where clause to see if they contain the null value

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• How to convert the Null value to 0 after the outer join?

  Hello guys
  
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  In response, the syntax will be:

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• Remove the NULL values and update the value according to the logic

  Hello

  The problem data

  CREATE TABLE VOLA (SRNO, NUMBER, zero

  NUMBER, A

  NUMBER);

  INSERTION of REM in VOLA

  TOGETHER TO DEFINE

  Insert in VOLA (SRNO, ONE) values (1,237.94);

  Insert in VOLA (SRNO, ONE) values (2, null);

  Insert in VOLA (SRNO, ONE) values (3,203.565);

  Insert in VOLA (SRNO, ONE) values (4,170.69);

  Insert in VOLA (SRNO, ONE) values (5,113.67);

  Insert in VOLA (SRNO, ONE) values (6,93.6);

  Insert in VOLA (SRNO, ONE) values (7,82.03);

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  Insert in VOLA (SRNO, ONE) values (9,63.59);

  Insert in VOLA (SRNO, ONE) values (10,61.415);

  Insert in VOLA (SRNO, ONE) values (11,60.015);

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  Insert in VOLA (SRNO, ONE) values (13,57.805);

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  Insert in VOLA (SRNO, ONE) values (15, null);

  Insert in VOLA (SRNO, ONE) values (16, null);

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  15th and 16th ranks.

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  But always looking for something better before looking to write code. No idea or help will be useful for me.

  I * think * you are looking for something like:

  WITH VOLA (SRNO, ONE)

  AS (select 1,237.94 from all the double union)

  Select 2, union null value double all the

  Select 3,203.565 from all the double union

  Select 4,170.69 from all the double union

  Select 5,113.67 from all the double union

  Select 6,93.6 from all the double union

  Select 7,82.03 from all the double union

  Select 8,66.675 from all the double union

  Select 9,63.59 from all the double union

  Select 10,61.415 from all the double union

  Select 11,60.015 from all the double union

  Select 12,58.235 from all the double union

  Select 13,57.805 from all the double union

  Select 14,56.965 from all the double union

  Choose 15, null of union double all the

  SELECT 16, NULL FROM dual)

  GET_VALUES (SELECT SRNO, ONE ACE,

  , LAST_VALUE (WE IGNORE NULLS) (ORDER BY SRNO CSA ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING) AS PREVIOUS_VALUE

  , first_VALUE (ONE IGNORE NULLS) over (ORDER OF SRNO CSA ROWS BETWEEN 1 SUITE AND FOLLOWS without TERMINALS) AS NEXT_VALUE

  FROM VOLA)

  SELECT SRNO, ONE, CASE

  WHEN IT IS NOT NULL, THEN WE

  OTHER CASES

  WHEN PREVIOUS_VALUE IS NOT NULL AND IS NOT NULL THEN (PREVIOUS_VALUE + NEXT_VALUE) NEXT_VALUE / 2

  WHEN THE PREVIOUS_VALUE IS NOT NULL, THEN PREVIOUS_VALUE

  WHEN THE NEXT_VALUE IS NOT NULL, THEN NEXT_VALUE

  END

  END AS NEW_VALUE

  OF GET_VALUES

  /

  HTH

• Add the Null value at the end of the collection layer

  I need to create layers at the end of the index of the layer and not at the beginning. Is this possible?

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  Dan

• calculated formula database field trying to insert the null value

  Hello
  
  I have 3 elements of database text amount, rate and result.
  I enter both values (quantity and frequency), and the property using formula 'result' Gets the computed value.
  On the screen all the values are displayed correctly but when trying to save my information text field 'result' tent to insert the null value.
  
  Any suggestions?
  
  Forms 11g
  
  Thanks in advance

  794018 wrote:
  Hello

  I have 3 elements of database text amount, rate and result.
  I enter both values (quantity and frequency), and the property using formula 'result' Gets the computed value.
  On the screen all the values are displayed correctly but when trying to save my information text field 'result' tent to insert the null value.

  Point formula should not be issue of database. And insert the value in the result column in the database is not good idea.
  Then, if you want to save it. create the database result item and write trigger (When-validate-point) on amount and filed rates and the trigger code, write

  :result:=:amount*:rate;
  

  To display the result on the form, create the database no item and change the formula property and write the formula.

  Hope this will help you

  If someone useful or appropriate, please mark accordingly.

• May I ask where clause to satisfy two conditions at the same time (and)

  Hello

  I wrote a few joins and usually in the final stage where condition with certain conditions be satisfied in where clause. In all conditions where I only want one and condition fulfilled only if both are collected.

