I need know why is the number linces
where I can found the number of grain for linces
Cloud programs don't use serial... numbers you, connect you to your cloud account paying to download & install & activate... you may need to sign out of the cloud and restart your computer and log into the cloud for things to work
If you subscribe to the cloud, you bought?
Tags: Adobe
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How do I know how much the number of materialized view columns
How do I know how much the number of materialized view columns
Thank you
Gopal
Best to include the owner too if you use all_tab_columns
Select count (*)
from all_tab_columns
where owner = "
." and table_name = "
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I have photoshop CS4. It gave me a serial number to activate a new computer. I was told that the account has been disabled before but it has never been. The number gave me blocks the application whenever I try to open. I've been waiting for Friday and all day today on the Adobe help. I need my CS4 deactivted from a spescific computer so I can reinstall
From your description, that you don't know do you have actually the license... seems someone gave it to you. You might have a hard time selling Support from Adobe. Licenses must be officially transferred through Adobe.
In all cases, you will need to communicate with them through chat and ask them to reset your activations. Ask any more than that or they will send you back here where no one can help you.
Chat support - the link below click the still need help? the option in the blue box below and choose the option to chat...
Make sure that you are logged on the Adobe site, having cookies enabled, clearing your cookie cache. If it fails to connect, try to use another browser.
Serial number and activation support (non - CC) chat
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Why is the number of images in LR 5.3 not equal to the total number of images.
Down at the bottom with tray slide in Lightroom, it lists the total number of images displayed, followed by the total number of images that is then followed buy the number of selected images. Once in one of my catalogs, it displays "all photographs 3872 of 3883 1 selected. I have no filters on. In the catalogue on the left side box, "All photographs" I selected. So, why it only shows me 3883 3872? How will I know what the 11 photographs are that it does not appear?
I saw a previous post where someone was weird numbers in order to synchronize the folder and they used "Export as Catalog" and he cleaned the wobbly catalog. Considering that you have only a few thousand files, it should go quickly if cut you everything in the export. You can then load the new catalog and see if he deleted things upward.
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Need a counter of the number of occurrences in a column.
Hello world.
I have 2 tables. A table is a simple table with the columns NAME and ID (unique). Table B has a lot of columns, but also a column called matching NAME of a constraint on Table A ID FK.
For a report, I need to create view with columns... ID and COUNT.
Basically, for each ID in table A, I need to get the number of times it appears in the name column of the Table B.
What is the best way to do this in Oracle PL SQL. I have version 11g, 10.3.6.
Thank you
CREATE OR REPLACE FORCE VIEW 'NAMES_VIEW' ('ID', 'COUNT') AS
Select A.ID AS 'ID', COUNT (A.ID) AS 'COUNT '.
of TABLE A, TABLE B
where A.ID = B.ID
B.NAME GROUP
/
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Can't be done I'm afraid.
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JasonYou can always put RP in the argument to delete the Session State in the URL - which will reset the pagination. So, if you include that in your URL, it should work.
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Need help finding the number of occurrences of a model.
Hi all
I need help to find the number of occurrences of a model in the column of the table data.
Consider the examples of data - column of a row in a table:
'S-S-S-A-S-S-P-S-S-B-S-A-P-S-S-C '.
My requirement is:
I should get the County of S that are immediately preceded by or P.
for the above data, I should get are counted as 3 + 2 + 1 = 6 (S-S-S-A, S-S-P, S - A)
The configuration data is stored as type VARCHAR2.
Thanks in advance,
Girish G
Published by: Girish G on July 21, 2011 23:22I don't know that there is a better way, then this one:
SQL> with dt as 2 (select 'S-S-S-A-S-S-P-S-S-B-S-A-P-S-S-C' str from dual) 3 SELECT SUM(Regexp_count(Regexp_substr(str, '(S\-?)+(A|P)+', 1, 4 Regexp_count(str, '(S\-?)+(A|P)+') - ( 5 LEVEL - 1 )), 'S')) len 6 FROM dt 7 CONNECT BY LEVEL <= Regexp_count(str, '(S\-?)+(A|P)+') 8 / LEN ---------- 6
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Windows says it can't open my shortcuts and I don't know why.
