Need a counter of the number of occurrences in a column.

Similar Questions

• Need help finding the number of occurrences of a model.

  Hi all
  
  I need help to find the number of occurrences of a model in the column of the table data.
  
  Consider the examples of data - column of a row in a table:
  
  'S-S-S-A-S-S-P-S-S-B-S-A-P-S-S-C '.
  
  My requirement is:
  
  I should get the County of S that are immediately preceded by or P.
  
  for the above data, I should get are counted as 3 + 2 + 1 = 6 (S-S-S-A, S-S-P, S - A)
  
  The configuration data is stored as type VARCHAR2.
  
  Thanks in advance,
  Girish G
  
  Published by: Girish G on July 21, 2011 23:22

  I don't know that there is a better way, then this one:

  SQL> with dt as
    2  (select 'S-S-S-A-S-S-P-S-S-B-S-A-P-S-S-C' str from dual)
    3  SELECT SUM(Regexp_count(Regexp_substr(str, '(S\-?)+(A|P)+', 1,
    4                                     Regexp_count(str, '(S\-?)+(A|P)+') - (
    5                                                  LEVEL - 1 )), 'S')) len
    6  FROM   dt
    7  CONNECT BY LEVEL <= Regexp_count(str, '(S\-?)+(A|P)+')
    8  /
  
         LEN
  ----------
           6
  

• Essbase calc script to determine the number of occurrence

  Hello

  is it possible within a calc script to determine the number of occurrence of a value in the account dimension?

  I have an account called ranks which can contain any value between 1 and 10.  I would like to know how many times each value is repeated for a specific cost center.  It's in a database of planning BSO.

  Thanks in advance for your contributions...

  CL

  This isn't the typical calculation you would do in an OLAP architecture, but yes it is certainly possible.

  you will need to create 10 accounts such as occurrence_of_1, occurrence_of_2 etc.

  Then you increment them according to the value of the 5th year.

  Don't forget to put in your calculation!

• How to get the number of occurrences per document

  Hello

  I have a table of documents (word, pdf, excel, txt) stored in the blob column. I want the SCORE to returns the number of occurrences in each document, so I use this piece of code:

  SELECT bdt.*, score_1, DBMS_CRYPTO SCORE (1). HASH(Archivo, 3) AS cod_hash

  OF crg_ctx_archivos_recibidos bdt

  WHERE CONTAINS

  (archivo,

  ' < query >

  < textquery = grammar 'SPANISH' lang = 'CONTEXT' > DEFINESCORE (paz, OCCURRENCE * 0.1) < / textquery >

  < score datatype = "INTEGER" algorithm = "COUNT" / >

  < / query > ', 1

  ) > 0

  ORDER BY PARTITION (1) DESC;

  However, I get a maximum score of 10, but I know that one of these documents have 490 games. How can I get the exact number of matches by document?

  Thanks in advance

  PD. I am using Oracle 11.2

  All the scores at the top inside to 100, so I don't think that you will be able to make the distinction between a document with 100 matches and the other with 490.

  Can you explain what you're trying to do with this?  There may be a way to use text search to find all docs with at least 100 shots, then their post-processing to order by the real number.

• Update resulted today in count of the number of messages in different folders disappear, except new

  I was asked to update to Thunderbird and did, when I came back later in the afternoon, the messages were always in each folder (sent for example), but the count of the number of messages in each category had disappeared.

  What about the small thing square on the line with the name above the part of the file. He has options for/unread and size

• Get the number of DISTINCT from several columns

  How can I get the number of DISTINCT from several columns?
  

  SQL> select count(distinct ename) from emp;
  
  COUNT(DISTINCTENAME)
  --------------------
                    14
  
  SQL> select count(distinct ename, job) from emp;
  select count(distinct ename, job) from emp
         *
  ERROR at line 1:
  ORA-00909: invalid number of arguments

  Hello

  select count(distinct ename || job) from emp;
  

  Kind regards

• count the number of occurrence in the table with toplink

  Hello!
  
  There is no way to create a query with the expressionbuilder or... to count the number of occurences in my table?
  I don't want to use the query " select count (*) from table .
  
  Thank you

  Not sure about the question. You are looking to get the SQL "select count (*) table" to use the framework of expression TopLink or pull you that SQL already and want something else?

  If you are looking just to get the count of a table/class, you can use a ReportQuery:
  ReportQuery rquery = new ReportQuery (ClassToQueryOn.class);
  rquery.addCount (); equivalent to count (*);

  session.executeQuery (rquery);

  You can use a report query to return data instead of objects and use the criteria for selection as a normal read request.

