How to merge the 4 document files under 1 name of file under XP?

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  How to count the number of nodes under each parent in any given xml. for example the xml below was
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  Book1 Tagus repeated twice... vice versa. do we need to make plsql lie we can achieve through sql
  
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  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  ACR < book1 > < / book1 >
  Lac < Book4 > < / Book4 >
  < / book >
  < library >
  ABC < book1 > < / book1 >
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  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
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  Select
  XMLQUERY ('count($doc/Books/descendant::*)' in the way of xmltype ("< books >
  < library >
  ABC < book1 > < / book1 >
  ACR < book1 > < / book1 >
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  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
  (< / books > ')
  as 'doc' of happy return) .getNumberVal () as node_count
  of the double
  
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  Published by: user7955917 on August 24, 2012 07:26

  Generic function how you want the query to be.

  If the structure is known in advance, as in your example a 'books' and then a 'library' root element, it's as simple as:

  SQL> select x1.parent_id, x2.child_name, count(*)
    2  from tmp_xml t
    3     , xmltable(
    4         '/books/bookstore'
    5         passing t.object_value
    6         columns parent_id   for ordinality
    7               , child_list  xmltype path '*'
    8       ) x1
    9     , xmltable(
   10         '/*'
   11         passing x1.child_list
   12         columns child_name varchar2(30) path 'name()'
   13       ) x2
   14  group by x1.parent_id, x2.child_name
   15  order by x1.parent_id, x2.child_name
   16  ;
  
   PARENT_ID CHILD_NAME                       COUNT(*)
  ---------- ------------------------------ ----------
           1 book1                                   2
           1 book2                                   1
           1 book4                                   1
           2 bookn                                   1
           2 bookn_1                                 1
           2 book1                                   1
           2 book2                                   1
           2 book3                                   2
           3 book1                                   1
           3 book2                                   1
  
  10 rows selected
   
  

  If you want a generic solution that works without knowledge of the structure, you will need a recursive approach, and most importantly, you should know which nodes in distinct, I suppose that the leafs?

  Also, please help if you can provide the link of reference on the function name() years what are the other expression, that I can use after the path

  You can start reading the documentation: http://docs.oracle.com/cd/E11882_01/appdev.112/e23094/xdb_xquery.htm#CBAGCBGJ

  The clause PATH expects a XQuery expression however before 11.2, we can put only simple XPath expressions.

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