If I put a shortcut on my desktop windows says it can't open it and I don't know why
The game, October 4, 2012 15:17:02 + 0000, JeanRaven wrote:
If I put a shortcut on my desktop windows says it can't open it and I don't know why
Right-click on the shortcut and choose Properties. On the shortcut tab.
What does say in the target?You say "Windows says it cannot open it", but please quote exactly
the text of the message you get verbatim.Ken Blake, Microsoft MVP
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Hello
I have a number of areas that require a Yes, no, n/a answer in a drop down. Then I need to auto calculate the number of times 'Yes' is selected, divided by the number of Yes and No of (but excludes the addition of the na in the denominator). Numerator = Countif("yes")/denominator = Countif ("Yes" or "no").
Thank you
OK, then you can use this code as the calculation script custom of the field where you want the result to appear (PC MCKTOTAL):
var totalYes = 0; var total = 0; for (var i=1; i<=5; i++) { var f = this.getField("PC MCKRow"+i); if (f.valueAsString=="Yes") { totalYes++; total++; } else if (f.valueAsString=="No") { total++; } } if (total==0) event.value = ""; else event.value = totalYes / total;
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get the number of the day of the week - any national locale is used
Hi all
My need is to get the number of the day of the week - any national local is used.
For example, Saturday's 6th day of the week in my country, because the week starts on Monday.
I heard that some countries start the week of Sunday.
So my need is to compile code that does not depend on local national.
How can I make it?
Oracle Database 11 g Enterprise Edition Release 11.2.0.1.0 - 64 bit Production
PL/SQL Release 11.2.0.1.0 - Production
"CORE 11.2.0.1.0 Production."
AMT for Linux: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production
Hello
2621671 wrote:
Hi all
My need is to get the number of the day of the week - any national local is used.
For example, Saturday's 6th day of the week in my country, because the week starts on Monday.
...
That's what you asked for, whatever your NLS settings:
1 + TRUNC (dt) - TRUNC (dt, 'IW')
If dt is a DATE, TRUNC (dt, 'IW') is the beginning of the ISO week containing dt. ISO weeks always start on Monday, whatever NLS_TERRITORY, or other NLS parameters.
I heard that some countries start the week of Sunday.
So my need is to compile code that does not depend on local national.
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Full Table Scan: logical reads are the same as the number of blocks
Hi people,
Please see the following execution plan:
Hash value of plan: 1148783227
---------------------------------------------------------------------------------------------------------------------------------------------------
| ID | Operation | Name | Begins | E - lines. A - lines. A - time | Pads | Bed | OMem | 1Mem | Used Mem.
---------------------------------------------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1. | 0 | 00:01:20.23 | 481K | 481K | | | |
|* 1 | HASH JOIN | | 1. 50351 | 0 | 00:01:20.23 | 481K | 481K | 7902K | 2074K | 7997K (0) |
|* 2 | HASH JOIN | | 1. 50351 | 31333 | 00:00:01.45 | 3138. 3134 | 17 M | 2295K | 18 M (0).
|* 3 | TABLE ACCESS FULL | INS_DCT_BUSINESS_FOLDER | 1. 50351 | 122K | 00:00:00.82 | 2262 | 2260 | | | |
| 4. TABLE ACCESS FULL | INS_DCT_CLAIM_DECEASED_FOLDER | 1. 73533 | 76656 | 00:00:00.34 | 876. 874. | | |
|* 5 | TABLE ACCESS FULL | INS_COMMON_PARTY | 1. 616K | 0 | 00:01:18.71 | 478K | 478K | | | |
---------------------------------------------------------------------------------------------------------------------------------------------------
Information of predicates (identified by the operation identity card):
---------------------------------------------------
1 - access("THIS_".") PARTY_PK "= 'PARTY1_'." PK")
2 - access("THIS_".") FOLDER_ID '= 'THIS_1_'.' FOLDER_ID")
3 filter (("THIS_1_". "STATUS" <>"10" AND "THIS_1_" "." " STATUS' <>' 07 "AND"THIS_1_". ((' ' STATUS ' <>' 08'))
5 filter (("PARTY1_". "CUSTOMER_ID" LIKE "%#CHAMP290501C #00000 ' AND 'PARTY1_'." CUSTOMER_ID' IS NOT NULL))
The full table on INS_COMMON_PARTY scan generated 478 K physical IO.
