Ignoring the Null value or 0 for an average of

Similar Questions

• The Null value as the default value for an input to a stored procedure parameter

  Hello
  
  How can we set the default values with the NULL value for the parameter in a stored procedure.
  

  create or replace procedure emp_proc ( p_test_input in varchar2
                                                      p_emp_id in number,
                                                      p_emp_name in varchar2,
                                                     p_manager_id in number )
  as
    begin
     if ( upper ( p_test_input ) = 'I' )
     then
        insert into emp
        values      ( p_emp_id  ,p_emp_name ,p_Manager_id,sysdate );
     elsif ( upper ( p_test_input ) = 'D' )
     then
        delete from emp
        where       emp_id  = p_emp_id;
     else
        dbms_output.put_line
           ( 'Please input ''A'' for ADD or ''D'' Delete  EMPLOYEE'
           );
     end if;
  end;

  As described above if I want to delete only the functioning
  
  I want to call this procedure without pass additional parameters.

   EXECUTE  emp_proc('D',1010);

  Published by: Rede on May 28, 2010 12:21
  
  Published by: Rede on May 28, 2010 12:22

  create or replace procedure emp_proc ( p_test_input in varchar2,
                                                      p_emp_id in number,
                                                      p_emp_name in varchar2 default null,
                                                     p_manager_id in number default null )
  

• Remove the NULL values and update the value according to the logic

  Hello

  The problem data

  CREATE TABLE VOLA (SRNO, NUMBER, zero

  NUMBER, A

  NUMBER);

  INSERTION of REM in VOLA

  TOGETHER TO DEFINE

  Insert in VOLA (SRNO, ONE) values (1,237.94);

  Insert in VOLA (SRNO, ONE) values (2, null);

  Insert in VOLA (SRNO, ONE) values (3,203.565);

  Insert in VOLA (SRNO, ONE) values (4,170.69);

  Insert in VOLA (SRNO, ONE) values (5,113.67);

  Insert in VOLA (SRNO, ONE) values (6,93.6);

  Insert in VOLA (SRNO, ONE) values (7,82.03);

  Insert in VOLA (SRNO, ONE) values (8,66.675);

  Insert in VOLA (SRNO, ONE) values (9,63.59);

  Insert in VOLA (SRNO, ONE) values (10,61.415);

  Insert in VOLA (SRNO, ONE) values (11,60.015);

  Insert in VOLA (SRNO, ONE) values (12,58.235);

  Insert in VOLA (SRNO, ONE) values (13,57.805);

  Insert in VOLA (SRNO, ONE) values (14,56.965);

  Insert in VOLA (SRNO, ONE) values (15, null);

  Insert in VOLA (SRNO, ONE) values (16, null);

  I have to remove the NULL values in column 1, the problem is that the position of the NULL values are not fixed, and it can be any position. If all the lines of the columns are null, then throw it away.

  If multiple NULL values are here so I have to do the math as follows to update null with the eigenvalues

  1. If the first line is null then take the 2nd value in row and update it.

  2. If the lines between both is null then take avg of prev and next value not null and refresh it.

  3. If the last value in the column is null, then then take prev and update, in this case last two are null, so I have to take value of prev 14 value line update in

  15th and 16th ranks.

  I want to put this pl/sql logic, somehow, that I thought have loop and counter aapproach and loops through the elements and check and update.

  But always looking for something better before looking to write code. No idea or help will be useful for me.

  I * think * you are looking for something like:

  WITH VOLA (SRNO, ONE)

  AS (select 1,237.94 from all the double union)

  Select 2, union null value double all the

  Select 3,203.565 from all the double union

  Select 4,170.69 from all the double union

  Select 5,113.67 from all the double union

  Select 6,93.6 from all the double union

  Select 7,82.03 from all the double union

  Select 8,66.675 from all the double union

  Select 9,63.59 from all the double union

  Select 10,61.415 from all the double union

  Select 11,60.015 from all the double union

  Select 12,58.235 from all the double union

  Select 13,57.805 from all the double union

  Select 14,56.965 from all the double union

  Choose 15, null of union double all the

  SELECT 16, NULL FROM dual)

  GET_VALUES (SELECT SRNO, ONE ACE,

  , LAST_VALUE (WE IGNORE NULLS) (ORDER BY SRNO CSA ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING) AS PREVIOUS_VALUE

