How would add labels to lines and columns of a spreadsheet?

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• I still have not found "help" to tell me how to remove all the lines and columns beyond those needed for my spreadsheet.

  I used several worksheets.  More allows me to specify the rows/columns and then delete them.  This is to remove all the lines/columns beyond those set up and formatted for my spreadsheet.   I tried many ways to remove all additional lines/columns, but without success.  I even took the time to scroll down/on to highlight all the unnecessary lines and columns, but they do not remove it.
  Any suggestions?  I used spreadsheets most allow me to specify the number of rows/columns for my worksheet

  You can ask your question in the office | Excel Forum because it is not really a problem of Windows XP performance and maintenance.

  Office | Excel

  http://answers.Microsoft.com/en-us/Office/Forum/Excel

  Also, providing specific information may help to get a faster response or better, such as the version of Office or Excel? version of Windows XP? Home, Pro, 32-bit or 64-bit.

  I hope this helps.

• How to write express line and column of the tables headers to a file

  HI guys, I work with that express table and display data using the express table. What I want to do, is that when I press save button results data in the specific table must be written to a text file. I am able to write the text file, but only the data is written. Y at - there a possiblity that I can also write lines and column headers and the data in the text file. Kindly guide me in this regard as soon as possible. I enclose the image also. Please watch this and guide me.

  Cordially Ehtisham Safdar.

  Hello

  Sorry for the late reply. Here is the VI, I hope it works for you. Rather than each element of the index and the addition of the row header, take advantage of the available icons and play with the nodes of property for a good solution.

  Concerning

  Gaze

• How would enable remote desktop connection and asking for help?

  How would enable remote desktop connection and asking for help?

  Do you mean on this site?  Sorry, but we don't do that.  We do not have the software required to make the connection (it's too expensive to buy personally) and even if we did we would not get in this practice.  We work by display.

  If you mean for someone else to help you, here is the procedure: http://www.howtogeek.com/howto/windows-vista/turn-on-remote-desktop-in-windows-vista/.

  I hope this helps.

  Good luck!

  Lorien - MCSA/MCSE/network + / has + - if this post solves your problem, please click the 'Mark as answer' or 'Useful' button at the top of this message. Marking a post as answer, or relatively useful, you help others find the answer more quickly.

• How to add the chapter name and page not for reference

  Hello

  How to add the chapter name and page not for reference in indesign CS6.

  Thank you

  Please try variable notion of text

• Add a table with the number of lines and columns JS

  Hello

  Simple question: what is the syntax for adding a table with a specified number of rows and columns? I don't get it. (I don't know how to add them later, but I want to do when I create the table). Here is the entry in the ESTK:

  Tables.Add (to: LocationOptions, reference: all, withProperties: Object): array

  Creates a new table.

  (optional): Data Type: LocationOptions, by default: LocationOptions.UNKNOWN
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  Reference: Data Type: no
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  withProperties: Data Type: object
  Initial values for the properties of the new Table (optional)

  Thank you

  Ariel

  After much experimentation, I found this works:

  t = app.selection [0].tables.add (LocationOptions.AT_BEGINNING, undefined, {columnCount:2, headerRowCount:1, bodyRowCount:5, footerRowCount:3});})

• How to add the new line?

  Hello

  I wrote a select statement, the data is displayed, and I want to add a new line, how do?

  There is no icon "more (add)" the above data.

  Then, you insert first a table, then in the other.

  If you choose multiple tables so you are most likely to join them in some way, and when joins between in the field (or even worse grouping functions) you're sure source of data you see actually (this is the reason why by default you cannot insert data from a select query), as it is perfectly possible to select only a single column in a single table , but if this table has multiple columns and one of them is defined as NOT NULL, and you're not selecting then you are out of luck and you cannot insert of your select query.

  There are cases when the insertion is possible and where it is not SQLDeveloper try even to guess if they can put your query, and is a good decision, when the data changes, it is always better to think first of my humble OPINION and you might forget that if edit you a query result grid.

• LiveCycle dynamic form adds too many lines and does not save properly

  Hello

  I'm fairly new to LiveCycle Designer.  I designed a few forms that behave in the same way, and I'm curious to know if someone would mind helping me find my mistake.

  I have a table that I need to be able to add and subtract lines.  If I add a line and fill in the information, it seems good.  If I save the form and re-open information disappeared and there are several added lines which are empty.  How can I fix?

  Document link: file - sharing Acrobat.com

  Thank you very much

  Loren

  Hey Loren,

  It's very strange, and I would say a bug in the binding process.  It seems that from Table2 Row1 elements can be picked up as part of the binding of the nested table, table 3, which has a line called Row1.