  Best regards
  Chris

• Help formula: count the number of whites in a column "up to the...» »

  name	string	metric
  Matthew		5
  brand		1
  brand	optimusPrime
  brand
  Luke		2
  Matthew	jamesLikesSteak
  John		3
  Luke	lukingGood
  Matthew
  Luke
  John	johnnyPop
  John

  Hey guys - so I do business with a bit of a problem in number. I have a number table - the table above is a simplified representation of the corresponding parts of the table. The left column 'name' is a series of 12 names repeated and 0 missing values. The "string" middle column is a column that has a lot of missing values by a formula based on another column that is not relevant to this problem. Who is not missing is all strings. The problem I have is in the 'metric ': right column

  I am trying to create a dynamic formula which will result in the numbers and blanks, exactly as above. My goal is to create a formula that, for each line, account the number of whites in the column 'chain' until we reach an empty 'string' which occurs next to "namesake" as in the line of housing the formula - and if there is no such a situation, so that it is empty. For example, if the second row (including header row) bears the name of "Matthew". The next time that a white 'string' occurs next to the name "matthew" is tenth. The number of whites that occur between the second row, and the ninth is 5 (lines 2, 3, 5, 6 and 8). I manually coded a small part of the table to use something like this (which would be installed in cell C2 in this example):

  = IF (B2 = "", COUNTBLANK(B2:B9), "")

  This formula produces the correct number for the first row of data (5), but it does not dynamically fulfill what I'm trying to do this since I am currently having the formula to find the next blank 'chain' that occur next to "name" in the formula line.

  I hope that someone has encountered anything like this before. I tried to go through all the functions and numbers from formulas, but so far I have not found much success.

  Hi BaronDe,

  I need to ask, "why you try to do this? So what you want is possible it will be a complex solution. It may be much easier to get your information in a different way. Indicate these blanks?

  You should know that COUNTBLANK() will not count a cell with a formula, even if this formula resolves to «»

  Quinn

• County and filter the number of occurrences of the string in an array

  Hello... I need to filter and count display for number of channels occur in a single column of an array of strings... I can't explain... below I represented all that is my need.  Column A is the array of input strings... Column B and C are the bays of the output...

  Column A column B column C

  Apple Apple 3

  Banana, mango 2

  Mango banana 1

  Apple

  Apple

  Mango

  Can someone help me...?

  Here, I wrote a small example of what I mentioned above.

  

• Try to count the number of records where some columns are met

  Using SQL in Toad against an Oracle table, I'm trying to count the number of records in a table where some columns are filled. For
  example, I need to know the total number of records from a table where
  
  ln_stop_cd is not null - 65000 records
  ln_process_cd is <>- 25000 0 records
  ln_opt_cd is not null - 7500 records
  
  and the record_type = "A".
  
  I know that the total individual records as described above. However, I do not know how
  the SQL to show for record_type = 'A' the total count is 97500 records. Any help would be
  appreciated.

  Hello

  It seems that the problem is that the indictment may overlap; You can count the same rank 0, 1, 2 or 3 times, depending on whether 0, 1, 2 or 3 of these 3 independent conditions are met.

  Try something like this:

  SELECT     COUNT (in_stop_cd)
        + COUNT (CASE WHEN in_process_cd  != 0        THEN 1 END)     -- this site doesn't like the other inequality operator
        + COUNT (in_opt_cd)        AS grand_total
  FROM    table1
  WHERE     dt          >= TO_DATE ('01-JUN-2011', 'DD-MON-YYYY')
  AND     dt          <  TO_DATE ('02-JUN-2011', 'DD-MON-YYYY')
  AND     record_type       = 'A'
  ;
  

  You want to make charges without making 3 assists separated through the table. The problem is the 3 original requests had slightly different WHERE clauses.
  Put these conditions in the WHERE clause and make other conditions apply only to the individual counties, either with a column instead of *, or using a CASE statement that contains the condition that applies only to the column.

  Also, the date is not a column name good. Do not compare the DATEs to strings. If your column is really a DATE and you want to ignore the hours, the minutes and seconds, then the best way is to compare the column with 2 other DATES, as shown above. It's more coding, but it is more efficient and more reliable.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  You don't have to display a large amount of data. You can probably give an excellent example of this problem with only 5 or 10 rows of sample data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

  Published by: Frank Kulash, August 4, 2011 11:27

• Need Adobe to reset the number of activations CS4 in order to activate the CS4 on a new computer. [was: Vicky - Chelsea photo lab.] NEED HELP AS SOON AS POSSIBLE]

  I have photoshop CS4. It gave me a serial number to activate a new computer. I was told that the account has been disabled before but it has never been. The number gave me blocks the application whenever I try to open. I've been waiting for Friday and all day today on the Adobe help. I need my CS4 deactivted from a spescific computer so I can reinstall

  From your description, that you don't know do you have actually the license... seems someone gave it to you.  You might have a hard time selling Support from Adobe.   Licenses must be officially transferred through Adobe.

  In all cases, you will need to communicate with them through chat and ask them to reset your activations.  Ask any more than that or they will send you back here where no one can help you.