But the table contains 479K
SQL > select dba_segments blocks where nom_segment = 'INS_COMMON_PARTY ';
BLOCKS
----------
479488
The 10046 trace file shows that each IO get back most of the time 16 blocks:
WAITING #11529215045786738576: nam = "direct path read" ela = file number 5619 = 27 dba first 1695088 block cnt = 16 obj = #= 19115 tim = 4076488005225
WAITING #11529215045786738576: nam = "direct path read" ela = 33322 file number = 26 dba first 758658 block cnt = 14 obj = #= 19115 tim = 4076488044875
WAITING #11529215045786738576: nam = "direct path read" ela = 2140 file number = 26 dba first 758672 block cnt = 16 obj = #= tim 19115 = 4076488053342
WAITING #11529215045786738576: nam = "direct path read" ela = 205 file number = 26 dba first 758688 block cnt = 16 obj = #= 19115 tim = 4076488054012
WAITING #11529215045786738576: nam = "direct path read" ela = 2057 file number = 26 dba first 758704 block cnt = 16 obj = #= 19115 tim = 4076488056622
WAITING #11529215045786738576: nam = "direct path read" ela = 22034 folder = 26 dba first 758720 block cnt = 16 obj = #= tim 19115 = 4076488079117
WAITING #11529215045786738576: nam = "direct path read" ela = 5516 file number = 26 dba first 758736 block cnt = 16 obj = #= 19115 tim = 4076488085001
WAITING #11529215045786738576: nam = "direct path read" ela = file number 4914 = 26 dba first 758752 block cnt = 16 obj = #= 19115 tim = 4076488090434
WAITING #11529215045786738576: nam = "direct path read" ela = file number 7748 = 26 dba first 758768 block cnt = 16 obj = #= tim 19115 = 4076488098836
WAITING #11529215045786738576: nam = "direct path read" ela = 1046 file number = 9 first dba = 1411 block cnt = 5 obj #= 19076 tim = 4076488101527
WAITING #11529215045786738576: nam = "direct path read" ela = file number 3882 = 9 first dba = 1424 block cnt = 8 obj #= 19076 tim = 4076488105439
WAITING #11529215045786738576: nam = "direct path read" ela = 1736 file number = 9 first dba = 1433 block cnt = 15 obj #= 19076 tim = 4076488107310
WAITING #11529215045786738576: nam = "direct path read" ela = 123 file number = 9 first dba = 1449 block cnt = 15 obj #= 19076 tim = 4076488107616
WAITING #11529215045786738576: nam = "direct path read" ela = 876 of file = 9 first dba = 1465 block cnt = 15 obj #= 19076 tim = 4076488108814
WAITING #11529215045786738576: nam = "direct path read" ela = file number 11326 = 9 first dba = 1481 block cnt = 15 obj #= 19076 tim = 4076488120464
WAITING #11529215045786738576: nam = "direct path read" ela = file number 2497 = 9 first dba = 1497 block cnt = 15 obj #= 19076 tim = 4076488123305
WAITING #11529215045786738576: nam = "direct path read" ela = 1382 file number = 9 first dba = 1513 block cnt = 15 obj #= 19076 tim = 4076488125037
WAITING #11529215045786738576: nam = "direct path read" ela = 799 file = 9 first dba = 1529 block cnt = 7 obj #= 19076 tim = 4076488126162
WAITING #11529215045786738576: nam = "direct path read" ela = 45 file number = 17 dba first = 1920 block cnt = 8 obj #= 19076 tim = 4076488126533
WAITING #11529215045786738576: nam = "direct path read" ela = 2593 file number = 18 dba first 1794 block cnt = 14 obj = #= 19076 tim = 4076488129290
WAITING #11529215045786738576: nam = "direct path read" ela = 1727 file number = 18 dba first = 1808 block cnt = 16 obj #= 19076 tim = 4076488131202
WAITING #11529215045786738576: nam = "direct path read" ela = 7308 file number 18 dba first = 1824 block cnt = 16 obj = #= 19076 tim = 4076488138872
WAITING #11529215045786738576: nam = "direct path read" ela = file number 514 = 18 dba first = 1840 block cnt = 16 obj #= 19076 tim = 4076488139735
WAITING #11529215045786738576: nam = "direct path read" ela = 110 file number = 18 dba first 1856 block cnt = 16 obj = #= 19076 tim = 4076488140232
WAITING #11529215045786738576: nam = "direct path read" ela = 114 file number = 18 dba first = 1872 block cnt = 16 obj #= 19076 tim = 4076488140689
WAITING #11529215045786738576: nam = "direct path read" ela = 114 file number = 18 dba first 1888 block cnt = 16 obj = #= 19076 tim = 4076488141146
WAITING #11529215045786738576: nam = "direct path read" ela = 113 file number = 18 dba first = 1904 block cnt = 16 obj #= 19076 tim = 4076488141603
WAITING #11529215045786738576: nam = "direct path read" ela = 695 of file = 19 dba first 1794 block cnt = 14 obj = #= 19076 tim = 4076488142645
WAITING #11529215045786738576: nam = "direct path read" ela = 549 of file = 19 dba first = 1808 block cnt = 16 obj #= 19076 tim = 4076488143540
WAITING #11529215045786738576: nam = "direct path read" ela = 1742 file number = 19 dba first 1824 block cnt = 16 obj = #= 19076 tim = 4076488145588
WAITING #11529215045786738576: nam = "direct path read" ela = file number 1834 = 19 dba first = 1840 block cnt = 16 obj #= 19076 tim = 4076488147769
................................
