == 0) then
$.rawValue = 0;
on the other
$.rawValue = (p4 - s4);
endif

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LAST_DAY)

---------

29 JANUARY 16

30 JANUARY 16

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Hello
Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?
Thanks in advance.

Try the below

SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

END as lastweekday,

BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

-(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

END as lastweekendday,

BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

END AS lastmonday

FROM (SELECT SYSDATE startdate,

SYSDATE + 300 enddate

THE DOUBLE)

CONNECT BY LEVEL<=>

How to get the last day of the week?
HII

I can get the week number of calendar for a given date using

SELECT to_char (to_date('04/04/2011','MM/DD/YYYY'), 'WW') FROM dual

can any body tell me, how to get the last day of the week?

and the answer should be: 04/08/2011(8th april)
Thank you
San

Published by: sandeep9 on April 4, 2011 03:50
Perhaps this...
```
SQL> select trunc(sysdate,'WW')+6 from dual;

TRUNC(SYSDATE,'WW')+
--------------------
08-APR-2011 00:00:00

SQL>
```

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How to get the maximum number of days in a month?

I use a dateField. where I can get the month. Now, I want to get the maximum number of days in a month.

How can I get it?

Please help me. and thanks in advance... []

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Class DateTimeUtilities

getNumberOfDaysInMonth (int month, int year)
Returns the number of days in the specified month

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If it is through the application or running in the background via SQL for the information is not important to me.
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the 'item_type' attribute must match the name of the WF?

Yes (internal name. For example OEOL).

The custom of those who will not be affected by the upgrade.

You must run the query that I provided before to identify if the workflow is used or not.

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How to get the 'DAY' based on the territory of current account held a number between

Hi all

Looks like I'm at the end of my intelligence here but how to get the 'DAY' based on the territory of current account with a number between 1 and 7? Oracle has functions to extract the day of the week, but I can't find the other way around.

SQL> select * from v$version;

BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
CORE    11.2.0.3.0      Production
TNS for Linux: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production

SQL> alter session set nls_territory=AMERICA;

Session altered.

SQL> select to_char (sysdate, 'D') from dual;

T
-
3

SQL> alter session set nls_territory=GERMANY;

Session altered.

SQL> select to_char (sysdate, 'D') from dual;

T
-
2

I need a way to know that the number '3' on the database with NLS_TERRITORY = AMERICA means a 'Tuesday' or the number '2' on a database with NLS_TERRITORY = GERMANY means "Tuesday" as well.

Hope I am clear enough.

And wish you all a happy new year :)

Kind regards
Smail

Use the format "IW" to get the date of Monday and the format "DAY" to get the "first day of the week. Then compare dates to see if they are identical.

ALTER SESSION SET NLS_TERRITORY = 'AMERICA';

SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday",
TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week",
MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON"
FROM DUAL CONNECT BY LEVEL <= 7;

Monday    NLS First day of week 1 if day 1 = SUN, 0 if MON
--------- --------------------- --------------------------
31-DEC-12 30-DEC-12                                      1
24-DEC-12 30-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1

alter session set nls_territory = 'FRANCE';

SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday",
TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week",
MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON"
FROM DUAL CONNECT BY LEVEL <= 7;

Monday   NLS First day of week 1 if day 1 = SUN, 0 if MON
-------- --------------------- --------------------------
31/12/12 31/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0

Or it could be simpler:

ALTER SESSION SET NLS_TERRITORY = 'AMERICA';

WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
SELECT INPUT_DAY,
TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
from data;

INPUT_DAY Day label
--------- ------------------------------------
        1 SUNDAY
        2 MONDAY
        3 TUESDAY
        4 WEDNESDAY
        5 THURSDAY
        6 FRIDAY
        7 SATURDAY

alter session set nls_territory = 'FRANCE';

WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
SELECT INPUT_DAY,
TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
from data;

INPUT_DAY Day label
--------- ------------------------------------
        1 MONDAY
        2 TUESDAY
        3 WEDNESDAY
        4 THURSDAY
        5 FRIDAY
        6 SATURDAY
        7 SUNDAY

How to get the difference in dates in days
Hi friends,

How to get the date difference between two dates exactly

date2-date1 days exactly... shouyld rounded to the nearest value of...

and one entire display i mean positive integer
Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

This gives negative also result
Hello

776317 wrote:
Hi friends,

How to get the date difference between two dates exactly

date2-date1 days exactly... shouyld rounded to the nearest value of...

Date1 - date2 is the exact number of days is after date2 date1. (It is as accurate as possible, given that the DATEs do not have fractions of a second).

and one entire display i mean positive integer
Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

You want to probably get the exact number of days first, then ROUND this number:
```
SELECT  ROUND (SYSDATE - TO_DATE (date_start, ...))   AS days
FROM    per_periods_of_service; 
```
Always pass arguments at least 2 to TO_DATE:
(1) the string to be converted, and
(2) a saying string how (1) is formatted

This gives negative also result

Right; If date1 is before date2 then date1 - date2 returns a negative number.
If you want to never get a negative value, use ABS (date2 - date1). If it returns 4, then you know that one of the DATEs was 4 days before the other, but you won't know who was earlier.

I hope that answers your question.
If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
Explain, using specific examples, how you get these results from these data.
Always tell what version of Oracle you are using.

How to get the date in the exact day in the field when another?
Hello

Please help me how to get the day of the week using another date field.

In fact, a field (week_day) has 1,2,3,4,5,6,7 here 1-, 2 - KILL like this.
another field has the date. After this date, go to this particular week and need to pick up the date of the Etiquettemois above. It should be this week there himself.

Thanks in advance!

Kind regards
Florian...

Published by: Florian on October 29, 2010 03:07
Maybe it's
```
select trunc(date_field,'D') + week_field - 1 from table
```

How to get the last day of the weekend rather than a month

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