  I changed the Row1 under Table3 to SubRow1 and it seems to work fine.

  I don't know how you want the buttons Add/Remove to work, but "this.parent.index" you will get the index of Cell1 (which will always be 1), you can "this.parent.parent.index".

  Concerning

  Bruce

• With CVI SQL Toolkit, how to add the new variable param column in a table.

  Dear all:

  I used the CVI Sql toolkit to create a database, but now I don't know how to add a new column to a table in variable param.

  I know, to add a column with the name of constant column could be down by below:

  DBImmediateSQL ((hdbc, "alter table table1 add column1 char [100]");

  But if Column1 is a param variablae how can I write the code? Please advise?  It will be appreciated if you could give me an example.

  Best regards!

  HI -.

  If you look at the parameters that you pass to the SQL function, you can see that the second parameter is a string constant. In your code, you can create an array of characters (string). You can then use sprintf to programmatically determine what will be the contents of this variable. In the function call, you can put the variable instead of the literal string, and you will have a customizable SQL statement.

  Hope this helps-

  John M

• How to draw a straight line and write on areas colored with Photoshop?

  I need to be able to draw a straight line and write about areas that I colored. I could do in PhotoStudio, but I don't know how to do in Photoshop.

  Use layers.  Text for writing on areas layers.  They can be changed.  You can change the text, font, size, color, Position, fusion and opacity and a layer style can be added.

  To draw the limes add a blank layer.  Select a brush and the color.  Left-click on one end of the line you want to draw. So without and the button to move the cursor to the other end of the line and press SHIFT + left.  Photoshop will draw the straight line between the two points that you clicked on.

  

• How to add a new line in the JavaScript editor?

  I have a script like this:

  var n = this.getField("score").value;

  If (n > = 0 & & n < 5) {}

  Event.Value = "The WP 100% Bond\nThe 10% Stock WP / 90% Bond\nThe WP 20% Stock / 80% Bond."

  }

  I want out of this line as...

  The leap from 100% WP

  The Stock of 10% WP or the Bond of 90%

  The Stock of 20% of WP or 80%

  But it's not to honor the \n for a newline. How in the heck can you add a new line? I tried \r, \r\n, \n\n. It is to add a space character and looks like this...

  The leap from 100% WP WP 10% Stock or the Bond of 90% 20% of WP Stock or Bond of 80%

  You can use \n like you did to indicate a new row or \r (carriage return). If this does not work, be sure to set the Multiline field on the Options tab of the field properties dialog box.

• How to add a horizontal line in RoboHelp 7 HTML

  HI - I work with RoboHelp 7 HTML. I want to add a horizontal line to my topic. I use RoboHelp as my editor. Working mainly in WYSWYG / Design mode and do not do much coding by hand in general, but sometimes I change the code. Because I couldn't find a way to WYSIWYG to add a line horizontal, so thought I would try the < hr / > tag.
  
  Unfortunately - it just shows up on top of the display page of design as a big, red evidence of the < hr / > tag.
  
  Suggestions?
  Thanks, Leisa

  So much worse... as simple as faulty code - Oh
  I told you I didn't hand code a lot...

  There

• How to add an imaginary line in the result of the value of a SELECT statement.

  Hello all-
  
  I have requirment to add an imaginary line in the result set of a SELECT statement.
  
  For example lets say it is a pay table having the following columns:
  
  Number of Payment_id
  status varchar2 (10)
  number amount
  date of payment_date
  
  so here's the data: -.
  
  Payment_id status amount payment_date
  applied 1 100 12/07/2008
  2 Reversed 200 01 / 06/2009
  Applied 3 300 01 / 07/2009
  
  
  Here is my SQL
  
  Select * form payment where payment_date > = 01/01/2009
  
  The output will be
  
  2 Reversed 200 01 / 06/2009
  Applied 3 300 01 / 07/2009
  
  My desired output is less than
  
  2 Reversed 200 01 / 06/2009
  Applied 3 300 01 / 07/2009
  reversed-200 2, 01 / 06/2009-(Dummy Row)
  
  Third line here is the imaginary line that I add when the status is "reversed".
  
  I would be very grateful for any help on this...
  
