How to get the week of the year in American Standard

Hello

I know that it might be a repetitive question, but has not found a convincing solution to him in any of the previous threads. I'm looking for a function (user defined, if someone has already written it) go the week of the year, American Standard. i.e., The week should begin on Sunday and end on Saturday (and NOT from Monday to Sunday)

03/01/2010 - should be the beginning of the 1st week of 2010... 10/01/2010 will be the beginning of the second week and so on
04/01/2009 - should be the beginning of the 1st week of 2009... 11/01/2009 will be the beginning of the second week and so on.

Does anyone have a function that takes a date as input and returns back the week of the year in the above format? Any help is greatly appreciated.

Thank you

You can add a day to your date in order to manipulate the weeks;

with t as (
   select to_date('02/01/2010','dd/mm/yyyy') dt from dual union all
   select to_date('03/01/2010','dd/mm/yyyy') from dual union all
   select to_date('09/01/2010','dd/mm/yyyy') from dual union all
   select to_date('10/01/2010','dd/mm/yyyy') from dual)
select dt, to_char(dt, 'Day') dy, to_char(dt+1, 'iw') wk
from t;

DT          DY        WK
----------- --------- --
02/01/2010  Saturday  53
03/01/2010  Sunday    01
09/01/2010  Saturday  01
10/01/2010  Sunday    02

Tags: Database

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Hello

I have a list of selection and when the user selects the list values are like this 201101,201102,201103

I tried like this

declare
T_DATE varchar2 (25);
Start
because me in 1.12 loop
Select TO_CHAR (ADD_MONTHS (SYSDATE, + 1), "YYYYMM") in the double T_DATE;
dbms_output.put_line (V_DATE);
end loop;
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But its bad and I can not get clear idea where to change the code

Thanks and greetings
Srikkanth.M
Srikkanth.M wrote:
Hello

I have a list of selection and when the user selects the list values are like this 201101,201102,201103

If you want to list for the current year from Jan 201101,201102, 201103... 201112, then try this
```
DECLARE
  v_Date  VARCHAR2(25);
  n_month NUMBER;
BEGIN
  SELECT extract (MONTH FROM sysdate) INTO n_month FROM dual;
  FOR i IN 1..12
  LOOP
    SELECT TO_CHAR(ADD_MONTHS(SYSDATE, (i-n_month)), 'YYYYMM')
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END;
```
Vivek L

How to get the year of Date data
Hi all

I have the following scenario:

County - Date - Code
5 DS - 01/09/2009
5 DS - 15/01/2009
5 LO - 21/01/2009
1. IT - 02/09/2009
5 DS - 03/09/2009
5 LO - 04/09/2009
4 DS - 05/09/2009
5 - IS - 06/09/2009
5 DS - 07/09/2009
5 - IS - 08/09/2009
3 DS - 09/09/2009
5 DS - 10/09/2009
5 LO - 11/09/2009
2 DS - 12/09/2009
5 DS - 01/09/2010
5 LO - 02/09/2010
4 DS - 03/09/2010

How can I only CDA data for 2009 and one year for 2010... Is meant by CDA 2009 data until the day of the date for example, if its 9 March today... TBE outcome will bring full jan, Feb and until the 9th day of March ' 09 and full jan, Feb and until the 9th day of March 10

Thank you

Published by: [email protected] on March 9, 2010 23:03

Published by: [email protected] on March 9, 2010 23:06
Something like:
```
where dt <= trunc(dt,'YYYY')+(trunc(sysdate,'DD')-(trunc(sysdate,'YYYY'))
```
"Dt" corresponding to your date column.

How to get the Date, month, year of the DateTimePicker

Hi, I am using the DateTimePicker.

There are several question about this command:

1. how to get the Date, month and year?

-With the help of myDateTime.value, I get this string ' Wed May 08 14:45 ICT 2013 '-> I have to manually analyze this? Because I need in format yyyy/mm/dd. Or can set the format of dateTimePicker.value?

