How to identify which switch in the Panel called the function?

Similar Questions

• Common cause of failure of the Mirage server in clustered environment and how customers will be switched to the other server in a cluster

  Hello

  Can someone share me information about common cause of failure of the Mirage server in clustered environment.

  And how customers will be switched to the other server in a cluster to continue their operations from the server failed.

  Kind regards

  C Bathesha

  In general, Mirage servers are not lacking. It is very rare (and not, for example, to problems of storage or endpoitns, which are more common).

  May raise problems of overload, memory or hardware malfunction too little.

  After that you make server standard troubleshooting (the etc system event log), you must file a Service request by VMware.

• How to identify columns that have the same data in a SQL query or function?

  Deal all,

  How to identify columns that have the same data in a SQL query or function? I have the sample data as below

  DEPT_ID

  EMP_ID

  Come on

  !CITYSTATECOUNTRY111 June 1983DELHIHUMAN RESOURCESIndia1218 January 1987DELHIHUMAN RESOURCESIndia1328 November 1985DELHIHUMAN RESOURCESIndia144 June 1985DELHIHUMAN RESOURCESIndia255 June 1983MUMBAIHDIndia266 June 1983MUMBAIHDIndia277 June 1983MUMBAIHDIndia288 Jun. 1983MUMBAIHDIndia399. June 1983GURGAONDLIndia31010 June 1983GURGAONDLIndia

  Now, I want to Indify columns that have the same data for the same Department ID.

  Is it possible in sql unique or do I have to write the function for this? Pls Help how to write?

  Thanks in advance.

  You can try this?

  WITH T1)

  DEPT_ID, EMP_ID, DATE OF BIRTH, CITY, STATE, COUNTRY

  ), ()

  SELECT 1, 1, TO_DATE('1.) June 1983', 'JJ. LUN. (YYYY'), 'DELHI', 'HR', 'INDIA' OF THE DUAL UNION ALL

  SELECT 1, 2, TO_DATE('18.) January 1987', 'JJ. LUN. (YYYY'), 'DELHI', 'HR', 'INDIA' OF THE DUAL UNION ALL

  SELECT 1, 3, TO_DATE('28.) November 1985', 'JJ. LUN. (YYYY'), 'DELHI', 'HR', 'INDIA' OF THE DUAL UNION ALL

  SELECT 1, 4, TO_DATE('4.) June 1985', 'JJ. LUN. (YYYY'), 'DELHI', 'HR', 'INDIA' OF THE DUAL UNION ALL

  SELECT 2.5, TO_DATE('5.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL

  SELECT 2.6, TO_DATE('6.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL

  SELECT 2.7, TO_DATE('7.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL

  SELECT 2.8, TO_DATE('8.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL

  SELECT 3, 9, TO_DATE('9.) June 1983', 'JJ. LUN. (YYYY'), 'GURGAON', 'DL', 'INDIA' OF THE DUAL UNION ALL

  SELECT 3.10, TO_DATE('10.) June 1983', 'JJ. LUN. (YYYY'), 'GURGAON', 'DL', 'INDIA' OF THE DOUBLE)

  SELECT DEPT_ID,

  RTRIM (XMLAGG (XMLELEMENT(A,VALS||',')). Extract ('//Text ()'), ',') COLUMNS_WITH_DUPLICATE

  DE)

  SELECT * FROM)

  SELECT DEPT_ID,

  EMP_ID,

  Date of birth

  CITY,

  STATE,

  COUNTRY

  DE)

  SELECT DEPT_ID,

  EMP_ID,

  Date of birth

  CITY,

  STATE,

  COUNTRIES,

  COUNT (*) OVER(PARTITION BY DEPT_ID ORDER BY EMP_ID DESC,DOB DESC,CITY DESC,STATE DESC, COUNTRY DESC) RN

  DE)

  SELECT DEPT_ID,

  CASE WHEN(CEID>1) AND THEN 'YES' ELSE 'NO' END AS EMP_ID.

  CASE WHEN(CDOB>1) THEN 'YES' ELSE 'NO' END AS DATE OF BIRTH,

  CASE WHEN(CCITY>1) AND THEN 'YES' ELSE 'NO' END AS CITY.

  CASE WHEN(CSTATE>1) AND THEN 'YES' ELSE 'NO' END AS STATE.