  If we look at the this funciton is I should meet (get_order_type (ogr.order_number) <>'R')) AND wh1.third_party_warehouse! = 'Y') but I'm not get rid off both that if order_type is 'R' they are removed and if tooling_group is yes then ther are removed the result. I'm trying with both below pointed out together how can check these conditions? I can do in where clause?

  ((sg.tooling_stock_group <> 'Y'))

  and

  (get_order_type (ogr.order_number) <>'R'))

  Of order_goods_received ogr

  LEFT JOIN part_master pm

  On ogr.part_number = pm.part_number

  -stock_groups sg left join

  SG stock_groups left join

  on pm.stock_group = sg.stock_group

  and ((sg.tooling_stock_group! = 'Y'))

  and (get_order_type (ogr.order_number)! = 'R'))

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  LEFT JOIN batch_record_1 br1

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  AND

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  AND

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  get_order_type (OGR.order_number) NOT IN ('L') AND

  OGR.returned_to_supplier_indicator not in('S','L') and

  -sg.tooling_stock_group <>'Y '.

  -((sg.tooling_stock_group <> 'Y') and (get_order_type (ogr.order_number) not in ('R')))

  -(get_order_type (OGR.order_number) <>'R' AND sg.tooling_stock_group <>'Y')

  ((sg.tooling_stock_group <> 'Y'))

  and

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  UNION

  (

  Thank you.

  Whenever you have a problem with such logic, you should try and draw a logic state diagram:

  In your case, you are looking to two variables, with two possible States (equal to a value or is not it)

  Then, take this sense of the sg.tooling_stock_group T and O as being the get_order_type (ogr.order_number) and create a state diagram logical based on your description of what you want.  We will use a value of "Y" to indicate we want to record and a value of "N" to indicate the folder should not be returned.

  Start with an empty logical diagram...

  T = 'Y' T! = « Y »
  +---------+---------+
  |         |         |
  |         |         |
  |         |         | O = 'R '.
  |         |         |
  |         |         |

  
  +---------+---------+
  |         |         |
  |         |         |
  |         |         | O! = « R »
  |         |         |
  |         |         |
  +---------+---------+

  First of all, you said: "If there is the result returned by the defined user function is"R"and the table that has the tooling_stock_group y then it should avoid this record."

  T = 'Y' T! = « Y »
  +---------+---------+
  |         |         |
  |         |         |
  |    N    |         | O = 'R '.
  |         |         |
  |         |         |
  +---------+---------+
  |         |         |
  |         |         |
  |         |         | O! = « R »
  |         |         |
  |         |         |
  +---------+---------+

  Then you said: "If order_type does not return" R' but the tooling_stock_group is 'Y', then I should not avoid recording ".

  T = 'Y' T! = « Y »
  +---------+---------+
  |         |         |
  |         |         |
  |    N    |         | O = 'R '.
  |         |         |
  |         |         |
  +---------+---------+
  |         |         |
  |         |         |
  |    Y    |         | O! = « R »
  |         |         |
  |         |         |
  +---------+---------+

  Now, you have not given any logic for the rest of the diagram, so I made the assumption that you do not want to avoid these records...

  T = 'Y' T! = « Y »
  +---------+---------+
  |         |         |
  |         |         |
  |    N    |    Y    | O = 'R '.
  |         |         |
  |         |         |
  +---------+---------+
  |         |         |
  |         |         |
  |    Y    |    Y    | O! = « R »
  |         |         |
  |         |         |
  +---------+---------+

  Now there are different ways to determine the location of the clause of this diagram.
  We could say that we want the records for all of the T column! = "Y" or all the records for all of the O line! " = R...

  where (sg.tooling_stock_group! = 'Y' or get_order_type (ogr.order_number)! = 'R')

  We say we want to EXCLUDE (using DO NOT) all records where T = "Y" AND O = "O" "

  If not (sg.tooling_stock_group = 'Y' and (ogr.order_number) get_order_type = 'R')

  Those are the two most logical ways to do.
  (In my previous answer, that we can see in this diagram, there is no need of the "or get_order_type (ogr.order_number).) (= 'R' "part, which is superfluous, but would not break it)

  Now let's look at your logic to see what it looks like to in the diagram...

  where ((sg.tooling_stock_group <> «Y»))
  and (get_order_type (ogr.order_number) <> 'R')
  )

  In a logic diagram that looks to...

  T = 'Y' T! = « Y »
  +---------+---------+
  |         |         |
  |         |         |
  |    N    |    N    | O = 'R '.
  |         |         |
  |         |         |
  +---------+---------+
  |         |         |
  |         |         |
  |    N    |    Y    | O! = « R »
  |         |         |
  |         |         |
  +---------+---------+

  As you can see, your logic was only targeting one of the 4 possible results for select records and excluding 3.

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