  , first_VALUE (ONE IGNORE NULLS) over (ORDER OF SRNO CSA ROWS BETWEEN 1 SUITE AND FOLLOWS without TERMINALS) AS NEXT_VALUE

  FROM VOLA)

  SELECT SRNO, ONE, CASE

  WHEN IT IS NOT NULL, THEN WE

  OTHER CASES

  WHEN PREVIOUS_VALUE IS NOT NULL AND IS NOT NULL THEN (PREVIOUS_VALUE + NEXT_VALUE) NEXT_VALUE / 2

  WHEN THE PREVIOUS_VALUE IS NOT NULL, THEN PREVIOUS_VALUE

  WHEN THE NEXT_VALUE IS NOT NULL, THEN NEXT_VALUE

  END

  END AS NEW_VALUE

  OF GET_VALUES

  /

  HTH

• PersistentStore.getPersistentObject returns the null value?

  I use a random key to retrieve a shape of the object PersistentStore

  persist is PersistentStore.getPersistentObject (KEY);.

  Works fine on the Simulator (OS 5), when I take the code signed to the device (BB OS 5.0 Bold 8900)

  For some reason, it returns null, without exception. Thereafter any API I inoke on PersistentStore / persist returns null without exception persist even when the null value.

  I don't know if it's one thing to eclipse debugger, but even if the debugger shows that objects are null. Controls null applied in the code seems to fail, what does code see these objects as non-null. Pheww! How is it possible.

  In this code still shows up as null, then safetyTable and orderedkeys. However, the value null check in the failure code.

  At a later stage in the code, when I try to access orderedkeys are null again! Are struggling with this problem for two days, all the pointers would be very comfortable.

                      persist = PersistentStore.getPersistentObject( KEY );
                      persistOrderedKeys = PersistentStore.getPersistentObject(KEY_ORDERED_KEYS);
                      safetyTable = (Hashtable)persist.getContents();
                      orderedKeys = (Vector)persistOrderedKeys.getContents();
                      if (safetyTable == null)
                      {
                          safetyTable = new Hashtable();
  
                          persist.setContents(safetyTable);
                          persist.commit();
                      }
  
                      if (orderedKeys==null)
                      {
                          orderedKeys=new Vector();
  
                          if (safetyTable.size()>0)
                          {
                              Enumeration addressKeys = safetyTable.keys();
                              while(addressKeys.hasMoreElements())
                              {
                                  orderedKeys.addElement((String)addressKeys.nextElement());
                              }
                          }
                          persistOrderedKeys.setContents(orderedKeys);
                          persistOrderedKeys.commit();
  
                      }
  

  "I don't know if it's one thing to eclipse debugger.

  I had problems of this kind when I don't have a level of operating system for the device I am debugging on.

• How to convert the Null value to 0 after the outer join?

  Hello guys
  
  My requirement is in fact 2 of outer join tables (that's how), and I got the outer join works very well, so in my report, I have values null of measures in another table of facts as a result of the outer join...
  
  Is there a way I can convert these nulls to 0?
  
  I realized that the null value is not stored in the table, it is just following the outer join because the NULL do not match records in other... So by default, I'm expected to get NULL values...
  
  Is there way to present these nulls to 0?
  
  Thanks a lot for your advice

  In response, the syntax will be:

  IFNULL (, 0)

  try and let us know how you go.
  See you soon
  Alastair

• Add the Null value at the end of the collection layer

  I need to create layers at the end of the index of the layer and not at the beginning. Is this possible?

  app.project.compItem.layers.addNull () puts a layer at the beginning of the collection of objects, but it should be at the end. Maybe I could add the null value, then rearange the index?

  Like this:

  var myNull = myComp.layers.addNull ();

  myNull.moveToEnd ();

  Dan

• calculated formula database field trying to insert the null value

  Hello
  
  I have 3 elements of database text amount, rate and result.
  I enter both values (quantity and frequency), and the property using formula 'result' Gets the computed value.
  On the screen all the values are displayed correctly but when trying to save my information text field 'result' tent to insert the null value.
  
  Any suggestions?
  
  Forms 11g
  
  Thanks in advance

  794018 wrote:
  Hello

  I have 3 elements of database text amount, rate and result.
  I enter both values (quantity and frequency), and the property using formula 'result' Gets the computed value.
  On the screen all the values are displayed correctly but when trying to save my information text field 'result' tent to insert the null value.