2 format on dateTimePicker self (on the user interface) is d/m/YY, I can't change to another format?

Thank you

dateTimePicker.value return a QDateTime not a string.

https://developer.BlackBerry.com/Cascades/reference/bb__cascades__datetimepicker.html#property-value

See more:

https://developer.BlackBerry.com/Cascades/reference/QDateTime.html#date

https://developer.BlackBerry.com/Cascades/reference/QDate.html

You can get
```
day = dateTimePicker.value.date().day()
month = dateTimePicker.value.date().month()
year= dateTimePicker.value.date().year()
dateYYYYMMDD = dateTimePicker.value.date().toString(Qt::ISODate)
dateYYYYMMDD2 = dateTimePicker.value.date().toString("YYYY/MM/DD")
dateYYYYMMDD3 = dateTimePicker.value.toString("YYYY/MM/DD")
```

How to get the last day of the week?
HII

I can get the week number of calendar for a given date using

SELECT to_char (to_date('04/04/2011','MM/DD/YYYY'), 'WW') FROM dual

can any body tell me, how to get the last day of the week?

and the answer should be: 04/08/2011(8th april)
Thank you
San

Published by: sandeep9 on April 4, 2011 03:50
Perhaps this...
```
SQL> select trunc(sysdate,'WW')+6 from dual;

TRUNC(SYSDATE,'WW')+
--------------------
08-APR-2011 00:00:00

SQL>
```

How to get the date of end of week max and its rows of a table

Hello

Table [temp2]
 
   id          name        dt
  123        a             2-mar-2010
  124        b            1-feb-2010
  125        c             3-apr-2010
  123        a             13-mar-2010
  125        c             13-mar-2010
  123        a             12-feb-2010

This table how to get this line by id - name (id and the name of the composite key) whose date is the date of last weekend (last Saturday).
for example, suppose to have IDs 123 values date February 12, 2010, 13-mar-2010 this date falls on the last Saturday 13-mar-2010, how to get the value of the line on Saturday last for all the unique id and the name?

So I wrote this but probably there a few traps...

select id,name,dt from (select id,name,dt,max(dt) over(partition by id,name) as 
max_date from temp2) t where dt=t.max_date and dt in ('3-apr-2010'
,'27-mar-2010','20-mar-2010','13-mar-2010')

Here I have spent in the in clause 4 last weekend dates manually (although either has been calculated by programming) in front.
Thank you

Here's another option:

SELECT     *
FROM
(
     SELECT     ID
     ,     NAME
     ,     MAX(CASE WHEN TO_CHAR(DT,'DY','NLS_DATE_LANGUAGE=ENGLISH') = 'SAT' THEN DT END) AS DT
     FROM     TEMP2
     GROUP BY ID, NAME
)
WHERE DT IS NOT NULL

It is always useful to provide the following information:

1. oracle version (SELECT * FROM V$ VERSION)
2. examples of data in the form to CREATE / INSERT commands.
3. expected results
4 explanation of the expected results (alias "business logic")
5. use.

 tags for #2 and #3. See FAQ (Link on top right side) for details.

How to get the 'DAY' based on the territory of current account held a number between

Hi all

Looks like I'm at the end of my intelligence here but how to get the 'DAY' based on the territory of current account with a number between 1 and 7? Oracle has functions to extract the day of the week, but I can't find the other way around.

SQL> select * from v$version;

BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
CORE    11.2.0.3.0      Production
TNS for Linux: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production

SQL> alter session set nls_territory=AMERICA;

Session altered.

SQL> select to_char (sysdate, 'D') from dual;

T
-
3

SQL> alter session set nls_territory=GERMANY;

Session altered.

SQL> select to_char (sysdate, 'D') from dual;

T
-
2

I need a way to know that the number '3' on the database with NLS_TERRITORY = AMERICA means a 'Tuesday' or the number '2' on a database with NLS_TERRITORY = GERMANY means "Tuesday" as well.

Hope I am clear enough.

