How to select the data that meet multiple criteria
name load_date-------- ----------------
Smith 11/02/2010
John 01/10/2009
Cindy 03/04/2010
Smith 03/10/2010
I want to select all names including load_date exist in February AND March.
Expected results: -.
Smith
I can use the intersect operator to get all the names that were given in February AND March by using the following query.
Select the name of the table where to_char ("load_date, ' FMMonth YYYY") = "February 2010"»
intersect
Select the name of the table where to_char ("load_date, ' FMMonth YYYY") = "March 2010"»
Y at - it an easier way to retrieve the same data that is similar to the use group by, having cluase etc?
Thanks in advance.
Hello
You can do it in one pass through the table with GROUP BY and HAVING:
SELECT name
FROM table_x
WHERE load_date >= DATE '2010-02-01' -- First date inside target range
AND load_date < DATE '2010-04-01' -- First date OUTSIDE target range
GROUP BY name -- not TRUNC (load_date, 'MONTH')
HAVING COUNT (DISTINCT (TRUNC (load_date, 'MONTH'))) = 2
;
Try to keep the columns indexed by themselves in comparisons; in this way, you can use indexes.
For example, if there is an index on load_date, then the above query could use, as load_date is only on one side of the > = or<>
A similar State
where to_char (load_date, 'FMMonth YYYY') = 'February 2010'
cannot use an index on load_date, because we do not compare load_date - we compare the results of TO_CHAR (load_date,...).
Published by: Frank Kulash, April 13, 2010 16:44
Fixed GROUP BY clause
Tags: Database
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