I do not understand this behavior using Expression of Table common Recuersive

I haven't used the RCTE much, but I'm using it each time as possible to better understand. Unfortunately, this one left me speechless.
WITH test_data as
  ( select  'Bob' nm,  11 grp,  1 rnk  from dual union all
    select  'Ray' nm,  12 grp,  1 rnk  from dual union all
    select  'Joe' nm,  12 grp,  2 rnk  from dual union all
    select  'Liz' nm,  13 grp,  1 rnk  from dual union all
    select  'Jan' nm,  13 grp,  2 rnk  from dual union all
    select  'Lea' nm,  13 grp,  3 rnk  from dual union all
    select  'Sam' nm,  14 grp,  1 rnk  from dual union all
    select  'Ozy' nm,  14 grp,  2 rnk  from dual union all
    select  'Fae' nm,  14 grp,  3 rnk  from dual union all
    select  'Lee' nm,  14 grp,  4 rnk  from dual
  )
, recurs ( grp, lst, rnk, nm  ) AS
( 
SELECT  grp, nm, rnk, nm
  from  test_data
where  rnk=1 
--and grp = 14
UNION ALL
SELECT  t.grp
    ------------------------------------------------------------------------------------- 
    -- Toggle the commenting of the next two lines to see the error ----------------------
    --, r.lst || ', ' || t.nm          --- This is the line that I would like to have work
    -- Instead, using the next line, to limit the length of the string concatenation, but the result is wrong
    , SUBSTR( r.lst, 1, 2000) || ', ' || t.nm
    ------------------------------------------------------------------------------------- 
    , t.rnk
    , t.nm
  FROM test_data t
    JOIN recurs r ON ( t.rnk = r.rnk + 1 
                     AND t.grp = r.grp)
)
SELECT recurs.*, LENGTH ( nm )  
FROM recurs
ORDER BY grp, rnk;                      
If I Uncomment a line (and comment out the line that accompanies it, at the same time), the error will be:
ORA-01489: result of string concatenation is too long
And by running the query of how it is demonstrated, this returns:
       GRP LST                  RNK NM  LENGTH(NM)
---------- ------------- ---------- --- ----------
        11 Bob                    1 Bob          3
        12 Ray                    1 Ray          3
        12 Ray, Joe               2 Joe          3
        13 Liz                    1 Liz          3
        13 Liz, Jan               2 Jan          3
        13 Liz, Jan, Lea          3 Lea          3
        14 Sam                    1 Sam          3
        14 Sam, Ozy               2 Ozy          3
        14 Sam, Ozy, Fae          3 Fae          3
        14 Sam, Ozy, Lee          4 Lee          3

10 rows selected.
Note that 'rnk = 4' record in "grp = 14". The value of "E" is outside the "lst".

Can someone make sense this for me?

It works, explicitly express the result to varchar2 (4000) in the anchoring of the union query.

SQL> WITH test_data as
  2    ( select  'Bob' nm,  11 grp,  1 rnk  from dual union all
  3      select  'Ray' nm,  12 grp,  1 rnk  from dual union all
  4      select  'Joe' nm,  12 grp,  2 rnk  from dual union all
  5      select  'Liz' nm,  13 grp,  1 rnk  from dual union all
  6      select  'Jan' nm,  13 grp,  2 rnk  from dual union all
  7      select  'Lea' nm,  13 grp,  3 rnk  from dual union all
  8      select  'Sam' nm,  14 grp,  1 rnk  from dual union all
  9      select  'Ozy' nm,  14 grp,  2 rnk  from dual union all
 10      select  'Fae' nm,  14 grp,  3 rnk  from dual union all
 11      select  'Lee' nm,  14 grp,  4 rnk  from dual
 12    )
 13  , recurs ( grp, lst, rnk, nm  ) AS
 14  (
 15  SELECT  grp, cast(nm as varchar2(4000)), rnk, nm
 16    from  test_data
 17  where  rnk=1
 18  --and grp = 14
 19  UNION ALL
 20  SELECT  t.grp
 21      -------------------------------------------------------------------------------------
 22      -- Toggle the commenting of the next two lines to see the error ----------------------
 23      , r.lst || ', ' || t.nm          --- This is the line that I would like to have work
 24      -- Instead, using the next line, to limit the length of the string concatenation, but the result is wrong
 25      --, SUBSTR( r.lst, 1, 2000) || ', ' || t.nm
 26      -------------------------------------------------------------------------------------
 27      , t.rnk
 28      , t.nm
 29    FROM test_data t
 30      JOIN recurs r ON ( t.rnk = r.rnk + 1
 31                       AND t.grp = r.grp)
 32  )
 33  SELECT recurs.*, LENGTH ( nm )
 34  FROM recurs
 35  ORDER BY grp, rnk;

       GRP LST                                   RNK NM  LENGTH(NM)
---------- ------------------------------ ---------- --- ----------
        11 Bob                                     1 Bob          3
        12 Ray                                     1 Ray          3
        12 Ray, Joe                                2 Joe          3
        13 Liz                                     1 Liz          3
        13 Liz, Jan                                2 Jan          3
        13 Liz, Jan, Lea                           3 Lea          3
        14 Sam                                     1 Sam          3
        14 Sam, Ozy                                2 Ozy          3
        14 Sam, Ozy, Fae                           3 Fae          3
        14 Sam, Ozy, Fae, Lee                      4 Lee          3

10 rows selected.

Tags: Database

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    |   0 | SELECT STATEMENT  |          |     1 |    57 |     3   (0)| 00:00:01 |
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