  Thank you
  Gerard

  Cartesion join against a shadow table is a useful method to create a fictitious line:

  with my_tab as (select 1 cust_id, 1 Payment_id, 'Applied' Status, 100 Amount, to_date('12/07/2008', 'mm/dd/yyyy') payment_date from dual union all
                  select 1 cust_id, 2 Payment_id, 'Reversed' Status, 200 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 1 cust_id, 3 Payment_id, 'Applied' Status, 300 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 1 Payment_id, 'Applied' Status, 100 Amount, to_date('12/07/2008', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 2 Payment_id, 'Reversed' Status, 200 Amount, to_date('01/05/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 3 Payment_id, 'Applied' Status, 300 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 4 Payment_id, 'Reversed' Status, -400 Amount, to_date('01/06/2009', 'mm/dd/yyyy') payment_date from dual union all
                  select 2 cust_id, 5 Payment_id, 'Applied' Status, 500 Amount, to_date('01/07/2009', 'mm/dd/yyyy') payment_date from dual),
                  --- end of mimicking your table
        dummy as (select 'Reversed' col1, 1 rn from dual union all
                  select 'Reversed' col1, 2 rn from dual)
  select mt.cust_id,
         mt.payment_id,
         mt.status,
         decode(dummy.rn, 2, -1*mt.amount, mt.amount) amount,
         mt.payment_date
  from   my_tab mt,
         dummy
  where  mt.status = dummy.col1 (+)
  order by mt.cust_id, mt.payment_id, dummy.rn nulls first;
  
  CUST_ID     PAYMENT_ID     STATUS     AMOUNT     PAYMENT_DATE
  1     1     Applied     100     07/12/2008
  1     2     Reversed     200     06/01/2009
  1     2     Reversed     -200     06/01/2009
  1     3     Applied     300     06/01/2009
  2     1     Applied     100     07/12/2008
  2     2     Reversed     200     05/01/2009
  2     2     Reversed     -200     05/01/2009
  2     3     Applied     300     06/01/2009
  2     4     Reversed     -400     06/01/2009
  2     4     Reversed     400     06/01/2009
  2     5     Applied     500     07/01/2009
  

  Published by: Boneist on January 7, 2009 23:10
  NB. You may need to mess around with the order if that is not in the order you want. You did not mention what the rules were for all orders expected, so I composed my own * {;-)

  Also, I added a (cust_id) identifier to differentiate different types of payments, as is usually the case. Remove unless it is not applicable to your case.

• How to add a value to a column of a string of pop up

  I am really inexperienced with spreadsheets, but asked me to help create a timesheet for a rotational system.

  I know that the time could be manually entered and calculated in duration but as there are only four options, let's say A, B, C travel and OFF, it would save a lot of time if there is a pop-up menu along side each name and under every day so that when a change is selected, the corresponding hours would be added in the total column.

  I actually created the spreadsheet with context menus as follows:

  08:00 - 15:00

  15:00 - 22:00

  Off

  08:00 - 18:00

  The reason why the 08:00 - 18:00 is in the end, it is a special change that only supervisors do.

  In any case, is there a way that these string values can be converted to hours to a total of column? I tried, very awkwardly, and I can't really follow the logic of the formulas of the numbers so I would be very grateful if someone could help me.

  I've included a selective screenshot in case my description is not very clear; Thank you.

  

  Hello Alf,

  The key to this is to use a lookup table for the transit time of list (as in your Menus pop up) and the number of normal hours for this position.

  Note this column of the table must match exactly to your Menus pop up (I added spaces on both sides of the hyphen).

  

  Then another table (hours) to account for the infeed Table and convert shifts in hours.

  Formula in B2 of table of the hours (and fill right and fill down)

  = INDEX (Lookup::$B,MATCH(Input::B2,Lookup::$A,0))

  My cheat for the combination of the INDEX sheet and MATCH:

  = INDEX (column, I want a value returned by,)

  MATCH (the value of my choice,

  Column, I want to search against.

  Enter ""0")).

  Finally, the formula in the column "hours worked" (right part of the input table)

  

  I2 = SUM (Hours::2:2)

  And fill down.

  Kind regards

  Ian.

  Edit: You can move (copy / paste) the table and the table to another worksheet hours to 'hide '. Ian.

• Matrix - vector lines and columns

  M1 (3,2) gives the element of line 3, column 2

  M1 (2) gives the second row of a matrix (as a vector line)

  Is there a way to return a column (other than transpose, store again and using the method above on the transposed matrix)?

  Tim Wessman wrote:
  

  Assuming that first here...

  Col(M1,1)

  Row(M1,1)

  @ Tim,.

  As Mmmm - created a post on the 39gii and commented on a post on the 39gii, this one is perhaps more likely to be on the 39gii?

  I think that your presumption re - expresses my presumption that the 39gii becomes brother forgot the premium?

  @ Mmmm.

  Try M1 (-c), where C is desired column number. For example M1(-2) for column 2.