How to query a date range?
I have a table containing data of holiday such as the sites they visit, and the date of their departure.I need a query that displays only the holidays departing in June 2011. I had to work for specific dates for example = June 2, 2011 "."
But if I try and make more than a date for example = June 2, 2011 ", 15/06/2011"... or just June in general it does not work.
Is there a way to do this? Use Query Builder by the way, I'm happy to use SQL commands if that's easier.
Thanks in advance!
Howdy
You must use BETWEEN ie.
WHERE column1 BETWEEN '01-JUN-2010' AND '30-JUN-2010'
See you soon
Ben
Tags: Database
Similar Questions
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Hello
I have the rest of the table. I want to merge the date ranges if dates are continuous and the value is the same. I use Oracle 10 g. Help, please.
START_DATE END_DATE VALUE
----------------------------------------------------------------
1/1/2008 12/31/2008 1234
1/1/2009 12/31/2009 1234
Exit statement SQL must be as follows:
START_DATE END_DATE VALUE
----------------------------------------------------------------
1/1/2008 12/31/2009 1234
Thanks in advance.
Published by: user3898545 on January 27, 2010 19:44Hello
user3898545 wrote:
Hello
Dates will not overlap but sometimes start_date can be equal to end_date in a row.Sorry, I'm not sure of that figure.
If the query I posted is not giving correct results, post some samples (CREATE TABLE and INSERT statements are best, but a clause WITH as Tubby displayed is correct) and the correct results, you need these data.Please suggest if something needs to be done through pl/sql performance is also the key.
I don't see how the PL/SQL will help in this problem.
When two lines need to be combined, the end_date ranked sooner than always exactly 24 hours before the start_date on the line later?
If so:WITH got_grp AS ( SELECT data.* , end_date - SUM (end_date + 1 - start_date) OVER ( PARTITION BY val ORDER BY start_date ) AS grp FROM data ) SELECT MIN (start_date) AS start_date , MAX (end_date) AS end_date , val FROM got_grp GROUP BY val , grp ORDER BY val , start_date ;
Published by: Frank Kulash, 28 January 2010 14:03
For example, a subquery added. -
How to query the data of Contact with multiple fields
How can I query the data of Contact with multiple fields?
For example, I'll get contacts which are changed after a point at the specified time and whose country is US. How could I make the chain of research of the SOAP API "Query"?
And I also want to know how to make a search term for RESTful API for contacts above.
Any suggestions?
Thank you.
Hi Biao,
The following document describes how query for multiple fields using the SOAP API: request a Contact from several fields.
And you can search multiple fields using the REST API with the & operator. For example, to search for a Contact by e-mail address and date of creation:
- " emailAddress ='[email protected]' & converted > = '1369828886'".
Hope this helps and please let us know if you need more information.
Thank you
Fred
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How to pass the date range as in URL filter go
Hello
I am trying to build a Url go that has two filters, date range & text. I built the url below, but he continues to throw an error. The url is not from the date max and the app starts following error:
Error: Status: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error occurred. [nQSError: 46048] Month DateTime value 0 0000-00-00 is off limits. (HY000)
Go to Url: https:companyUrl? GB & Options = rfd & Path = / shared/CompanyID/link & P0 = 2 & P1 = eq & P2=CustomObject4.%22Indexed%20Pick%201%22 & P3 = Leasing & bet = P4 & P5 = ""-CustomObject4 Custom Attributes '. " ZDate_26 & P6 = 2 + Date % 20'2014-08-01'+ day % 20'2014-12-31'
Please suggest.
Thank you
Kiran.It seems that you convert the data type of char to date in the URL, I don't think that this is possible.
Your code is like
& P6 = 2 + Date % 20'2014-08-01'+ day % 20'2014-12-31'It suppose to be & P6 = 2 + 2014-08-01 + 2014-12-31
I suggest doing the formatting for this filed using column properties and try.
Hope this help, pls mark if yes ;)
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How to query these data as a tree structure
Hi, how to write a query to manipulate data like tree structure report? The rules for the structure of the tree are: CORE is always a node root (level 1), level 2 is a location any is not have "/" exclude those beginning of slot with PWR. This tree structure can continue to level 3 and so on
POSITION OF SLOT CORE F1 FAN PWR/1 1 2 1/0 1/1 1/2 1/0/0 1/0/1 G1 G4 G4/0 G4/1 Output, * the order of level 2 is not necessary must begin with the F1, it can be any value of level 2
CORE
F1
FAN
PWR/1
1
1/0
1/0/0
1/0/1
1/1
1/2
2
G1
G4
G4/0
G4/1
Hello
If you want to CONNECT BY queries, you need to know the parent of each element. Here's a way to do it:
WITH got_parent AS
(
SELECT slot_position
CASE
WHEN slot_position = 'CORE '.
