How to post jsp code snippets without losing the bet in shape

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• How to remove a basedOn style without losing the bet in shape

  I have a problem that I solved in my case, but I wonder if there is a cleaner solution. I have a function that removes the basedOn of a paragraph style or a character style that is passed. I thought that it worked, but it came to my attention that the character styles were losing their formatting when their basedOn style has been deleted (in fact, the value '[No Style character]'). Set the style basedOn the "[None]" style has the same effect. I also tried to create a dummy no style and use it as my base, same effect. When you do this through InDesign UI, the formatting is preserved, so I think it's a bug. My solution has been to create a new character style, all properties of the first style (except basedOn and properties) copy on it, delete the original style (replace with the new style), and then rename the new style to match the old. Far as I can tell it works, but it seems exaggerated. Does anyone have a better suggestion or hint?

  Here is the code that causes the problem:

  function unBaseStyle(funcSty){
      //Current style name.
      var myStyName = funcSty.name;
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      if (myStyName.lastIndexOf("[", 0)  != -1) {return false;}
      else{
          var myBaseStyName = funcSty.basedOn.name;
          //Checks that the base style isn't undefined (which would indicate that it is already [No ... Style] and also that it isn't bracketed.
          if (myBaseStyName == undefined || myBaseStyName.lastIndexOf("[", 0)  != -1) {return false;}
          else{
              //If the style is a paragraph style, bases it on [No Paragraph Style].
              if (funcSty instanceof ParagraphStyle){funcSty.basedOn = "[No Paragraph Style]";}
              //If the style is a character style, bases it on [No Character Style].
  //--->This is the line that causes the problem. funcDoc.characterStyles("None") has the same effect.
              else{funcSty.basedOn = "[No Character Style]";}
              return true;
          }
      }
  }
  

  Here is my code to work:

  function unBaseStyle(funcDoc, funcSty){
      //Current style name.
      var myStyName = funcSty.name;
      //If the style is surrounded in brackets it is a default InDesign style and should not be unbased. In that case, skips to next style.
      if (myStyName.lastIndexOf("[", 0)  != -1) {return false;}
      else{
          var myBaseStyName = funcSty.basedOn.name;
          //Checks that the base style isn't undefined (which would indicate that it is already [No ... Style] and also that it isn't bracketed.
          if (myBaseStyName == undefined || myBaseStyName.lastIndexOf("[", 0)  != -1) {return false;}
          else{
              //If the style is a paragraph style, bases it on [No Paragraph Style].
              if (funcSty instanceof ParagraphStyle){funcSty.basedOn = "[No Paragraph Style]";}
              //If the style is a character style, bases it on [No Character Style].
                  else{
                      var funcStyName = funcSty.name;
                      var newSty = funcDoc.characterStyles.add(funcStyName + " basedOnCopy");
                      var p
                      for (p in funcSty){
                          if (funcSty.hasOwnProperty(p) && p != "basedOn" && p != "properties"){
  //-->This copies over the properties; wrapped in try/catch because some properties are read-only.
                              try{newSty[p] = funcSty[p];}catch(e){}}
                      }
                      funcSty.remove(newSty);
                      newSty.name = funcStyName;
              return true;
          }
      }
  }
  

  Am I missing something or is my solution more or less the way forward?

  Hi cchimi,

  Easily check if a style property is inherited is a question open for me

  Perhaps our fellow Scripting Guys have some ideas on this point.

  In regards to your routine of rewriting from scratch , a better approach (although not fully tested) may be:

  function unBaseStyle(/*ParagraphStyle|CharacterStyle*/sty)
  {
      var o = sty.properties;
      if( !o.hasOwnProperty('basedOn') || 0 <= o.name.indexOf('[') ) return;
      o.basedOn = "$ID/None";
      sty.properties = o;
  }
  

  @+

  Marc

• How to use reveal all this without losing the work of culture?

  My workflow is to editing and cropping of images. I need the flexibility to perform any order.

  When I use the crop tool, I continue to delete the cropped Pixels unchecked. When I edit the images I want to edit the complete picture, not cropped image.

  If I use reveal all to make alterations on the full image after cropping, I lose my job of cropping. Is there a solution?

  How to use reveal all this without losing the work of culture?

  How to take a bath without getting wet?

  Enter drollery side you could use a path of access to store the current size before calling "Reveal everything", then later on the path as a selection of load, switch to the crop tool and hit.

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• How can I copy properties related without losing the connection to the control?

  I have dealt with a problem that is boring when copying / pasting properties. If the properties are bound to a control when copy them, they lose this link in the pasted version.

  Basically, the paste does not really the expected behavior of 'copy', 'paste' that results is different from the copied item. Is there a way to get around this in addition to having to go to each of them and re - link manually?

  Here are the excerpts to demonstrate the problem:

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  After pasting:

  

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