  CASE WHEN(CCOUNTRY>1) THEN 'YES' ELSE 'NO' END AS A COUNTRY

  DE)

  SELECT DISTINCT

  DEPT_ID,

  CEID,

  CDOB,

  CITY,

  CSTATE,

  CCOUNTRY

  DE)

  SELECT DEPT_ID,

  COUNT (*) TO THE CEID (DEPT_ID PARTITION, EMP_ID),.

  COUNT (*) ON CDOB (DEPT_ID SCORE, DATE OF BIRTH),

  COUNT (*) ON THE CITY (DEPT_ID PARTITION, CITY),

  COUNT (*) ON CSTATE (DEPT_ID PARTITION, STATE).

  COUNT (*) ON CCOUNTRY (DEPT_ID, COUNTRY PARTITION)

  FROM T1)))

  WHERE RN = 1)

  UNPIVOT (CLO FOR (VALS) IN (EMP_ID, DATE OF BIRTH, CITY, STATE, COUNTRY)))

  WHERE COLS = "YES".

  DEPT_ID GROUP;

  OUTPUT:

  DEPT_ID COLUMNS_WITH_DUPLICATE
  --------- ------------------------

  1 CITY, COUNTRY, STATE
  2 CITY, COUNTRY, STATE
  3 CITY, COUNTRY, STATE

  Post edited by: Parth272025

• How can I escape commas inside the function listQualify?

  I have

  am a newbie in coldfusion. I need help. My database has records of names of companies as: abc, Inc. For now I'm using this query:

  SELECT DISTINCT COMPANY FROM ComapanyTable WHERE (Company IN (#ListQualify(form.cCompanyList2, "'", ",")#))

  This problem is that it separates CBA, Inc..

  SELECT DISTINCT Company FROM CompanyTableWHERE (Company IN ('abc',' Inc.','xyz','Inc.'))

  I need to get the list, as it is, i.e. as: "abc, Inc.", "xyz, Inc." so that I can later insert these values into a new table.

  Insert the code:

  <cfquery name="insertPair" datasource="#DSN#" dbtype="ODBC"> INSERT INTO tblChildCompanyToParent (Parent_Account_ID, Child_Account_ID) SELECT DISTINCT <cfqueryparam value = "#form.pCompanyList#" CFSQLType = "CF_SQL_VARCHAR">, Company FROM CompanyTable WHERE Company IN (<cfqueryparam value="#ValueList(insertSelect.Company,';' )#" CFSQLType = "CF_SQL_VARCHAR" list="true" separator=";">) </cfquery>

  Code of the selection list

  <select multiple name="cCompanyList2" id="cCompanyList2" class="selectCCompany" data-attribute="selCCompany" size="10"> <cfloop query="childCompanyList"> <option value="#childCompanyList.Child_Account_ID#">#childCompanyList.Company#</option> </cfloop> </select>

  Y at - it anyway to solve this problem.

  Thank you for your help.

  I managed to fix it.

  I posted the solution to StackOverflow

  SQL - how can I escape commas inside the function listQualify? -Stack overflow

  Thank you once again!

• How to identify which instance is associated with what earphone

  Hi all
  I have created a DB instance. Suppose that named 'B '. but there is already another this DB instance. Named 'A '.
  Then, I created a listener instance DB 'B '.
  
  Now, my what, is that HOW can I identify which instance is associated with what listener.
  
  (2) if I create listener can also created service. If I stopped that service and then I can fire the query or Login again, WHAT will be the expected result.
  I tried to ask people of my answer. but not convinced.
  Please help me for this.
  Thanks in advance

  See the listener.ora file. It is usually $ORACLE_HOME/network/admin/listener.ora

  You can see what listener is associated with a file.

  Details will generally be like this

  >
  LSNR1 =
  (DESCRIPTION_LIST =
  (DESCRIPTION =
  (ADDRESS_LIST =
  (ADDRESS = (PROTOCOL = TCP) (HOST = instance1)(PORT = 1666))
  )
  )
  )

  LSNR2 =
  (DESCRIPTION_LIST =
  (DESCRIPTION =
  (ADDRESS_LIST =
  (ADDRESS = (PROTOCOL = TCP) (HOST = instance2)(PORT = 2666))
  )
  )
  )

  >

  >
  If I create listener can also created service. If I stopped that service and then I can fire the query or Login again, WHAT will be the expected result.
  I tried to ask people of my answer. but not convinced.
  >

  A listener is used when a client wants to connect to the database server. If you connect directly to the server without using the name of the instance, then you can connect even if you stop the service.