THEN NULL
WHEN slot_position NOT LIKE "% / %".
OR slot_position LIKE '% PWR '.
THEN THE "HARD CORE".
Of OTHER SUBSTR (slot_position
1
, INSTR (slot_position, ' / ', - 1)-1
)
END AS parent
FROM table_x
)
SELECT LPAD (' ', 4 * (LEVEL - 1))
|| slot_position AS padded_slot_position
OF got_parent
START WITH parent IS NULL
Parent = slot_position PRIOR CONNECTION
;
If you would care to post CREATE TABLE and INSERT instructions for the sample data, and then I could test this.
An alternative to CONNECT BY would generate a string similar to slot_position, but including all ancestors, such as:
CORE
CORE/1
CORE/1/0
CORE, 1, 0, 0
-
How to use the Date range parameter.
Dear all,
In the human resources Module, I developed a leave leave of synthesis report that gathers data from employees on.
The end user will pass the parameter of date_start and date_end.
The question is, if an employee only e-123 takes leave of 22 July 2013 to August 10, 2013
and the user passes the parameter for the month of July date_start = 1 July 2013 "and date_end = July 31, 2013" for the sub condition
"AND TRUNC (Pab.DATE_START) > =: Date_START - July 1, 2013.
"AND TRUNC (Pab.DATE_END) < =: Date_END - July 31, 2013.
Emp E-123 appears in the report.
But if the user passes the parameter of the month August 1 August 2013 ", 31 August 2013", EMP - 123 does not...
Please suggest how to write the condition he can for all conditions.
Kind regards
Afzal.
Hello
OR condition is to be enclosed with parentheses.
If place you within the parenthesis, then take no time to deal with.
-
Respecetd guru,
I have the task of representing date at the end of each month of start of range.
it show like this...
01-sep-2009 to 30-Oct-2009
so now...
plez help me.can you give example of this... so on can be something like this
SQL> select to_char(trunc(sysdate,'mm'),'dd-mon-yyyy')||' to '||to_char(last_day(sysdate),'dd-mon-yyyy') dt from dual; DT -------------------------- 01-sep-2009 to 30-sep-2009
Please explain more clearly.
-
Copy files from specific date ranges in a Batch file
I'm trying to copy files from a folder with many subfolders to another drive using a batch file. I want to copy the files in the date ranges specific (e.g. 01/01/2016 to 03/31/2016).
I use this with Xcopy command:
xcopy "C:\Users\John\Pictures\*.*" F:\BACKUP\Pictures/s/h/i/y
It works, but I want to send groups of files by date for the different destination folders. I'm having a problem by specifying a date range in the command line.
Is this possible with xcopy or robocopy? Does anyone know how to list the date rang in the command?
Thankss in advance,
John
Hello
Please contact Microsoft Community.
I understand you wanted to know about the files and folders by using the copy command line.
I suggest you go through the links below:
Refer to the suggestion given by SpiritX MS MVP replied on 14 August 2010 and check if that helps:
If the still the problem persists, I suggest you to post your query on TechNet:
Feel free to write us again with the status of the issue.
-
Hi Experts,
Kindly inviting you to advise how to generate a Date Range as
JAN-01-14
JAN02-14
JAN03-14
JAN04-14
.
.
.
.
UP TO
DEC-31-14 or any DATE i.e Date between two months as JAN - 14 JUL-14.
Also, please indicate how do if I need to generate it between two years as 2013 and 2015.
Hello
Saroha Amit wrote:
Hi Frank,.
Please suggest where to use TO_CHAR in your suggestion.
Rather than display a DATE in the SELECT clause, you can use TO_CHAR, where 1 is the DATE, like this:
WITH target_dates AS
(
SELECT DATE ' 2014-01-01' AS first_date
, DATE '' 2014-01-04 AS last_date
OF the double
)
SELECT TO_CHAR ( first_date + LEVEL - 1).
, "MONDD-YYYY".
) AS a_date
OF target_dates
CONNECT BY LEVEL<= 1="" +="" last_date="" -="">=>
;
-
How to get the second Monday of each month in a given date range?
In Oracle forms, how to get the second Monday of each month in a given date range?
I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?