  Chat support - the link below click the still need help? the option in the blue box below and choose the option to chat...

  Make sure that you are logged on the Adobe site, having cookies enabled, clearing your cookie cache.  If it fails to connect, try to use another browser.

  Serial number and activation support (non - CC) chat

  https://helpx.Adobe.com/contact.html?step=PHSP-PHXS_downloading-installing-setting-up_lice nsing-activation_stillNeedHelp

• Need help to find the number of the sequence of CCTV

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  In fact, I am nothing to do with it, but need to find the owner of the car as it did something bad to somebody and run from the place.

  Please do the needful.

  Can't be done I'm afraid.

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• Count of the number of months with unpaid for the last six months

  Hello

  I now table to store the daily presence of each employee

  ATTENDANCESHEET
  EMPID	PAYROLLDATE	UNPAID
  1	10/01/2013	6
  1	10/02/2013	2
  1	11/01/2013	0
  1

  11/02/2013

  0

  1

  12/01/2013

  0

  1

  12/02/2013

  0

  1

  01/01/2014

  0

  1

  01/02/2014

  0

  1

  02/01/2014

  0

  1

  02/02/2014

  0

  1

  03/01/2014

  45

  1

  03/02/2014

  0

  2

  03/01/2014

  0

  2

  03/02/2014

  0

  I want to get the number of months used unpaid in the past 6 months (excluding the current).

  If the month of payroll, I'm in treatment is 4, 2014, I spend 4 as payrollmonth and 2014 as payroll year

  The application must check the latest 6 month data and number of months for which there is any unpaid value

  In the case above for month 4, 2014, the power required is

  EmpID	County
  1	2
  2	0

  I use oracle 10g

  EXAMPLES OF DATA

  create the table attendancesheet as

  (

  Select 1 as empid, to_date (January 10, 2013 ',' DD/MM/YYYY ') as payrolldate, 6 paid by union double all the

  Select 1 as empid, to_date (10 February 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (January 11, 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 11, 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (12 January 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 12, 2013 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (1 January 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 1, 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (January 2, 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (February 2, 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 1 as empid, to_date (3 January 2014 ',' DD/MM/YYYY ') as payrolldate, 45 paid by union double all the

  Select 1 as empid, to_date (3 February 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid by union double all the

  Select 2 as empid, to_date (3 January 2014 ',' DD/MM/YYYY ') as payrolldate, 0 as default all the double union

  Select 2 as empid, to_date (3 February 2014 ',' DD/MM/YYYY ') as payrolldate, 0 paid double

  );

  Help, please

  Hello

  So, you want to count the distinct months for 6 months before (not included) the given month; is this fair?

  Here's one way:

  VARIABLE month VARCHAR2 (2)

  Year VARIABLE VARCHAR2 (4)

  EXEC: months: = '4';

  EXEC: year: "2014"; =

  WITH got_end_date AS

  (

  SELECT TO_DATE (: month |) '/' || : year

  , ' MM/YYYY ".

  ) AS end_date

  OF the double

  )

  SELECT a.empid

  , COUNT (DISTINCT

  CASE

  WHEN a.unpaid > 0

  THEN TRUNC (a.payrolldate, 'MONTH')

  END

  ), Cnt

  Of attendancesheet one

  JOIN e-got_end_date WE a.payrolldate > = ADD_MONTHS (e.end_date-6)

  AND a.payrolldate< >

  GROUP BY a.empid

  ORDER BY a.empid

  ;

  If you use a WHERE clause to exclude the lines with some outstanding = 0 (or unpaid is NULL), then you would get no output for employees like empid = 2 in this example.  A WHERE clause ignores an entire line, so I used an expression BOX just a value.

• I need know why is the number linces

  where I can found the number of grain for linces

  Cloud programs don't use serial... numbers you, connect you to your cloud account paying to download & install & activate... you may need to sign out of the cloud and restart your computer and log into the cloud for things to work

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• Count of the number of days in a calendar month according to the year

  Hi all

  On my table, column 1 is the list of months over several years.

  Column 2 is the activity number od each month.

  Column 3 I want an average rate of activity per day during the month, which should be: (C2 / number of days according to C1) %

  Problem: I can't find a fomula give me the number of days, particularly in February when the year is leap.

  Any help is appreciated.

  Thank you all,

  Lopez

  PS: by the way, with this new version of Apple Comunity I seem to have lost my previous questions about the numbers.

  

  Hey Lopez,

  EOMONTH(A1,0) (end of month) will GET help you.

  Column B is Date & time format to display only the month and year (actually the 1st of the month, but the day is not displayed).

  

  Formula in C2 (fill down)

  = EOMONTH(B2,0)

  The end of the month 0 months later.

  

  Formula in D2 (fill down)

  = DAY (C2)

  February 2015 (non-leap years) shows 28

  February 2016 (leap year) shows 29

  Kind regards

  Ian.