  Check it,

  C:\Windows\system32>lsnrctl stop
  
  LSNRCTL for 32-bit Windows: Version 10.2.0.3.0 - Production on 03-MAY-2011 23:06
  :22
  
  Copyright (c) 1991, 2006, Oracle.  All rights reserved.
  
  Connecting to (DESCRIPTION=(ADDRESS=(PROTOCOL=IPC)(KEY=EXTPROC1)))
  The command completed successfully
  
  C:\Windows\system32>sqlplus ganesh
  
  SQL*Plus: Release 10.2.0.3.0 - Production on Tue May 3 23:06:36 2011
  
  Copyright (c) 1982, 2006, Oracle.  All Rights Reserved.
  
  Enter password:
  
  Connected to:
  Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - Production
  With the Partitioning, OLAP and Data Mining options
  
  SQL> select * from dual;
  
  D
  -
  X
  
  SQL>
  

  But if you try to connect from a client, or use the name of the instance, while connectineg
  you get the error like that,

  SQL> conn ganesh@ganesh
  Enter password: ******
  ERROR:
  ORA-12541: TNS:no listener
  
  Warning: You are no longer connected to ORACLE.
  SQL> 
  

  If you see, I used the name of the @ganesh instance.

  G.

• Please help me identify which port is the port of USB 3.0 HP Compaq 15 - s001TU (G8D87PA)

  Hello Experts,

  Today, I got my 15-s001TU (G8D87PA) computer laptop HP Compaq. First of all thanks to HP & manufacturer to create this wonderful product. It seems absolutely stunning after opening the box. I opted for free Dos version, which equals no BONES.

  In any case I use it for 7 hours with latest version of Ubuntu 14.04 - 1 LTS and experinced is great. But I can't able to identify which USB port is a USB 3.0 among all available USB ports. In this model, there are three USB ports available - two located right off DVD player and one located next to left hand next to the LAN port and all are in black color.

  Now the litarature provided with this laptop is very in the Appendix, so anyone who can let me know which one is USB 3.0, it will be very useful.

  Thanks for the help.

  ArijitB14 wrote:
  

  Hello Experts,

  Today, I got my 15-s001TU (G8D87PA) computer laptop HP Compaq. First of all thanks to HP & manufacturer to create this wonderful product. It seems absolutely stunning after opening the box. I opted for free Dos version, which equals no BONES.

  In any case I use it for 7 hours with latest version of Ubuntu 14.04 - 1 LTS and experinced is great. But I can't able to identify which USB port is a USB 3.0 among all available USB ports. In this model, there are three USB ports available - two located right off DVD player and one located next to left hand next to the LAN port and all are in black color.

  Now the litarature provided with this laptop is very in the Appendix, so anyone who can let me know which one is USB 3.0, it will be very useful.

  Thanks for the help.

  Page 6 and 7 through 15 HP Notebook PC Compaq 15 Notebook PC Maintenance and Service of Guide

  The single USB port on the left side is the 3.0 a

  Kind regards

• How to know which update causes the system crash

  Can you tell us how to check the update is the culprit?

  Hi Steve,.

  Inorder to know which update is the cause of the crash of the system, you can install the updates one by one. Firstly uninstall the updates that have been recently installed.

  Uninstall the update:

  1. click on start and type "update installed" in the searc box. Click on view installed updates

  2. right click on the update you want to uninstall. Once the uninstall is complete, reboot the computer.

  3. install the updates one by one.

  You would get to know what update is at the origin of the disorder. You can hide this particular update.

• How to find which user have the Channel Manager

  Hello
  
  How to find which user are responsible for R12 Channel Manager.
  
  And how to invite the partner already in the list of my partners.
  
  Please answer me as soon as possible
  
  Thank you
  Vivek

  How to find which user are responsible for R12 Channel Manager.

  You can run 'The responsibility one users' simultaneous program or run the script in (how to find Out who the responsibility has been granted to A specific user? [ID] 304687.1).

  Please answer me as soon as possible

  For the responses of the ASAP, please log an SR.

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• How to identify which disk rawdevice is named as VOL1 in ASM OS level

  Hi friends,
  
  creation of the disk using the ASMLIB
  I want to know which drive is named as VOL1, VOL2, VOL3 etc. LINUX operating system.
  
  I know using v$ asm_disk we can query name, path, status, tag, etc...
  
  I want to know what raw device disk is named or configured as VOL1 (LINUX) operating system
  
  Thanks in advance.
  
  Rajesh.
  