WITH month_range AS
(
SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month
, TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month
OF the double
)
SELECT NEXT_DAY (6 + ADD_MONTHS (first_month
, LEVEL - 1
)
, 'MONDAY '.
) AS second_monday
OF month_range
CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)
;
Thanks in advance.
Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below
SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.
THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')
Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7
END AS second_day
FROM (SELECT SYSDATE startdate,
SYSDATE + 300 enddate
THE DOUBLE)
CONNECT BY LEVEL<=>=>
-
Hi Experts,
A very happy new year to all of you (a little in advance)!
I have a table where I have the id of employee and the task assigned with the start dates and end dates. Overlap in the dates of the tasks is a data delivers however I know how to spot them and eliminate. There is therefore no date of tasks that overlap
Employee_id
Task_No
Task_Start_date
Task_End_Date
Examples of data
1 T1 1 January 2014 February 28, 2014
1 T2 March 1, 2014 31 December 2014
2 T1 23 January 2014 31 December 2014
2 T2 1 January 2015 December 31, 2073 (means end of time)
3 T3 1 January 2014 July 15, 2014
3 T4 August 1, 2014 31 December 2014
T5 4 1 January 2014 December 31, 2073
I want to design a query where I provide the end date and it will list all the employees that are free for the same day from 1 January 2014. Thus, for example, if I give December 31, 2014, it will list the
EmpId (first day where the employee is free)
2 January 1, 2014
3 July 16, 2014
If I give the end = end date of time(31-Dec-2013), result-
EmpId (first day where the employee is free)
1 January 1, 2015
2 January 1, 2014
3 July 16, 2014
If I give the end = date January 31, 2014, expected - result
EmpId (first day where the employee is free)
1 January 1, 2015
I conceived after the request, but he intercepted not 2 employee ID. Also, it provides no flexibility to change end date-
Select *.
from (select employe_id,
task_start_date,
task_end_date,
lag (task_end_date, 1, task_start_date) on prev_end_date (partition by employee_id arrested by task_start_date)
of shop.employee_tasks
where task_end_date > = trunc (sysdate))
where task_start_date - prev_end_date > 1
Thanks in advance!
Kind regards
This is an example of what I call the query 'free time': you have the dates when you are busy and you want the dates where you are free.
You can find a nice solution for the problem of base here: ask Tom "SQL Query to find gaps in the date ranges" (search for solution of Anthony Boucher). Please note that this solution works even with the date ranges overlap.
To apply the solution here, first create the test data (please do it yourself in the following questions).
create table t(Employee_id, task_no, Task_Start_date, task_end_date) as select 1, 'T1', to_date('01-jan-2014'), to_date('28-feb-2014') from dual union all select 1, 'T2', to_date('01-Mar-2014'), to_date('31-Dec-2014') from dual union all select 2, 'T1', to_date('23-jan-2014'), to_date('31-dec-2014') from dual union all select 2, 'T2', to_date('01-jan-2015'), to_date('31-dec-2073') from dual union all select 3, 'T3', to_date('01-jan-2014'), to_date('15-jul-2014') from dual union all select 3, 'T4', to_date('01-aug-2014'), to_date('31-dec-2014') from dual union all select 4, 'T5', to_date('01-Jan-2014'), to_date('31-Dec-2073') from dual;
In the query, you must add records for yesterday and for the "end date" you want. This allows you to "free time" before and after the date ranges in your table.
Now, you partition by order of Task_Start_date and employe_id. Using the analytical function of the max (task_end_date), you get the last date of end so far. Add 1 and you get the first time (maybe). To make sure that the date is free, it must be before the next start date.
variable end_date varchar2(64) exec :end_date := '31-Dec-2073'; -- with boundaries as ( select trunc(sysdate)-1 task_start_date, trunc(sysdate)-1 task_end_date from dual union all select to_date(:end_date)+1, to_date(:end_date)+1 from dual ), data as ( select * from t where task_end_date >= trunc(sysdate) and task_start_date < :end_date union all select distinct a.employee_id, null, b.task_start_date, b.task_end_date from t a, boundaries b ) select employee_id, min(free_start) free_start from ( select employee_id, max(task_end_date) over (partition by employee_id order by task_start_date)+1 free_start, lead(task_start_date) over (partition by employee_id order by task_start_date)-1 free_end from data ) where free_start <= free_end group by employee_id;
EMPLOYEE_ID FREE_START 1 JANUARY 1, 15 2 1 JANUARY 14 3 16 JULY 14 -
HOW CAN I SORT MICROSOFT MONEY BY A DATE RANGE?
