How to store an alphanumeric value 10000.

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  You can use the convert to Dynamic data VI and configure it to convert a single scalar value. This will give you a floating point number that you can enter for the comparison group.

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  public class ArrAvg {}

  Public Shared Sub main (String [] args) {}

  int arr [10] = new int [10];

  inputNumbers (arr);

  }

  void int inputNumbers (int arr [10]) {}

  int i;

  TextField field1 = new JTextField();

  TextField Field2 = new JTextField();

  Field3 TextField = new JTextField();

  String value1 = field1.getText ();

  String value2 = field2.getText ();

  String value3 = field3.getText ();

  val1 = Integer.parseInt (value1);

  val2 = Integer.parseInt (value2);

  val3 = Integer.parseInt (value3);

  for (i = 0; i < 10; ++ I) {}

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  }

  }

  Some body please guide me.

  Zulfi.

  I have stored text field in ArrayList so i should traverse the ArrayList. But when i am converting the contents of Arraylist into integer, i am getting type mismatch despite the fact that my ArrayList is of String type.
  
  
  

  Yes - the ArrayList to string but you create an iterator for object

  Iterator itr = al.iterator (); getting iterator of arraylist to iterate through the items

  This method of "al.iterator" () returns the iterator; for your use case E-online String. See the API

  https://docs.Oracle.com/javase/8/docs/API/Java/util/ArrayList.html

  You set it to 'Iterator' which is NOT a generic, so only objects are returned.

  So get back to string.

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  Is it possible to avoid "iterator"?

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  Hi Sir,
  
  I have a request that is
  
  
  Select to_char (date ' 1900 - 01 - 01 + 1439 /(24*60), ' DD/MM/YYYY HH24:MI:ss') twice;
  
  
  
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  v_nshiftmax: = to_char (date ' 1900 - 01 - 01 + 1439 /(24*60), "DD/MM/YYYY HH24:MI:SS");
  
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  Hi all
  I have a string that contain alphanumeric values.
  I want only numeric values in this string.
  FRO this purpose.
  I created a varry
  

  TYPE tab IS VARRAY(10) OF VARCHAR2(10) ;
     var tab

  ;
  variable var of type varray contain this string
  
  and now I want to check each character in this string at end of validation
  
  How can I check this particular string
  
  can I use loop?

  Hello

  If str is a string, then

  REGEXP_LIKE ( str
              , '^[[:digit:]]+$'
              )
  

  Returns TRUE if and only if str contains digits (0 ith 9) and nothing else.
  Here's a way you can use REGEXP_LIKE in PL/SQL:

  SET     SERVEROUTPUT     ON
  
  DECLARE
      str          VARCHAR2 (10)     := '123.4';
  BEGIN
      IF  REGEXP_LIKE ( str
                    , '^[[:digit:]]+$'
                )
      THEN
       dbms_output.put_line (  str
                      || ' is all digits.'
                      );
      ELSE
       dbms_output.put_line (  str
                      || ' contains something besides digits, or is NULL'
                      );
      END IF;
  END;
  /
  

  Published by: Frank Kulash, December 12, 2011 09:13
  Added PL/SQL example

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