  Published by: rajeysh on June 3, 2010 15:49

  And for this, you can use oracleasm querydisk. Using that you can identify which device marked for asm or not. for example you can see below the example.

  [oracle@localhost init.d]$ sqlplus "/as sysdba"
  
  SQL*Plus: Release 10.2.0.4.0 - Production on Thu Jun 3 11:52:12 2010
  
  Copyright (c) 1982, 2007, Oracle.  All Rights Reserved.
  
  Connected to:
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bit Production
  With the Partitioning, OLAP, Data Mining and Real Application Testing options
  
  SQL> select path from v$asm_disk;
  
  PATH
  --------------------------------------------------------------------------------
  /dev/oracleasm/disks/VOL2
  /dev/oracleasm/disks/VOL1
  
  SQL> exit;
  
  [oracle@localhost init.d]$ su
  Password:
  [root@localhost init.d]# /sbin/fdisk -l
  
  Disk /dev/sda: 80.0 GB, 80000000000 bytes
  255 heads, 63 sectors/track, 9726 cylinders
  Units = cylinders of 16065 * 512 = 8225280 bytes
  
     Device Boot      Start         End      Blocks   Id  System
  /dev/sda1   *           1        1305    10482381   83  Linux
  /dev/sda2            1306        9401    65031120   83  Linux
  /dev/sda3            9402        9662     2096482+  82  Linux swap / Solaris
  /dev/sda4            9663        9726      514080    5  Extended
  /dev/sda5            9663        9726      514048+  83  Linux
  
  Disk /dev/sdb: 80.0 GB, 80026361856 bytes
  255 heads, 63 sectors/track, 9729 cylinders
  Units = cylinders of 16065 * 512 = 8225280 bytes
  
     Device Boot      Start         End      Blocks   Id  System
  /dev/sdb1               1        4859    39029886   83  Linux
  /dev/sdb2            4860        9729    39118275   83  Linux
  [root@localhost init.d]# ./oracleasm querydisk /dev/sdb1
  Device "/dev/sdb1" is marked an ASM disk with the label "VOL1"
  [root@localhost init.d]# ./oracleasm querydisk /dev/sdb2
  Device "/dev/sdb2" is marked an ASM disk with the label "VOL2"
  [root@localhost init.d]# ./oracleasm querydisk /dev/sda1
  Device "/dev/sda1" is not marked as an ASM disk
  [root@localhost init.d]# 
  

  Also in windows:

  C:\Documents and Settings\comp>asmtool -list
  NTFS                             \Device\Harddisk0\Partition1           140655M
  ORCLDISKDATA1                    \Device\Harddisk0\Partition2             4102M
  ORCLDISKDATA2                    \Device\Harddisk0\Partition3             4102M
  NTFS                             \Device\Harddisk0\Partition4           152617M
  
  C:\Documents and Settings\comp>
  

  It's answering your question. :-)

• How to identify objects granted to the public

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• How to write to .subckt with the function I - V

  Hi all

  Now, I am trying to build a Spice model for a type of diode high voltage for 13 Multisim. Because I do not have the LED electronic settings, and I only have the function of the I - V, I tried to write a file .subckt for him.

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  Any body can help me to check if my .subckt is correct or not? Thank you.

  It seems that the convergence error is caused by a discontinuity the diode to connection 53V.  Run DC scan using the test circuit.

  

  To prevent the discontinuity, use the express following with the fi works instead. You can give it a small current when V (A1, A2) is less to 0V.

  B1 A1 A2 I=if(((V(A1)-V(A2))-51)>0,((0.581*(V(A1)-V(A2))*(V(A1)-V(A2))/3/3-18.4*(V(A1)-V(A2))/3+144.66)/1000),-230u)

  The attached circuit have a resistance using convergence.

  You can simplify your expression for readability:

  -(V, (A1), (A2) V) = V (A1, A2)

  -If you can do the expression in this form, it will simply be the calculation ax ^ 2 + bx + c

• 5520 photosmart all-in-one: how to identify which cartridge needs replacing on 5520

  My computer showed me the message that the printer ink is running low.  I open the printer to replace the cartridge, but I don't see what cartridge, color or black, that has to be changed.  On my previous printer, low cartridge has been identified by a flashing light.

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  Hello

  Since the home printer screen, tap ink icon (symbol of gout).

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• How to identify a pirate on the computer?

  Original title: How can I find out what files/info (shared without permission) have been hacked by someone I know) on my computer...

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  Here it is in plain English:

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