I have Microsoft Money 2007 on my computer and I am trying to sort all of my information by date range. Janrary 2009 - January 2010, how do I do that?
Hello
Please repost in the silver forum
Use this forum to discuss Microsoft Money. This includes money, more and more older versions.
-
How to increase the available on report date range
Hi gurus,
On the BigBrother report page, we can define the date range considered. The date start and end on our BigBrother cannot be defined until 2010 (see this screen below). How can I report for 2012 and beyond?
Any help will be very appreciated!
Michael
Micheal,
Here's how I did it.
I have the latest version for free.
Modify the [BBHOME]/www/help/bb-rep.html file
Line 95:
And also to line 153:
I hope this helps!
-
How to filter for a range of dates calendar events in OS10
In earlier versions of BlackBerry, I used blackberry.find.FilterExpression to filter the events calendar for a specific range of dates.
However for BlackBerry OS10 I scoured the web to find a way to do it. I found:http://developer.blackberry.com/html5/apis/blackberry.pim.calendar.calendarfindoptions.html
I also googled a lot of other sites, but I am unable to understand how to use CalendarFindOptions to refine the calendar of events of a specific timetable. For example, the current week or the next 7 days.
I found this code example...
Function listEvents (limit) {}
Calendar var = blackberry.pim.calendar;
var CalendarFindOptions = calendar. CalendarFindOptions;
var findOptions = {}
'Sort': [{}
"fieldName": CalendarFindOptions.SORT_FIELD_SUMMARY.
'desc': false
}],
'detail': CalendarFindOptions.DETAIL_AGENDA,
'limit': limit
};But unable to find examples how adequately limited by date?
I'm guessing that something like this:
'Start': new Date (' January 1, 2013, 13:00 "): CalendarFindOptions.SORT_FIELD_START.
'end': new Date (' January 1, 2013, 16:00 "): CalendarFindOptions.SORT_FIELD_STOP.But it is an assumption and does not work I can find no example of how do
Any help would be appreciated
See the example for pimcalendar on Github:
https://github.com/BlackBerry/BB10-WebWorks-samples/tree/master/pimcalendar
You can find the JS to set filters of beginning and end starts here:
https://github.com/BlackBerry/BB10-WebWorks-samples/BLOB/master/pimcalendar/index.html#L107
-
How the lack of dates online results of the query and convert the output
Hi Experts,
My inline query returns the data in this format
2-jan-2016 10 4-jan-2016 33 5-jan-2016 20 7-jan-2016 70 8-jan-2016 77
I want to display the output as
1-jan-2016 2-jan-2016 3-jan-2016 4-jan-2016 5-jan-2016 6-jan-2016 7-jan-2016 8-jan-2016 9-jan-2016 10-jan-2016 0 10 0 33 20 0 70 77 0 0
Can you please help me with query how over the missing dates, is it tier, collar or pivot?
Thanks in advance.
Kind regards
IVW
Hello
Is that what you are looking for?
WITH
SampleSet
AS (SELECT TO_DATE (' 2 January 2016', 'DD-mon-yyyy') dt, val 10 FROM DUAL)
UNION ALL
SELECT TO_DATE (' 4 January 2016', 'DD-mon-yyyy'), 33 FROM DUAL
UNION ALL
SELECT TO_DATE (' 5 January 2016', 'DD-mon-yyyy'), 20 FROM DUAL
UNION ALL
SELECT TO_DATE (' 7 January 2016', 'DD-mon-yyyy'), 70 FROM DUAL
UNION ALL
SELECT TO_DATE (' 8 January 2016', 'DD-mon-yyyy'), 77 FROM DUAL
)
sample_rn as
(
Select
DT
val
, dt - min (dt) (order 1) + 1 rn
2 line_no
Of
SampleSet
order by
DT
)
mindate as
(select min (dt) dt sampleset)
dates in the FORM
(
SELECT
DT + level 1 - dt
null val
level rn
1 line_no
Of
MinDate
CONNECT BY ROWNUM<= 10 ="" --="" number="" of="">=>
)
a, as
(
Select
to_char Col (DT)
rn
line_no
Of
dates d
Union
Select
to_char Col (Val)
rn
line_no
Of
sample_rn
where
RN<= 10 ="" --="" number="" of="">=>
)
Select
*
Of
a pivot (pass the max (col) of rn (1,2,3,4,5,6,7,8,9,10))--liste of columns 1 to))What makes a list with 2 rows. Line 1 has dates starting with the first data of sampleset. and line 2 has the values. The number of columns, you can determine yourself.
Kind regards
Peter
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