  Point formula should not be issue of database. And insert the value in the result column in the database is not good idea.
  Then, if you want to save it. create the database result item and write trigger (When-validate-point) on amount and filed rates and the trigger code, write

  :result:=:amount*:rate;
  

  To display the result on the form, create the database no item and change the formula property and write the formula.

  Hope this will help you

  If someone useful or appropriate, please mark accordingly.

• where clause to see if they contain the null value

  So I've finalized my function but now am having some problems:
  
  the bl field (or the v_bl parameter) has null values in it. When I run the function using the "Select FH ('ACCESS', NULL, 8675309') From dual; I get a NULL return value because it uses the variable to compare with q.bl and you can not have q.bl = null in a Where clause.
  
  The main problem is when the parameters are passed, a line can have the same prob and site, but the bl might be different as null, which would give a different lname.
  
  
  In where clause I need to have something that will compare the parameter with the bl field. Sometimes it's null sometimes is not, but we need to find the line concerned. I made the "BOLD" in the question police
  
  Here are two possible lines in the data
  prob bl site lname
  ACCESS Smith 8675309 (null)
  54321 8675309 Johnson ACCESS
  
  so in theory, if the function is called with the parameters FH ('ACCESS', NULL, 8675306')
  He would return the lname: Smith
  
  and conversely FH ("ACCESS", "54321 ', 8675309") would return Johnson
  
  Here's the function
  
  create or replace
  Function FH
  (v_prob IN varchar2, v_bl IN varchar2, v_site IN varchar2)
  RETURN varchar2
  AS
  v_lname varchar2 (16);
  
  BEGIN
  
  S.Lname SELECT INTO v_lname
  Of
  request q
  JOIN THE
  s response
  On
  (q.order = s.order)
  
  WHERE
  q.BL = v_bl AND - where it is
  q.site = v_site AND
  q.prob = v_prob AND
  s.Lname IS NOT NULL;
  
  RETURN v_lname;
  END;
  
  
  
  -When I run the FH ('ACCESS', NULL,' 86753) function, it returns an empty value and not the family name
  
  Published by: user11210446 on May 28, 2009 17:03
  
  Published by: user11210446 on May 28, 2009 17:03

  user11210446 wrote:
  If v_bl is Null in the where clause it would even say q.bl = Null which will not work.

  Matches the NULL value
  (1) either you have to say-> q.bl IS NULL
  OR
  (2) WHERE the NVL (q.bl-99) = NVL (v_bl-99) - this will be true if q.bl and v_bl both are NULL
  NULL = NULL evaluates to TRUE, so you use NVL

  SS@XE > select * from dual where null = null ;
  
  no rows selected
  
  SS@XE > select * from dual where null is null ;
  
  D
  -
  X
  
  SS@XE > select * from dual where NVL(null,-1) = NVL(null,-1) ;
  
  D
  -
  X
  

  SS

• test for the null value to IN request (null, 'a ', ' b', 'c')

  Hello

  Oracle 10.2.0.4

  I think the following query is incorrect, in my opinion. (there is an index on the collar, but NULL values are ignored?

  SELECT COUNT (*) < table > where col in (null, 'a ', ' b', 'c')

  It works (no errors) and forth fast enough.

  However, I think the correct query would

  SELECT COUNT (*) < table > where IS NULL or neck neck ('a', 'b', 'c')

  It takes a lot of time. As I see it, he performs a table scan for part of the value NULL and use the index for the rest, as the index cannot be used for NULL values.

  I would appreicate an explanation on this matter, particularly why Oracle accepts the first query "where col in (null, 'a ', ' b', 'c')" without any problem.

  Thank you

  A null value is not equal to what whatsoever, not even another null value. This is consistent with the definition of the ANSI. For your first request is not what you think it does, even if it is not syntactically incorrect.

  The second query is correct. If you want to use an index, you must create a bitmap index (which requires Enterprise Edition licenses), because they do not include the values NULL, unlike B * tree index.

• Replace the Null values with zero in MDB

  Hello
  
  How can I replace Null values with zero in MDB. I tried NVL (column_name, 0), he said: syntax error.
  
  Thanks for your time and your help.

  Hello

  In the layer of Buisenss you always use IFNULL (column, 0)

  Concerning
  Adil

  Published by: adil.harrab on April 8, 2011 17:33

• Returns the null value in HasMap.get ().

  Hi all.
  Just read the docs of java on hashmap and was interested in this topic the get() method:
  
  A NULL return value does not necessarily mean that the map contains no mapping for the key; It is also possible that the map explicitly maps the key null. The containsKey operation may be used to distinguish these two cases.
  