WAITING #11529215045786738576: nam = "direct path read" ela = file number 113966 = 19 dba first 52960 block cnt = 16 obj = #= 19076 tim = 4076492053842
WAITING #11529215045786738576: nam = "direct path read" ela = file number 3173 = 19 dba first 52976 block cnt = 16 obj = #= 19076 tim = 4076492057550
WAITING #11529215045786738576: nam = "direct path read" ela = file number 3486 = 19 dba first 52992 block cnt = 16 obj = #= 19076 tim = 4076492061390
WAITING #11529215045786738576: nam = "direct path read" ela = 2288 file number = 19 dba first 53008 block cnt = 16 obj = #= 19076 tim = 4076492064029
WAITING #11529215045786738576: nam = "direct path read" ela = file number 4692 = 19 dba first 53024 block cnt = 16 obj = #= 19076 tim = 4076492069069
WAITING #11529215045786738576: nam = "direct path read" ela = 1239 file number = 19 dba first 53040 block cnt = 16 obj = #= 19076 tim = 4076492070657
WAITING #11529215045786738576: nam = "direct path read" ela = file number 2365 = 19 dba first 53056 block cnt = 16 obj = #= 19076 tim = 4076492073373
WAITING #11529215045786738576: nam = "direct path read" ela = 227 file number = 19 dba first 53072 block cnt = 16 obj = #= 19076 tim = 4076492073970
WAITING #11529215045786738576: nam = "direct path read" ela = 215 file number = 19 dba first 53088 block cnt = 16 obj = #= 19076 tim = 4076492074531
WAITING #11529215045786738576: nam = "direct path read" ela = 204 of file = 19 dba first 53104 block cnt = 16 obj = #= 19076 tim = 4076492075082
WAITING #11529215045786738576: nam = "direct path read" ela = 198 file number = 19 dba first = 53120 block cnt = 16 obj #= 19076 tim = 4076492075626
WAITING #11529215045786738576: nam = "direct path read" ela = 217 file number = 19 dba first 53136 block cnt = 16 obj = #= 19076 tim = 4076492076191
WAITING #11529215045786738576: nam = "direct path read" ela = 216 number of file = 19 dba first 53152 block cnt = 16 obj = #= 19076 tim = 4076492076755
WAITING #11529215045786738576: nam = "direct path read" ela = 1199 file number = 19 dba first 53168 block cnt = 16 obj = #= 19076 tim = 4076492078302
.......................................................
STAT #11529215045786738576 id = 5 cnt = 0 pid = 1 pos = obj 2 = 19076 op ='TABLE ACCESS FULL INS_COMMON_PARTY (cr = 478541 pr = 478534 pw = time 0 = US 98541439 cost = size 141729 = map 132638015 = 616921)'
To me that the number of e/s is about 479488/16 = 29968 e / s
Why is the number of e/s so close to the number of blocks?
Am I missing something here?
Thanks for your help
The column entitled "bed" is the number of blocks read, not the number of read requests.
Concerning
Jonathan Lewis
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