And wish you all a happy new year :)

Kind regards
Smail

Use the format "IW" to get the date of Monday and the format "DAY" to get the "first day of the week. Then compare dates to see if they are identical.

ALTER SESSION SET NLS_TERRITORY = 'AMERICA';

SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday",
TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week",
MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON"
FROM DUAL CONNECT BY LEVEL <= 7;

Monday    NLS First day of week 1 if day 1 = SUN, 0 if MON
--------- --------------------- --------------------------
31-DEC-12 30-DEC-12                                      1
24-DEC-12 30-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
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alter session set nls_territory = 'FRANCE';

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FROM DUAL CONNECT BY LEVEL <= 7;

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-------- --------------------- --------------------------
31/12/12 31/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0

Or it could be simpler:

ALTER SESSION SET NLS_TERRITORY = 'AMERICA';

WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
SELECT INPUT_DAY,
TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
from data;

INPUT_DAY Day label
--------- ------------------------------------
        1 SUNDAY
        2 MONDAY
        3 TUESDAY
        4 WEDNESDAY
        5 THURSDAY
        6 FRIDAY
        7 SATURDAY

alter session set nls_territory = 'FRANCE';

WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
SELECT INPUT_DAY,
TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
from data;

INPUT_DAY Day label
--------- ------------------------------------
        1 MONDAY
        2 TUESDAY
        3 WEDNESDAY
        4 THURSDAY
        5 FRIDAY
        6 SATURDAY
        7 SUNDAY

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Please help me. and thanks in advance... []

NET. RIM. Device.API.util
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Windows XP mode - 7: how to get the Realtek Audio Drivers with GS Wavetable outside normal? Instead of RDP Audio driver!

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Hello
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Thanks in advance.

Try the below

SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

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-(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

END as lastweekendday,

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SYSDATE + 300 enddate

THE DOUBLE)

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How to get the date for the first Monday of each month

Dear members,

How to get the date for the first Monday of each month.

I wrote the following code

SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL

But he looks at complex bith.

Abhishek

Published by: 9999999 on 8 March 2013 04:30

Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

select  sysdate current_date,
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/

CURRENT_D FIRST_MON
--------- ---------
08-MAR-13 04-MAR-13

SQL>

Here is the list of the first Monday of the month of this year:

with t as(
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select  dt first_of_the_month,
        trunc(dt + 6,'iw') first_monday_the_month
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/

FIRST_OF_ FIRST_MON
--------- ---------
01-JAN-13 07-JAN-13
01-FEB-13 04-FEB-13
01-MAR-13 04-MAR-13
01-APR-13 01-APR-13
01-MAY-13 06-MAY-13
01-JUN-13 03-JUN-13
01-JUL-13 01-JUL-13
01-AUG-13 05-AUG-13
01-SEP-13 02-SEP-13
01-OCT-13 07-OCT-13
01-NOV-13 04-NOV-13

FIRST_OF_ FIRST_MON
--------- ---------
01-DEC-13 02-DEC-13

12 rows selected.

SQL>

SY.

How to get the date in the exact day in the field when another?
Hello

Please help me how to get the day of the week using another date field.

In fact, a field (week_day) has 1,2,3,4,5,6,7 here 1-, 2 - KILL like this.
another field has the date. After this date, go to this particular week and need to pick up the date of the Etiquettemois above. It should be this week there himself.

Thanks in advance!

Kind regards
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Published by: Florian on October 29, 2010 03:07
Maybe it's
```
select trunc(date_field,'D') + week_field - 1 from table
```

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Hello

For the first time post here, but I wonder how to get the text of the titles have the same effect as the video behind her.

For my video, I use 'bad tv' and other effects such as Gaussian that obviously changes the appearance of video, creating the look of VHS. However, I then inserted text via the title, but it normally appears. How can I make this text have the same effects as the video behind it?

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One way is to create a clip made up based on the title and the original clip. Then apply the effect.

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Good luck.

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How to get the week of the year in American Standard

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