  I took in a case, which has been talked about: If the map allow nulls, returned by get() null will be just one key of the pair-> null value. But the second case is not clear to me. Please, show me an example for the latter case, when get() can returned null.

  sphinks wrote:
  I took in a case, which has been talked about: If the map permits null values, returned by get() null will be just a key pair-> null value. But the second case is not clear to me. Please, show me an example for the latter case, when get() can returned null.

  There is no second case. There is a single case, if you put a null value in a map, get() will return null. And because of that, if you need to know if a certain key is in the containsKey() worksheet should be used instead of the get() method.

• Several lines in duplicate with the null value displayed in the combined analysis rpt

  Dear all,
  
  Our requirement is to display users open tasks (my open tasks) on the home page. So I created a report called open my tasks.
  
  The columns to display are subject, account name, due date, owner. If I use only the 'activities' notification area, and then I can not retrieve tasks that have NULL of the account name. SOD ignore and filter the tasks with the NULL account name if I display the name of the account.
  
  So I used a combined analysis of activity report activity with itself i.e. area statement. All columns except account name in one of them where I used "instead of the name of Account.Account.
  
  It now also displays tasks with NULL account name. But there is another question. These activities when there is an account name, display double - double rows - an account name and othet without account name (for example, NULL).
  
  Please can you help how to solve above or meet the requirement in an alternative way?
  
  Thank you
  Niraj

  VR;

  (1. any activity with account) + (2. All activities - 3. Activities with account)

  1 account name because it is
  2 maintain a column empty "
  3 write the instruction box and change the name of the account by white ")

  Dinesh

• Displaying a string instead of the "null" value in the columns of answers

  Hi, is it possible to display a string (e.g. "no data") in responses instead a NULL value in a column of a table or a PivotTable? I read everything by using the formula in the column section in the answers, but I do not understand what expression should be used... could you help me?
  
  Is this kind of possible substitution only in the web interface of answers, or still in BI Admin meta - data? I would be very interested to recognize from analysis UDML in metadata,
  Thanks in advance!

  You must do this in the business model and the Mapping layer

  Go to the properties of the column

  1. in general tab, you have "use existing columns of logic as a source.
  Select this check box. Click the period (...)
  In the formula for the column, you can add the condition of ifnull
  In this col formula editor, you can choose the logical columns.

  2. on the Data Type tab, you have the maps and logical sources
  Here too you can achieve.
  In this col formula editor, you can choose physical columns.

  Kind regards
  Rambeau

• See the Null value in the measures

  I need to create a report using the SAP BW query.
  I have columns project, task, level and Hrs (measure)
  
  Project-> task-> level-> Hrs (measure)
  -----------------------------------------------------------------------------------
  one-> a.1-> 1-> null (no value)
  -> a.2-> 2-> null (no value)
  -------------> a.3 ----------------> 3 --------> 300
  ------------------------------------------------------------------------------------
  
  "Task" is the structure of distribution, a.1, a.2 are level relative to a.3.
  
  As we can see the 'h' is the total (cumulative) of the 'Project' = 'a '. When a.3 for value but a.2, obtained a.1 null.
  
  I can see null values in BEx (Business Explorer, SAP BW) report but not in OBIEE report.
  
  In short, we can display null values in action.
  
  Hope I explained it correctly.
  
  Please, help me in this regard.

  PS the reason why you see the values all here when you have only dimensions, but then they disappear when you've done is because of the way the request is generated. OBIEE don't happen in the fact table to what you actually shoot a column of the table of facts in your report. Once you do this, the generated SQL code using an inner join and causes dimensional Records label.

  -Joe

• Evolution of the null value in the data view tab

  Is it possible to update a null value in the data view table tab? When I delete the value, it creates a sql such as
  
  Update table set column is where id = 1;.
  
  How to fill a null from the data tab?

  I met (and displayed) on this same problem some time. (See forum article "invalid column index: getValidColumnIndex" in SQL Developer 1.5.4 . "") Jim Smith pointed out it seems to be the reappearance of an old bug.

  There are some alternatives. One is "do-it-yourself" in the SQL or SQL worksheet * more. (I.e., "UPDATE someTable SET someColumn = NOTHING WHERE tablePKColumn = pkValue;". The other is to use an earlier version of SQL Developer for that in the view of table data. (I still have Developer SQL 1.5.1 installed just for this reason).

  I hope this helps.

  Hrsg.:.